Answer:
E. Iodine
Explanation:
To answer this question, we use periodic trends of the Periodic Table of Elements to help us out. Electron Affinity increase going up and to the right. Since all of our elements are in the same period, we look to see which element is the farthest right. In that case, Iodine is our answer.
merits of modern periodic table?
Answer:
Merits of modern periodic table:The wrong position of some elements like argon, potassium, cobalt and nickel due to atomic weights have been solved by arranging the elements in the order of increasing atomic number without changing their own places.The isotopes of some element have the same atomic numbers. Therefore, they find the same position in periodic table.It separates metals from non-metals.The groups of the table are divided into sub groups A and B due to their dissimilar properties which make the study of elements specific and easier.The representative and transition elements have been separated.Hope this helps...
Good luck on your assignment...
1. A 5.05 g sample of quartz (SiO2) contains 2.36 g of silicon. What are the percentages of silicon
and oxygen in quartz?
A) 53.3% Si and 46.7% 0
B) 46.7% Si and 53.3% 0
C) 29.9% Si and 70.1% 0
D) 70.1% Si and 29.9% 0
E) 46.7% Si, and insufficient information to calculate %O
Answer: B) 46.7% Si and 53.3% O
Explanation:
To calculate the mass percent of element in a given compound, we use the formula:
[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{total mass}}\times 100\%[/tex]
Mass of quartz [tex](SiO_2)[/tex] = 5.05 g
Mass of silicon = 2.36 g
Mass of oxygen = Mass of quartz [tex](SiO_2)[/tex] - mass of silicon = 5.05g - 2.36 g = 2.69 g
[tex]\text{Mass percent of silicon}=\frac{\text{Mass of silicon}}{\text{total mass of quartz}}\times 100=\frac{2.36}{5.05}\times 100=46.7\%[/tex]
[tex]\text{Mass percent of oxygen}=\frac{\text{Mass of oxygen}}{\text{total mass of quartz}}\times 100=\frac{2.69}{5.05}\times 100=53.3\%[/tex]
Thus the percentages of silicon and oxygen in quartz are B) 46.7% Si and 53.3% O
The mass percent of silicon in quartz has been 46.7%, and the mass percent of oxygen has been 53.3%. Thus, option B is correct.
Mass percent can be described as the percent composition of an element in a chemical compound. Percent of element can be given as:
Percent mass = [tex]\rm \dfrac{Mass\;of\;element}{Mass\;of\;sample}\;\times\;100[/tex]
The mass of silicon in the sample has been = 2.36 grams
The total mass of sample = 5.05 grams.
The percent mass of silicon can be given as:
Percent mass of silicon = [tex]\rm \dfrac{2.36}{5.05}\;\times\;100[/tex]
Percent mass of silicon = 46.7%
The compound has been composed of silicon and oxygen. Thus, the mass percent of quartz can be given as:
100% Quartz = %Silicon + % Oxygen
100% Quartz = 46.7% + % Oxygen
The mass % of oxygen = 100 - 46.7%
The mass % of oxygen = 53.3%
The mass percent of silicon in quartz has been 46.7%, and the mass percent of oxygen has been 53.3%. Thus, option B is correct.
For more information about the mass percent, refer to the link:
https://brainly.com/question/5394922
What intermolecular interactions could be formed between remdesivir and water molecules?
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.
2C8H18+25O2⟶16CO2+18H2O
How many moles of CO2 are emitted into the atmosphere when 27.6 g C8H18 is burned?
Answer:
[tex]n_{CO_2}=1.93 gCO_2[/tex]
Explanation:
Hello,
In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:
[tex]n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}} *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2[/tex]
Which also corresponds to the following mass:
[tex]m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2[/tex]
Best regards.
The average bond length in C-C in benzene (C6H6) is between single and double bond lengths. This is due to which of the following effect?
1. Due to its refractive index2. Due to the possession of resonance3. Due to its H atoms4. Due to the H-bonds
Answer:
2. Due to the possession of resonance
Explanation:
In the benzene ring, the electrons that results in the bonds between the carbon atoms are delocalized. That is, they do not belong to a specific carbon atom. It is this unique feature that enables them to have a bond length between single and double bond lengths.
This feature is as a result of resonance.
The correct option is 2.
Erbium metal (Er) can be prepared by reacting erbium(III) fluoride with magnesium; the other product is magnesium fluoride. Write and balance the equation for the reaction.
Answer:
2ErF3 +3Mg = 3MgF2 + 2Er
Explanation:
This is a single replacement equation where there are 2 metals. The bonds are broken and new bonds are formed again by Mg and F.
