Answer:
7.5 grams
Explanation:
From the question,
(R/R')ᵇ = 2ᵃ.................... Equation 1
Where b = half life, R = Original mass of iodine, R' = Remaining mass of Iodine after disintegration, a = Total time taken.
⇒ R/R' = 2ᵃ/ᵇ............... Equation 2
Given: R = 60 grams, a = 24 days, b = 4 days
Substitute these values into equation 2
60/R' = 2²⁴/⁸
60/R' = 2³
R' = 60/2³
R' = 60/8
R' = 7.5 grams
Temperature is independent of mass
A- True
B- False
Answer:
False. Temperature is independent of volume
Answer: the answer False sorry if its wrong
Explanation: have a nice day\night buddy
why brittles of a paint brush spread when in water and cling when taken out of water
Answer:
surface tension
Explanation:
because of surface tension in water
Kepler's second law states that a line from the sun to a planet sweeps out equal areas in equal times. 2 d coordinate system with an elliptical orbit of planet around the sun. The elliptical orbit is centered at the origin. The Sun is located on the x axis between the origin and the far left edge of the orbit. The Planet is on the orbital path in the first quadrant and has a velocity vector that is pointing counter-clockwise on the orbital path. There is a line connecting the sun and the planet. The Perihelion is marked as the point where the orbit crosses the x axis closest to the Sun. The Aphelion is marked as the point where the orbit crosses the x axis farthest away from the Sun. The aphelion is the point in the orbit where the planet is the furthest distance from the sun, The perihelion is the point at which the planet is closest to the sun. At which point must the speed of the planet be greater
Answer:
the speed is higher in the PERIHELIUM
Explanation:
As stated in your statement, Kepler's second law says that a vector from the sun to the planet also sweeps equal in equal times. This is a consequence that the sun-planet system is isolated, therefore the angular momentum is conserved.
L = r x p = m r x v
where m is the planet mass and the Sun is considered fixed
Let's analyze this expression, if the anglar momentum is a constant when r is less (perihelion) the speed must increase, so that the product remains fixed
So the speed is higher in the PERIHELIUM
what is the range of plane if the angle of the projective is 30° with a speed of √2g?
Answer:
The range is 17.32 m
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Initial velocity (u) = √2g
Acceleration due to gravity (g) = 10 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine2θ /g
R = (√2g)²Sine 2θ / g
R = 2g² × Sine (2×30) / g
R = 2g × Sine 60
R = 2 × 10 × 0.8660
R = 17.32 m
Therefore, the range is 17.32 m
What could damage the eardrum and bones of the middle ear?
a) earwax
b) harmful noise
c) hammer
d) anvil
Answer:
B or D
Explanation:
I wanna say B but I don't really know if it's a trick question
my explanation for D is that anvils are usually 110 decibles and ear drums usually are damaged when exposed to 82dbs or higher at a consistant rate so I'd imagine that'd be the answer I hoped this helped
Answer:
the answer is B
Explanation:
Any harmful noises can be bad. yes, an Anvil and Hammer can be bad but so can explosions and gun fire and having music to loud
A 8.57-m ladder with a mass of 21.4 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 258 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.63 rad/s2 about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder
Answer:
[tex]1311.5\ \text{Nm}[/tex]
Explanation:
l = Length of ladder = 8.57 m
m = Mass of ladder = 21.4 kg
F = Force on ladder = 258 N
[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Net torque is given by
[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]
The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].
Un coche que lleva una velocidad constante de 90 km/hora durante 2 horas ¿Cuánto espacio recorre?Si encuentra un obstáculo en la carrera y tiene que parar 10 segundos calcula la aceleración
Answer:
(i) El coche recorre 180 kilómetros.
(ii) El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Explanation:
El problema se divide en dos partes. La primera es el coche viajando a velocidad constante y la segunda consiste en una decelaración hasta alcanzar el reposo.
Primera parte - Viaje a velocidad constante
La distancia recorrida por el coche se calcula mediante la siguiente ecuación cinemática:
[tex]x = v\cdot t[/tex] (1)
Donde:
[tex]x[/tex] - Distancia recorrida, en kilómetros.
[tex]v[/tex] - Velocidad, en kilómetros por hora.
[tex]t[/tex] - Tiempo, en horas.
