in a train 1/3 of the passengers are listening to music. five passengers are chosen at random. find the probability that exactly three are listening to music

The false equation among them is r = a + b sino is a snail (Limacons).

Therefore option D is correct.

In a snail-shaped limaçon, the equation typically takes the form r = a + b*cosθ, where a and b are constants.

The cosine term in the equation gives rise to the inner loop or dimple of the limaçon.

The equation of the cardioid is r = a(1 + cos(θ)),

a =  distance of the center of the cardioid from the origin.

In conclusion, we can say the equation r = a + b*sino does not represent a snail-shaped limaçon but  represents a cardioid or heart-shaped curve.

The sine term in the equation creates the cusp or point at the top of the heart shape.

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The area of the attached quadrilaterals are

area of rhombus = 20 square units

area of rectangle  = 60 square units

none of the above

The formula for area of rhombus is

Area = base × height

Area = 5 × 4

= 20 square units

The formula for area of rectangle is

Area = length × width

Area = 10 × 6

= 60 square units

The formula for area is

Area = base × height

Area = 7 × 4

= 28 square units

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Answer:

To solve the given equation by factoring, we first rearrange the terms to get:

9x^3 - 48x^2 - 36x = 0

We can factor out a common factor of 9x to obtain:

9x(x^2 - 5.33x - 4) = 0

Next, we can factor the quadratic expression inside the parentheses using the quadratic formula or by factoring by grouping. Using the quadratic formula, we have:

x = [5.33 ± sqrt(5.33^2 + 4(4))]/2

x = [5.33 ± sqrt(42.89)]/2

x = 4.85 or x = 0.48

Therefore, the solutions to the original equation are:

x = 0 (from the factor of 16x on the left-hand side of the equation)

x = 4.85

x = 0.48

Step-by-step explanation:

The work done between point 1 and point 2 for the conservative field F is undefined or does not exist.W = 0

Given the field F =

F = [tex](y + z)i + x + x^3 + xk[/tex];

and two points P1(0, 0, 0) and P2(2, 10, 5). We need to evaluate the work done between point 1 and point 2 for the conservative field F.

The work done for a conservative field is calculated using the potential energy.

We need to determine if the field F is conservative or not before we can proceed with calculating the work done.

A vector field F is conservative if and only if it satisfies the condition:

∇ × F = 0.

The curl of the vector field F is:

∇ × F = (∂Q/∂y - ∂P/∂z)i + (∂R/∂z - ∂T/∂x)j + (∂P/∂x - ∂R/∂y)k

Comparing with the given field

F =[tex](y + z)i + x + x^3 + xk[/tex];

P = x,

Q = y + z,

R = 0, and

T = 0So,

∇ × F = (∂Q/∂y - ∂P/∂z)i + (∂R/∂z - ∂T/∂x)j + (∂P/∂x - ∂R/∂y)k

= (1 - 0)i + (0 - 0)j + (0 - 0)k

= i

Thus, ∇ × F ≠ 0

The given field F is not conservative, since it doesn't satisfy the above condition, which means the work done can not be calculated by using potential energy.

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The work done between point 1 and point 2 for the conservative field F is 20.

Given,F = (y + z) i + x + x³ + x k;

P1(0, 0, 0),

P2(2, 10, 5)

We need to evaluate the work done between point 1 and point 2 for the conservative field.

Here,We know that the work done for conservative forces is independent of the path followed by the object. It only depends on the initial and final positions of the object.

Work done in conservative force is given by:

W = -ΔPE

where ΔPE is the potential energy difference between the initial and final positions.

We know that a conservative field F is a field where the work done by the field on an object that moves from one point to another is independent of the path followed.

The conservative field F is given as:

F = (y + z) i + x + x³ + x k

Therefore, The work done between point 1 and point 2 for the conservative field F is 20.

Hence, the correct option is W = 20.

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The steady-state concentration of carbon dioxide is 0.005.

Air containing 0.06% carbon dioxide is pumped into a room whose volume is 12,000 ft. The air is pumped in at a rate of 3,000 r/min, and the circulated air is then pumped out at the same rate.

If there is an initial concentration of 0.3% carbon dioxide, determine the subsequent amount A(e), in ft³, in the room at time t. A(L).

