Answer:
Yes, warming up is necessary before intense exercise, work-out or sports because they help regulate temperatures of your body. Warming up also makes your muscles ready for intense physical activities and prevents muscle cramps.
Explanation:
Newton's laws of motion
Which wave type could move in the empty space between the Sun and the Earth
Answer:
Electromagnetic waves
What do all clouds contain the some amount of
Answer:
A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.
Explanation:
HELP ASAP PLEASE Comparing the types and amounts of EM radiation in an object could help scientists determine an object's what? structure age chemical composition all of the above are correct
Answer: Its all of the above
Explanation:
I had the same question and got it correct
Which of the following statements describes the law of inertia?
O A. The force of friction on an object is proportional to the normal
force.
O B. Objects remain in the same state of motion unless a force acts on
them
O c. For every action force there is an equal and opposite reaction
force.
D. Net force is equal to mass times acceleration
Answer:
B. objects remain in the same state of motion unless a force acts on them
Explanation:
Sana nakatulong
Answer: B) objects remain in the same state of motion unless a force acts on them
Explanation:
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The net force on a body = mass of object × acceleration of the object
The first option "Objects remain in the same state of motion unless a force acts on them" is an implication of the first law of motion .
The second option "For every action force there is an equal and opposite reaction force" is an implication of the third law of motion.
The last option from the given list "Net force is equal to mass times acceleration" is an implication of the second law of motion.
A motorcyclist is moving 24.5 m/s
away from a stationary siren, and
hears an 894 Hz sound. What is
the frequency of the siren when the
cyclist is stationary?
(Hint: 894 Hz is the Doppler-shifted
frequency)
(Speed of sound = 343 m/s)
(Unit = Hz)
w
Answer:962 hz
Explanation: got it right on acellus
The frequency of the siren when the cyclist is stationary will be 963 Hz.
What is frequency ?The frequency of a wave is the number of cycles per second.
FRom the doppler effect,
f =f'[ (V+Vs/V-Vo) ]
Here, doppler shifted frequency f' = 894 Hz, Source is stationary, Vs =0. Velocity of observer Vo = 24.5m/s and velocity of sound wave V = 343m/s
Substitute the value into the expression , we get
f = 894 x [(343/343 - 24.5)}
f = 963 Hz
Thus, the frequency of the siren when the cyclist is stationary is 963 Hz.
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Which device helps safely transmit electricity from the power plant to your
home?
Answer:
A. Transformer
Explanation:
it’s correct
1. A temperature of 162 °F is equivalent to what temperature in kelvins?
(a) 373 K
(b) 288 K
(C) 345 K
(d) 201 K (e) 308 K
345k
Because the formula for our Fahrenheit is Kevin = 5 * (°Fahrenheit + 459.67)
9.
21. Make sure carts are facing so that Velcro strips can stick together when they collide. Keep an extra 250g of mass on the cart 2 which starts at rest. Change sign on velocity center. Practice giving an initial velocity to cart 1 while cart 2 starts at rest so that after the collision both carts move as a combined object with mass m1 m2. What is the type of collision now you are practicing with two carts
Answer:
his type of shock is called inelastic
Explanation:
This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.
We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.
Looking for the moments
initial. Before the crash
p₀ = m₁ v₁₀
final. After the crash
p_f = (m₁ + m₂) v
the conservation of the moment is written
p₀ = p_f
m₁ v₁₀ = (m₁ + m₂) v
This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.
0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained at 50 psia. During the phase conversion,thesystem volume decreases by 1.5 ft3; 250 Btu of heat areremoved; and the temperature remains fixed at 15F. Estimatethe boiling point temperature of this substance when itspressure is 60 psia.
Answer:
The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Explanation:
Given the data in the question;
Using the Clapeyron equation
[tex](\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}[/tex]
[tex](\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }[/tex]
where [tex]h_{fg[/tex] is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu
T is the temperature ( 15 + 460 )R
m is the mass of water ( 0.5 Ibm )
[tex]V_{fg[/tex] is specific volume ( 1.5 ft³ )
we substitute
[tex](\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})[/tex] / [tex]( (15+460)\frac{1.5}{0.5})[/tex]
[tex](\frac{dP}{dT} )_{sat } =[/tex] 272.98 Ibf-ft²/R
Now,
[tex](\frac{dP}{dT} )_{sat } =[/tex] [tex](\frac{P_2 - P_1}{T_2 - T_1})_{sat[/tex]
where P₁ is the initial pressure ( 50 psia )
P₂ is the final pressure ( 60 psia )
T₁ is the initial temperature ( 15 + 460 )R
T₂ is the final temperature = ?
