Mia bought 8 copies of the same book. She spent $32.
What was the cost of one book?

Answer:

204 R45

Step-by-step explanation:

Answer: The answer will be 205 R2

Step-by-step explanation:

I know this because the steps to dividing are:

D - Divide

M - Multiply

S - Subtract

B - base(total)

If you do all of those steps then you'll get 205 R2

R = remainder(left overs)

So, the answer will be 205 R2

Answer:

use the linear equation of a line

equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

now u do the rest

Answer:

A. -5

Step-by-step explanation:

-9 + 4 = -5

hope this helps

Answer:

54

Step-by-step explanation:

hi

Answer:

That old mans change in height is -1 1/4 over 5 years.

Step-by-step explanation:

Answer:

-5/4 cm would be the answer.

Step-by-step explanation

This is the answer because -1/4 cm multiplied by 5 years would equal -5/4 cm.

Step-by-step explanation:

1) 13.57

+2.93

With this, we subtract from the back Meaning we add starting from back to forward;

13.57

+2.93

16.50

We have that because when you add 7 and 3 you get 10 so we write the 0 there and add the remaining 1 to the 5 making it 6 and then 6 plus 9 will give you 15 then we write the 5 then we add the remaining 1 to the 3 making it 4 then we add the 4 to the 2 making it 6 after this there is no remainder so we just write the 1.

Answer:

He can make 4 batches of sugar cookies.

Step-by-step explanation: 4x1/2=2 and because he lost 1 cup, he only has 2 cups left

Answer:

After solving the compound inequality [tex]1.5x-1>6.5 \ or \ 7x+3<-25[/tex] we get [tex]\mathbf{x>5 \ or \ x<-4}[/tex]

Option B is correct.

Step-by-step explanation:

We are given compound inequality: [tex]1.5x-1>6.5 \ or \ 7x+3<-25[/tex]

We will first solve the inequalities to find the value of x, then will draw the graph.

[tex]1.5x-1>6.5 \ or \ 7x+3<-25\\1.5x-1+1>6.5+1 \ or \ 7x+3-3<-25-3\\1.5x>7.5 \ or \ 7x<-28\\x>\frac{7.5}{1.5} \ or \ x<\frac{-28}{7}\\x>5 \ or \ x< -4[/tex]

So, after solving the compound inequality [tex]1.5x-1>6.5 \ or \ 7x+3<-25[/tex] we get [tex]\mathbf{x>5 \ or \ x<-4}[/tex]

Now, the number line will be as shown in figure.

The description as given in options is:

A number line goes from negative 10 to positive 10. An open circle appears at negative 4 and positive 5. The number line is shaded from negative 4 toward negative 10. The number line is also shaded from positive 5 toward positive 10.

so, Option B is correct.

Answer:

the answer is b

Step-by-step explanation:

2020 edge

Answer:

A) - 54.48

Step-by-step explanation:

Just plug it into the calculator like this;  (-68.1) x 0.8, which equals -54.48.

the answer is negative because you multiplied a positive # and a negative #.

Answer:

[tex]a = p*q\\b = (p*s)+(q*r)\\c = r*s[/tex]

Step-by-step explanation:

The standard form of trinomial is given as:

[tex]ax^2+bx+c[/tex]

And the factored form is:

[tex](px+r)(qx+s)[/tex]

In order to find the values of a,b and c in terms of p,q,r and s we will take the factored form, multiply it and then compare it with the standard form.

So,

[tex](px+r)(qx+s)\\=px(qx+s)+r(qx+s)\\= pqx^2+psx+qrx+rs\\= pqx^2+(ps+qr)x+rs[/tex]

Now comparing it with the standard form of trinomial

We will compare the co-efficients of x^2, x and the constant

By comparing, we get

[tex]a = pq = p*q\\b = ps+qr = (p*s)+(q*r)\\c = rs = r*s[/tex]

Hence,

[tex]a = p*q\\b = (p*s)+(q*r)\\c = r*s[/tex]

Answer:

Step-by-step explanation:

[tex]1\frac{1}{3} - 2\frac{1}{5} +\frac{7}{10}[/tex]

[tex]=-\frac{13}{15} +\frac{7}{10}[/tex]

