Answers
[tex]81c {}^{2} - 4 = (9c - 2)(9c + 2)[/tex]
since it is in the form of:
[tex]x {}^{2} - y {}^{2} = (x - y)(x + y)[/tex]
2)
[tex]75x {}^{2} - 27y {}^{2} = (5 \sqrt{3} x - 3 \sqrt{3} y)(5 \sqrt{3} x + 3 \sqrt{3} y)[/tex]
3)
[tex]z {}^{2} + 12z + 36[/tex]
[tex]z {}^{2} + 6z + 6z + 36[/tex]
[tex]z(z + 6) + 6(z + 6)[/tex]
[tex](z + 6)(z + 6)[/tex]
[tex](z + 6) {}^{2} [/tex]
4)
[tex]4f {}^{2} + 18f + 18f + 81[/tex]
[tex]2f(2f + 9) + 9(2f + 9)[/tex]
[tex](2f + 9)(2f + 9)[/tex]
[tex](2f + 9) {}^{2} [/tex]
5)
[tex]49a {}^{2} - 14a + 1[/tex]
[tex](7a - 1) {}^{2} [/tex]
6)
[tex]x {}^{4} - 16[/tex]
[tex](x {}^{2} - 4)(x {}^{2} + 4)[/tex]
Related Questions
Helpppppp!!!
(Show work)
Answers
Answer:
( - y - 3 , - x - 1 )
Step-by-step explanation:
( x , y ) ----> ( - y , x ) ----> ( - y - 3 , x + 1 ) ----> ( - y - 3 , - x - 1 )
PLEASE HELP WILL GIVE BRAINLIEST
Answers
Answer:
(2, -1)
Step-by-step explanation:
x = 2, y = −1
4.5
3
5
х
Find the length of x
Answers
3
5
х
Find the length of x= 3
For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.
an = (-3) n - 1
an = -3 · an - 1 where a1 = -1
an = -3 · an - 1 where a1 = 1
an = -1 · (-3) n - 1
Answers
Answer:
an = -3 · an - 1 where a1 = -1.
Step-by-step explanation:
The first term a1 = -1 and the common ratio is -3 so ecah term is formed form the previous one by multiplying by -3.
There are 221 students on a field trip.
. Five students ride in a van.
. The rest of the students fill 6 buses.
Enter an equation that can be solved to find the number of students, s, that are on each bus. Enter your response in
the first response box.
Enter the number of students that are on each bus. Enter your response in the second response box.
Answers
The equation that models the students is a linear equation
The equation that models the number of students in each bus is 6x = 216, and the number of students in each bus is 36
How to determine the equation?The given parameters are:
Students = 221
Van = 5
The rest students = 6 buses
Start by calculating the number of students remaining:
Remaining students = 221 - 5
Remaining students = 216
Represent the number of students in each bus with x.
So, we have:
6 buses * x = Remaining students
This gives
6x = 216
Divide both sides by 6
x = 36
Hence, the equation that models the number of students in each bus is 6x = 216, and the number of students in each bus is 36
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help me please!! will choose brainlyest if you get it right
Answers
Please help, again. I really need this grade!
Answers
H=1208/18= 67.11, SD= 4.54
(5,63), (7,61), (4,60), (6.5,64), (12,77), (9,72), (8,66),(4,65), ((9,70), (8,69),(7.5,65),(4,62), (6.5,65), (6,66), (11.5,67),(10.5,71), (10.5,74),(11,71)
HELPP PLEASE!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
Third one down |2s + 1| -3
Step-by-step explanation:
there is no value of s where it is valid
Please Help! Will give Brainlest!
Answers
Answer:
amplitude = 2
Step-by-step explanation:
the amplitude is the distance from the x- axis(midline ) to the maximum value , that is
amplitude = 2
[tex]\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\ [/tex]
Option B ( 2 ) ✓
the amount by which the graph of the function travels above and below its midline.OR,
[tex] \sf{amplitude = distance \: from \: undisturbed \: position \div centre \: line \: to \: through \: or \: peak \: }[/tex]
[tex]\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}[/tex]
[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]
the diameter of a circle is 13.8cm. Find the length of its radius
Answers
Hello!
R = D/2
R= 13,8/2 => 6,9cm
The length of the circle's radius is 6.9 cm.
The diameter of a circle is twice the length of its radius. So, to find the length of its radius (r), you can divide the diameter (d) by 2.
Given: Diameter (d) = 13.8 cm
Length of radius (r) = d / 2
r = 13.8 cm / 2
r = 6.9 cm
The length of the circle's radius is 6.9 cm.
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At which point would the graphs of the equations below intersect?
{
3
x
−
4
y
=
−
2
−
6
x
+
5
y
=
7
3x-4y = -2 -6x+5y = 7
A.
(
−
2
,
−
1
)
(
-
2
,
-
1
)
B.
(
2
,
−
1
)
(
2
,
-
1
)
C.