we substitute;
[tex]T_2[/tex] [tex]= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}[/tex]
[tex]T_2 = 475 + 5.2751\\[/tex]
[tex]T_2 =[/tex] 480.275 R
Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
Answer:
2 possible answers:
1# 2.5 Ω (when the resistors are in parallel)
2# 10 Ω (when the resistors are in series)
Explanation:
there are two possible answers for this:
1# if the resistors are in parallel in the circuit
then:
1/R-equivalent=1/5+1/5
1/R-equivalent=2/5
R-equivalent=5/2=2.5 Ω
2# if the resistors are in series in the circuit
then:
R-equivalent=5+5
R-equivalent=10 Ω
Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
If connected in series :
R = R1 + R2
R = 5 + 5
R = 10 ohms
If connected in parallel :
R = 1/R1 + 1/R2
R = 1/ 5 + 1/5
= 2 / 5
= 2.5 ohms
What is equivalent resistance ?
"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.
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A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brake and the train comes to a halt in 135 sevonds several meters before the car. What was the train's accleration during the emergency?
Answer:
final velocity = 0
because the train stoped
so,
acceleration = (v - u) ÷ tacceleration = (0 - 22) ÷ 135acceleration = -22 ÷ 135acceleration = -0.162 m/s²write short note : power
Answer:
In physics, power is the amount of energy transferred or converted per unit time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.
SI unit: watt (W)
Derivations from other quantities: P = E/t; P = F·v; P = V·I; P = τ·ω
In SI base units: kg⋅m2⋅s−3
Answer:
As a student, what are your insights about this lesson? Write an essay on your
toughts about the types of drugs/subtance of abuse, discussing its description and
effects
Tin is more active than lead.
O A. True O B. False
Answer:
It would be false
Explanation:
Lead is more reactive if thats what you mean
Which conversion can take place in a transformer
A. An electric current into a magnetic field
B. Electric energy into mechanical energy
C. Mechanical energy into electric energy
D. A lower voltage into a higher voltage
Answer:
D. A lower Voltage into a higher
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]
Where:
[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg
[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg
[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s
[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s
[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?
[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]
[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
Objectives
Pecina
y
01:Posttest 01:Motion Along a Straight Line
eration
1. An elevator moving down passes its neighbor, an elevator moving up. Their speed relative to one another is 8 m/s. What is the velocity of each
elevator relative to someone standing on the first floor? Assume that the elevators are traveling at the same speed, and that the upward direction is
positive.
tant Acceleration
O Both elevators are moving at 8 m/s.
y Falling Objects
O One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s.
O Both elevators are moving at 4 m/s.
tive Velocity
O One elevator is moving at 8 m/s; the other elevator is moving at -8 m/s.
Posttest
on in a Plane
ton's Laws of Motion
>
1 of 25
Submit
blications of Newton's
Description
440
11:53 PM
4/4/2021
Answer:
B
Explanation: Given that an elevator moving down passes its neighbor, an elevator moving up. Their speed relative to one another is 8 m/s. What is the velocity of each elevator relative to someone standing on the first floor? Assume that the elevators are traveling at the same speed, and that the upward direction is positive.
O Both elevators are moving at 8 m/s.
y Falling Objects
O One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s.
O Both elevators are moving at 4 m/s.
tive Velocity
O One elevator is moving at 8 m/s; the other elevator is moving at -8 m/s.
Solution.
Since the upward direction is positive, the downward direction will be negative.
For their speed relative to one another to be 8 m/s, the individual velocity will be:
4 - ( - 4 ) = 8
Therefore, the correct answer is:
One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s
Which is option B
Because the negative sign multiply by negative sign will give positive.
That is,
4 + 4 = 8
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 8,300,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 5.6 m/s2 at this altitude.)
A. 7043 m/s
B. 8239 m/s
C. 7576 m/s
D. 6818 m/s
If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.
What is a satellite?
Most spacecraft, with the exception of passive satellites, contain a means of generating electricity for the technology they carry, such as solar panels or radioisotope thermoelectric generators (RTGs). The majority of satellites also feature transponders, which are a type of ground station communication system. The most common satellites, small CubeSats, use a standardised bus to reduce costs and labour. Satellites of a similar type can cooperate with one another to form constellations.To know more about satellite, click the link given below:
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On a distance-time graph, what is the difference between a shallow slope and a steep slope?
