Level 7 make a path si that the Sun of the numbers is equal to the answer.Up, down left or right. You can solve this because you’re really bright.
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Given different numbers on squares A, B, C, D, E, and F, you can identify that the "Answer" is the number in the last square:
[tex]-2[/tex]By definition, a Sum is the result of an Addition. Then, you need to find the corresponding path so that when you add the corresponding numbers you get this sum:
[tex]-2[/tex]- You can start by adding all the numbers from A to F, in order to check if the sum is the wanted one:
[tex]-9.4+8.3-7.6+6.7-5.8+4.9=-2.9[/tex]- You can add the numbers from squares A, B, E, and F, in order to check their sum:
[tex]-9.4+8.3-5.8+4.9=-2[/tex]Hence, the answer is:
[tex]Code:ABEF[/tex]Related Questions
find the volume of the specified solid. use 3.14 as the approximate value of pi, and round your answer to the nearest tenth.find the volume of a cylinder whit the radius 5 cm and height 10 cm.
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ANSWER
[tex]785.0[/tex]EXPPLANATION
Given;
[tex]\begin{gathered} r=5 \\ h=10 \end{gathered}[/tex]Recall, that the volume of a cylinder is calculated using;
[tex]\pi r^2h[/tex]Substituting the vales;
[tex]\begin{gathered} \pi r^{2}h \\ \pi=3.14 \\ A=3.14\times5^2\times10 \\ =3.14\times250 \\ =785.0 \end{gathered}[/tex]George is given two circles, circle O and circle X, as shown. If he wants toprove that the two circles are similar, what would be the correct second stepin his proof?Given: The radius of circle O is r, and the radius of circle X is .Prove: Circle Ois similar to circle X.1.C = 2rr and C'= 2rr' by the definition of circumference.2._3. d= 2rand d = 2r by the definition of diameter.d= 2r4. d'= 2r andby the division property of equality.5d=2rby the substitution property.and6. Circle Ois similar to circle Xbecause all the linear dimensions are in thesame proportion.
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Answer: B
The correct second step for the given proof is;
[tex]\begin{gathered} \frac{C}{C^{\prime}}=\frac{2\pi r}{2\pi r^{\prime}} \\ and\text{;} \\ \frac{C}{C^{\prime}}=\frac{r}{r^{\prime}} \end{gathered}[/tex]by the division property of equality.
Explanation:
We want to find the correct second step for the given proof.
Recall that from division property of equality, when we have;
a=b and c=d, dividing the equations by each other, the equation will still be equal;
[tex]\frac{a}{c}=\frac{b}{d}[/tex]For the given Prove;
statement 1 states that the circumference circle 1 and 2 can be expressed as;
[tex]\begin{gathered} C=2\pi r \\ \text{and} \\ C^{\prime}=2\pi r^{\prime} \end{gathered}[/tex]So, for step 2;
Applying the division property of equality, we have;
[tex]\begin{gathered} \frac{C}{C^{\prime}}=\frac{2\pi r}{2\pi r^{\prime}} \\ \text{which then equals;} \\ \frac{C}{C^{\prime}}=\frac{r}{r^{\prime}} \end{gathered}[/tex]Therefore, the correct second step for the given proof is;
[tex]\begin{gathered} \frac{C}{C^{\prime}}=\frac{2\pi r}{2\pi r^{\prime}} \\ and\text{;} \\ \frac{C}{C^{\prime}}=\frac{r}{r^{\prime}} \end{gathered}[/tex]by the division property of equality.