[tex]=-\frac{1}{6}[/tex]

Answer:

uh is  it 2 and o.6 i think

Step-by-step explanation:

Step-by-step explanation:

H hvuvuvuvuvuv9yvig kg

Answer:

p = 304

Step-by-step explanation:

Given p is inversely proportional to q² then the equation relating them is

p = [tex]\frac{k}{q^2}[/tex] ← k is the constant of proportion

To find k use the condition p = 19 when q is 8, then

19 = [tex]\frac{k}{8^2}[/tex] = [tex]\frac{k}{64}[/tex] ( multiply both sides by 64 )

k = 1216

p = [tex]\frac{1216}{q^2}[/tex] ← equation of proportion

When q = 2, then

p = [tex]\frac{1216}{2^2}[/tex] = [tex]\frac{1216}{4}[/tex] = 304

The value of p is equal to 304 when q is equal to 2

Given :

If p is inversely proportional to the square of q

when y is inversely proportional to x then [tex]y=\frac{k}{x}[/tex]

given that p is inversely proportional to the square of q. the equation becomes

[tex]p=\frac{k}{q^2}[/tex]

when p is 19 the value of q is 8

Replace the values and find out k

[tex]p=\frac{k}{q^2}\\19=\frac{k}{8^2}\\19=\frac{k}{64}\\[/tex]

Multiply both sides by 64

k=1216

Now we find out p when q is 2

Replace k value and q value to find out p

[tex]p=\frac{k}{q^2} \\\\p=\frac{1216}{2^2} \\p=304[/tex]

The value of p is equal to 304 when q is equal to 2

Learn more :  brainly.com/question/16069814

Answer:

(2^3 square root 12)(3^3 square root 2)​(32 square root)

Step-by-step explanation:

i lie

Answer:

432

Step-by-step explanation:

I checked it trust me

45- 3, 5, 9

369- 3, 9

7870- 2, 5, 10

1976- 2, 4,

6003- 3, 9

136- 2, 3, 4

1674- 2, 3, 6, 9

35496- 2, 3, 4, 6, 9

Answer:

yes its a right trinagle

Step-by-step explanation:

well first it has a right corner which is a right angle you can tell by putting your hand like a L

Answer: It contains 88 g of zinc.

Step-by-step explanation:

Given: The ratio of zinc to copper is 4 to 13.

Ratio can be written as [tex]\dfrac4{13}[/tex]

A jar of the chemical contains 286 g of copper.

Let the quantity of zinc be x.

By using the direct proportion rule:[tex]\dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}[/tex]

[tex]\dfrac{x}{286}=\dfrac{4}{13}\\\\ x=\dfrac{286\times4}{13}\\\\\Rightarrow\ x=88[/tex]

Hence,  It contains 88 g of zinc.

Answer: 1.45

Step-by-step explanation:

Answer:

Step-by-step explanation:

3.8-2.923

Change to 3.800 to match the number of digits in the second number. Work from right to left. 3 minus 0 is 7. work our way over until the end. You should get 0.877 for an answer.

Answer:

y = 2x -2

Step-by-step explanation:

When you shift down or up, you move down or up the y-axis. Here, the 6 was the y-intercept, so you subtract 8 from 6.

Answer:

I would put a shade over the region of x <= -5.

Step-by-step explanation:

The look of the graph would be a shaded rectangle over the line x = -5.

Hope this helped!

Answer:

Draw a closed circle on -5 and shade to the left

Step-by-step explanation:

Answer:

w=1.5 or w=13.5

Step-by-step explanation:

this is one answer:

multiply w on both sides to leave u with

4.5=3w

divide both sides by 3

[tex]\frac{4.5}{3}=\frac{3w}{3}[/tex]

1.5=w

_____________________

this is the second one if the first one is wrong:

multiply 4.5 on both sides so that the 4.5/w would leave u with just only w alone.

then 3*4.5=13.5

w=13.5

hope dis helps if not then im not dat smart enough ;?

Answer:First suppose that the roots of the equation

x2−bx+c=0(1)

are real and positive. From the quadratic formula, we see that the roots of (1) are of the form

b±b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2.

For the root or roots to be real, we require that b2−4c≥0, that is, b2≥4c. In order for them to be positive, we require that

b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√>0.

