Match each phylum with the correct description
cnidarians
internal skeletons made of hardened plates
echinoderms
radial symmetry and stinging cells
arthropods
jointed body parts and an external skeleton
annelids
segmented body and closed circulatory
system

Answer:

convection

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Explanation:

Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.

Explanation:

Given: Mass of calcium carbonate = 45 g

Volume = [tex]100 cm^{3}[/tex]

Convert [tex]cm^{3}[/tex] into L as follows.

[tex]1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L[/tex]

Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.

[tex]No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol[/tex]

Molarity is the number of moles of solute present in a liter of solution.

Hence, molarity (or mass concentration) of given solution is calculated as follows.

[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M[/tex]

Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.

Answer:

25.42 grams

Explanation:

The specific heat of water is 4.18 J/g •°C, so that means that it takes 4.18 joules of energy to raise one gram of water 1 °C.

Change in temp = 55 - 15 = 40°C

So we can calculate how much energy it would take to raise the temp of one gram of water by one degree using the following

(4.18 J/g•°C) * (40°C) * (1 gram) = 167.2 J

So if it takes 167.2 J of energy to raise on gram of water 40°C, we now we can calculate the amount of grams of water that can heated with 4250 J of energy

(4250 J) ÷ (167.2 J) = 25.42 grams of water can be heated from 15°C to 55°C

Answer:

A-Sphalerite + Dioxygen+Zinc Oxide+Sulfur Trioxide

B-Sodium+Magnesium+Sodium iodide

Explanation:

Heyyy love good luck i may be wrong on letter B so if it is thats my bad but A should be correct :)

Answer:

22.67 L of PH₃

Explanation:

The balanced equation is:

[tex]P_4 (s) + 6H_2(g) \to 4PH_3(g)[/tex]

From the equation:

[tex]34 L \times \dfrac{1 \ mol \ of H_2 }{22.4 \ L \ H_2} \times \dfrac{4 \ mol \ of \ PH_3}{6 \ mol \ H_2} \times \dfrac{22.4 \ L \ PH_3}{1 \ mol \ PH_3}[/tex]

= 22.67 L of PH₃

Answer:

1. 1.33 gram of carbon

2. 2.38g of carbon dioxide

Explanation:

From the given information:

Total amount of CO₂ = 4.86 grams

Atomic mass of C = 12 g/mole

molar mass of CO₂ = 44 g/mole

∴

The mass of the Carbon (C) in grams is:

[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

= 1.33 gram of carbon

2.

Here, the total amount of CO₂ = unknown

Atomic mass of O₂ = 32 g/mole

molar mass of CO₂ = 44 g/mole

amount of oxygen = 1.73 g

∴

The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

= 2.38 g of carbon dioxide

Answer:

500J (joules)

Explanation:

since heat is is the product of mass, change in temperature, and specific heat, the solution can be found from the equation q = mcΔt, heat is 50 * .5 * 20 = 500J

Answer:

THERE ANSWER IS C

Explanation:

Answer:

1. The empirical formula => C₆H₁₀OS₂

2. Molecular formula => C₃₆H₆₀O₆S₁₂

Explanation:

1. Determination of the empirical formula.

Carbon (C) = 2.96 g

Hydrogen (H) = 0.414 g

Oxygen (O) = 0.675 g

Sulphur (S) = 2.96 g

Divide by their molar mass

C = 2.96 / 12 = 0.247

H = 0.414 / 1 = 0.414

O = 0.675 / 16 = 0.042

S = 2.96 / 32 = 0.0925

Divide by the smallest

C = 0.247 / 0.042 = 6

H = 0.414 / 0.042 = 10

O = 0.042 / 0.042 = 1

S = 0.0925 /0.042 = 2

Therefore, the empirical formula is

C₆H₁₀OS₂

2. Determination of the molecular formula.

Molar mass of compound = 972 g/mol

Empirical formula => C₆H₁₀OS₂

Molecular formula =>?