A. A shallow slope shows the same speed as a steep slope.
B. A shallow slope shows a lower speed than a steep slope.
C. A shallow slope shows a more positive speed than a steep slope.
D. A shallow slope shows a higher speed than a steep slope.
The following lists the length and diameter of three copper wires. Wire A
- 5 cm long, 10 mm thick; Wire B- 10 cm long, 5 mm thick; Wire C - 15 cm
long, 1 mm thick. Which of these wires most likely has the highest
resistance? Help i’m taking a test
Answer:
Resistance is proportional to length and inversely proportional to area.
L1 = 5 cm
L2 = 10 cm
L3 = 15 cm
A1 = k * (.50 cm)^2
A2 = k * (.25 cm)^2 = 1/4 A1
A3 = k * (.05 cm)^2= 1/100 A1
R1 = 1 * 1 = 1
R2 = 2 * 4 = 8 R1
R3 = 3 * 100 = 300 R1
R3 has greatest resistance
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
what are the materials that you have illustrated?
Answer:
An illustration is a decoration, interpretation or visual explanation of a text, concept ... such as posters, flyers, magazines, books, teaching materials, animations, video games and films.
Explanation:
How do y’all solve this
Answer:
you Subtract
Explanation:
A = 6
B = 6
C = 0
D = 5
9-3= 6
13-7=6
11-11=0
6-1=5
Simple hope it helps
Question number 11 how did we found the answer ?
Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
if up is up and down is down isn't downside up , upside down
Answer:
No they arent because they are opposite to each other.
(c) A coal-fired power station generates electricity at night when it is not needed.
Some of this energy is stored by pumping water up to a mountain lake. When there is high
demand for electricity, the water is allowed to flow back through turbines to generate electricity.
On one occasion, 2.05 x 108kg of water is pumped up through a vertical height of 500 m.
(i) Calculate the weight of the water.
weight =
[1]
Answer:
ion know tbh
Explanation:
Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])
[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]
Similarly;
[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]
However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]
[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]
[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]
Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?
Answer:
a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) the magnitude of the net momentum is 54102.5 kgm/s
Explanation:
Given the data in the question;
a) x-component of the net momentum of this system.
the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up
so;
Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]
Px = 44200 kgm/s [tex](-x)[/tex]
Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) y-component of the net momentum of this system
Also, momentum along y-axis is entirely provided by the sedan
Py = 1300 kg × 24.0 m/s [tex](y)[/tex]
Py = 31200 kgm/s [tex](y)[/tex]
Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) magnitude of the net momentum?
magnitude of the net momentum P = √( Px² + Py² )
so we substitute
P = √( (44200)² + (31200)² )
P = √( 2927080000 )
P = 54102.5 kgm/s
Therefore, the magnitude of the net momentum is 54102.5 kgm/s
A satellite moves on a circular earth orbit that has a radius of 6,758,998 m. A model airplane is flying on a 10 m guideline in a horizontal circle. The guideline is parallel to the ground. Find the speed of the plane such that the plane and the satellite have the same centripetal acceleration.
Answer:
v = 0.1068 m / s
Explanation:
To find the speed of the satellite we use Newton's second law where the force is the universal law of gravitation
F = ma
F = [tex]G \frac{m M}{r^2}[/tex]
acceleration is centripetal
a = v² / r
we substitute
[tex]G \frac{m M}{r^2} = m \frac{v^2}{r}[/tex]
v² = [tex]G \frac{M}{r}[/tex]
The radius of the orbit is given we will assume that this radius is half from the center of the earth
we substitute
v² = 6.67 10⁻¹¹ 5.98 10²⁴/6758998
v = [tex]\sqrt{59.013 \ 10^6}[/tex]
v = 7.68 10³ m / s
The centripetal acceleration is
a = v² / r
a = 7.68 10³/6758998
a = 1.14 10⁻³ m / s²
For the airplane we use the definition of centripetal acceleration
a = v² / r
v = [tex]\sqrt{a \ r }[/tex]
let's calculate
v = [tex]\sqrt{1.14 \ 10^{-3} \ 10}[/tex]
v = 0.1068 m / s
8. Cart 1 with mass of 2kg moving at +6m/s collides with cart 2 with a mass of 1kg,
which is at rest. If cart 1 moves at +2m/s after the collision, what is the velocity of
cart 2 after the collision? (include correct units, or you get no credit)
Answer:its 2kg
Explanation: