Answer:
B. [tex]100 = 132.12sin2\theta[/tex]
Step-by-step explanation:
Given the horizontal distance in meters traveled by a projectile modeled by the function [tex]h = \frac{v_o^{2} }{4.9}sin\theta cos\theta[/tex]. If the initial velocity is 36 meters/second, the equation we would you use to find the angle needed to travel 100 meters is shown below;
[tex]h = \frac{v_o^{2} }{4.9}sin\theta cos\theta[/tex]
from trigonometry identity,
[tex]sin2\theta = 2sin\theta cos\theta\\sin\theta cos \theta = \frac{sin2\theta}{2}[/tex]
The equation will become;
[tex]h = \frac{v_o^{2} }{2*4.9}(sin2\theta)\\[/tex]
[tex]h = \frac{v_o^{2} }{2*4.9}sin2\theta[/tex]
Given h = 100 meters and v = 36 m/s
[tex]100 = \frac{36^{2} }{9.8}sin2\theta\\100*9.8 = 1296sin2\theta\\100 = \frac{1296}{9.8} sin2\theta\\100 = 132.12sin2\theta[/tex]
Answer:
132.12sin(2theta)=100
Step-by-step explanation:
The variables m and n are inversely correlated. When m = 22, n = 51. What is m when n = 6?
Answer:
m = 187
Step-by-step explanation:
Given m and n are inversely correlated then the equation relating them is
m = [tex]\frac{k}{n}[/tex] ← k is a constant
To find k use the condition when m = 22, n = 51
22 = [tex]\frac{k}{51}[/tex] ( multiply both sides by 51 )
1122 = k
m = [tex]\frac{1122}{n}[/tex] ← equation of correlation
When n = 6, then
m = [tex]\frac{1122}{6}[/tex] = 187
The value of m will be equal to 187 when both the numbers are an inverse function of each other.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Given that m and n are inversely correlated then the equation relating them is
m = K / n ← k is a constant
To find k use the condition when m = 22, n = 51
22 = k / 51 ( multiply both sides by 51 )
1122 = k
m = 1122 / n ← equation of correlation
When n = 6, then
m = 1122 / 6 = 187
Therefore, the value of m will be equal to 187 when both the numbers are an inverse function of each other.
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Find the fraction half way between 1/7 and 1/5
Answer:
6/35
Step-by-step explanation:
add ¹/7+¹/5 =12/35
divide 12/35 by 2
=6/35
If the family decreases the clothing budget by 3 percent, what amount will it have to spend on clothing?
nearest dollar
$266
$466
$645
$665
Answer: $466
Step-by-step explanation:
Answer:
b.$466
Step-by-step explanation:
Emily put $3000.00 in a 2 year CD paying 4% interest compounded monthly. After 2 years she withdrew all her money. What is the amount of the withdrawl?
Answer:
A=3244.8 dollars
Step-by-step explanation:
A=p(1+r)^t
A=3000(1+0.04)^2
A=3244.8 dollars
find the slope and y intercept of the line y=7/5x-3 5/7; 3 3; 7/5 7/5;-3 -3; 7/5
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question
y = 7/5x - 3
Comparing with the above formula
Slope / m = 7/5c/ y intercept = - 3Hope this helps you
The value of the slope of the line is 7/5 and the y-intercept is -3
Given the line equation :
y = 7/5x - 3The general form of the equation is :
y = bx + cslope = b ; intercept = cComparing the equations :
b = 7/5 c = -3Hence, the slope and y-intercept are 7/5 and -3
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In a different plan for area codes the first digit could be any number from 3 through 6 the second digit was either 5,6,7 or 8 and the third digit could be any number except 5. With this plan how many different area codes are possible?
Answer:
144 codes are possible
Step-by-step explanation:
Okay for the first digit, we shall be selecting one out of 3,4,5,6.
Meaning we are selecting one out of four choices
The number of ways this can be done is 4C1 ways = 4 ways
For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways
And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices
So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes
DatGuy! Sekkrit! Wishing! Anyone? Find the discriminant of 3x²+5x-2 = 0
Answer:
49
Step-by-step explanation:
[tex]3x^2+5x-2 = 0[/tex]
Apply discriminant formula : [tex]D = b^2- 4ac[/tex]
[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]
[tex]D = b^2- 4ac[/tex]
Plug in the values for a, b, and c.