1. Scott's monthly salary is $2,296. How much is withheld from Scott's payeach month for social security tax? Use a social security tax rate of7.65%a $164.25b. $175.64c. $158.20
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You have the following information:
- Scott's montly salary is $2,296
- Social security tax rate is of 7.65%
In order to calculate how much is withheld from Scott's pay each month, you have to calculate the 7.65% of the Scott's salary. You proceed as follow:
(7.65/100)(2,296) = (0.0765)(2,296) = 175.64
that is, the percentage is divided by 100. Next, the previous result is multiplied by the salary. In this way you can calculate the amount of money which corresponds to a 7.65%
Hence, $175.64 are withhold from the Scott's salary
4 Drag the tiles to the correct boxes. Not all tiles will be used. Match each equation with a value of x that satisfies it. 18 1 2 -3 5 CO ✓02 + 7 4 ♡ (ir — 2)4 Reset Next
Answers
You need to solve for "x" in each equation given in the exercise:
Equation 1
[tex]\sqrt[]{x^2+7}=4[/tex]- You need to apply the following property:
[tex](\sqrt[n]{a})^n=a[/tex]Then:
[tex]\begin{gathered} (\sqrt[]{x^2+7})^2=(4)^2 \\ \\ x^2+7=16 \end{gathered}[/tex]- Subtract 7 from both sides of the equation:
[tex]\begin{gathered} x^2+7-(7)=16-(7) \\ x^2=9 \end{gathered}[/tex]- Finally, you have to take the square root of both sides of the equation:
[tex]\begin{gathered} \sqrt[]{x^2}=\pm\sqrt[]{9} \\ \\ x_1=\sqrt[]{9}=3 \\ \\ x_2=-\sqrt[]{9}=-3 \end{gathered}[/tex]In order to know which one satisfies the equation, let's substitute both values into the original equation and evaluate.
Then, for:
[tex]x=3[/tex]You get:
[tex]\begin{gathered} \sqrt[]{(3)^2+7}=4 \\ \sqrt[]{16}=4 \\ 4=4\text{ (True)} \end{gathered}[/tex]For:
[tex]x=-3[/tex]You get:
[tex]\begin{gathered} \sqrt[]{(-3)^2+7}=4 \\ 4=4(\text{True)} \end{gathered}[/tex]When a negative value has an even exponent, the result is always positive.
Equation 2
[tex](x-2)^{\frac{1}{4}}=2[/tex]- You need to apply this property:
[tex]a^{\frac{1}{n}}=\sqrt[n]{a}[/tex]Then:
[tex]\sqrt[4]{x-2}^{}=2[/tex]- Now, applying the property:
[tex](\sqrt[n]{a})^n=a[/tex]You get:
[tex]\begin{gathered} (\sqrt[4]{x-2}^{})^4=(2)^4 \\ x-2=16 \end{gathered}[/tex]- Finally, adding 2 to both sides of the equation, you get:
[tex]\begin{gathered} x-2+(2)=16+(2) \\ x=18 \end{gathered}[/tex]Check the answer:
[tex]\begin{gathered} \sqrt[4]{18-2}^{}=2\text{ } \\ 2=2(\text{True)} \end{gathered}[/tex]Equation 3
[tex]\sqrt[3]{1-x}=-1[/tex]- Knowing the properties explained before, you get:
[tex]\begin{gathered} (\sqrt[3]{1-x})^3=(-1)^3 \\ 1-x=-1 \\ \end{gathered}[/tex]- Now you can subtract 1 from both sides of the equation:
[tex]\begin{gathered} 1-x-(1)=-1-(1) \\ -x=-2 \end{gathered}[/tex]- Finally, you have to multiply both sides of the equation by -1:
[tex]\begin{gathered} (-1)(-x)=(-2)(-1) \\ x=2 \end{gathered}[/tex]Check the solution:
[tex]\begin{gathered} \sqrt[3]{1-2}=-1 \\ \sqrt[3]{-1}=-1 \\ -1=-1(\text{True)} \end{gathered}[/tex]The answer is:
Write the simplest polynomial function with integral coefficients that has the give. Zeros
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Step 1:
Write the zeros of the polynomial
[tex]\text{x = 7, x = }\pm\text{7i}[/tex]Note: A complex zero must have both negative and positive values.
Step 2:
Write the factors of the polynomial.