(
−
1
,
2
)
(
-
1
,
2
)
D.
(
−
1
,
−
2
)
Answers
Answer:
can't explain without you arranging your mathematical expression
Solve the equation . 5x+17=42
Answers
-17 -17
5X = 42
—— ——
5 5
X = 5
Answer:
x = 5
Step-by-step explanation:
5x+17=42
5x + 17 - 17 = 42 - 17
Dylan owns a bag that contains 7 blue marbles, 5 purple marbles, 12 red marbles, and 6 orange marbles. If he randomly pulls a marble from the bag, What is the probability of him pulling a red marble? What is the probability of him pulling a blue or purple marble?
Answers
Answer:
The probability of him pulling a red marble is 12 to 30. The probability of him pulling a blue or purple marble is also 12 to 30.
Step-by-step explanation:
7+5+12+6=30 (all colors)
12 to 30 red ones
7+5+12+6=30 (all colors) and
7+5=12 (blue + purple)
12 to 30 blue or purple
Fill in the table using this function rule
y=2x+2
Photo ⬇️
Answers
Answer:
Step-by-step explanation:
Put the values of x to the equation y = 2x + 2 and calculate the value of y:
x = 2
y = 2 · 2 + 2 = 4 + 2 = 6
x = 5
y = 2 · 5 + 2 = 10 + 2 = 12
x = 6
y = 2 · 6 + 2 = 12 + 2 = 14
x = 8
y = 2 · 8 + 2 = 16 + 2 = 18
please show steps to solve the problem thank you
Answers
Answer:
65 total number of boys
Step-by-step explanation:
In the boys row there are 45 "Blue" boys and 20 "Orange" boys.
You can add these numbers up together to find the answer to this problem.
45 + 20 = 65
65 total number of boys
45+20 = 65
Find the smallest number by which 350
must be multiplied to give a perfect square.
Answers
Answer:
the smallest number by which 350 by answer is 15
Can sombody solve this please. :)
Answers
144 x m - 309.6 = 50.4
Add 309.6 to both sides:
144 - 309.6 + 309.6 = 50.4 + 309.6
Simplify the arithmetic:
144 x m = 50.4 + 309.6
Simplify the arithmetic:
144 x m =360
m = 5/2
(h+1)^2=16 solve using square root property
Answers
Answer: h = 3
Step-by-step explanation:
(h+1)² = 16
h+1 = √16
h+1 = 4
h = 3
Hope this helped :)
Answer:
[tex]h=3, \ h=-5[/tex]
Step-by-step explanation:
[tex](h+1)^2=16[/tex]
[tex](h+1)^2=16[/tex]
[tex]\sqrt{(h+1)^2} = \±\sqrt{16}[/tex] <== you take the square root of both sides
[tex](h+1) = \±\ 4[/tex] <== you take the square root of both sides
[tex](h+1) = +\ 4, \ (h+1) = -\ 4[/tex] <== separate into 2 equations and solve
[tex]h+1 = 4, \ h+1 = -\ 4\\\\. \ -1 -1, \ \ \ \ -1\ \ \ \ -1\\\\h=3, \ h=-5[/tex]
Hope this helps!
can someone help me? it’s due in a few hours
Answers
Answer:
cars value decreases in value exponentially
Step-by-step explanation:
cant really read it but say that the cars value decreases in value exponentially and compare that to however the other cars decrease in value over time
A rectangle has length 1. 5 times the width, and perimeter 12 cm. What are the dimensions of
the rectangle?
Answers
Answer:
Length = 3.6
Width= 2.4
Step-by-step explanation:
A rectangle has length 1. 5 times the width, and perimeter 12 cm. What are the dimensions of
the rectangle?
So a rectangle has 2 longer sides and 2 shorter sides.
Knowing the length is 1.5 times the width
and perimeter of 12 centimeters.
The Perimeter is the adding of all the values around a shape. A rectangle has 4 sides so you add up all the sides.
1.5w+1.5w+w+w=12
5w=12
12/5=w
w=2.4
To figure the length just multiply 1.5*2.4=3.6
And That is how you solve it :)
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If you need any help, im at your service :)
Christopher opened a savings account with $1800 that pays no interest. He deposits an additional $90 each week thereafter. How much money would Christopher have in the account 42 weeks after opening the account?
Answers
Answer:
I think 5580
Step-by-step explanation:
You move the 1800 away for a bit so since it's 42 weeks you have to multiply 90 and 42 then add that to 1800.
Lines j and k are intersected by line m. At the intersection of lines j and m, the uppercase left angle is 93 degrees. At the intersection of lines k and m, the bottom right angle is 93 degrees.
Given the information in the diagram, which theorem best justifies why lines j and k must be parallel?
alternate interior angles theorem
alternate exterior angles theorem
converse alternate interior angles theorem
converse alternate exterior angles theorem
Answers
Answer: converse alternate exterior angles theorem
Step-by-step explanation:
The angles are alternate exterior angles.