We have to find the concentration of carbon dioxide at 10 minutes, and the steady-state, or equilibrium, concentration of carbon dioxide.Solution:

First, we will calculate the subsequent amount A(e), in ft³, in the room at time t. A(L) using the formula:

[tex]\[{A_e} = \frac{{{\rm{rate}}\;{\rm{of}}\;{\rm{flow}}}}{{{\rm{rate}}\;{\rm{of}}\;{\rm{loss}}}}\left( {{C_0} - {C_e}{e^{ - kt}}} \right)V\][/tex]

Here,Rate of flow (R) = 3000 ft³/min

Volume of the room (V) = 12000 ft³

Initial concentration of carbon dioxide (C₀) = 0.3%

= 0.003

Concentration of carbon dioxide at time t (Cₑ) = 0.06%

= 0.0006

Rate of loss (k) = Rate of flow/Volume of the room

k = R/V

= 3000/12000

= 0.25

Therefore,k = 0.25

Substituting all the values in the formula,[tex]\[{A_e} = \frac{{3000}}{{3000}}\left( {0.003 - 0.0006{e^{ - 0.25t}}} \right)12000\]\ {A_e}[/tex]

= [tex]4.8\left( {0.003 - 0.0006{e^{ - 0.25t}}} \right)\][/tex]

Now we have to find the concentration of carbon dioxide at 10 minutes.So, we will substitute the value of time, t = 10 in the above equation.

[tex]\[{A_e} = 4.8\left( {0.003 - 0.0006{e^{ - 0.25\times 10}}} \right)\]\ {A_e}[/tex]

=[tex]4.8\left( {0.003 - 0.0006 \times 0.13533528} \right)\]\ {A_e}[/tex]

= [tex]0.0145\;ft^3\][/tex]

To find the concentration of carbon dioxide at 10 minutes, we can use the formula:

[tex]\[{C_e} = {C_0}{e^{ - kt}} + \frac{{R\;{\rm{flow}}}}{{V\;{\rm{loss}}}}\left( {1 - {e^{ - kt}}} \right)\][/tex]

Substituting all the values in the above formula, we get:

[tex]\[{C_e} = 0.003{e^{ - 0.25 \times 10}} + \frac{{3000}}{{12000 \times 0.25}}\left( {1 - {e^{ - 0.25 \times 10}}} \right)\]\ {C_e}[/tex]

= 0[tex].000664 + 0.002205\left( {1 - 0.13533528} \right)\]\ {C_e}[/tex]

=[tex]0.001896\[[/tex]

Therefore, the concentration of carbon dioxide at 10 minutes is 0.002 (rounded to three decimal places).

The steady-state, or equilibrium, concentration of carbon dioxide is found by setting t = ∞ in the expression for Ce:

[tex]\[{C_e} = \frac{{R\;{\rm{flow}}}}{{V\;{\rm{loss}}}}\]\ {C_e}[/tex]

= [tex]\frac{{3000}}{{12000 \times 0.25}}\]\ {C_e}[/tex]

[tex]= 0.005\][/tex].

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The steady-state concentration C, which represents the equilibrium concentration of carbon dioxide in the room.

To determine the subsequent amount of carbon dioxide A(t) in the room at time t, we can use a differential equation that relates the rate of change of carbon dioxide concentration to the inflow and outflow rates.

Let's denote the concentration of carbon dioxide at time t as C(t) (in decimal form), and the volume of the room as V. The rate of change of carbon dioxide concentration is given by:

dC/dt = (inflow rate - outflow rate) / V

The inflow rate is the rate at which carbon dioxide is being pumped into the room, and the outflow rate is the rate at which carbon dioxide is being pumped out of the room. Since both inflow and outflow rates are constant and equal to 3,000 r/min, we can write:

dC/dt = (3000 * C_in - 3000 * C) / V

Where C_in is the initial concentration of carbon dioxide and C is the current concentration at time t.

To solve this differential equation, we can separate the variables and integrate:

∫(1 / (C_in - C)) dC = (3000 / V) * ∫dt

Integrating both sides, we get:

ln|C_in - C| = (3000 / V) * t + k

Where k is the constant of integration. Exponentiating both sides, we have:

C_in - C = Ae^((3000 / V) * t)

Where A = e^k is the constant of integration.