[tex]\begin{gathered} x\text{ = 7 and x = }\pm7i \\ x-7=0\text{ } \\ x^2\text{ = -49 is the samd as (x = }\pm7i) \\ x^2\text{ + 49 = 0} \\ \text{The thre}e\text{ factors are: x - 7, x - 7i , and x + 7i} \end{gathered}[/tex]Step 3:
[tex]\begin{gathered} \text{Multiply x - 7 and x}^2\text{ + 49 to get the simplest polynomial} \\ (x-7)(x^2\text{ + 49)} \\ x^3+49x-7x^2\text{ - 343} \\ x^3-7x^{2^{}}\text{ + 49x - 343} \end{gathered}[/tex]Final answer
[tex]x^3-7x^2\text{ + 49x - 343}[/tex]The Firgure shows three quadrillaterals on a coordinate grid:Which of the following statements is true about the three quadrillaterals?A: Q and W are similar but not congruent.B: W and S are similar and congruent.C: W and Q are similar and congruent. D: Q and S are similar but not congruent.
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Given the quadilaterals:
Q, W and S
Similar figures are figures that have the same shape but not the same size while congruent figures are figures that have the same shape and size.
From the figure given, we have the following dimensions:
QUadilateral Q:
Length = 5
Width = 2
Quadilateral W:
Length = 10
Width = 5
Quadilateral S:
Length = 5
Width = 2
• Quadilateral Q, W, and S are similar because they all have the same shape.
• Quadilateral Q and quadilateral S are congruent because they have the same shape and size.
• Quadilateral Q and W are similar but not congruent.
• Quadilateral W and S are similar but not congruent
Therefore, the correct statement from the options about the three quadilaterals is:
Q and W are similar but not congruent.
ANSWER:
Q and W are similar but not congruent
The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in either college or high school:HighLowQ1Q3IQRMedianMeanσCollege206818101413.35.2High School2035.51610.511115.4Which of the choices below best describes how to measure the spread of these data?(Hint: Use the minimum and maximum values to check for outliers.) Both spreads are best described by the IQR. Both spreads are best described by the standard deviation. The college spread is best described by the IQR. The high school spread is best described by the standard deviation. The college spread is best described by the standard deviation. The high school spread is best described by the IQR.Can you please help me understand how to solve this problem?
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Firstly, let us check for the outliers as instructed in the question
For college,
Q3 = 18
Q1=8
IQR = 10
maximum = 20
minimum = 6
For there to be outliers, The maximum must be greater than Q3 + 1.5(IQR) or the minimum must be less than Q1 -1.5(IQR)
Q3 + 1.5(IQR) = 8 + 1.5(10) = 23
Q1 -1.5(IQR) = 6 - 1.5(10) = -9
The maximum (20) is not greater than 23 and the minimum (6) is not less than -9. Hence we can conclude that college data has no outlier
For High school,
Q3 = 16
Q1= 5.5
IQR = 10.5
maximum = 20
minimum = 3
Q3 + 1.5(IQR) = 16 + 1.5(10.5) = 31.75
Q1 -1.5(IQR) = 5.5 - 1.5(10.5) = -10.25
The maximum (20) is not greater than 31.75 and the minimum (3) is not less than -10.25. Hence we can conclude that High school data has no outlier
Since both spreads have no outliers, The best way to describe the spreads is by their IQR.
The makes the correct answer to be the first option that is (Both spreads are described by their IQR)
Explain in words how you would graph the equation [tex] \frac{1}{3}x + y = 5[/tex]
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The Slope-Intercept form of the equation of a line is:
[tex]y=mx+b[/tex]Where "m" is the slope of the line and "b" is the y-intercept.
You have the following equation:
[tex]\frac{1}{3}x+y=5[/tex]So you can solve for "y" in order to write it in Slope-Intercept form:
[tex]y=-\frac{1}{3}x+5[/tex]You can identify that:
[tex]\begin{gathered} m=-\frac{1}{3} \\ \\ b=5 \end{gathered}[/tex]Knowing the slope and the y-intercept, you can graph the equation:
1. Plot the value of "b" on the Coordinate plane.
2. Remember that:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So the numerator indicates the number of units you need to move from the y-intercept and if you must move up or down, and the denominator indicates if you must move right or left and the number of units you need to move from the y-intercept.
