Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower. Obtain and interpret a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus using Agresti and​ Coull's method.
Construct and interpret the 95​% confidence interval. Select the correct choice below and fill in the answer boxes within your choice.
​(Round to three decimal places as​ needed.)
A. The proportion of students who eat cauliflower on​ Jane's campus is between___ and __ 95​% of the time.
B.There is a 95​% chance that the proportion of students who eat cauliflower in​ Jane's sample is between __ and __.
C. There is a 95​% chance that the proportion of students who eat cauliflower on​ Jane's campus is between __ and__.
D. One is 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between __ and __.

Answers

Answer 1

Answer:

A 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                              P.Q.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of students who eat cauliflower

           n = sample of students

           p = population proportion of students who eat cauliflower

Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95

P( [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95

Now, in Agresti and​ Coull's method; the sample size and the sample proportion is calculated as;

[tex]n = n + Z^{2}__(\frac{_\alpha}{2})[/tex]

n = [tex]24 + 1.96^{2}[/tex] = 27.842

[tex]\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_) }{2} }{n}[/tex] = [tex]\hat p = \frac{2+\frac{1.96^{2} }{2} }{27.842}[/tex] = 0.141

95% confidence interval for p = [ [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]

 = [ [tex]0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }[/tex] , [tex]0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }[/tex] ]

 = [0.012, 0.270]

Therefore, a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between 0.012 and 0.270.


Related Questions

Eparture time of a car is 0540 hours and it traveled for 45 minutes before it reached its destination. At what time did the car arrived at its destination : *

Answers

Answer:

The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6.

Step-by-step explanation:

Departure time = 0540 Hours means 5: 40 am or 40 minutes past 5 in the morning.

Now add 45 mins

Hours : Minutes

      5:        40

      +         45

    5      :    85

But 1 hour contains 60 minutes so 85 - 60 gives 25 minutes . those 60 minutes = 1 hour are carried over the hours and added .

Hours : Minutes

       1

      5:        40

      +         45

    6      :    25

The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6 in the morning.

what the formula of speed

Answers

Answer:

The formula for speed is s=(distance traveled)/(time elapsed)

Answer:

[tex]\huge \boxed{S =\frac{d }{t} }[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

The formula to find speed is as follows:

[tex]\Longrightarrow \ \ \displaystyle \sf speed =\frac{distance \ travelled }{time \ taken}[/tex]

[tex]\Longrightarrow \ \ \displaystyle S =\frac{d }{t}[/tex]

[tex]\rule[225]{225}{2}[/tex]

WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning.

Answers

Answer:

A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.

Step-by-step explanation:

Answer:

WHEN U GRAPH WITH A CALCULATOR  IT IS MUCH MORE ACCURATE

ESPECIALLY IF THERE R FRACTIONS AND DECIMALS AND THE GRAPHING CALCULATOR GOES ON FOREVER WHERE AS THE GRAPHING PAPER  ENDS

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

          ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                         PEACE!

(pic inside) What is the approximate value of the function at x = 1?

Answers

Answer: -2

Step-by-step explanation:

When x = 1, y = -2.

Hope it helps <3

If f ( x) = 4x
2 and g( x) = 5x , what is
g( f (2x)) ?

Answers

Answer: 40x

First, let's find f(2x)

[tex]f(2x)=4(2x)=8x[/tex]

Using this, let's find g(f(2x)):

[tex]g(f(2x))=g(8x)=5(8x)=40x[/tex]

That's the answer. Let me know if you need any clarifications, thanks!

Answer:

80x²

Step-by-step explanation:

f(x) = 4x², g(x) = 5x

f(2x) = 4(2x)² = 16x²

g(f(2x)) = 5(16x²) = 80x²

A small cargo plane currently has 140 pounds of cargo aboard. In addition, n boxes weighing 45 pounds each will be brought aboard. Suppose that the total weight of the cargo on board must be less than p pounds. Using the values and variables given, write an inequality describing this.