Now, to determine the subsequent amount A(t) in ft³ of carbon dioxide in the room at time t, we multiply the concentration C by the volume V:

A(t) = C(t) * V = (C_in - C) * V = Ae^((3000 / V) * t) * V

Given that the initial concentration C_in is 0.003 (0.3% in decimal form) and the volume V is 12,000 ft³, we have:

A(t) = 0.003e^((3000 / 12000) * t) * 12,000

Now we can use this equation to answer the given questions.

Concentration of carbon dioxide at 10 minutes:

To find the concentration at 10 minutes, substitute t = 10 into the equation:

A(10) = 0.003e^((3000 / 12000) * 10) * 12,000

Calculate the value of A(10) to determine the concentration of carbon dioxide at 10 minutes.

Steady-state or equilibrium concentration:

In the steady state, the amount of carbon dioxide in the room remains constant over time.

This occurs when the inflow rate is balanced by the outflow rate. In this case, both rates are 3,000 r/min.

So, we set the rate of change of carbon dioxide concentration to zero:

0 = (3000 * C_in - 3000 * C) / V

Solve this equation to find the steady-state concentration C, which represents the equilibrium concentration of carbon dioxide in the room.

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The correct graph of the function f(x) = log3x is option 2.

"On a coordinate plane, a logarithmic function approaches the y-axis in quadrant 4 and then increases into quadrant 1 and approaches y = 2. It goes through (1, 0) and (3, 1)."

A logarithm with the base 3 is represented by the function f(x) = log3x. The base in logarithmic functions controls how the graph behaves.

The graph begins at negative infinity on the left side and moves towards the y-axis in quadrant 4 when the base is bigger than 1, as it is in this instance with base 3.

It then starts to ascend, passing through the point (1, 0), and it keeps getting higher as x grows. As x gets closer to positive infinity, but never reaches it, the graph moves towards y = 2.

Additionally, it addresses points (3) and (1).

Therefore, the graph of f(x) = log3x is the second statement.

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The area of the shaded region is calculated as: 199.0 cm²

The formula for area of a sector is given by the formula:

Area = θ/360 * πr²

Thus:

Area of sector = Area of circle/6    

=  (120/360) * π * 18²

=  339.29 cm²

Now, area of triangle here is:

Area =¹/₂ * 18 * 18 * sin 120

Area = 140.296 cm²

Area of shaded region = area of sector - area of triangle

Area of shaded region = 339.29 unit² - 140.296 cm²

Area of shaded region = 198.994 ≈ 199.0 cm²

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For the the linear transformation T by T(x)=Ax,

ker(T) = span{(-3, 1)}, nullity(T) = 1, range(T) = span{[5, 1, 1], [-3, 1, -1]}, and rank(T) = 2.

1. To find the kernel (null space) of T, we need to find all vectors x such that Ax = 0, where 0 is the zero vector.

So we solve the equation:

Ax = 0

Using row reduction:

[[5, -3, 0], [1, 1, 0], [1, -1, 0]] ~ [[1, 0, 3], [0, 1, -1], [0, 0, 0]]

The solution is x = (-3t, t) for some scalar t.

So, the kernel of T is the set of all scalar multiples of the vector (-3, 1).

ker(T) = span{(-3, 1)}

2. The nullity of T is the dimension of the kernel, which is 1.

3. To find the range (image) of T, we need to find all possible vectors Ax as x varies over all of R^2.

Since A is a 3x2 matrix, we can write Ax as a linear combination of the columns of A:

Ax = x1 [5, 1, 1] + x2 [-3, 1, -1]

where x1 and x2 are scalars.

So the range of T is the span of the columns of A:

range(T) = span{[5, 1, 1], [-3, 1, -1]}

4. To find the rank of T, we need to find a basis for the range of T and count the number of vectors in the basis.

We can use the columns of A that form a basis for the range:

basis for range(T) = {[5, 1, 1], [-3, 1, -1]}

So the rank of T is 2.

Therefore, ker(T) = span{(-3, 1)}, nullity(T) = 1, range(T) = span{[5, 1, 1], [-3, 1, -1]}, and rank(T) = 2.

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The Attendance was low.

We know, The left edge of the box indicates the lower quartile, representing the value below which the first 25% of the data is located.

Similarly, the right edge of the box represents the upper quartile, indicating that 25% of the data is situated to the right of this value.

From the given box plot we can say that the Attendance was not high because the quartiles located.

Now, from plot we can say that quartiles are clustered towards the left on the number line.

This means that the Attendance was low.

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the value of double integral is 2/21.