In this case, since the slope is negative, you know that the line is decreasing from left to right, you must move 1 unit up and 3 units to the right. Then draw a second point.
3. The line will pass through the y-intercept and the second point found using the slope.
The answer is:
I would solve for "y" in order to write the equation in Slope-Intercept form. Then I would plot the y-intercept on the Coordinate plane to have the first point and use the slope to find the second point. Using the slope I'd move 1 unit up and 3 units to the right from the y-intercept. I'd draw the line passing through those points.
How much time will be needed for $37,000 to grow to $40,871.02 if deposited at 4% compounded quarterly?Do not round until the final answer. Then round to the nearest tenth as needed.
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We are given the following information
Deposit amount = P = $37,000
Accumulated amount (or ending balance) = A = $40,871.02
Interest rate = r = 4% = 0.04
Compounding interval = n = 4 (quarterly)
We are asked to find the number of years (t)
Recall that the compound interest formula is given by
[tex]A=P(1+\frac{r}{n})^{n\cdot t}[/tex]A = Accumulated amount (or ending balance)
P = Principle amount (or deposit amount)
r = Interest rate in decimal
n = Number of compounding in a year
t = Number of years
Now let us substitute the given values into the above formula and solve for (t)
[tex]\begin{gathered} 40,871.02=37,000(1+\frac{0.04}{4})^{4\cdot t} \\ \frac{40,871.02}{37,000}=(1+0.01)^{4\cdot t} \\ \frac{40,871.02}{37,000}=(1+0.01)^{4\cdot t} \\ 1.1046=(1.01)^{4\cdot t} \end{gathered}[/tex]Now take log on both sides
[tex]\begin{gathered} \ln (1.1046)=\ln (1.01^{4\cdot t}) \\ \ln (1.1046)=4t\ln (1.01)^{} \\ 4t=\frac{\ln (1.1046)}{\ln (1.01)^{}} \\ 4t=9.997 \\ t=\frac{9.997}{4} \\ t=2.49 \\ t=2.5\: \text{years} \end{gathered}[/tex]Therefore, it would take 2.5 years
Find the amount of increase if 780 is increased by 20%
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To determine the amoun of increased we just need to multiply the original amount by the percentage in decimal form. In this case the percentage is 20% so its decimal representation is 0.2, hence we have:
[tex]780(0.2)=156[/tex]Therefore, the amount of increase is 156.
For which values of x does each expression make sense?the square root of |x|+1I'll upload a picture
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Recall that the square root of y is defined for all
[tex]y\ge0.[/tex]Now, we know that
[tex]|x|\ge0,[/tex]for all x in the real numbers.
Then:
[tex]|x|+1>0.[/tex]Therefore, the expression makes sense for all x in the real numbers.
Answer:
[tex]\R\text{.}[/tex]Answer:
Step-by-step explanation:
A grilled chicken salad at a popular fast food restaurant contains 680 milligrams (mg) of sodium, which is 27% of the recommended daily amount. What is the total recommended daily amount, in milligrams, of sodium? (Round your answer to one decimal place.)
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Solution:
Let the recommended daily amount be x. Thus;
[tex]\begin{gathered} 0.27x=680mg \\ \\ x=\frac{680}{0.27}mg \\ \\ x=2518.5mg \\ \\ \end{gathered}[/tex]ANSWER: The total recommended daily amount is 2518.5milligram of sodium.