Si sabemos que [tex]v = 90\,\frac{km}{h}[/tex] y [tex]t = 2\,h[/tex], entonces la distancia recorrida por el coche es:
[tex]x = v\cdot t[/tex]
[tex]x = 180\,km[/tex]
El coche recorre 180 kilómetros.
Segunda parte - Deceleración
Asumiendo que la deceleración del coche es constante, se determina mediante la siguiente ecuación cinemática:
[tex]a = \frac{v-v_{o}}{t}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial, en metros por segundo.
[tex]v[/tex] - Velocidad final, en metros por segundo.
[tex]t[/tex] - Tiempo, en segundos.
Si sabemos que [tex]v_{o} = 25\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], entonces la deceleración experimentada por el coche es:
[tex]a = -2.5\,\frac{m}{s^{2}}[/tex]
El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Can you describe how and why the molecules move from one side to the other?
The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.
The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.
The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.
The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.
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When electrons are shared unequally a/an
bond is formed
do the planets orbit the sun in a perfect circle
Answer:
All the planets in the Solar System orbit the Sun. When planets orbit the Sun, they don’t move around in a perfect circle. They all follow an 'elliptical path', meaning it looks more like an oval.
Explanation:
Answer:no planets orbit the sun in a perfect circle because they travel in a slightly elliptical orbit
Explanation:
A or B??????????????
Susan uses a system of pulleys to lift a 355 N box, but she only exerts 25 N. What is the MA of the pulley system?
Answer:
oof
Explanation:
oof
Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]
let's calculate
v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]
v = 17.30 m / s
A volleyball of mass 0.28 kg is dropped from the top of the bleachers (height equals 12 m). What is the speed of the volleyball right before it hits the gym floor?
Answer:
hope this help pls give me brainless
The speed of the volleyball with a mass of 0.28 kg and height of 12 m will be 15.336 m/s.
What is Speed?
Speed is the rate of change of distance of an object with respect to time. Speed is a scalar quantity as it has only magnitude and no direction. The SI unit of speed is meter per second (m/s).
PE = KE
Potential Energy = Kinetic energy
mgh = 1/2 mv²
where, m is the mass of object,
g is the acceleration due to gravity,
h is the height of the object,
v is the speed of the object
gh = 1/2v²
2gh = v²
v = [tex]\sqrt{2gh}[/tex]
v = [tex]\sqrt{2(9.8)(12)}[/tex]
v = [tex]\sqrt{235.2}[/tex]
v = 15.336 m/s
Therefore, the speed of the volleyball will be 15.336 m/s.
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The image above shows a raging mountain river in full flood. What do you think is making the water brown in color?
Answer:
FloodPlains
Explanation:
The floodplains mix with the dirt in the water in which then makes it brown. You're welcome:)
The floodplain is making the water brown in color.
A flood plain area can be defined as a specific land area prone to be flooding.Floodplain areas are often found in the coastline of streams and/or rivers.The brown color is due to the presence of soil that mixes with water.In conclusion, the floodplain is making the water brown in color.
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If the mass of the cement is 15000kg. calculate the density of this cement sample in kgm-3
The density of this cement sample is equal to [tex]2727.27\;kg/m^3[/tex]
Given the following data:
Mass of cement = 15000 kgLength = 1.1 mWidth = 2 mHeight = 2.5 mTo calculate the density of this cement sample:
First of all, we would determine the volume of the rectangular block.
[tex]Volume = length \times width \times height\\\\Volume = 1.1 \times 2 \times 2.5\\\\Volume = 5.5 \;m^3[/tex]
Now, can calculate the density of this cement sample:
Mathematically, the density of a substance is given by the formula;
[tex]Desnity =\frac{Mass}{Volume}[/tex]
Substituting the values into the formula, we have;
[tex]Density=\frac{15000}{5.5} \\\\Density =2727.27\;kg/m^3[/tex]
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Note: 1.1 m, 2 m, 2.5 m are the figures provided from a rectangular block of cement.
8.How long is a day? A year?
Answer:
24 hours. 365 days
Explanation:
1. Which term is the name given to the underwater mountains in the
middle of oceans? *
mid-ocean crust
mid-ocean mountas
mid-ocean ridges
mid-ocean basins
Answer:
The name given to the underwater mountains in the middle of oceans is;
Mid-ocean ridges
Explanation:
Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.
The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.
Series circuit when you had one bulb and battery voltage was at 9 volts, what was current into battery?
