Kate has five sandwiches to share with three of her friends. If each person gets the same amount of sandwich, how much will each person get?

Answer:

1. Degree= 6, trinomial

2. degree= 4, binomial

Step-by-step explanation:

1. The largest exponent is 6 making it the degree and there are three terms because (m^5n^2), (mn^2), (n^6).

2. Since (9a^2bc^2) has the more than 1 exponent, you add them and the  degree is 4. There are two terms because (2a^3b), (9a^2bc^2).

Answer:

mathematical represents alot of stuff in the really world

The number of distinct subset of the set is an illustration of combination

There are 34 distinct subset of the set that have three digit sums

The set is given as:

S = {1,8,9,39,52,91}

Group the elements

S = {(1,8),9,39,52,91}

So, we have:

S ={s1,s2,s3,s4,s5}

To have a three-digit sum, the sum of the selected elements must be 100 or above.

The number of ways the above set can be selected is:

[tex]n_1 = 4 * [^3C_1 + ^3C_2 + ^3C_3] + 1[/tex]

Evaluate

[tex]n_1 = 4 * [3 + 3 + 1] + 1[/tex]

[tex]n_1 = 29[/tex]

The set can be further rearranged as:

S = {(52,39),9,(8,1)}

i.e.

S = {b1,b2,b3}.

The number of ways the above set can be selected such that the sum is 100 or above is:

[tex]n_2 = 2 * [^2C_1] + 1[/tex]

Evaluate

[tex]n_2 = 2 * 2 + 1[/tex]

[tex]n_2 = 5[/tex]

So, the total number of ways is:

[tex]n = n_1 +n_2[/tex]

This gives

[tex]n = 29 +5[/tex]

[tex]n = 34[/tex]

Hence, there are 34 distinct subset of the see that have three digit sums

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There are 34 distinct subsets of the see that have three-digit sums.

When we know that S is a subset of T, we place the circle representing S inside the circle representing T.

The set is given as:

S = {1,8,9,39,52,91}

Group the elements

S = {(1,8),9,39,52,91}

S ={s1,s2,s3,s4,s5}

To have a three-digit sum, the sum of the selected elements must be 100 or above.

The number of ways the above set can be selected is:

[tex]\rm n_1=4\times (^3C_1+^3C_2+^3C_3)+1\\\\n_1=4(3+3+1)+1\\\\n_1=4 \times 7+1\\\\n_1=28+1\\\\n_1=29[/tex]

The set can be further rearranged as:

S = {(52,39),9,(8,1)}

S = {b1,b2,b3}.

The number of ways the above set can be selected such that the sum is 100 or above is:

[tex]\rm n_2=2\times ^2C_1+1\\\\n_2= 2\times 2+1\\\\n_2=4+1\\\\n_2=5[/tex]

The distinct subsets of the set are;

[tex]\rm n_1+n_2=29+5 =34[/tex]

Hence, there are 34 distinct subsets of the see that have three-digit sums.

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Step-by-step explanation:

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The two numbers are illustrations of system of equations

The two numbers are 2.7 and 37.3

Let the numbers be x and y.

So, we have the following equations

x + y = 40

xy = 100

To determine the value of the variables, we simply plot the graph of both equations

From the graph, we have the following result

(x,y) = (2.7, 37.3)

Hence, the two numbers are 2.7 and 37.3

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Answer:

30.37

Step-by-step explanation:

Answer:

[tex]164 \div 5.40 ={\ 30.3704{}}[/tex]

The answer is 30.3704

Answer:

1

Step-by-step explanation:

[tex] \tan \bigg( \frac{5\pi}{4} \bigg) \\ \\ = \tan \bigg( \pi + \frac{\pi}{4} \bigg) \\ \\ = \tan \bigg(\frac{\pi}{4} \bigg) \\ \\ = 1[/tex]

[tex]\tan \left(\dfrac{5 \pi}4 \right)\\\\\\=\tan \left(2 \cdot \dfrac{\pi}2 + \dfrac \pi4\right)\\\\\\=\tan \left(\dfrac{\pi}4 \right)\\\\\\=1[/tex]

The length of the radius will be 22 units.

The radius of a circle is defined as the distance of the center of the circle to its outer layer. It is a locus of a point present at some distance from the center point.

Now from the question, we have an expression:

[tex]r=(\dfrac{6}{85} )\times(\dfrac{85}{12} )\times (\dfrac{121}{36} )\times (\dfrac{157}{12} )[/tex]

By solving the above equation we get

[tex]r=(\dfrac{18997}{864} )[/tex]

[tex]r=22[/tex]

Hence the length of the radius will be 22 units.

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Answer:

85/12

Step-by-step explanation:

The volume of the container is the amount of can in it

The contents weigh 1047.1 ounces

The given parameters are:

Volume = 28.3 cubic feet

Average weight of can = 37 ounces per cubic foot

So, the weight of the container would be:

Weight = Volume * Average weight of can

Substitute known values

Weight = 28.3 cubic feet * 37 ounces per cubic foot

Evaluate the product

Weight = 1047.1 ounces

Hence, the contents weigh 1047.1 ounces

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Answer:

not

Step-by-step explanation:

Answer:

4/5 and -4/5 are not same because

4/5=

6.965 + 3.25 + 1.79 = 12.005, now, let's apply a 7% taxation on that

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 12.005}}{\left( \cfrac{7}{100} \right)12.005}\implies 0.84035~\hfill \underset{total~bill}{\stackrel{12.005~~ + ~~0.8435}{12.84535}} \\\\\\ 20~~ - ~~12.84535\implies 7.15465~~\approx ~~ \$7.15[/tex]

Answer:

Step-by-step explanation:

diameter = 6 in

r = 6/2 = 3 in

h = 8 in

[tex]\textbf{Area of cylinder = $2\pi r(r+h)$ }[/tex]

                              [tex]= 2*3.14*3*(3+8)\\\\= 2*3.14*3*11\\\\= 207.24 \ in^{2}[/tex]

Answer:

☐ [tex]\displaystyle \textcolor{blue}{A.}\:\angle{S}\:and\: \angle{J}[/tex]

☑ [tex]\displaystyle \textcolor{blue}{B.}\:\angle{G}\:and\: \angle{M}[/tex]

☐ [tex]\displaystyle \textcolor{blue}{C.}\:\angle{H}\:and\: \angle{P}[/tex]

☑ [tex]\displaystyle \textcolor{blue}{D.}\:\angle{R}\:and\: \angle{U}[/tex]

Explanation:

Accourding to the Vertical Angles Theorem, vertical angles are considered congruent. So, we need to make sure find all pairs of angles that reflect each other like a mirror [NO LINEAR INTERFERENSES], and those would be the above checked checkboxes.

I am joyous to assist you at any time.

Answer:

105/330 = 21/66 = 7/22

7/22 is the answer I think

Step-by-step explanation:

n(U) = 330

n(A) = 85

n(B) = 200

n(A n B) = 60

Now,

n(A U B) = n(A) + n(B) - n(A n B)

or, n(A U B) = 85 + 200 - 60

or, n(A U B) = 285 - 60 = 225

Now,

n(A U B) compliment = n(U) - n(A U B)

n(A U B) compliment = 330 - 225

so, n(A U B) compliment = 105

Now,

probability = 105/330

Answer:

SW = 130

Step-by-step explanation:

[tex]2(2x+5)=5x-20[/tex]

This is what the equation should be because this is a rectangle.

[tex]4x+10=5x-20[/tex]

Once you finish simplifying, move the numbers and variables over to get this.

[tex]x=30[/tex]

Then do multiplication and addition to get 130.

Answer:

18 is 30% of 60

Step-by-step explanation:

Try to line up percents % and the actual numbers they represent.

number : precent

       60  is 100%

        18  is x %

cross multiply

x·60 = 100·18

divide both sides by 60 to isolate x

x = ((100·18)/60

x = 30

The Area of the shaded portion = area of 5 shaded squares = 80 in.².

Area of a square = s², where the edge length is s.

Edge length of each small square = 12/3 = 4 in.

Area of the shaded portion = area of 5 shaded squares = 5(s²)

s = 4 in.

Area of the shaded portion = 5(4²)

Area of the shaded portion = 80 in.²

Therefore, the Area of the shaded portion = area of 5 shaded squares = 80 in.².

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Answer: 18,086.4 cubic units

Step-by-step explanation:

the radius squared: 3×3.14×4²=150.72.

If you want to make 120 candles, multiply that number by 120: 150.72×120=18086.4.

Answer:

[tex]\displaystyle Dependency\:[Infinitely\:Many\:Solutions][/tex]

Explanation:

In the bottom equation, moving [tex]\displaystyle -2x[/tex]to the oppocite side will give you the linear standard equation above it, therefore numerous solutions will occur.

I am joyous to assist you at any time.

Answer:

150

Step-by-step explanation:

area of your base (bh/2) 3x8/2 = 12

2 bases = 24

3 faces ---- Face1 - 7x5= 35 ------Face2 - 7x5 = 35 ------Face3 - 8x7 = 56

24 + 35 + 35 + 56 = 150

Answer:

The apothem (sometimes abbreviated as apo) of a regular polygon is a line segment from the center to the midpoint of one of its sides. Equivalently, it is the line drawn from the center of the polygon that is perpendicular to one of its sides.

Step-by-step explanation:

Apothem In a regular polygon the line from the center to the mid-point of an outer side is a(n).

It is a polygon having six faces.

The volume of a cube is a side cube.

We have,

The apothem of a regular polygon is a line segment from the center to the midpoint of any one of its sides.

Thus,

The line from the center to the mid-point of an outer side is a(n) is Apothem.

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Area :-

[tex]\\ \rm\rightarrowtail side^2[/tex]

[tex]\\ \rm\rightarrowtail 13^2[/tex]

[tex]\\ \rm\rightarrowtail 169[/tex]

Square root:-

From the table, it is found that there is a [tex]\frac{5}{12}[/tex] probability that parents will have 1 boy and 1 girl if they have a total of two children.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, out of 12 experiments, 5 resulted in one of each, hence:

[tex]p = \frac{5}{12}[/tex]

There is a [tex]\frac{5}{12}[/tex] probability that parents will have 1 boy and 1 girl if they have a total of two children.

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The Laplace transform of f(t) = cos² t is equal to the following expression: [tex]\mathcal {L} \{\cos^{2} t\} = \frac{1}{2\cdot s} - \frac{s}{2\cdot (s^{2}+2)}[/tex].

In this we need to rewrite the given function in terms of sines and cosines, whose Laplace transforms are well known. There is the following trigonometric formula:

[tex]\cos ^{2} t = \frac{1-\cos 2t}{2}[/tex]   (1)

Now we proceed to apply the Laplace transforms:

[tex]\mathcal {L} \{f(t)\} = \frac{1}{2}\cdot \mathcal {L} \left\{1 \right\}-\frac{1}{2}\cdot \mathcal {L}\left\{\cos 2t\right\}[/tex]

[tex]\mathcal {L} \{\cos^{2} t\} = \frac{1}{2\cdot s} - \frac{s}{2\cdot (s^{2}+2)}[/tex]

The Laplace transform of f(t) = cos² t is equal to the following expression: [tex]\mathcal {L} \{\cos^{2} t\} = \frac{1}{2\cdot s} - \frac{s}{2\cdot (s^{2}+2)}[/tex]. [tex]\blacksquare[/tex]

The statement is poorly formatted, the correct form is shown below:

Find [tex]\mathcal {L}\{f(t)\}[/tex] by first using a trigonometric expression. (Write your answer as a function of s). f(t) = cos² t

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Answer:

Step-by-step explanation:

A "shaded area" problem can be worked by directly computing the area of the shaded shape, or by decomposing the figure in a convenient way. Here the overall square can be decomposed into unshaded triangles and a shaded square. The triangles have dimensions given, but the smaller square does not. Work must necessarily proceed from given dimensions to arrive at the values associated with dimensions not given.

For a problem like this, working the last question first can make it easier.

The total area is the area of a square 6+3 = 9 units on a side. Its area is ...

  Total area = s² = (9 units)² = 81 units²

__

The area of each of the four non-shaded triangles is ...

  A = 1/2bh = 1/2(6 units)(3 units) = 9 units²

There are 4 triangles with that area that are not shaded, so ...

  Non-shaded region = 4 × (9 units²) = 36 units²

__

The shaded region is that portion of the total area that is not Non-shaded. Its area will be the difference ...

  Shaded area = Total area - Non-shaded area

  Shaded area = 81 units² -36 units² = 45 units²

Answer:

ab and ac are congruent with each other

Answer:

BC > AC

Step-by-step explanation:

∠A > ∠B (Given)

Side opposite to larger angle is larger and side opposite to smaller angle is smaller.

->AC < BC

or

BC > AC