Answers

Answer:

The inequality that represents this situation is: [tex]140 + 45*n < p[/tex]

Step-by-step explanation:

Since the plane already had 140 pounds on board and "n" boxes will be loaded on it, then the weigh of each box multiplied by the number of box should be the extra cargo on the plane. This extra cargo added to the previous load must be less than the limit of cargo the plane can take as shown below:

[tex]140 + 45*n < p[/tex]

If a cone is 5 meters tall and has a radius of 3 meters, What is its volume? 15π m3 60π m3 45π m3 30π m3

Answers

Answer:

V = 15 pi m^3

Step-by-step explanation:

The volume of a cone is

V = 1/3 pi r^2 h

The radius is 3 and the height is 5

V = 1/3 pi ( 3)^2 *5

V = 15 pi m^3

Answer:

15 pi m3

Step-by-step explanation:

Find the area of the shape shown below.

Answers

Answer:

28

Step-by-step explanation:

We divide the shape covenientely, like this, and area 1 is 4*4=16

area 2=4*4/2=8

area 3= 2*4/2=4

Area total = Area 1 + Area 2 + Area 3=16+8+4=28


Determine the inequality represented by the following diagram

Answers

Hiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Answer the problem below

Answers

Answer:

D. 4z^3

Step-by-step explanation:

First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3

Hope this helps, if you want me to explain more, feel free to ask questions.

Have a good day! :)

Answer:

4 z^3

Step-by-step explanation:

( 64 z^9) ^ 1/3

Rewriting 64 as 4^3

( 4^3 z^9) ^ 1/3

We know that ( ab) ^c = a^c  * b^c

4^3 ^ 1/3 z^9  ^ 1/3

We know that a^ b^c = a^ ( b*c)

4^(3 * 1/3) z^ (9  * 1/3)

4 ^ ( 1)  z^ ( 3)

4 z^3

An exponential growth function has a base that is____one?
Please help

Answers

Answer:

greater than

Step-by-step explanation:

An exponential growth function has a base that is__greater than__one.

If the base is less than one, it will be a decay function.

Note: the above assumes an exponent greater than one as well.

Select all that apply. If x^2+b/ax+c/a=0 ; then: The sum of its roots = -b/a? The difference of its roots =-b/a? The product of its roots = c/a?The division of its roots = c/a? I can select multiple.

Answers

Answer:

             The first and the third

Step-by-step explanation:

[tex]x^2+\frac bax+\frac ca=0\\\\ ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\qquad\quad x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\\\x_1+x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}+\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-2b}{2a}=\dfrac{-b}a\\\\\\x_1\cdot x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\cdot\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\\\\{}\ \ =\dfrac{b^2-b\sqrt{b^2-4ac}+b\sqrt{b^2-4ac}-(\sqrt{b^2-4ac})^2}{2a}=\dfrac{b^2-(b^2-4ac)}{4a^2}=\\\\{}\ \ =\dfrac{b^2-b^2+4ac}{4a^2}=\dfrac{4ac}{4a^2}=\dfrac{c}{a}[/tex]

[tex]x_1-x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}-\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-2\sqrt{b^2-4ac}}{2a}=\frac{-\sqrt{b^2-4ac}}{a}\\\\\\x_1\div x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}\div\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-b-\sqrt{b^2-4ac}}{2a}\,\cdot\,\frac{2a}{-b+\sqrt{b^2-4ac}}=\\\\=\frac{-b-\sqrt{b^2-4ac}}{-b+\sqrt{b^2-4ac}}=\frac{b+\sqrt{b^2-4ac}}{b-\sqrt{b^2-4ac}}=\frac{b^2+2\sqrt{b^2-4ac}+b^2-4ac}{b^2-b^2+4ac}=\frac{2b^2+2\sqrt{b^2-4ac}-4ac}{4ac}=[/tex]

[tex]=\frac{b^2+\sqrt{b^2-4ac}-2ac}{2ac}[/tex]

two bags and four hats cost $100 in all. three bags and seven hats cost $164 in all. what is the cost of 1 hat?

Answers

Answer:

Bags = 22

Hat = 14

22 x 2 = 44

14 x 4 = 56

So the first part is true

3 x 22 = 66

7 x 14 = 98

So the second part is true

14 is the answer

It's trial and error

Step-by-step explanation:

An item is selling for $7,000. This item gets a discount and it is now $4,900. What percentage was the discount?