The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1). Find the midpoint of FGa- 0,4b- 1,-2c- 5,2d- -4,0
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In this case, since we have to find the midpoint of FG, we only need to focus on that segment. In order to find the midpoint of a line that focuses through the points (x1,y1) and (x2,y2), we can apply the formula:
[tex]\begin{gathered} xm=\frac{x1+x2}{2} \\ ym=\frac{y1+y2}{2} \end{gathered}[/tex]Where xm is the x-coordinate and ym the y-coordinate of the midpoint (xm,my), in this case the points of the segment FG are (-5,-3) and (-3,3), if we replace s their values into the above equation, we get:
[tex]\begin{gathered} xm=\frac{-5+(-3)}{2}=\frac{-5-3}{2}=\frac{-8}{2}=-4 \\ ym=\frac{-3+3}{2}=\frac{0}{2}=0 \end{gathered}[/tex]Then, the midpoint of FG is (-4,0)
2. Point T lies on segment AK IFAT is 47 meters long & TK is 28 meters long, how long is AK? AK = 47 AK = 19 AK = 75 AK28
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To find the length of AK
AT= 47m and Tk =28m
Since T lies on AK
Then;
AK = AT + AK
= 47 + 28
=75
Therefore AK is 75 meters long
which expression is equivalent to -28x²-35x-7A) (7x-3) (-4x+3)B) (-7x-7) (4x+1)C) (7x+3) (-4x-3)D) (-7x+7) (4x-1)
Answers
which expression is equivalent to -28x²-35x-7
A) (7x-3) (-4x+3)
B) (-7x-7) (4x+1)
C) (7x+3) (-4x-3)
D) (-7x+7) (4x-1)
we have
-28x^2-35x-7
Solve the quadratic equation by graphing
see the attached figure
The zeros of the function are
x=-1 and x=-1/4
therefore
-28x^2-35x-7=-28(x+1)(x+1/4)
simplify
-28(x+1)(x+1/4)=-(7)(4)(x+1)(x+1/4)=(-7x-7)(4x+1)
therefore
answer is option BGabe has 5 birdcages. He keeps 5 birds in each cage.How many birds does Gabe have? Use a bar diagram to represent the problem.3rd grade student
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First let's represent the problem using a bar diagram:
As we can see, each bar represent a different cage and it's height represents the number of birds for each one of them.
Now, once Gabe has 5 cages and each of them has 5 birds, he has 5*5 = 25 birds.
A pond maintenance
technician earns $15.90 per hour for the
first 40 hours he works in 1 week and
1.5 times that rate for each additional
hour that he works. How much money
does he earn working 43 hours
in 1 week?
Answers
The worker gets $707.55 for Working 43 hours in a week.
What is work?To do something which needs physical or mental effort, in order to earn money or to achieve something.
Given that a worker earns $15.90 per hour for the first 40 hours in a week, he gets 1.5 times of the rate for each additional hour he works.
Therefore, his total earning = 40*15.90 + 15.90*1.5*3 = $707.55
Hence, The worker earned $707.55 for 43 hours working.
For more references about work;
https://brainly.com/question/18094932
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Mark mowed some lawns on Saturday and $32. What information is needed to find how much money Mark earned per hour mowing lawns?
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Answer:
The information needed is the number of hours Mark spent mowing the lawn.
[tex]H\text{. how many hours Mark spent mowing lawns}[/tex]Explanation:
Given that Mark mowed some lawns on Saturday and earned $32.
To determine the amount earned per hour mowing the lawns
[tex]\text{Amount per hour =}\frac{\text{ total amount earned}}{\text{ number of hours spent mowing}}[/tex]Therefore, the information needed is the number of hours Mark spent mowing the lawn.
[tex]H\text{. how many hours Mark spent mowing lawns}[/tex]Find the perimeter of the figure shown. Round your answer to the nearest tenth.
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To calculate the perimeter fo the figure you have to add all of its sides, so the first steo is to determine the length of said sides:
Side AD
This side is parallel to the x-axis.
To determine the length of this side you have to calculate the difference between the x-coordinates of points D and A.
[tex]AD=x_D-x_A=4-(-4)=4+4=8[/tex]Side CD
You'll have to use the pythagoras theorem to calculate this since its not parallel to either axis:
The theorem states that
[tex]a^2+b^2=c^2[/tex]The sum of squares of the base and height of a triangle is equal to the square of its hypotenuse.
