Answer:
6.23 mm
Explanation:
The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...
a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²
Then the force on the car (in addition to that required to counter gravity) is ...
F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N
The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...
((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm
The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.
_____
We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).
Answer:
Explanation:
Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,
its centrifugal acceleration = speed^2 / radius
= 23^2 / 600
= 0.8817 m/s^2
The centrifugal force in turn = mass * acceleration
= 1300 * 0.8817
= 1146.17 N
This force is absorbed by suspension springs of the four wheels.
Given spring constant of 4.6 x 10^4 N/m and 4 springs total,
the extra compression = Force / number of springs / spring constant
= 1146.17 / 4 / 4.6 x 10^4
= 0.006229 m
= 6.23 mm
Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.
How would natural cycles (day/night, moon phases) change if gravity did not
exist?
Answer: Eh, we would be dead...
Explanation: First off, the moon is orbiting us for one reason, gravity. and if the switch for gravity just flicked off, poof! The moon would be speeding away at 1,000-2,000 hours! And the reason that we orbit the sun is gravity too. So every planet would fling into space. Everything in the UNIVERSE would fling into space. That much flying debris would eventually smash into earth. Well, if we did survive that, then we would freeze instantly because when we travel too far away from the star that we orbit, the planet would become very life-threateningly cold. And in this case, we are traveling away from the sun, which is the star we orbit. If we still manage to survive THAT, then we...would actually die from the start, cuz what holds our planet together? You guessed it-gravity.
Which of the following would increase the gravitational force between the Earth and the Moon the most?
A- Double the Mass of the Earth
B- Double the Mass of the Moon
C- Cut the distance between the Earth and Moon in half
D- None of the above
Answer:
i think C is the answer
Explanation:
The gravitational force between the Earth and Moon will increase by cutting the distance between the Earth and Moon in half. Hence, option (C) is correct.
The given problem is based on the concept of gravitational force. The force of attraction between the two massive bodies in a space is known as the gravitational force. Let us consider the mass of Earth and moon as M and m such that the gravitational force between each is,
[tex]F = \dfrac{G \times M \times m}{R^{2}}[/tex]
Here,
G is the universal gravitational constant.
R is the distance between the Earth and Moon.
Clearly, the forces between the Earth and Moon varies directly with the masses of Earth and Moon and inversely with the distance between the Earth and Moon. Since, masses are the constant parameters, hence reducing the distance will increase the gravitational force.
Thus, we can conclude that the gravitational force between the Earth and Moon will increase by cutting the distance between the Earth and Moon in half. Hence, option (C) is correct.
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w
х
2. Identify the correct statement about the diagrams above.
O Y represents a mixture and Z represents an element.
O Y represents an compund and X represents a pure substance.
O X represents a mixture and W represents a pure substance
O W represents an element and Y represents a mixture.
Answer: W represents an element Y represents a mixture
Explanation: I just took a quiz on this and got it right. Good Luck
QUESTION
The strongest Stars used to be called
what?
Answer:
Absolute magnitude
Explanation:
The brightness a star would have if it were at 10 pc from Earth is called Absolute magnitude.
8. A dog runs with an initial speed of 7.5 m/s on a waxed floor. It slides to a stop in 15 sec. What
is the acceleration?
(10 Points)
O-7.5 m/s
-0.5 m/s2
O -7.5 m/s2
7.5 mi/hr
Answer:
-0.5 m/s²
Explanation:
Step 1: Given data
Initial velocity of the dog (u): 7.5 m/sFinal velocity of the dog (v): 0 m/s (Stop)Time elapsed (t): 15 sStep 2: Calculate the acceleration of the dog
The acceleration (a) is equal to the change in the velocity over the time elapsed.
a = v - u / t
a = 0 m/s - 7.5 m/s / 15 s
a = -0.5 m/s²
You walk 8 blocks West, 2 blocks South, 9 blocks East, 3 blocks North, 4 blocks South. What
is the displacement between your starting and endpoints? What is the angle of displacement?
someone pls help me it’s important and i don’t know how to answer it!!