[tex]D = 5^2- 4(3)(-2)[/tex]
Evaluate.
[tex]D = 25- 12(-2)[/tex]
[tex]D = 25- - 24[/tex]
[tex]D=25+24[/tex]
[tex]D=49[/tex]
Answer:
49
Step-by-step explanation:
3x²+5x-2 = 0
This is in the form
ax^2 + bx + c=0
a=3 b=5 c = -2
The discriminant is
b^2 -4ac
5^2 -4(3) (-2)
25 + 24
49
The discriminant is 49
3m-(m + 5) when m = 11 help
Answer:
17
Step-by-step explanation:
3m-(m + 5)
Distribute the minus sign
3m -m -5
Combine like terms
2m -5
Let m =11
2*11 -5
22-5
17
Answer:
[tex]17[/tex]
Step-by-step explanation:
[tex]3m-(m + 5)[/tex]
[tex]m= 11[/tex]
Plug m as 11 in the expression.
[tex]3(11)-(11+5)[/tex]
Evaluate.
[tex]33-16[/tex]
[tex]=17[/tex]
Use the screen shot to find the x
Answer:
69
Step-by-step explanation:
A triangle has a 180 degree angle so you do 180-111=69
Answer: x=24
Step-by-step explanation:
lets say 94 is ∠ a
41 is ∠ b
___ ∠ c
111∠ d
x ∠ e
so with that you will figure out that ∠ c is to find X
108-94-41= 45
so ∠ c is 45
now you can ∠a ∠ b∠ c
with that yo take
108-111-45=24
So X=24
|3x+9|= 30
Answer: x=7, -13
Answer:
[tex]\boxed{x=7, \: x=-13}[/tex]
Step-by-step explanation:
[tex]|3x+9|= 30[/tex]
Solve for absolute value.
There are two possibilities.
One possibility:
[tex]3x+9=30\\3x=21\\x=7[/tex]
Second possibility:
[tex]3x+9=-30\\3x=-39\\x=-13[/tex]
1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.
2. compare the following ratios
i) 2:3 and 4:5
ii) 11:19 and 19:21
iii) ½ : ⅓ and ⅓ : ¼
iv ) 1⅕ : 1⅓ and ⅖ : 3/2
v) if a : b = 6:5 and b:c = 10:9, find a:c
vi) if x : y = ⅙:⅛ and y : z = ⅛: ⅒, find X : z
sorry many questions
Answer:
Step-by-step explanation:
Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.
If the weight of an alloy = x kgs
Then weight of copper = [tex]\frac{9}{7+9}\times (x)[/tex]
= [tex]\frac{9}{16}\times (x)[/tex]
And the weight of zinc = [tex]\frac{7}{7+9}\times (x)[/tex]
= [tex]\frac{7}{16}\times (x)[/tex]
If the weight of zinc = 31.5 kg
31.5 = [tex]\frac{7}{16}\times (x)[/tex]
x = [tex]\frac{16\times 31.5}{7}[/tex]
x = 72 kgs
Therefore, weight of copper = [tex]\frac{9}{16}\times (72)[/tex]
= 40.5 kgs
2). i). 2 : 3 = [tex]\frac{2}{3}[/tex]
4 : 5 = [tex]\frac{4}{5}[/tex]
Now we will equalize the denominators of each fraction to compare the ratios.
[tex]\frac{2}{3}\times \frac{5}{5}[/tex] = [tex]\frac{10}{15}[/tex]
[tex]\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}[/tex]
Since, [tex]\frac{12}{15}>\frac{10}{15}[/tex]
Therefore, 4 : 5 > 2 : 3
ii). 11 : 19 = [tex]\frac{11}{19}[/tex]
19 : 21 = [tex]\frac{19}{21}[/tex]
By equalizing denominators of the given fractions,
[tex]\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}[/tex]
And [tex]\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}[/tex]
Since, [tex]\frac{361}{399}>\frac{231}{399}[/tex]
Therefore, 19 : 21 > 11 : 19
iii). [tex]\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}[/tex]
[tex]=\frac{3}{2}[/tex]
[tex]\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}[/tex]
= [tex]\frac{4}{3}[/tex]
Now we equalize the denominators of the fractions,
[tex]\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}[/tex]
And [tex]\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}[/tex]
Since [tex]\frac{9}{6}>\frac{8}{6}[/tex]
Therefore, [tex]\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}[/tex] will be the answer.