This immediately tells us that b>0, but we can go further. We can rearrange this to get

b>b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√,

which (assuming that b>0) is true if and only if

b2>b2−4c,

since both sides of the inequality are positive so we may square. But then

4c>0.

That is, if the roots are real and positive then b>0 and b2≥4c>0.

Now suppose that b>0 and b2≥4c>0.

Then the roots of (1) are real since b2−4c≥0, and b>0 guarantees that the root b+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√ is positive.

So it remains to show that b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√>0. We have that

4c>0,

so that

b2>b2−4c,

then square rooting shows that

b>b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√,

so the roots of (1) are real and positive, as required.

Approach 2

the curve y equals x squared minus b x plus c showing two positive roots for y equals zero

This is intended to be a proof without words! We have from the diagram that:

If c, b and b2−4c are all positive, there are two real positive roots for x2−bx+c=0 (if b2=4c, we have two real positive equal roots).

If there are two real positive roots for x2−bx+c=0, then c and b are positive and b2−4c is non-negative.

(Why is the distance between the roots b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√?)

Approach 3

When solving problems about the roots of polynomials, it is often useful to find expressions those roots must satisfy and see if this tells us anything new. If α and β denote the roots of the equation, then

x2−bx+c=(x−α)(x−β)=x2−(α+β)x+αβ

and so α+β=b and αβ=c.

We also know that the roots of a quadratic equation are real if and only if the discriminant is non-negative, that is, if and only if b2−4c≥0.

Using these facts, if α and β are both real and positive, then b=α+β>0, c=αβ>0 and b2≥4c, as above.

Conversely, if b>0 and b2≥4c>0, then we know the discriminant is positive and hence both roots are real. We also have that

αβ>0(2)

and

α+β>0.(3)

As α and β are both real, by (2), we know that α and β are either both positive or both negative. However, if α and β were both negative, then (3) could not possibly hold. Hence α and β are both positive, as required.

We now sketch on a graph the region where b>0, c>0 and b2≥4c:

The curve b squared = 4 c as a quadratic with the c-axis vertical and the b-axis horizontal. The region below it is shaded.

The region of the b-c plane for which b>0, c>0 and b2≥4c

Sketch the region of the b-c plane in which the roots of the equation are real and less than 1 in magnitude.

We know that in order for the roots to be real we need b2≥4c as in the first part. We now need to find the region where

−1<b±b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2<1.(4)

We have b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2≤b+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2 so we only need to consider the values for which both

−1<b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2andb+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√2<1.

Firstly, we will consider the values for which

b+b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√<2.

Rearranging gives

b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√<2−b.

So b<2, as the square root is non-negative, and we can square both sides to get

b2−4c<4−4b+b2,

which we may rearrange to find c>b−1.

We will now consider the values for which

−2<b−b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√.

Similarly, we can rearrange to get

b2−4c⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√<b+2.

So b>−2, and we can, as before, square to get

b2−4c<b2+4b+4,

and hence c>−b−1.

To sketch the graph, we start by considering the boundary curves b2=4c, c=b−1 and c=−b−1, and the points at which they intersect. We can see that the two lines only intersect when b=0 and c=−1, and the lines intersect the curve when

b2=4b−4andb2=−4b−4

which rearrange to

(b−2)2=0and(b+2)2=0.

This tells us that each line intersects with the curve in only one place and so these lines must be tangent.

Is there a way we could have deduced this directly from (4)?

What do the lines being tangent signify in terms of our equation x2−bx+c=0?

Is this a representation of a well-known property of these equations?

Sketching the graph then yields the following picture:

The graph with the previous curve and the lines 4 c = 4 b minus 4 and 4 c = minus 4 b - 4. Each line touches the curve once and the two lines intersect at (0, minus 1). The region between the three lines/curves is shaded.

The shaded region is where b2≥4c, c>b−1, c>−b−1 and −2<b<2

We might notice that when we derived the inequalities c>b−1 and c>−b−1, a lot of the work we did was very similar.

We might also notice that the graph above is symmetric about the c axis. Why is this?

Does the graph give us any ideas about how we might deduce one inequality from the other?

Step-by-step explanation: