Mathematics High School

In ΔPQR, r = 4.9 cm, ∠R=21° and ∠P=104°. Find the length of p, to the nearest 10th of a centimeter.

Answers

Answer 1

Answer:

Step-by-step explanation:

In PQR, R = 4.9 Cm, R=21 And P=104. Find The Length Of P, To The Nearest 10th Of A Centimeter.
Answer 2

The answer is  the length of p, to the nearest 10th of a centimeter is 13.3 cm .

What is the law  of sines ?

he Law of Sines (or Sine Rule) is very useful for solving triangles.

According to the law ,

When we divide side a by the sine of angle A

it is equal to side b divided by the sine of angle B

and also equal to side c divided by the sine of angle C

[tex]\rm \dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/tex]

It is given that in Δ PQR

r = 4.9 cm

angle R = 21

angle P =104

Length of p needs to be found

Therefore by using above equation

[tex]\rm \dfrac{r}{sinR} = \dfrac{p}{sinP}[/tex]

[tex]\rm \dfrac{4.9}{sin21^{0}} = \dfrac{p}{sin104^{0}}[/tex]

p= 13.3 cm

Therefore the length of p, to the nearest 10th of a centimeter is 13.3 cm .

To know more about law of sines

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Step-by-step explanation:

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Answer:

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Brandon Brandon Drew the two congruent squares shown he divided one square into 2 congruent triangular parts he divided the other square into 2 congruent rectangular parts

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Incomplete question: Options

(a) Each triangular part and each rectangular part represents 1/2 the area of one square.

(b) Each triangular part has an area that is greater than the area of each rectangular part.

(c) Each triangular part and each rectangular part represents 1/4 the area of one square

(d) Each rectangular part has an area that is greater than the area of each triangular part.

See attachment for squares

Answer:

(a) Each triangular part and each rectangular part represents 1/2 the area of one square.

Step-by-step explanation:

Given

See attachment

Required

Which statement is true

Before the division, the area of both squares is:

[tex]Area = l * w[/tex]

After the division:

The area of the triangle is:

[tex]Area = \frac{1}{2} * base * height[/tex]

[tex]A_1 = \frac{1}{2} * l * w[/tex]

Substitute Area for l * w

[tex]A_1 = \frac{1}{2} *Area[/tex]

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[tex]Area = length * width[/tex]

The length of the rectangle is now half the length of the original square.

So, we have:

[tex]A_2 = \frac{1}{2} l * w[/tex]

Substitute Area for l * w

[tex]A_2 = \frac{1}{2} *Area[/tex]

From the values of A1 and A2, we can conclude that (a) is true

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Is this what you mean?

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

What is the dividend? the question

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Answer:

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Step-by-step explanation:

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Give your answer in its simplest form

Answers

Answer:

[tex] \frac{1}{2} [/tex]

Step-by-step explanation:

[tex] \frac{130}{260} = \frac{1}{2} [/tex]

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What is a fraction?

Fractions are used to represent smaller pieces (or parts) of a whole.

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The fraction of boys of 11 years = 130/260 = 1/2

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For more references on fractions, click;

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Answers

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Step-by-step explanation:

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