Er has a +3 charge and F has a -1 charge. You switch it around and you get ErF3. Then you add the second reactant, Mg. The product is MgF as stated, and Mg has a charge of +2 and F has -1. You switch it again and you get MgF2. Then the second product Er is there.
Now we have
ErF3+Mg=MgF2+Er
So we balance the equation because of the law of conservation of mass.
Make F equal, so we add the coefficents 2 and 3
2ErF3+Mg=3MgF2+Er
And now Mg and Er need balancing so
2ErF3+3Mg=3MgF2+2Er
Hope this helped
What is the absolute magnitude of the rate of change for [NH3] if the
rate of change for [Hz] is 9.00 M/s in the reaction 2 NH3(g) → N2(g) +
3 H2(g)?
Answer:
[tex]r_{NH_3,abs} =6.00\frac{M}{s}[/tex]
Explanation:
Hello,
In this case, we can write the law of mass action for the undergoing chemical reaction, based on the rates and the stoichiometric coefficients:
[tex]\frac{1}{-2}r_{NH_3} =\frac{1}{1} r_{N_2}=\frac{1}{3}r_{H_2}[/tex]
In such a way, knowing the rate of formation hydrogen (H₂), we can know the rate of change of ammonia, that must be negative for consumption:
[tex]r_{NH_3} =\frac{-2}{3}r_{H_2}=\frac{-2}{3}*9.00\frac{M}{s} \\\\r_{NH_3} =-6.00\frac{M}{s}[/tex]
Nevertheless, the absolute magnitude will be positive:
[tex]r_{NH_3,abs} =6.00\frac{M}{s}[/tex]
Best regards.
Chemistry question. Image attached.
Answer:
The answer to your question is given below
Explanation:
The balanced equation for the reaction is given below:
CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)
1. Writing an expression for the equilibrium constant, K.
The equilibrium constant, K for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.
Thus, we can write the equilibrium constant, K for the reaction as follow:
CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)
K = [CaCO3] [H2]⁴ / [CaO] [CH4] [H2O]²
2. Based on the value of K, more products will be in the equilibrium mixture since the value of K is a positive large number.
At 1 atm, an unknown sample melts at 49.9 °C and boils at 209.5 °C. If the temperature is 0°C, what is the state of matter for the sample?
Answer:
The correct answer is solid.
Explanation:
Based on the given information, it is evident that at 1 atm pressure and 49.9 degrees C the melting of the sample takes place, that is, the unknown sample transforms into the liquid at the mentioned temperature. It can also be said that below 49.9 degrees C, the sample stays at solid-state. From all this, we can also state that at temperature 49.9 degrees C, both the liquid and the solid-state of the sample stays at equilibrium.
As one goes higher, that is, above 49.9 degrees C and up to 209.5 degrees C, the sample remains at liquid state. However, the boiling point of the sample is 209.5 degrees C, which shows that the sample becomes gas above 209.5 degrees C. Thus, the sample remains at solid-state below 49.9 degrees C, at liquid state between 49.9 degrees C to 209.5 degrees C, and a gaseous state above 209.5 degrees C. Hence, if the temperature is 0 degrees C, then solid will be the state of matter for the sample.
A 10.0 mL sample of calcium hydroxide solution required 26.85 mL of 0.225 M hydrochloric acid for neutralization. The balanced equation is:
Answer:
[tex]C_{base}=0.302M[/tex]
Explanation:
Hello,
In this case, we can evidence that when calcium hydroxide solution reacts with hydrochloric acid solution, the balanced neutralization reaction turns out:
[tex]2HCl(aq)+Ca(OH)_2\rightarrow CaCl_2(aq)+2H_2O(l)[/tex]
Moreover, the concentration of neutralized calcium hydroxide can be computed by using the 2:1 mole ratio between the base and the acid:
[tex]C_{acid}V_{acid}=2*C_{base}V_{base}\\\\C_{base}=\frac{C_{acid}V_{acid}}{2*V_{base}} =\frac{0.225M*26.85mL}{2*10.0mL}\\ \\C_{base}=0.302M[/tex]
Regards.
a solution of unknown molecular substance is prepared by dissolving 0.50g of the unknown in 8.0g of benzene. the solution freezes at 3.9. determine the molar mass of the unknown
Answer:
THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.
Explanation:
Mass of the unknown substance = 0.50 g
Freezing point of the solution = 3.9 °C
Freezing point of pure benzene = 5.5 °C
Freezing point dissociation constant Kf = 5.12°C/m
First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.
Change in temperature = 5.5 -3.9 = 1.6 °C
Next is to calculate the number of moles or molarity of the compound that dissolved.