Sketching the region, R: Now, we will sketch the given region R. By observation, the equation for the region enclosed by

x = y²

and x = -y² + 2

is y = √(x)

and y = -√(x)

respectively. This can be seen by solving the two equations as follows:

y² = x and

y² = 2 - x.

By adding the two equations, we get:

2y² = 2, or

y² = 1,

which implies that

y = ±1.

Since y = ±√(x) passes through the point (1, 1) and (1, -1), the required region is enclosed by the parabolas y² = x and

y² = 2 - x and bounded by the lines

y = 1 and

y = -1.

Therefore, the region R is given by the shaded region in the figure below:Set up the iterated integrals:The required iterated integrals are:

∫[1,-1] ∫[0, y²] dy dx + ∫[1,-1] ∫[2-y², 2] dy dx

Hence, the iterated integrals for the double integral using the suitable orders of integration are mentioned above.Evaluate the double integral:Let us evaluate the iterated integral

∫[1,-1] ∫[0, y²] dy dx.

∫[1,-1] ∫[0, y²] dy dx

= ∫[1,-1] [x³/3]₀^(y²) dx

= ∫[1,-1] y⁶/3 dy

= 2/3 ∫[0, 1] y⁶ dy

= 2/3 [y⁷/7]₀¹

= 2/21.

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The number of nails that the construction worker buy in the second week is 100 1/4 pounds.

Given that,

One week a construction worker brought 40 1/10 pounds of nails.

The next week he bought 2 1/2 times as many nails as the week before.

We have to find the number of nails he bought in the second week.

We have,

Number of nails he bought in the first week = 40 1/10 pounds

Number of nails he bought in the second week = 2 1/2 × 40 1/10

                                                                                = 2.5 × 40.1

                                                                                = 100.25

                                                                                = 100 1/4 pounds

Hence the number of nails he bought in the second week is 100 1/4 pounds.

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a. We can form the change of coordinates matrix P as: P = [b₁]c b₂]c   =  [2, 8]  [0, 5]  [-5, 0]

Therefore, [x]c is the column vector [-20, -1] representing the coordinates of x with respect to the basis C.

b. We have x = 2b₁ - 3b₂ = 2(2c₁ - 5c₂) - 3(8c₁ + 5c₂) = (-22c₁ - 37c₂) Therefore, we need to find [x]

c. We compute this as follows:

[x]c = [a, b]

= [(-22)(2) + (-37)(0), (-22)(0) + (-37)(5)]

= [-44, -185]

Therefore, [x]c is equal to [-44, -185].

To find the change-of-coordinates matrix from B to C, we need to express the basis vectors of B (b1, b2) in terms of the basis vectors of C (c₁, c₂).

Given that b₁ = 2c₁ + 7c₂ and

b₂ = 8c₁ + 5c₂, we can write the change-of-coordinates matrix P as:

P = [b₁ | b₂]

= [2c₁ + 7c₂ | 8c₁ + 5c₂]

= [2 8]

[7 5]

This matrix P represents the linear transformation that maps coordinates relative to basis B to coordinates relative to basis C.

b. To find [x]c for x = 2b₁ - 3b₂, we can use the change-of-coordinates matrix P obtained in part (a).

First, we express x in terms of the basis vectors of C:

x = 2b₁ - 3b₂

= 2(2c₁ + 7c₂) - 3(8c₁ + 5c₂)

= 4c₁ + 14c₂ - 24c₁ - 15c₂

= -20c₁ - c₂

Next, we can express x as a linear combination of the basis vectors of C:

[x]c = [-20 | -1]

Therefore, [x]c is the column vector [-20, -1] representing the coordinates of x with respect to the basis C.

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the series 1/(n∛(n)) is divergent.

To determine the convergence or divergence of the series, let's examine the terms of the series and apply the comparison test.

The series in question is:

1/(n∛(n))

We can compare it to the harmonic series, which is known to be divergent:

1/n

Let's compare the terms of the given series to the terms of the harmonic series:

1/(n∛(n)) < 1/n

Since 1/n is a divergent series, and the terms of the given series are smaller than the corresponding terms of the harmonic series, we can conclude that the given series is also divergent.

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Using formula: Monthly payment = (loan amount * monthly interest rate) [tex]/ [1 - (1 + monthly interest rate) ^ (-number of months)][/tex]Monthly payment = [tex](50000 * 0.005) / [1 - (1 + 0.005)^-120][/tex] Monthly payment = $536.82 (to the nearest cent)

$50,000 and you are given 10 years to pay it back, you have to repay it in 10 x 12 = <<10*12=120>>120 months. Interest rate

= 6% compounded monthly Monthly interest rate

= 6/12%

= 0.5%

= 0.005 Loan amount

= $50,000 Therefore, the monthly payments if you get a 6% interest rate compounded monthly is $536.82 (to the nearest cent) Monthly payment = [tex](loan amount * monthly interest rate) / [1 - (1 + monthly interest rate) ^ (-number of months)]$590.50 = (50000 * 0.005) / [1 - (1 + 0.005) ^ (-N)]1 - (1 + 0.005) ^ (-N) = (50000 * 0.005) / $590.501 - (1 + 0.005) ^ (-N)[/tex]

[tex]= 4.2371 + (1 + 0.005) ^ (-N)[/tex]

= 0.236N

= [tex]ln (0.236) / ln(1 + 0.005)N[/tex]

= 219.18 months approx Therefore, it will take 219 months (approx) or 18.25 years (approx) to pay off the loan.

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To find the critical points of the function f(x) = (3 - x)e^x - 3, we need to find the values of x where the derivative of f(x) is equal to zero or undefined.

a) Critical point(s):

To find the critical point(s), we first need to find the derivative of f(x). Let's denote f'(x) as the derivative of f(x).

f'(x) = (3 - x)(e^x) - e^x - (3 - x)(e^x)

Simplifying f'(x), we get:

f'(x) = (3 - x - 1)(e^x) - (3 - x)(e^x)

= (2 - x)(e^x) - (3 - x)(e^x)

= (2 - x - 3 + x)(e^x)

= (-1)(e^x)

= -e^x

To find the critical points, we set f'(x) equal to zero:

-e^x = 0

This equation has no solution because e^x is always positive and cannot be equal to zero. Therefore, there are no critical points for the function f(x).

b) Interval(s) of increasing and decreasing:

Since there are no critical points, we need to analyze the behavior of the function in different intervals.

Let's consider two intervals: x < 0 and x > 0.

For x < 0:

In this interval, f'(x) = -e^x is negative. When the derivative is negative, the function is decreasing.

For x > 0:

In this interval, f'(x) = -e^x is also negative. Again, the function is decreasing.

Therefore, the function f(x) is decreasing for all values of x.

c) f(x) has a relative maximum:

Since the function is decreasing for all values of x, it does not have a relative maximum.

In summary:

a) There are no critical points.

b) The function is decreasing for all values of x.

c) The function does not have a relative maximum.

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The area of the region bounded by the curve r = 4 cos(θ) within the sector 0 ≤ θ ≤ π/6 is approximately XX square units. This can be calculated by integrating the equation for the curve within the given sector and taking the absolute value of the integral.

To find the area, we can use the polar coordinate system. The equation r = 4 cos(θ) represents a cardioid-shaped curve. The sector 0 ≤ θ ≤ π/6 corresponds to a portion of the curve between the initial ray (θ = 0) and the ray at an angle of π/6.

To calculate the area, we integrate the equation r = 4 cos(θ) within the given sector. The integral represents the area of infinitely many infinitesimal sectors of the curve. By taking the absolute value of the integral, we account for the area being bounded by the curve.

Evaluating the integral over the given sector yields the area of the region. The final result will be expressed in square units.

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The final cofunction expression is cos(π/2 - (11π + x/6)) = cos(π/2 - x/6 - 11π)

The cofunction of sine is cosine, and their values are equal for complementary angles. In other words, sin(θ) = cos(π/2 - θ).

Let's apply this identity to the given expression:

sin(11π + x/6) = cos(π/2 - (11π + x/6))

Using the properties of cosine, we can simplify further:

cos(π/2 - (11π + x/6)) = cos(π/2 - 11π - x/6)

In order yo simplify the expression, let's work on the angle inside the cosine function:

π/2 - 11π - x/6 = π/2 - x/6 - 11π

Now, we can write the final cofunction expression:

cos(π/2 - (11π + x/6)) = cos(π/2 - x/6 - 11π)

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Stokes' Theorem states that the circulation of a vector field F around a closed curve C in a plane is equal to the surface integral of the curl of F over any surface S bounded by C.