Answer:
...............,........................
What is called mass per unit
volume of a substances? | ककसी पदाथष के
द्रव्यमान प्रतत इकाई आयतन को क्या कहते हैं?
A : Mass | द्रव्यमान
B : Weight | भार
C : Density | घनत्व
D : Volume | आयतन
Ans:
C : Density | घनत्व
Answer:
Density
Explanation:
The definition of density of a substance is the quotient between its mass and its volume. Such results in the mass per unit of volume.
8. Using Newton's second law, solve the following problems using
GFFS.
a. A force of 35N is applied to a 25kg object, what is its
acceleration??
b. What force is required to accelerate a 14kg object at 4.5
m/s2?
c. Calculate the mass of an object that accelerated at a rate of
2.7 m/s2 by a force of 18N.
Answer:
a) 1.4 m/s2
b) 63N
c) 6.66kg
2.9030 cm has 4 significant digits.
TRUE OR FALSE
Answer: false
Explanation:
A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis
ball moving 22 m/s to the left. After the collision, the tennis ball is moving
32.7 m/s to the right. What is the velocity of the basketball after the collision?
Assume an elastic collision occurred.
A. 10.9 m/s to the right
B. 10.9 m/s to the left
C.3.6 m/s to the left
D. 3.6 m/s to the right
Answer:b
Explanation:
The final velocity of the basketball after it undergoes collision with the tennis ball is 6.49m/s.
What is Final velocity?The final velocity is a vector quantity which measures the speed and direction of a moving object after it has reached its maximum acceleration and distance.
Given data,
mass of basket ball (m₁) = 0.6kg
mass of tennis ball (m₂) = 0.04kg
velocity of basket ball (v₁) = 7.2m/s
velocity of tennis ball (v₂) = 22m/s
velocity of basket ball (v₃) =?
velocity of tennis ball (v₄) = 32.7m/s
We already know that the expression for elastic collision is given as
m₁v₁ +m₂v₂ = m₁v₃ + m₂v₄
Substituting these values, we get
0.6 × 7.2 + 0.04 × 22 = 0.6 × x + 0.04 × 32.7
4.32 + 0.88 = 0.6x + 1.308
Solving for x we have,
3.892 = 0.6x
x = 3.892 /0.6
x=6.49m/s
Therefore, the velocity of the basketball after the collision is 6.49m/s.
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which graph best demonstrates the general relationship between mass and temperature similar to the trend of thermal energy absorbed by your sand and water samples
Answer: the first one
Explanation: got it right on edg
Answer:
The first graph
Explanation:
Correct on Edge 2022! :]
A hammer drives a nail into a piece of wood. Which of the following correctly
identifies the pair of equal and opposite forces involved.
A. The hammer exerts a force on the nail: the nail exerts a force on the wood
B. The hammer exerts a force on the nail: the wood exerts a force on the nail.
C. The nail exerts a force on the hammer: the hammer exerts a force on the wood.
D. The hammer exerts a force on the nail: the nail exerts a force on the hammer.
Answer:
D
Explanation:
The statement which correctly describes the pair of equal and opposite forces involved is that the hammer exerts a force on the nail: the nail exerts a force on the hammer. Thus, the correct option for this question is D.
What is Force?Force may be defined as the process that significantly involves the pulling and pushing of an object with mass which stimulates itself to change its velocity accordingly. It is a type of vector quantity because it has both magnitude and direction.
According to Newton's third law of motion, if object A exerts a force on object B, then object B must significantly exert a force of equal magnitude and opposite direction on object A. Here, object A is a hammer, and object B is a nail.
Therefore, the hammer exerts a force on the nail: the nail exerts a force on the hammer is the statement that correctly describes the pair of equal and opposite forces. Thus, the correct option for this question is D.