Helppppppppppppppppppp
Answers
Answer:
8/27
Step-by-step explanation:
It says to use V=s^3.
s is the the side length of the cube which is 2/3 in this case.
So to get your answer you have to do: (2/3)^3 or 2/3 x 2/3 x 2/3.
Can someone please answer & show work? Thanks.
Answers
Which value is a solution to x <
Answers
Answer:
0
Step-by-step explanation:
it less than 4 so u can't pick 4,so it is any number less than 4
Answer:
B) 0
Step-by-step explanation:
The open circle on 4 and the arrow pointing to the left means x < 4
x < 4 means that x is smaller than 4
4 = 4 incorrect as this says 4 is equal to 4
0 < 4 CORRECT as zero is smaller than 4
5 > 4 incorrect as 5 is bigger than 4
4.5 > 4 incorrect as 4.5 is bigger than 4
The length of one leg of an isosceles right triangle is 3 ft. What is the perimeter of the triangle? 3 3 StartRoot 2 EndRoot ft 3 3 StartRoot 3 EndRoot ft 6 3 StartRoot 2 EndRoot ft 6 3 StartRoot 3 EndRoot ft.
Answers
The perimeter of the isosceles right triangle comes to be 6+3√2.
Given that the length of one leg of an isosceles right triangle = 3 ft
What is an isosceles right triangle?A right-angle triangle having sides other than hypotenuse equal to each other is called an isosceles right triangle.
So, The length of the other leg of an isosceles right triangle = 3 ft
From Pythagoras theorem
Hypotenuse²=Perpendicular²+Base²
So, in the given isosceles right triangle
Hypotenuse²=Leg 1²+Leg2²
Leg 1=Leg2 = 3 feet
Hypotenuse² = 3²+3²
Hypotenuse = 3√2 ft.
So, the perimeter of the triangle = 3+3+ 3√2
The perimeter of the triangle =6+3√2
Therefore, The perimeter of the isosceles right triangle comes to be 6+3√2.
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Answer:
6 + 3 StartRoot 2 EndRoot ft
Step-by-step explanation:
Edge2022
Use the linear inequality + 8y 24 for Part A, Part B, and Part C. Part A: Determine the boundary line, and state whether the line will be dashed or solid. Part B: Which half-plane should be shaded? Describe where you should shade using the language "above" or "below" the line. Part C: Show your work for Part B to show how you determined which half-plane to shade.
Answers
Answer:
Given inequality: [tex]x+8y\leq 24[/tex]
Part A
Solid line: ≤ or ≥
Dashed line: < or >
Therefore, the line will be solid.
Part B
Shading above the line: y > or y ≥
Shading below the line: y < or y ≤
Therefore, shade below the line.
Part C
Make y the subject to determine where to shade.
Given inequality:
[tex]x+8y\leq 24[/tex]
Subtract x from both sides:
[tex]8y\leq 24-x[/tex]
Divide both sides by 8:
[tex]y\leq 3-\dfrac18x[/tex]
[tex]\\ \rm\Rrightarrow x+8y\leqslant 24[/tex]
#Part A
as ≤ is present line will be dashed#Part B
Put (0,0)
0+8(0)≤240≤24Satisfied
Shading below the line and towards origin
#Part C
turn into y=mx+b form
8y≤-x+24y≤-1/8x+36,402.66 divided by 459438.26
Answers
Answer: 0.0139358
Step-by-step explanation: 999,999,999,999,999,999,999,999,999,999,999% sure!
You can buy jars of the same jam in two sizes.
Answers
Step-by-step explanation:
Large Jar 540g for 2.16
540/2.16 = 250
(Always divide by the smallest ratio)
= 250g per 1£
Small Jar 360g for 1.37
360/1.37=262.77g
= 262.77g per 1£
Small Jar is the best value for money, more grams, same price.
What are quadratic equations? What are some examples?
Answers
Answer:Examples of quadratic equations are: 6x² + 11x – 35 = 0, 2x² – 4x – 2 = 0, 2x² – 64 = 0, x² – 16 = 0, x² – 7x = 0, 2x² + 8x = 0 etc. From these examples, you can note that, some quadratic equations lack the term “c” and “bx.”
Step-by-step explanation:
A quadratic equation in the variable x is an equation of the form ax^2 + b x + c = 0, where a, b, c are real numbers, a ≠ 0.
What are quadratic equations?Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations.
The standard form of a quadratic equation is;
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax^2 + bx + c where a, b, c, ∈ R and a ≠ 0.
These are the following examples of the quadratic equation;
x^2-2x
x^2+5x+6
x^2-5x
Any equation of the form p (x) = 0, where p (x) is a polynomial of degree 2, is a quadratic equation.
If we write the terms of p (x) in decreasing order of their degrees, then we get the standard form of the equation.
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