Answers

The discount percentage was 1 - (4900/7000) = 30%

7000-0.3*7000=4900

Answer:

30%

Step-by-step explanation:

Discount =$7000-$4900

Discount% =

[tex] \frac{2100}{7000} \times 100 \\ = \frac{210000}{7000 } \\ = \frac{210}{7} = 30[/tex]

If you have 2345 and you multiple it by 2 divide it by 6 and add on 22299 what will the answer be?

Answers

Answer:

69242/3 or 23080.666667

Step-by-step explanation:

2345 is multiplied by 2. Then the result is divided by 6. Then 22299 is added to the final result.

2345 × 2

= 4690

4690/6

= 2345/3

2345/3 + 22299

= 69242/3

This is probably pretty easy, I could solve all the other ones but I got stuck on this one.

Answers

Answer:

78

Step-by-step explanation:

Let x be the score on the next test

We are averaging 6 tests and want an average of 75

( 82+91+38+78+83+x) /6 = 75

Multiply each side by 6

( 82+91+38+78+83+x) = 75*6

( 82+91+38+78+83+x)  =450

Combine like terms

x+372 = 450

Subtract 372 from each side

x+372-372 = 450-372

x =78

1. In your own words please describe a Relations vs. Function

2. please describe the mathematical order of operation(photo attached)

Answers

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

1. Relations are the set of y (output) and x (input) values that are related. A function is when each input has a relation with one output.

2. The mathematical formula is the formula of Pythagoras theorem. Where the length c (hypotenuse) is equal to the square root of the sum of the legs squared.


[tex] \sqrt[3]{y} = a(c + \frac{1}{x})[/tex]

Answers

Greetings from Brasil...

Here we don't have much to go

∛Y = A.(C + 1/X)

∛Y = (AC + A/X)

raising both members to the cube.....

(∛Y)³ = (AC + A/X)³

from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³

Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³

Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]

Please answer this in two minutes

Answers

Answer:

[tex] s = 14.1 [/tex]

Step-by-step explanation:

Given:

<S = 31°

SQ = r = 9

SR = q = 21

s = ?

To find s, use the Law of Cosines:

s² = r² + q² - 2rs*cos(S)

[tex] s^2 = 9^2 + 21^2 - 2*9*21*cos(31) [/tex]

[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]

[tex] s^2 = 522 - 324.02 [/tex]

[tex] s^2 = 197.98 [/tex]

[tex] s = 14.1 [/tex] (nearest tenth)

Draw a diagram of this statement,
Fifteen thousand dollars was raised by the booster club. This was two thirds of
the goal.
Use your diagram to determine the percent by which the booster club fell short of their goal

Answers

Answer:

The percentage by which the booster club fell short is 33% as shown on the chart

Step-by-step explanation:

To represent the given data pictorially, a pie chart is suitable

The circumference of the pie chart will represent the amount to be raised by the booster club and a sector of the circle which is two-thirds of the circumference represents the amount raised

Given that the amount raised = 2/3×Goal = $15,000, we have;

We represent the amount raised as a sector of the circle as follows;

Sector angle = 2/3×360° = 240°

Total sector of goal amount = Entire circle = 360°

Amount club fell short = 360° - 240° = 120°

The goal amount = 3/2 × $15,000

Percentage by which the club fell short = 120/360×100 = 1/3×100 = 33.33%

Ama has a rectangular garden measuring 12m and 25m.He wants to divide it into square plots of equal sizes .What is the largest sized square he can use?

Answers

The largest sized square should be a 12m x 12m square

Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem?

Answers

Answer:

The additional information required to prove ΔDEF ~ ΔPQR is the value of the ratio DE/PQ which has to be equal to three-halves for ΔDEF to be similar to ΔPQR

Step-by-step explanation:

Given DF/PR = FE/RQ = 3/2

The Side Side Side,  SSS, similarity theorem states that where there are two triangles that have corresponding sides that are proportional to each other, the two triangles are said to be similar

Given ΔDEF and ΔPQR, have sides DF/PR = FE/RQ, to prove that ΔDEF and ΔPQR, then the additional information required is the ratio of the third sides of the triangles which is DE/PQ.