Using the formula:
Δt = i Kf m
Assume i = 1
So,
1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene
x = 1.6 * 0.008 / 5.12
x = 0.0128 / 5.12
x = 0.0025 moles.
Next is to calculate the molar mass using the formula, molarity = mass / molar mass
Molar mass = mass / molarity
Molar mass = 0.50 g /0.0025
Molar mass = 200 g/mol
Hence, the molar mass of the unknown compound is 200 g/mol
What is the ion symbol for an atom with twenty (20) protons and eighteen (18) electrons?
Answer:
[tex]Ca^{2+}[/tex]
Explanation:
From the periodic table, we can see that the atom with 20 protons is Calcium (Ca).
Each proton has a +1 charge, while each electron has a -1 charge.
Since in this ion, there's 20 protons but only 18 electrons, meaning it has a net charge of +2.
Hence, the ion symbol for the required proton is
[tex]Ca^{2+}[/tex].
(make sure the charge symbol is behind the value.)
Answer:
Ca²+
I agree with the one above
Calculate the molarity of a 14.17 mL solution which contains 453.76 mg of sodium sulfate (used in dyeing and printing textiles,
Answer:
0.226 mol/L
Explanation:
The following data were obtained from the question:
Volume = 14.17 mL
Mass of sodium sulphate, Na2SO4 = 453.76 mg
Molarity =..?
Next, we shall determine the number of mole in 453.76 mg of Na2SO4. This is illustrated below:
Molar mass of Na2SO4 = (2x23) + 32 +(16x4) = 142g/mol
Mass of Na2SO4 = 453.76 mg = 453.76×10¯³ g
Mole of Na2SO4 =..?
Mole = mass /Molar mass
Mole of Na2SO4 = 453.76×10¯³ / 142
Mole of Na2SO4 = 3.20×10¯³ mole
Finally, we shall determine the molarity of Na2SO4 solution as follow:
Mole of Na2SO4 = 3.20×10¯³ mole
Volume = 14.17 mL = 14.17/1000 = 1.417×10¯² L
Molarity =?
Molarity = mole /Volume
Molarity = 3.20×10¯³ / 1.417×10¯²
Molarity = 0.226 mol/L
Therefore, the molarity of the sodium sulphate, Na2SO4 solution is 0.226 mol/L
A buffer solution is 0.100 M in both HC7H5O2 and KC7H5O2 has a pH of 4.19. Which of the fo pH values would you expect from the addition of a small amount of a dilute solution of a strong base?
A. 5.79
b. 4.49
c. 3.69
d. 3.89
Identify each of the following half-reactions as either an oxidation half-reaction or a reduction half-reaction.
H2(g) → 2H+(aq) + 2e- oxidation
Cu2+(aq) → + 2e-Cu(s) reduction
Write a balanced equation for the overall redox reaction. Use smallest possible integer coefficients.
Answer:
H₂(g) + Cu²⁺(aq) → 2H⁺(aq) + Cu(s)
Explanation:
In a redox reaction, one half-reaction is the oxidation (where the atom loss electrons) whereas the other reaction is the reduction (Where the atom is gaining electrons.
In the reactions:
H₂(g) → 2H⁺(aq) + 2e⁻ oxidation
Here, the reaction is written as the oxidation because the hydrogen H₂ is in oxidation state 0 and H⁺ in +1. That means each atom is loosing one electron.
Cu²⁺(aq) + 2e⁻ → Cu(s) reduction
And here, the Cu²⁺ is in +2 oxidation state and after the reaction is in Cu(s) 0 state. Thus, each atom is gaining 2 electrons.
The sum of both reactions is:
H₂(g) + Cu²⁺(aq) + 2e⁻ → 2H⁺(aq) + 2e⁻ + Cu(s)
Subtracting the electrons in both sides of the reaction:
H₂(g) + Cu²⁺(aq) → 2H⁺(aq) + Cu(s)The cylinder shown contains 0.79 moles of nitrogen, 0.19 moles of oxygen and 0.02 moles carbon dioxide, a total of 1.00 mole of molecules in the approximate proportion in which they are present in air. Of the three gases, only carbon dioxide is appreciably soluble in the water in the well at the bottom. Assume an equilibrium between dissolved and undissolved carbon dioxide at the beginning and sufficient time lapse to reestablish that equilibrium after the change described. If 0.02 mole of carbon dioxide is forced into the cylinder, the solubility of carbon dioxide ... a) increases by a factor of about 50. b) increases by a factor of about 2. c) increases by 2%. d) remains unchanged. e) decreases.
Answer:
b) increases by a factor of about 2.