Molecular formula = [C₆H₁₀OS₂]ₙ

Molecular formula = molar mass of compound

Thus,

[C₆H₁₀OS₂]ₙ = 972

[(12×6) + (10×1) + 16 + (32×2)]n = 972

[72 + 10 + 16 + 64]n = 32

162n = 972

Divide both side by 162

n = 972 / 162

n = 6

Molecular formula = [C₆H₁₀OS₂]ₙ

Molecular formula = [C₆H₁₀OS₂]₆

Molecular formula = C₃₆H₆₀O₆S₁₂

Answer:

All of the following statements are true regarding wood versus metal except:

c) Under sustained loads wood stops to deform

Explanation:

Wood is known to deform under stress.  It undergoes warping, thereby, losing its original straight shape when its moisture unevenly dries up.  Even concrete deforms under long-time loads.  Similarly, wood, under sustained loads, experiences faster deformation than it ordinarily warps.  To prevent further wood deformation, it must be treated, and its moisture dried up evenly.

Answer:

(b) fully filled valence s orbitals

Explanation:

Electron configuration of Be: 1s22s2

2s2 is fully filled

Answer:

d.) granulated

Because the granulated sugar has a greater surface area.

240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an unknown mass of iron (specific heat = 0.444 J/gºC, initial temperature 500°C). When equilibrium is reached,The answer for this would be 69.6

You use q = mcΔT, but you assume aluminum = water and crack for This the final temperature.

We need to look up heat values (c) for aluminum and h20. This will uses 0.901 for aluminum and 4.18 use water

: (10)(130 - T)(0.901) = (200.0)(T - 25 (6)

Hence, The answer for this would be 69.6.  

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Answer:

New volume = 2.03 L

Explanation:

Given that

Initial temperature, T₁ = 25°C = 298 K

Initial volume, V₁ = 2L

Final temperature, T₂ = 30°C = 303 K

We need to find the final volume. The mathematical form of Charle's law is given by :

[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}[/tex]

Put all the values,

[tex]V_2=\dfrac{2\times 303}{298}\\\\V_2=2.03\ L[/tex]

so, the new volume is equal to 2.03 L.

Answer:

They cause boys' and girls' bodies to develop

Answer:

True! A transverse wave does move a medium at an obtuse angle to the wave!!

Answer:

False

Explanation:

Answer:

It’s answer #2

Explanation:

I only know this because i just got it wrong

The correct structural formula for the acid that is poured into the beaker is CH₃COOH.

Acetic acid is also called ethanoic acid. It is form as a byproduct of fermentation. It forms vinegar. Vinegar is 4 to 6% acetic acid with water.

It is widely used in homes as cleaning agent, in cooking, washing etc.

Thus, the correct option is 2, CH₃COOH.

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Answer:

Molarity = moles ÷ liters

to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)

Na = 22.989769

Br = 79.904

molar mass of NaBr = 102.893769

6.6g ÷ 102.893769 = 0.064143826 moles of NaBr

0.064143826 moles ÷ 0.60 liters = 0.1069 molar concentration or 11 %

Answer:

Branched chain

Cycloalkane

Straight chain

Explanation:

Answer:

Conduction

Explanation:

I took the course

Answer:

B. conduction

Answer:

D

Explanation:

Answer:

LiCl.

Explanation:

Hello there!

In this case, since it is known that the ionic compounds are specially formed between metals and nonmetals, it is possible for us to discard CO and PCl5 as they have both nonmetals.

On the other hand, since the bonds between nonmetals and transition metals like iron and copper may not be completely ionic due to the electronegativity trend, we infer that the most likely ionic compound is LiCl because of the large electronegativity difference.

Regards!

Answer:

The molecules in gasoline (octane, the chemical formula shown) contain chemical energy. This energy is transformed into kinetic energy that allows a car to race on a racetrack.

Strata are the layers of rock or soil that are distinguishable from other layers that have been laid down upon one another over the history of the earth.

A strata is the horizontal layer of rocks or sedimentary rocks that are laid upon another or arranged one on top of another that is separated by adjacent beds planes or layers.

Therefore, Strata are the layers of rock or soil that are distinguishable from other layers that have beenlaid down upon one another over the history of the earth.

Learn more about strata below.

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