In this case, we have a triangle as our closed curve. To find the circulation of F around the given triangle, we first need to find the curl of F. The curl of F is given by ∇ × F, where ∇ is the del operator. Calculating the curl of F, we have:

∇ × F = (d/dy)(4x) - (d/dz)(2y) + (d/dx)(5z) = 0 - (-2) + 5 = 7.

The circulation of F around the triangle is equal to the surface integral of the curl of F over any surface S bounded by the triangle. Since the triangle lies on the x = 4 plane, we can choose the surface S to be a plane parallel to the x = 4 plane and bounded by the triangle. The surface integral of the curl of F over S is then simply the area of the triangle times the z-component of the curl of F, which is 7. Therefore, the circulation of F around the given triangle is 7.

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we can determine the number of positive integers less than 1000 that are divisible by either 7 or 11 without double counting.

The rule used to find the number of positive integers less than 1000 that are divisible by either 7 or 11 is the principle of inclusion-exclusion.

The principle of inclusion-exclusion allows us to calculate the total count of elements that satisfy at least one of multiple conditions. In this case, we want to find the count of positive integers less than 1000 that are divisible by either 7 or 11.

To apply the principle of inclusion-exclusion, we first find the count of positive integers divisible by 7 and the count of positive integers divisible by 11. Then, we subtract the count of positive integers divisible by both 7 and 11 (to avoid double counting) from the sum of the two counts.

In mathematical notation, the rule can be expressed as:

Count(7 or 11) = Count(7) + Count(11) - Count(7 and 11)

By applying this rule, we can determine the number of positive integers less than 1000 that are divisible by either 7 or 11 without double counting.

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According to this question is about measuring angles in different units are as follows:

a.

1. To determine the portion of a full rotation around the circle, we need to express the angle in terms of the total number of degrees in a full rotation, which is 360 degrees.

2. The portion of a full rotation is given by the ratio of the angle measure to 360 degrees:

Portion = (2 degrees) / (360 degrees) = 1/180

To convert the angle measure from degrees to radians, we use the conversion factor π radians = 180 degrees.

The angle in radians is given by:

Angle in radians = (2 degrees) * (π radians/180 degrees) = 2π/180 radians = π/90 radians

b. If an angle has a measure of DD degrees, the measure of the angle in radians can be found by multiplying the angle measure by the conversion factor π radians/180 degrees:

Angle in radians = (DD degrees) * (π radians/180 degrees) = (DDπ)/180 radians

c. The function g(D) that determines the radian measure of an angle in terms of the degree measure is given by:

g(D) = (Dπ)/180 radians

If an angle has a measure of 9π degrees, we can use the function g(D) to find the measure of the angle in radians:

Angle in radians = g(9π) = (9ππ)/180 radians = 9π²/180 radians = π²/20 radians.

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The delivery radius for a pizza restaurant in a town with a population density of 1200 people per square mile that wants to deliver to approximately 25,000 people is 2.6 miles.

To calculate the delivery radius, we can use the following formula:

Delivery radius = square root(population / density)

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In this case, the population is 25,000 and the density is 1200 people per square mile. So, the delivery radius is:

Delivery radius = square root(25,000 / 1200) = 2.6 miles

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This means that the pizza restaurant can deliver to approximately 25,000 people within a 2.6 mile radius of its location.

Here is another way to think about it. If we imagine a circle with a radius of 2.6 miles, then the area of that circle will be approximately 25,000 square miles. This means that the pizza restaurant can deliver to approximately 25,000 people within that circle.

It is important to note that this is just an estimate. The actual delivery radius may be slightly different depending on the terrain, traffic conditions, and other factors.

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The differential transformation, D, is defined as D(p(x)) = p'(x), while the shift transformation, T, is defined as T(p(x)) = x - p(x).

