Answer: 3/8 of the class went to the evening session.
Explanation:
So it says on Sunday 3/4 of an 8th grade class went to see the movie.But we do not know the real population of the 8th grade class. But is says that out of the 3/4 of the students that went to the movie have of them went in the afternoon so we will multiply 1/2 by 3/4 to find out how many people went to the afternoon session.
3/4 * 1/2 = 3/8 So we know that 3/8 of the 3/4 of the class went in the afternoon so we will now subtract 3/8 from 3/4 to find out what fraction went in the evening.
[tex]\frac{3}{4} - \frac{3}{8}[/tex] = [tex]\frac{6}{8} - \frac{3}{8} = \frac{3}{8}[/tex]
To think about it if half of the 3/4 of the class went in the afternoon then another have will go in the evening.
c. What is the probability that the child will have red hair color?
0. LIOC PODIVIU VALOITUS.
O A. red / red, red / blond, and blond / blond
OB. red/blond and blond/red
C. red / red, red / blond, blond/red, and blond / blond
OD. red/ red and blond / blond
5. The probability that a child of these parents will have the blond / blond genotype is
Round to two decimal places as needed.)
Answer:
The probability that the child will have red hair color is 0.75.
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Explanation:
It is provided that each parent has the genotype red / blond which consists of the pair of alleles that determine hair color, and each parent contributes one of those alleles to a child.
The possible outcomes for the hair color of the child are:
S = {R/R, R B, B/R and B/B}
There are four possible outcomes.
Compute the probability that the child will have red hair color as follows:
[tex]P(\text{R})=P(\text{R/R})+P(\text{R/B})+P(\text{B/R})[/tex]
[tex]=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}\\\\=\frac{3}{4}\\\\=0.75[/tex]
Thus, the probability that the child will have red hair color is 0.75.
Compute the probability that a child of these parents will have the blond / blond genotype as follows:
[tex]P(\text{B/B})=\frac{1}{4}=0.25[/tex]
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Answer:
The probability that the child will have red hair color is 0.75.
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Explanation:
It is provided that each parent has the genotype red / blond which consists of the pair of alleles that determine hair color, and each parent contributes one of those alleles to a child.
The possible outcomes for the hair color of the child are:
S = {R/R, R B, B/R and B/B}
There are four possible outcomes.
Compute the probability that the child will have red hair color as follows:
Thus, the probability that the child will have red hair color is 0.75.
Compute the probability that a child of these parents will have the blond / blond genotype as follows:
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Find the volume, in cubic inches, of the composite solid below, which consists of a 4 -inch square solid rectangular bar that is 16 inches in length. The bar has a 2 -inch diameter cylinder hole cut out of the center of the bar from the top of the bar through the entire length of the bar. Use 3.14 to find the volume. Enter only the number.
Answer:
10 in³
Explanation:
given:
square box = 4 in², length = 16 in
bar diameter = 2 in, length = 16 in
box volume (in solid) = 4 in² * 16 in = 64 in³
bar volume = pi * d² / 4 = 3.14 * 2² / 4 * 16 in = 50.24 in³
Volume of slotted box = 64 - 50 = 10 in³
Suppose that 80% of books are classified as fiction. Two books are chosen at random. What is the probability that both books ara fiction?
Answer:
64% or 16/25
Explanation:
To calculate probability, we first find the fraction for the number of books that are fiction.
[tex]80= \frac{4}{5}[/tex]
To find out what the probability of choosing a fiction book twice, we multiply 4/5 with 4/5 to get our probability if we selected a book twice.
[tex]\frac{4}{5} *\frac{4}{5} = \frac{16}{25} \\0.64[/tex]
The probability of choosing two fiction books is a 16/25, or 64% chance.