Side CD will be the hypothenuse of this triangle, and the base and height will be given by the difference x and y coordinates of points D and C, so:
[tex]\begin{gathered} CD^2=(x_C-x_D)^2+(y_C-y_D)^2 \\ CD^2=(2-4)^2+(4-(-3))^2 \\ CD^2=53 \\ CD=\sqrt[]{53}\cong7.28 \end{gathered}[/tex]Side BC
You have to apply the same procedure as with side CD:
[tex]\begin{gathered} BC^2=(x_C-x_B)^2+(y_C-y_B)^2 \\ BC^2=(2-(-3))^2+(4-2)^2 \\ BC^2=40 \\ BC=\sqrt[]{40}=2\sqrt[]{10}\cong6.32 \end{gathered}[/tex]Side AB
You have to use the theorem to calculate this side length too:
[tex]\begin{gathered} AB^2=(x_B-x_A)^2+(y_B-y_A)^2 \\ AB^2=(-3-(-4))^2+(2-(-3))^2 \\ AB^2=26 \\ AB=\sqrt[]{26}\cong5.099 \end{gathered}[/tex]Using the calculated side lengths you can calculate the perimeter:
[tex]P=AD+CD+BC+AB=8+\sqrt[]{53}+2\sqrt[]{10}+\sqrt[]{26}=26.703\cong26.7[/tex]The perimeter of the figure is 26.7 units
A carpenter's square is used on the circular part of a blueprint. SQ = UQ.What is the measure of SQ?60°90°SU45°180°180°
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Step 1: Observe the given figure state the obvious angles
[tex]\text{SQU}=90^0(\text{angle in a semicircle)}[/tex][tex]SQ\cong QU(given)[/tex][tex]\begin{gathered} \text{If SQ}\cong QU,\text{ then }\Delta SQU\text{ is an isosceles triangle} \\ \text{Hence, the base angles are equal} \end{gathered}[/tex][tex]i\mathrm{}e\text{. QSU}=\text{QUS}[/tex][tex]\begin{gathered} \text{QSU}+\text{QUS}=90^0(\text{Complimentary angles)} \\ 2\text{QUS}=90^0 \\ \text{QUS}=\frac{90^0}{2} \end{gathered}[/tex][tex]\text{QUS}=45^0[/tex]Hence, arc QS=45°
Which of the following graphs shows a translation of triangle A below?A.B.C.D.
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Answer: We have to pick the option that shows the translation of the triangle A, the translation has to be along the x or y-axis, and the stretching compressing, and inverting of the triangle do not count as the translation:
According to the translation rules, the answer is as follows:
[tex]\text{ Option \lparen B\rparen}[/tex]solving the system linear equation by substitution 2x-8y=10x=4y+7
Answers
No solution
Explanations:The given system of equations is:
2x - 8y = 10......................(1)
x = 4y + 7.............................(2)
Substitute equation (2) into equation (1)
2(4y + 7) - 8y = 10
8y + 14 - 8y = 10
8y - 8y = 10 - 14
0 = -4 ( This is false)
This means that the system of equations has no solutions
Also by oberving the two equations, we would see that they are parallel equations because they have equal slope (1/4). A system of parallel equations has no solution since there is no point of intersection.
You have two exponential functions. One has the formula h(x) = 3*-2. The other function, g(x), has the graph shown below. Which inequality below is true for all points on the indicated interval? Og(x) h(x) on the Interval -2 SXs2 O 91%) 2 h) on the Interval -35X53 Og) Sh on the Interval -3 SX33 Ogl*) shim on the interval -25 Xs2
Answers
Answer: g(x) ≥ h(x) on the interval -2 ≤ x ≤ 2.
Explanation
The graph of h(x) is:
As we can see, the intersection with the y-axis is the negative numbers of y and g(x) is in the positive numbers of y.
Then, on the interval of -2 ≤ x ≤ 2, g(x) ≥ h(x).
If a chord of a circle subtends a minor arc, then the length of the chord is less than the length of the diameter. O A. If a chord of a circle does not subtend a minor arc, then the length of the chord is not less than the length of the diameter. O B. If the length of a chord of a circle is less than the length of the diameter, then the chord subtends a minor arc, C. If a chord of a circle subtends a major arc, then the length of the chord is greater than the length of the diameter. OD. If the length of a chord of a circle is equal to the length of the diameter, then the chord does not subtend a minor arc.
