N2 + 3H2 Right arrow. 2NH3 What is the percent yield of NH3 if the reaction of 26.3 g of H2 produces 79.0 g of NH3? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100..

Answers

Answer 1

Answer:

53.4%

Explanation:

N₂ + 3H₂ → 2NH₃

Given that:

26.3 g of H₂ react with N₂ to produce 79.0 g of NH₃

Then:

The number of moles of H₂ = 26.3g of H₂ * (1 mol of H₂/ 2.02g of H₂)

= 13.05 mol of H₂

The number of moles of NH₃ = 13.05 mol of H₂ * ( 2mol of NH₃/ 3 mol of H₂)

= 8.697 mol of NH₃

The mass of NH₃ = 8.697 mol of NH₃ *( 17.04g of NH₃/ 1 mol of NH₃) = 148.1 g of NH₃

The percent yield = actual yield/ theoretical yield * 100%

The percent yield = ( 79.0 g/ 148.1 g )* 100%

The percent yield ≅ 53.4 %

Answer 2

Answer:

53.4

Explanation:


Related Questions

54. Copper(I) sulfide is formed when copper and sulfur are
heated together. In this reaction, 127 g of copper reacts
with 41 g of sulfur. After the reaction is complete, 9 g of
sulfur remains unreacted. What is the mass of copper
sulfide formed?
SEL
Ma

Answers

Answer:

159g

Explanation:

Copper (I) sulfide is formed by the chemical reaction between copper and sulfur. Copper is a limiting reagent that results in the formation of 190.26 grams of copper(I) sulfide.

What is a limiting reagent?

A limiting reagent is defined as the reactant that gets completely utilized in the reaction and affects the amount of the product formation. On the contrary, the excess reagent is present in more amounts.

Given,

Mass of copper = 127 gm

Mass of sulfur = 41 gm

Moles of copper:

n = mass ÷ molar mass

n = 127 ÷ 63.546

n = 1.99

Moles of sulfur:

n = 41 ÷ 32.065

n = 1.27

The reaction is shown as:

Cu + S → CuS

Here, 9 g of sulfur remains unreacted and hence is an excess reagent, and copper being consumed is a limiting reagent.

Here, 1 mole of copper reacts to form 1 mole of copper sulfide hence, 1.99 moles of Cu produces, 1.99 moles of copper sulfide.

Mass of CuS is calculated as:

Mass = moles × molar mass

Mass = 1.99 mol × 95.611 g/mol

= 190.26 grams

Therefore, 127 gm of copper and 41 gm of sulfur produces 190.26 grams of copper sulfide.

Learn more about limiting reagents, here:

https://brainly.com/question/26905271

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Do all irreversible reactions go to completion? If so why?

Answers

Answer:

True

Explanation:

All irreversible reactions go to completion because the process cannot proceed in the backward direction.

A reversible reaction is one that does not go into completion in one direction.

An irreversible direction completely uses up the reactants to form the products and goes into completion.

These reactions can only proceed in one direction and not both.

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Answers

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Answer:ok

Explanation:

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