I'm going to pick a number between 0 and 10 inclusive, multiply it by 5, add 7 to the result, multiply that sum by 2, then pick a number between 0 and 10 to add to my product, then subtract 6. My result is 45. What is the product of the two numbers I picked?

Answers

Answer 1

We want to find the two numbers you picked, we will find that the two numbers you picked are 3 and 7.

First, you pick a number between 0 and 10, let's say that the number is N.

Then multiply it by 5 and add 7, so we get:

(5*N + 7)

Now we multiply this by 2

2*(5*N + 7)

Now we add another number between 0 and 10, let's call it M.

We need to add that to the product, and then subtract 6, and that will be equal to 45.

2*(5*N + 7) + M - 6 = 45

Now let's simplify the expression:

2*(5*N + 7) + M = 45 + 6 = 51

10*N + 14 + M = 51

10*N + M = 51 - 14 = 37

10*N + M = 37

With this, we want to find the values of N and M, but remember that these two values belong to the interval [0, 10]

So the only two solutions are:

N = 3 and M = 7

such that:

10*3 + 7 = 30 + 7 = 37

So the two numbers you picked are 3 and 7.

If you want to learn more, you can read:

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Learn more here:

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STEPS MUST.​

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We have to Find:

The value of x

[tex] \sf \longmapsto5^{ - x }= 6[/tex]

Let's start.

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Take the minus from (-x) and put in on log(6)

[tex] \sf \longmapsto \: x = \dfrac{ -log(6) }{ + log(5)} [/tex]

Done

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Answers

Answer:

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Answer:

2a:

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[tex]=(a^2+\frac{4}{5})(a^4-\frac{4a^2}{5}+\frac{16}{25} )[/tex]

---------------------------------------------

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Will give brainliest

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