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A 70 kg student is riding on a skateboard at 4m/s. A 60 kg student is also riding a
skateboard at 4 m/s. Which statement below demonstrates an understanding of
Newton's 1st Law of Motion?
A. Since both students are traveling at the same speed they must have the same
inertia
B. Since both students are traveling at the same speed they must have the same
mass
C. One student has more mass and therefore more inertia
5. Why should the free ends of a conduction tester not be connected for a long
time?
If the free ends of conduction tester are connected for long time , The cell of the battery will drain very quickly
rt A How much work does the electric motor of a Van de Graaff generator do to lift a positive ion (q=e) if the potential of the spherical electrode is 2.0 MV ?
Answer:
W = 2.0 MeV = 3.2*10⁻¹³ J
Explanation:
Assuming that the ion is located originally at a point where the electrostatic potential is zero, the change in energy of the ion is just the change in electrostatic potential times the charge of the ion, as follows:[tex]\Delta E = e*V = 1.6e-19 C * 2.0e6 V = 2.0 MeV = 3.2e-13 J[/tex]
This change in energy, assuming no friction present, must be equal to the work done by the motor on the ion:W = 2.0 MeV = 3.2*10⁻¹³ J.
HELP!
Which process of heat transfer makes milk boil?
Answer:
milk is raised to a certain level for sometimes and immediately cooled to the lower degree
a horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
Answer:
12.5m/s
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = 12.5
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
Online Content: Site 1
How do wetlands reduce flooding and erosion? (Site 1)
Answer:
Wetlands reduce flooding and erosion by filtering water.
Explanation:
Answer:
Wetlands reduce flooding and erosion by filtering water.
Explanation:
a hole is punched at a height h in the side of a container of height h0. The container is full of water. If the water is to shoot as far as possible horizontally, (a) how far from the bottom of the container should the hole be punched? (b) Neglecting frictional losses, how far (initially) from the side of the container will the water land?
Imagine you are outside playing with a dog. The dog runs back and forth, left to right. What is the best way to describe how fast the dog's motion is?
The direction the dog moves.
The distance the dog moves over a certain amount of time.
The distance the dog moves.
Answer:
It is B.
Explanation:
This is because you want to see how fast the dog moves and the best way to find out is by seeing how fast it moves in a certain amount of time. pls brainly!
Nora notices water droplets on the grass in the morning. It did not rain during the night. Which statement is true about this change of state?
Mass was added to the water particles, resulting in deposition.
Energy was added to the water particles, resulting in evaporation.
Mass was removed from the water particles, resulting in sublimation.
Energy was removed from the water particles, resulting in condensation.
Answer:
Mass was added to the water particles, resulting in deposition.
Explanation:
Answer: The energy was removed from the water particles resulting in condensation
Explanation Think about when you leave a cup of ice of and after a while you see water droplets thats what happened to the grass in the morning and thats called condensation.
A metal wire has a circular cross section with radius 0.800 mm. You measure the resistivity of the wire in the following way: you connect one end of the wire to one terminal of a battery that has emf 12.0 V and negligible internal resistance. To the other terminal of the battery you connect a point along the wire so that the length of wire between the battery terminals is d. You measure the current in the wire as a function of d. The currents are small, so the temperature change of the wire is very small. You plot your results as I versus 1/d and find that the data lie close to a straight line that has slope 600 A⋅m.
Required:
What is the resistivity of the material of which the wire is made?