If DE/PQ = Three-halves, the two triangles ΔDEF and ΔPQR are similar, if not, that is DE/PQ ≠ Three-halves, then the two triangles ΔDEF and ΔPQR are not similar.

Answer:

D: DE/PQ = 3/2

Step-by-step explanation:

Did it on edge 2020

find the value of x.

Answers

Answer:

  A.  7

Step-by-step explanation:

The problem is poorly specified, so technically cannot be answered with a specific number.

If we assume the "horizontal" lines are all parallel, then the one marked 21-x has a length that is the average of the other two:

  (17 +11)/2 = 21 -x

  14 = 21 -x

  x = 21 -14 = 7

The value of x is 7.

_____

The attachment shows what happens when the lines are not parallel. The range of the midline lengths is from 3 to 14 for the segment lengths shown.

U
480
S
d
T
b
R.
C
P
1549
Q

Answers

Answer:

a = 26°

b = 48°

c = 26°

d = 106°

The local ice cream shop offers 3 different types of cones and 15 different flavors of ice cream. How many possible ice cream cones (one scoop) can a customer order? a 40 b 18 c 45 d 35

Answers

Answer:

45

Step-by-step explanation:

There are 3 cones and 15 flavors

Multiply the number of cones by the number of flavors

3*15

45

There are 45 possible combinations

2 There are x fish in a pond.
Omar puts 5 more fish in the pond.
How many fish are in the pond now?​

Answers

Answer:

x+5

Step-by-step explanation:

We are adding fish

There were x and then we added 5

There are now

x+5

Answer:

x+5

Step-by-step explanation:

since there are x fish, adding five more would make it x+5        

How does the period of f(x)= cos⁡(2x) relate to the period of the parent function cos⁡ x?

Answers

Answer:

Both have the same period which is 2π

Step-by-step explanation:

vertical stretch of the graph f(x)= x² by a factor of 5

PLEASE HELP!!​

Answers

Answer:

f(x) = 5x^2

Step-by-step explanation:

A vertical stretch is in the y direction

y = Cf(x)  C > 1 stretches it in the y-direction

f(x) = 5x^2

can someone help....​

Answers

Answer:

-7 is no, -2 is no, 7 is no, and 10 is yes

Step-by-step explanation:

-5+9*(-7)>58

-5+-63>58

-68>58

-5+9*(-2)>58

-5+-18>58

-23>58

-5+9*(7)>58

-5+63>58

58>58

-5+9*(10)>58

-5+90>58

85>58

so the only one that is a solution is v=10, hope this helps

Answer: No, No, No, Yes

Step-by-step explanation:

Solve the equation for "v":

-5 + 9v > 58

      9v > 63

        v > 7

Check the options to see if they make a true statement:

-7 > 7    False

-2 > 7    False

7 > 7     False

10 > 7   TRUE!

A life insurance company sells a $100,000 one year term life insurance policy to a 30-year old male for $475. The probability that the male survives the year is .999172. Find the expected value for the insurance company.

Answers

Answer:

The expected value for the insurance company is $392.20.

Step-by-step explanation:

The expected value of a random variable, X is:

[tex]E(X)=x\cdot P(X)[/tex]

It is provided that a life insurance company sells a $100,000 one year term life insurance policy to a 30-year old male for $475.

The probability that the male survives the year is, P(S) = 0.999172.

Then the probability that the male does not survives the year is:

P (S') = 1 - P (S)

        = 1 - 0.999172

P (S') = 0.000828

The amount the company owes the male if he survives is, S = $475.

The amount the company owes the male if he does not survives is,

S' = $475 - $100,000 = -$99525.

Compute the expected value for the insurance company as follows:

[tex]E(\text{Insurance Company})=S\cdot P(S)+S'\cdot P(S')[/tex]

                                     [tex]=(475\times 0.999172)+(-99525\times 0.000828)\\=474.6067-82.4067\\=392.20[/tex]

Thus, the expected value for the insurance company is $392.20.

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