IV). [tex]1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}[/tex]
[tex]=\frac{6}{5}\times \frac{3}{4}[/tex]
[tex]=\frac{18}{20}[/tex]
[tex]=\frac{9}{10}[/tex]
Similarly, [tex]\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}[/tex]
[tex]=\frac{4}{15}[/tex]
By equalizing the denominators,
[tex]\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}[/tex]
Similarly, [tex]\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}[/tex]
Since [tex]\frac{270}{300}>\frac{80}{300}[/tex]
Therefore, [tex]1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}[/tex]
V). If a : b = 6 : 5
[tex]\frac{a}{b}=\frac{6}{5}[/tex]
[tex]=\frac{6}{5}\times \frac{2}{2}[/tex]
[tex]=\frac{12}{10}[/tex]
And b : c = 10 : 9
[tex]\frac{b}{c}=\frac{10}{9}[/tex]
Since a : b = 12 : 10
And b : c = 10 : 9
Since b = 10 is common in both the ratios,
Therefore, combined form of the ratios will be,
a : b : c = 12 : 10 : 9
find three examples of corporate logos. do they incorporate symmetry? if so, and what kind? your response should be 3-5 sentences long
Answer:
Symmetry is the property of an object to retain its shape even if it is turned or turned.
The three corporate logos are McDonald, Shell, Snapcaht
McDonald company logo is symmetrical and it is a reflective symmetry.
Shell logo is symmetrical and it is also reflective symmetry.
Snaphcat logo is symmetrical and it is also reflective symmetry.
Please answer this in two minutes
Answer:
366.6 mm²
Step-by-step explanation:
Step 1: find XY using the Law of sines.
Thus,
[tex] \frac{XY}{sin(W)} = \frac{WY}{sin(X)} [/tex]
m < W = 180 - (70+43) (sum of angles in a triangle)
W = 180 - 113 = 67°
WY = 24 mm
X = 43°
XY = ?
[tex] \frac{XY}{sin(67)} = \frac{24}{sin(43)} [/tex]
Cross multiply:
[tex] XY*sin(43) = 24*sin(67) [/tex]
[tex] XY*0.68 = 24*0.92 [/tex]
Divide both sides by 0.68 to solve for XY
[tex] \frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68} [/tex]
[tex] XY = 32.47 [/tex]
XY ≈ 32.5 mm
Step 2: find the area using the formula, ½*XY*WY*sin(Y).
Area = ½*32.5*24*sin(70)
Area = ½*32.5*24*0.94
= 32.5*12*0.94
Area = 366.6 mm² (nearest tenth)
If a number is added to the numerator of StartFraction 11 Over 36 EndFraction and twice the number is added to the denominator of StartFraction 11 Over 36 EndFraction , the resulting fraction is equivalent to one third . Find the number.
Answer:
The number is 3
Step-by-step explanation:
The fraction is 11/36
let
x = no. added to the numerator
2x = no. added to denominator
We have,
x+11/2x+36=1/3
Cross multiply
3(x+11) = (2x + 36)
3x + 33 = 2x + 36
Collect like terms
3x - 2x = 36 - 33
x=3
The number is 3
Check:
3+11/6+36=1/3
14/42=1/3
solve for x ax+3x=bx+5
Answer:
x=5/a-b+3
Step-by-step explanation: Since we don't know a or b, we'll leave them as is. Shift all terms with x to the left and keep 5 on the right (ax+3x-bx)=5. x is a factor of that, so you'd change it to x(a-b+3)=5. Then, divide by (a-b+3). If a and b had set values, then just add all the x values and solve.
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Lets do this step by step.
Simplify 5 by ( b - x)
Apply the distributive property.
[tex]5b + 5 ( -x ) = 2b + ax[/tex]
Multiply -1 by 5.
[tex]5b - 5x = 2b + ax[/tex]
Subtract ax from both sides of the equation.
[tex]5b - 5x - ax = 2b[/tex]
Move all terms not containing x to the right side of the equation.
Subtract 5b from both sides of the equation.
[tex]-5x - ax = -3b[/tex]
Subtract 5b from 3b.
[tex]-5x - ax = -3b[/tex]
Factor x out of -5x - ax .
[tex]x ( -5 - a ) = -3b[/tex]
Divide each term by = -3b.
Divide each term in x ( -5 - a) = -3b by - 5 -a.
[tex]\frac{x( -5 - a)}{-5 - a} = \frac{-3b}{-5 - a}[/tex]
Cancel the common factor of -5 - a.
[tex]x = \frac{-3b}{-5 - a}[/tex]
Simplify [tex]\frac{-3b}{-5 - a}[/tex]
[tex]x = \frac{3b}{5 + a}[/tex]
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Could you maybe give brainliest..?
❀*May*❀
One liter of paint is needed to cover all 6 sides of a cubical block. How many liters will be needed to cover all 6 sides of a second cubical block whose edge is twice as long as an edge on the first block?
Will mark brainlist
Answer:
4 liters
Step-by-step explanation:
Let's assume that the side lengths of the cubical block are 2 inches.
This means that one of the sides area is 4 in².
Multiplying this by 6 (for there are 6 sides) gets us 24 in².
So one liter of paint covers 24 in².
Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are [tex]2\cdot2 = 4[/tex] inches.
So the area of one side is 16 in².
Multiplying this by 6 (as there are 6 sides) gets us 96 in².
To find how many liters of paint this will take, we divide 96 by 24.
[tex]96\div24=4[/tex]
So 4 liters of paint will be needed for the second cubical block.
Hope this helped!
The cosine function reaches a value of 0 when x is equal to
Answer:
Step-by-step explanation:
The values of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.
What is the result of adding these two equations?
62 + 2y = -2
3x - 2y = -5
Answer:
x = -7/9; y = 4/3.
Step-by-step explanation:
I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.
If you add the two...
(6x + 3x) + (2y + (-2y)) = (-2 + (-5))
9x + 0 = -7
9x = -7
x = -7/9
6(-7/9) + 2y = -2
-42/9 + 2y = -18/9
2y = 24/9
y = 24/18
y = 12/9
y = 4/3
Hope this helps!
PLS HELP !! I’ll appreciate it
In a two-column proof, what would you write in the reason column for any statement that is given to
you?
Answer:
explanation
Step-by-step explanation:
the reason for your statement is just your explanation of why you think that.
find the value of x and y if the distance of the point (x,y) from (-2,0) and (2,0) are both 14 units.
Answer:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).
Step-by-step explanation:
distance formula
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
We want the distance, d, from points (-2, 0) and (2, 0) to be 14.
Point (-2, 0):
[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
Point (2, 0):
[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
We have a system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
Since the right sides of both equations are equal, we set the left sides equal.
[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]
Square both sides:
[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]
Square the binomials and combine like terms.
[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]
[tex] 4x = -4x [/tex]
[tex] 8x = 0 [/tex]
[tex] x = 0 [/tex]
Now we substitute x = 0 in the first equation of the system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{4 + y^2} = 14 [/tex]
Square both sides.
[tex] y^2 + 4 = 196 [/tex]
[tex] y^2 = 192 [/tex]
[tex] y = \pm \sqrt{192} [/tex]
[tex] y = \pm \sqrt{64 \times 3} [/tex]
[tex] y = \pm 8\sqrt{3} [/tex]
The points are:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex]
What is the total number of common tangents that can be drawn to the circles?
Answer:
The answer would be zero. This is due to the fact that the tangent is a line on a point around the circle. These two circles share no common tangents.
Step-by-step explanation:
The number of the common tangent to the concentric circles is zero. Option D is correct.
Two concentric circles are given in the figure, and common tangents to the circles are to be determined.
The circle is the locus of a point whose distance from a fixed point is constant i.e center ( h, k ). The equation of the circle is given by[tex](x-h)^2 + (y-k)^ = r^2[/tex]. where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.
Since the line passes through the circumference of the circle is known as a tangent to the circle and the common tangent of the concentric circle is not possible because the tangent to the inner circle results secant to the outer circle.
Thus, the number of the common tangent to the circles is zero. Option D is correct.
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02.06A LC) Which number is not in scientific notation? 02.06A
the answer is (A) you cant have 11 it should be 1.1 x 10^22
Question 1
52 + 2 × (9) + 6 =
Answer:
76Step-by-step explanation:
Use BODMAS rule:
B = Bracket
O = Of
D = Division
M = Multiplication
A = Addition
S = Subtraction
Now, let's Solve,
[tex]52 + 2 \times (9) + 6[/tex]
First, we have to multiply the numbers:
[tex] = 52 + 18 + 6[/tex]
Add the numbers:
[tex] = 76[/tex]
Hope this helps...
Good luck on your assignment...
Find the missing side length of the right triangle shown. Round to the nearest tenth, if
necessary.
Answer:
? = 26 in
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )
? = [tex]\sqrt{676}[/tex] = 26
Answer:
26 inch
Step-by-step explanation:
unknown side can be found using Pythagorean theorem
a*a+b*b=c*c
24*24+10*10=c*c
576+100=c*c
√676=c
c=26inche
which geometric solid is formed by rotating the rectangle about line m?
Answer:
rectangular prism
Step-by-step explanation:
check by rotating the shape in images
Find the value of x.
08*
ος
Ο Α. 58ο
Ο Ο Ο
Ο Β. 32ο
C. 669
D. 68ο
Answer:
x = 66°
Step-by-step explanation:
Hello,
This question involves use of rules or theorems of angles in a right angled triangle
<DAB + <BAC = 180°
Sum of angles on a straight line = 180°
98° + <BAC = 180°
<BAC = 180° - 98°
<BAC = 82°
Now, we can use <BAC to find x because some of angles in a triangle is equal to 180°
32° + 82° + x = 180°
Sum of angles in a triangle = 180°
114° + x = 180°
x = 180° - 114°
x = 66°
Angle x = 66°
anyone plss heeelp me...i only need answer 6c..
Answer:
6c1; [tex]Area = 81.12m^2[/tex]
6cii: See Explanation
Step-by-step explanation:
Given
[tex]A = 3p^2[/tex]
[tex]0 \leq p \leq 6[/tex]
Where A represents Area and P represents Width
Required
Solve 6c
Please note that because you only need 6c, I'll solve using calculations;
Solving 6ci:
Area of the cage, when width is 5.2m
Substitute 5.2m for p in[tex]A = 3p^2[/tex]
[tex]A = 3 * 5.2m^2[/tex]
[tex]A = 3 * 27.04m^2[/tex]
[tex]A = 81.12m^2[/tex]
Hence, the area of the cage is 81.12m²
Solving 6cii:
Area of the cage, when width is 40m
From the range of value of p: [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p
However, if the range is extended; the value of Area is as follows;
Substitute 40m for p
[tex]A = 3 * 40m^2[/tex]
[tex]A = 3 * 1600m^2[/tex]
[tex]A = 4,800m^2[/tex]
what is the slope of the line that goes through the points (-1 4) and (14 -2)?
Answer:
Slope is -0.4 or 2/5
Step-by-step explanation:
x , y x^2,y^2
(-1,4) (14,-2)
y^2-y^1/x^2-x^1
-2-4/14-(-1)
-6/15
=-2/5 or -0.4.
Hope this helps. If right pls give me brainliest thank you.
Answer:
it is -2/5
Step-by-step explanation:
There are four inequalities that define the region R.
One of these is y
Find the other three inequalities,
Answer:
[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]
Step-by-step explanation:
The region R is surrounded by 4 lines, the first one is y=x+1, the second one is y=0 or the axis x, and the third and fourth one need to be calcualted.
To find the equation of a line through the points (x1,y1) and (x2, y2) we can use the following equation:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Then, our third line is going to be the line that passes through the points (2,0) and (4,3), so the equation is:
[tex]y=\frac{3-0}{4-2}(x-2)\\y=\frac{3}{2}x-3[/tex]
Our fourth line is the line that passes through the points (3,0) and (0,3), so the equation is:
[tex]y=\frac{3-0}{0-3}(x-3)\\y=-x+3[/tex]
Then we can say that the other three inequalities are:
[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]
Please help me.. I'm very confused about this
Answer:
C
Step-by-step explanation:
1:draw a very simple Cartesian plane for the graph
2:label the quadrants 1-4 from top right round to bottom right as 4
3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)