Answer:
The value is [tex]\rho = 4.02 *10^{-8} \ \Omega \cdot m[/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 0.800 mm = 0.0008 \ m[/tex]
The voltage of the battery is [tex]emf = 12.0 V[/tex]
The slope is [tex]s = 600 \ A \cdot m[/tex]
Generally the resistance is mathematically represented as
[tex]R = \frac{\rho * d }{A }[/tex]
Generally the current is mathematically represented as
[tex]I = \frac{V}{R}[/tex]
=> [tex]I = \frac{V}{\frac{\rho * d }{A }}[/tex]
=> [tex]I = \frac{V * A }{\rho} * \frac{1}{d}[/tex]
Comparing this equation to that of a straight line we see that the slope is
[tex]s = \frac{V * A }{\rho}[/tex]
So [tex] 600 = \frac{V * A }{\rho}[/tex]
Here A is the cross-sectional area of the wire which is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * (0.0008 )^2[/tex]
=> [tex]A = 2.011*10^{-6} \ m^2[/tex]
So
[tex] 600 = \frac{12.0 * (2.011*10^{-6}) }{\rho}[/tex]
=> [tex]\rho = \frac{12 * 2.011*10^{-6} }{600}[/tex]
=> [tex]\rho = 4.02 *10^{-8} \ \Omega \cdot m[/tex]
When does a scatter plot show a correlation?
Answer:
Mark brainliest please
Explanation:
If the data points make a straight line going from the origin out to high x- and y-values, then the variables are said to have a positive correlation .When there is no clear relationship between the two variables, we say there is no correlation between the two variables.
Suppose Tom Harmon17 is standing at the exact center of the Ohio State football field18 on the 50 yard line. The field is 300 feet long and 160 feet wide. Suppose the ball leaves Harmon’s hand at a height of six feet and has initial velocity v(0) = 40i + 39j + 32k feet per second where j points toward the sideline, i points toward the end zone, and k = i × j points straight up. The acceleration due to gravity is −32k feet per second squared and the mass of the football is .45 kilograms.
(a) Determine a parameterization for the position of the football at time t seconds after it is thrown.
(b) Suppose David Nelson19 catches the ball when it is six feet above the ground. Is Nelson in bounds or out of bounds when he catches the ball? (Assume Nelson’s toes are touching the ground directly below the ball when he catches the ball.)'
Answer:
a) x = 40 t , y = 39 t , z = 6 + 32 t - 16 t ², b) x = 80 feet , y = 78 feet , the ball came into the field
Explanation:
a) This is a projectile launch exercise, where in the x and y axes there is no acceleration and in the z axis the acceleration of the acceleration of gravity, let's write the equations of motion in each axis
Since the cast is in the center of the field, let's place the coordinate system
x₀ = 0
y₀ = 0
z₀ = 6 feet
x-axis (towards end zone, GOAL zone)
x = xo + v₀ₓ t
x = 40 t
y-axis (field width)
y = y₀ + [tex]v_{oy}[/tex] t
y = 39 t
z axis (vertical)
z = z₀ + v_{oz} t - ½ g t²
z = 6 + 32 t - ½ 32 t²
z = 6 + 32 t - 16 t ²
b) The player catches the ball at the same height as it came out, so we can find the time it takes to arrive
z = 6
6 = 6 + 32 t - 16 t²
(t - 2)t = 0
t=0 s
t= 2 s
The ball position
x = 40 2
x = 80 feet
y = 39 2
y = 78 feet
the dimensions of the field from the coordinate system (center of the field) are
x_total = 150 feet
y _total = 80 feet
so we can see that the ball came into the field
The diagram below represents an electromagnetic wave. Please Help
Answer:
I'm pretty sure it's A
Explanation:
bc the crest is is the point on the wave
The particle model shows the image of the moving object.
TRUE OR FALSE
ANSWER AND I WILL GIVE YOU BRAINILIEST
Answer:
it does show the objects position
What is the acceleration along the ground of a 18 kg wagon when it is pulled with a force of 91 N at an angle of 35° Above the horizontal?
Answer:
4.1 m/s²
Explanation:
Net force in the x direction equals the mass times the acceleration.
∑F = ma
91 cos 35° = (18 kg) a
a = 4.1 m/s²
Answer:
Explanation:
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Describe two similarities and two differences between electric and magnetic field lines. (Consider such things as where they originate and terminate, how they are related to the direction and strength of the field, whether they are closed curves or lines, and whether there's anything you can say about their flux through a closed surface.). Others
Answer:
Please see below as the answer is self- explanatory.
Explanation:
Similarities:The field vector is tangent to the field lines at any point of the trajectory.The density of field lines is proportional to the strength of the field.Differences:Electrostatic Field lines originate in charge distributions of positive charges and end in charge distributions of negative charges.Magnetic Field lines are closed lines, due to there are no isolated magnetic charges discovered yet.Electrostatic Field lines have the direction of the trajectory taken by a positive test charge.Magnetic Field lines have the direction defined by right-hand rule.Vector net flux of electrostatic field lines through a closed surface is equal to the net charge enclosed by the surface.Vector net flux of magnetic field lines through a closed surface is always zero.Similarities
Field vectorDensity of field linesDifferences
Dispersions of positive charges .No separated attractive charges.Electric and Magnetic field lines.Similarities:
The field vector is tangent to the field lines at any point of the trajectory. The density of field lines is relative to the quality of the field.
Differences:
Electrostatic Field lines begin in charge dispersions of positive charges and conclusion in charge dispersions of negative charges.
Magnetic Field lines are closed lines, due to there are no separated attractive charges found yet.
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Vaccinations _____.
always prevent disease
never cause side effects
provide artificial immunity
are rarely given more than once
Suppose that a Ferrari and a Porsche begin a race with a moving start, and each moves with constant speed. One lap of the track is 2 km. The Ferrari laps the Porsche after the Porsche has completed 9 laps. If the speed of the Ferrari had been 10 km/h less, the Porsche would have traveled 18 laps before being overtaken. What were the speeds of the two cars?
Answer:
Porsche = 180 kmph
Ferrari = 200 kmph
Explanation:
Given that
The distance of one lap = 2 km
The distance the Ferrari laps the Porsche = 9 laps
The distance the Ferrari will lap the Porsche with 10 km/h less speed = 18 laps
So we say let,
the speed of the Ferrari = S(f),
the speed of the Porsche = S(p), and
the time that lapse before two cars lapped = t
From the question, we're told that
(S(f) * t1) - (S(p) * t1) = 2 km, also
S(p) * t1 = 9 * 2 = 18 km
Referring back to the initial equation
(S(f) * t1) = 2 + (S(p) * t1)
(S(f) * t1) = 2 + 18 = 20 km
Going back to the question again, we're told that
(S(f) - 10) * t₂ - S(p) * t₂ = 2 km
S(p) * t₂ = 18 * 2 = 36 km
So that,
(S(f) - 10) * t₂ = 2 km + S(p) * t₂
(S(f) - 10) * t₂ = 2 + 36 km = 38 km
(S(f) - 10) * t₂ = 38 km
S(p) * t₂ (36 km) = 2 * S(p) * t₁ (18 km),
S(p) * t₂ = 2 * S(p) * t₁, collect like terms
t₂ = 2t₁
(S(f) - 10) * 2t₁ - S(p) * 2t₁ = 2 km
(S(f) - 10) * 2t₁ = 38 km
(S(f) - 10) * 2t₁ = 38 km
2t₁ * S(f) - 2t₁ * 10 = 38 km
S(f) * t₁ = 20 km,
2 * 20 km - 2t₁ * 10 = 38 km
2t₁ * 10 = 2 * 20 km - 38 km
2t₁ * 10 = 2 km
20t₁ = 2 km
t₁ = 2/20 = 0.1 hour = 6 minutes
This means that
S(p) * t₁ = 18 km
S(p) * 0.1 h = 18 km
S(p) = 18 km/0.1 h = 180 km/h
The speed of the Porsche = S = 180 km/h
S(f) * t₁ = 20 km
S(f) × 0.1 h = 20 km
S(f) = 20 km/0.1 h = 200 km/h
The speed of the Ferrari = S = 200 km/h