1) .90amps
2) .40amps
3) .30 amps
Answer:
incomplete question, resistor must be there
Explanation:
PLEASE HELP - In running a ballistics test at the police department, Officer Rios fires a 6.1g bullet at 350 m/s into a container that stops it in 0.32 min. What average force stops the bullet?
Answer:
–0.11 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 6.1 g
Initial velocity (u) = 350 m/s
Time (t) = 0.32 mins
Final velocity (v) = 0 m/s
Force (F) =?
Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
0.32 mins = 0.32 × 60 = 19.2 s
Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:
Initial velocity (u) = 350 m/s
Time (t) = 19.2 s
Final velocity (v) = 0 m/s
v = u + at
0 = 350 + (a × 19.2)
0 = 350 + 19.2a
Collect like terms
0 – 350 = 19.2a
–350 = 19.2a
Divide both side by 19.2
a = –350 / 19.2
a = –18.23 m/s²
Next, we shall convert 6.1 g to Kg.
1000 g = 1 Kg
Therefore,
6.1 g = 6.1 g × 1 Kg / 1000 g
6.1 g = 0.0061 Kg
Finally, we shall determine the force. This can be obtained as follow:
Mass (m) = 0.0061 Kg
Acceleration (a) = –18.23 m/s²
Force (F) =?
F = ma
F = 0.0061 × –18.23
F = –0.11 N
NOTE: The negative sign indicates that the force is in opposite direction.
Answer:
–0.11 N.
Explanation:
Hope this helps
This was merely an accident and I did not mean to post a question.
Answer:
ok a good rest of your day
Explanation:
580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum (m=3)?
(Remember, nano means 10^-9.)
(Unit=deg)
Answer:
0.66 degrees
Explanation:
The computation of the angle of the third dark interference is shown below:
The condition of the minima is
Path difference = (2n +1) × [tex]\lambda[/tex]÷ 2
For third minima, n = 2
Now
xd ÷ D = (2 × 2 + 1) × [tex]\lambda[/tex]÷ 2
d tan Q_3 = 5[tex]\lambda[/tex] ÷ 2
tan Q_3 = 5[tex]\lambda[/tex] ÷ 2d
Q_3 = tan^-1 × (5[tex]\lambda[/tex] ÷2d)
= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)
= 0.66 degrees
Can anyone help me!!!
I need this really soon!!!!
Q. Rama's weight is 40kg . She is carrying a load of 20 kg up to a height of 20 metres. What work does she do? Also mention the type of work
Also show step by step explanation. please!!
No links!!!!
No spams!!!!
Answer:
W = 1,176 10⁴ J
Explanation:
Work is defined by
W = F . d
bold indicates vectors
W = F d cos θ
In this case we must find the force to raise the load and the branch, suppose that the rate of rise is constant, this is the most common case
Σ F = 0
F - W₁ - W₂ = 0
where W1 is the weight of the branch and w2 wl weight of the load
F = (m₁ + m₂) g
This force is directed upwards and the displacement is upwards, therefore the angle is zero and the cos 0 = 1
we substitute in the work equation
A = (m₁ + m₂) g d
let's calculate
W = (40 + 20) 9.8 20
W = 1,176 10⁴ J
This is the work done by the external force
how to test the pH level of a soap?
Answer:
One of the most common is to use pH strips.
Explanation:
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
[tex]Thrust = mv[/tex]
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]
Thrust = 200 N
Find the displacement in meters a runner would travel in 5 hours at an average velocity of 12km/h to the southwest
*show you work pleasee*
]
Answer:
60,000m
Explanation:
Convert km/h to m/s by multiplying with 1000/3600.
Convert hours to seconds by multiplying with 3600.
Because displacement is a vector quantity and deals with the shortest distance between points, simply plug it into the equation s=vt.
What is Newton’s 3rd Law of Motion?
a. Name an example and be sure to tell HOW it demonstrates the law.
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.
Explanation:
Please solve Question 10
Answer:
Time = 0.6secs
Explanation:
10) Distance = speed * time
Given the following
Distance = 204m
Speed/velocity = 340m
Get the time
Time = distance/velocity
Time = 204/340
Time = 0.6secs
Renewable energy resources like solar energy and wind power are still too expensive to be practical on a large scale. True or False?
Answer: False
Explanation:
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]