need help with ASAP please

G=m×g

since g=10N,

G=48.4×10

G=484

I hope it's true .d

good luck

Answer: 11.1cm

Explanation:

Object distance (u) = 32cm

Image distance(v) = 17cm

Focal length(f) =?

Lens formular:

1/f = 1/u + 1/v

1/f = 1/32 + 1/17

Taking the L. C. M of 17 and 32

1/f = (17 + 32) / 544

1/f = 49/544

Taking the reciprocal

f = 544/49

f = 11.1 cm

Therefore, Focal length of the lens is 11.1cm

Answer:

Capillary Action.

Explanation:

Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.

Answer:

(x +1), (x -5) and (x +1)

Explanation:

The computation of the factorization is shown below

Data provided in the question

[tex]X^3 - 3x^2 - 9x - 5[/tex]

Based on the above information, the factors are

Now we have to open these equations in order to get the factors which are as follows

[tex]= x^3 + x^2 - 4x^2 - 4x - 5x - 5[/tex]

[tex]= x^2( x + 1) - 4x ( x + 1) - 5(x + 1)[/tex]

[tex]= (x + 1) (x^2 - 4x - 5)[/tex]

[tex]= (x + 1)(x^2 -5x + x - 5)[/tex]

So,

= (x + 1) (x - 5) (x + 1)

Therefore the (x +1), (x -5) and (x +1) are the factors of the mention polynomial give in the question

Answer:

The are both moving at the same speed

Explanation:

Given the following :

Tom = 2.4km in 20 minutes

Max = 3.6km in 30 minutes

To calculate the rider moving at a faster spedd, we need to calculate the speed of each rider.

Speed = distance / time

Tom's speed :

Distance = 2.4km = 2.4 × 1000 = 2400meters

Time = 20 minutes = 20 × 60 = 1200 seconds

Speed = (2400 / 1200) = 2 meter per second

Max's speed :

Distance = 3.6km = 3.6 × 1000 = 3600meters

Time = 30 minutes = 30 × 60 = 1800 seconds

Speed = (3600 / 1800) = 2 meter per second

Both Tom and Max are riding at the same speed(rate)

Answer:

I wouldnt say SI unit isnt important but the Metric System certainly is. And Metric System is more closer to SI unit than imperial unit. Amongst many , the most important one is the ease of use. We upgraded the number system to base 10, why hesitate to import the measurement units to base 10.

Explanation:hop this thelps you !!! :0 :)

Answer:

  v = -4 m / s

Explanation:

The average speed of a body is defined by the distance traveled in a given time interval

     v = (x₂ -x₁) / (t₂ -t₁)

in this case the end point is x₂ = -10 m and the start point is x₁ = 10 m, the negative sign is because the point is below the reference that can be considered as zero point

let's calculate

     v = (-10 - 10) / 5

     v = -20 / 5

      v = -4 m / s

Answer:

False

Explanation:

Answer:

COMPACTED MOLECULES

Explanation:

The molecules are compacted in a solid

Answer:

Explanation:

Given height of lamp from the ceiling = 2.6m

mass of the lamp = 3.8kg

acceleration due to gravity = 9.81m/s²

As the body falls to the ground, it falls under the influence of gravity.

Gravitational potential energy = mass*acc due to gravity * height

Gravitational potential energy  = 3.8*2.6*9.81

Gravitational potential energy  = 96.923 Joules

b) Kinetic energy = 1/2 mv²

m = mass of the body (in kg)

v = velocity of the body (in m/s²)

To get the velocity v, we will use the equation of motion [tex]v^{2} = u^{2}+2gh[/tex]

[tex]v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s[/tex]

Since mass = 3.8kg

[tex]K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules[/tex]

c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s

Answer:

3200kg

Explanation:

F=ma

16000=5m

m=3200kg

Hope this helps!

The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.

It is given that:

If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons

As we know,

Newton's second law:

F = ma

Here F is the force acting on an object.

m is the mass of the object

a is the acceleration of the object.

a = 5 m/s²

F = 16,000 N

m = 3200kg

16000 = 5m

3200 kg

Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

Learn more about the mass here:

https://brainly.com/question/15959704

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