Answers
Reading all the options, the only one that is a converse of the sentence given is the second one:
If the lenght of a chord of a circle is less than the length of the diameter, then the chord subtends a minor arc.
Both sentences are equivalent, the words are just reorganized, but the idea is the same.
It is predicted that in t years, the population of a country will be P (t) = 50e ^ (0.02t) million inhabitants. A) What will be the rate of change of the population in 10 years. B) What will be the relative rate of the population in t years? Is this rate constant?
Answers
A) What will be the rate of change of the population in 10 years.
[tex]\begin{gathered} \text{Get the derivative of the }P(t)\text{ with respect to }t \\ \frac{dP}{dt}(50e^{0.02t})=50(0.02)e^{0.02t} \\ \frac{dP}{dt}(50e^{0.02t})=e^{0.02t} \end{gathered}[/tex]Substitute t = 10, to the derivative of P(t)
[tex]\begin{gathered} P^{\prime}(t)=e^{0.02t} \\ P^{\prime}(10)=e^{0.02(10)} \\ P^{\prime}(10)=e^{0.2} \\ P^{\prime}(10)=e^{0.2} \\ P^{\prime}(10)=1.02020134 \\ \\ \text{Round off to two decimal place} \\ P^{\prime}(10)=1.02 \end{gathered}[/tex]Therefore, the rate of change of the population in 10 years is 1.02 million.
B) What will be the relative rate of the population in t years? Is this rate constant?
[tex]\begin{gathered} \text{The relative rate of the population in t years is the first derivative of }P(t) \\ P^{\prime}(t)=e^{0.02t} \end{gathered}[/tex]The rate is not constant, as it depends on how much time t has passed.
I need help with this I need to know what I’m doing wrong.. do I need to put a negative for (y+8^2) or a positive 8 so confused… help #4
Answers
Answer:
( x + 5)^2 + y^2 = 41
Explanation:
The equation we have is
[tex]x^2+10x+y^2-16=0[/tex]Let us add 25 to both sides
[tex]x^2+10x+y^2-16+25=25[/tex]A bit of rewriting gives
[tex](x^2+10x+25)+y^2-16=25[/tex]Since x^2 + 10x + 25 = ( x+ 5)^2, the above becomes
[tex](x+5)^2+y^2-16=25[/tex]Adding 16 to both sides gives
[tex](x+5)^2+y^2=25+16[/tex][tex]\boxed{\left(x+5\right)^2+y^2=41.}[/tex]which is our final answer!
6198 mabovesea levelDenaliThe lowest point in North America is in DeathValley, California, which is 86 metres below sealevel at its lowest point. The highest point isDenali, a mountain in Alaska, with an elevationof 6198 metres above sea level. What is thedifference in their elevations?sea levelDeath Valley86 mbelowsea level
Answers
To determine the difference between the elevations, we have to subtract the height of the highest point by the lowest point. Therefore we have:
[tex]\begin{gathered} \Delta h=6198-(-86) \\ \Delta h=6198+86 \\ \Delta h=6284 \end{gathered}[/tex]There is a difference of 6284 meters between their elevations.
Find the requested unknown angle of the following triangles using a calculator
Answers
ANSWER
44.43°
EXPLANATION
We have a right triangle and we know the lengths of the hypotenuse and the opposite leg to the unknown angle, so we can use the sine of the angle to find it,
[tex]\sin \theta=\frac{7}{10}[/tex]Solving for θ,
[tex]\theta=\sin ^{-1}\mleft(\frac{7}{10}\mright)[/tex]Now, using a calculator, we find that the angle is 44.43°, rounded to the nearest hundredth of an angle.
Which of the following is the additive Inverse of ? 2 0-2 0 1 3 02
Answers
The additive inverse of a number is what we add to a number to get
-5(k+6) + 7(k-4)Please simplify ASAP
Answers
We proceed to apply distributive property in all parentheses
- 5 k - 30 + 7 k - 28
and combine like terms (- 5k + 7 k = 2 k) and (- 30 - 28 = - 58):
2 k - 58