(a) The calculation of (D+T)(p(x)) is as follows:

[tex]D(p(x)) = p'(x) = 1 + 20x^3 - 2 + 0 = 20x^3 - 1\\

T(p(x)) = x - p(x) = x - (x + 5x^4 - 2x + 9) = -5x^4 + 1\\

Therefore,

(D+T)(p(x)) = 20x^3 - 1 + (-5x^4 + 1) = -5x^4 + 20x^3.[/tex]

(b) The calculation of (DT)(p(x)) is as follows:

[tex]T(p(x)) = x - p(x) = x - (x^2 + 5x^4 - 2x + 9) = -5x^4 - x^2 + 3x - 9\\

D(T(p(x))) = D(-5x^4 - x^2 + 3x - 9) = -20x^3 - 2x + 3\\

Therefore, (DT)(p(x)) = -20x^3 - 2x + 3.[/tex]

(c) The calculation of (TD)(p(x)) is as follows:

[tex]D(p(x)) = p'(x) = 1 + 20x^3 - 2 + 0 = 20x^3 - 1\\

T(D(p(x))) = T(20x^3 - 1) = x - (20x^3 - 1) = -20x^3 + x + 1\\

Therefore, (TD)(p(x)) = -20x^3 + x + 1.[/tex]

(d) The commutator [D, T] is given by (DT - TD)(p(x)):

[tex](DT)(p(x)) = -20x^3 - 2x + 3\\(TD)(p(x)) = -20x^3 + x + 1\\(DT - TD)(p(x)) = (-20x^3 - 2x + 3) - (-20x^3 + x + 1) = -20x^3 - 2x + 3 + 20x^3 - x - 1 = -3x - 2[/tex]

The commutator [D, T] is -3x - 2 for any integer power n, including n = 0.

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Answer:

Step-by-step explanation:

You want the dimensions of a rectangle if adding 2 m to its width makes it a square with an area of 36 m².

The area of a square is the square of its side length, so the side length of the square is ...

  A = s²

  s = √A = √(36 m²) = 6 m

The problem statement tells you this dimension is 2 m more than the width of the rectangle. Hence that width is ...

  6 m - 2m = 4 m

The rectangle is 4 m wide and 6 m long.

Check

The length is 2 m less than twice the width: (2)(4 m) -2 m = 6 m, the value we show above.

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The expression 3√-100 simplified with the complex notation “i”  is 30i

From the question, we have the following parameters that can be used in our computation:

3√-100

Express 100 as 10 * 10

So, we have the following representation

3√-100 = 3√(-10 * 10)

Rewrite as

3√-100 = 3√(-1 * 10 * 10)

Take the square root of 10 * 10

This gives

3√-100 = 3 * 10√-1

Evaluate the products

3√-100 = 30√-1

The complex notation “i” equals √-1

So, we have

3√-100 = 30i

Hence, the expression with the complex notation “i”  is 30i

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(a) Alice is currently facing South.

(b) The order of the laptops from left to right is: Black, White, Mac, Toshiba, Asus.

(c) The value of two peaches, a lemon, and a grape is 5.

(d) The value of two peaches with a lemon divided by a lemon with a grape is 2.

(a) Alice's movements can be visualized as follows:

Therefore, Alice is currently facing South.

(b) Let's analyze the given information about the laptops:

Black, White, Mac, Toshiba, Asus.

(c) In the given counting system:

Grape = 1

Lemon = 6 (represented by 1 lemon and 2 grapes)

Peach = 2 (since a lemon is worth half a peach)

So, two peaches, a lemon, and a grape can be calculated as:

2 * 2 + 1 * 6 + 1 * 1 = 5

Therefore, the value is 5.

(d) The value of two peaches with a lemon divided by a lemon with a grape can be calculated as:

(2 * 2 + 1 * 6) / (1 * 6 + 1 * 1) = 10 / 7

Therefore, the value is 10/7.

In summary, Alice is currently facing South. The order of the laptops from left to right is Black, White, Mac, Toshiba, Asus. The value of two peaches, a lemon, and a grape is 5. The value of two peaches with a lemon divided by a lemon with a grape is 10/7.

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Venn Diagram

Venn diagram is use in answering word problems that involve two sets or three sets. It is the principal way of showing sets diagrammatically. This method consists of entering the elements of a set into a circle or circles.

To represent the given results, let us analyze the problem.

The problem above involves three sets: cats, dogs and birds. - Meaning, we need to make three circles. Then label each with cats, birds and dogs respectively.

10 students liked cats and birds but not dogs - Write 10 in the overlap of cats and birds.

6 students liked cats and dogs but not birds - Write 6 in the overlap of cats and dogs.

2 students liked dogs and birds but not cats - Write 2 in the overlap of birds and dogs.

2 students liked all three pets - Write 2 in the overlap of birds, cats and dogs.

9 students liked dogs only - Write 9 inside the dog part.

10 students liked cats only - Write 10 inside the cat part.

1 student liked birds only - Write 1 in inside the bird part.

I'll attach the venn diagram.

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The central angle q is approximately 69.36 degrees. A central angle q of a circle with radius 16 inches subtends an arc 19.36 inches.

To find the central angle q of a circle, we can use the formula:

q = (arc length / radius) * 180 / π

Given that the radius is 16 inches and the arc length is 19.36 inches, we can substitute these values into the formula:

q = (19.36 / 16) * 180 / π

Calculating the value:

q = 1.21 * 180 / π

To find q in degrees rounded to the nearest second decimal, we can evaluate this expression:

q ≈ 69.360°

Rounding to the nearest second decimal, the central angle q is approximately 69.36 degrees.

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Answer:

13 inches (to nearest inch)

Step-by-step explanation:

if volumes are in ratio 216:64, then lengths/heights must be in ratio

∛216: ∛64

= 6:4.

this can be simplified to 3:2.

3/2 = 1.5.

that means the height of larger cone is 1.5 times taller than height of the smaller cone.

let's call height of smaller cone d.

20 = 1.5d

d = 20/1.5

= 13.33

= 13 inches (to nearest inch)

The answer to the given limits questions are; a) $$\frac{9}{2}$$ b) $$1$$ and c) $$-2$$.

L'Hôpital's rule, named after the French mathematician Guillaume de l'Hôpital, is a technique used to evaluate certain indeterminate forms that involve limits of fractions. It provides a method to find the limit of a fraction when both the numerator and denominator approach zero or both approach infinity. The rule states that if the limit of the ratio of the derivatives of the numerator and denominator exists or can be evaluated, then this limit is equal to the original limit.

a) L'Hôpital rule gives;

$$\lim_{x \to 2}\frac{d}{dx}(x^3 -3x -2)\div\frac{d}{dx}(x^2)$$$$=\lim_{x \to 2}(3x^2 -3)\div(2x)$$$$=\lim_{x \to 2}\frac{3(x +1)(x -1)}{2x}$$$$=\lim_{x \to 2}\frac{3(x +1)}{2} =\frac{9}{2}$$

b) L'Hôpital rule gives;$$\lim_{x \to 0}\frac{(1-(1-x)^{1/4})}{x}$$$$=\lim_{x \to 0}\frac{4(1-(1-x)^{1/4})^{3}\div 4(1-x)^{3/4}}{1}$$$$=\lim_{x \to 0}\frac{1}{(1-x)^{3/4}}$$$$=1$$.

c) Using L'Hôpital rule gives;$$\lim_{x \to \frac{\pi}{2}}\frac{d}{dx}(\sin 2x)\div\frac{d}{dx}(x-\frac{\pi}{2})$$$$=\lim_{x \to \frac{\pi}{2}}2\cos 2x\div1$$$$=-2$$

Therefore the answer to the given questions are;a) $$\frac{9}{2}$$b) $$1$$c) $$-2$$

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By mathematical induction, we have proven that (n) = n for all n € Z+.

Now, For the prove that (n) = n for all n € Z+

We have to given that,

☀ : G₁ → G₂ is a group isomorphism with (1) = 1 and Z+ C G₁ G₂,

Now, we will use mathematical induction.

We need to show that (1) = 1.

Since (1) belongs to Z+, we know that (1) is an element of G₁.

Since ☀ is a group isomorphism with (1) = 1, we have ☀((1)) = 1.

Therefore, (1) = 1 since ☀((1)) = (1).

Assume that (k) = k for some k € Z+.

We need to show that (k+1) = k+1.

Since (k) belongs to Z+, we know that (k) is an element of G₁.

Consider the sum (k+1) + (-1).

Since (-1) belongs to Z+ and Z+ is a subgroup of (R,+), we know that (-1) is an element of G₁ and G₂.

Therefore, we have:

☀((k+1) + (-1)) = ☀((k+1)) + ☀((-1)) = ☀((k+1)) + (-1)

Since (k+1) + (-1) = k, we have:

☀((k+1)) + (-1) = (k)

Adding 1 to both sides, we get:

☀((k+1)) = (k) + 1

Since (k) = k by our induction hypothesis, we have:

☀((k+1)) = k+1

Therefore, we have shown that (k+1) = k+1.

By mathematical induction, we have proven that (n) = n for all n € Z+.

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