Explanation:
Ignore the nitrogen and oxygen. Each gas acts independently of the others.
You have 0.02 mol of CO₂ gas at some pressure in equilibrium with the CO₂ in solution.
According to Graham's Law,
S = kp
That is, the solubility of a gas in a liquid is directly proportional to its partial pressure above the liquid.
If you add another 0.02 mol of CO₂, you have doubled the number of moles.
According to Avogadro's Law, doubling the number of moles doubles the pressure.
According to Graham's Law, doubling the pressure doubles the solubility.
The solubility of CO₂ increases by a factor of two.
Identify the element of Period 2 which has the following successive ionization energies, in kJ/mol. IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IE5, 10992 IE6, 13329 IE7, 71345 IE8, 84087
1. How much heat is gained by nickel when 29.2 g of nickel is warmed from 18.3°C to 69.6°C? The specific heat of nickel is 0.443 J/(g · °C
Answer:
THE HEAT REQUIRED TO RAISE 29.2 G OF NICKEL BY 51.3 °C IS 663.60 J
Explanation:
Mass of nickel = 29.2 g
Temperature change = 69.6 °C - 18.3°C = 51.3 °C
Specific heat of nickel = 0.443 J/g °C
Heat = unknown
The heat of reaction of nickel is the amount of heat needed to raide a unit mass of nickel by 1 °C
Mathematically.
heat = mass * specific heat * change in temperature
Heat = m C ΔT
Heat = 29.2 * 0.443 * 51.3
Heat = 663.596 J
The heat needed to raise 29.2 g of nickel by 51.3 °C is approximately 663.60 J
Dry ice is solid carbon dioxide. A 0.050-g sample of dry ice is placed in an evacuated 4.6-L vessel at 30 °C. Calculate the pressure inside the vessel after all the dry ice has been converted to CO2 gas.
The answer is 6.1*10^-3 atm.
The pictures and explanations are there.
Ideal gas law is valid only for ideal gas not for vanderwaal gas. The equation used to solve this is PV=nRT. Therefore the pressure of carbon dioxide gas is 0.005 atm.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature.
Mathematically the relation between Pressure, volume and temperature can be given as
PV=nRT
where,
P = pressure of carbon dioxide gas=?
V= volume of carbon dioxide gas=4.6L
n =number of moles of carbon dioxide gas = given mass ÷Molar mass
=0.050g÷44g/mol
=0.001mole
T =temperature of carbon dioxide gas=303K
R = Gas constant = 0.0821 L.atm/K.mol
substituting the given values, we get
P×4.6L=0.001×0.0821×303
=0.005 atm
Therefore the pressure of carbon dioxide gas is 0.005 atm.
To learn more about ideal gas equation, here:
https://brainly.com/question/14826347
#SPJ5
Write the condensed electron configuration for the manganese atom. When writing your answers, do not add spaces and do not try to italicize the orbitals.
Answer:
[tex][Ar]4s^23d^5[/tex]
Explanation:
Hello,
In this case, we write the electron configuration of the manganese atom by noticing its atomic number is 25, so we fill the orbitals and levels up-to 25 electrons as shown below:
[tex]1s^22s^22p^63s^23p^64s^23d^5[/tex]
Moreover, for the condensed electron configuration, we consider the previous noble gas, that is argon, electron configuration which is:
[tex]1s^22s^22p^63s^23p^6[/tex]
By cause of its atomic number that is 18. In such a way, we combine argon's electron configuration with manganese's to obtain its condensed version:
[tex][Ar]4s^23d^5[/tex]
Regards.
If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limiting reagent? 2Al + 3CuCl -> 2AlCl3 + 3Cu
Answer:
Copper (II) chloride.
Explanation:
Hello,
In this case, considering the described reaction which is also given as:
[tex]2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu[/tex]
For us to identify the limiting reactant we first compute the available moles of aluminium:
[tex]n_{Al}=512gAl*\frac{1molAl}{27gAl}=19.0molAl[/tex]
Next, we compute the consumed moles of aluminium by the 1147 grams of copper (II) chloride by using their 2:3 molar ratio:
[tex]n_{Al}^{consumed}=1147gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2}*\frac{2molAl}{3molCuCl_2} =5.69molAl[/tex]
Thereby, we can infer aluminium is in excess since less moles are consumed than available whereas the copper (II) chloride is the limiting reactant.
Best regards.
When Carl Woese developed the modern system of classification, he broke the previous kingdom of into the two kingdoms of Bacteria and Archaea
Answer:
the answer is monerans
Explanation:
When Carl Woese developed the modern system of classification, he broke the previous kingdom of Monera into the two kingdoms of Bacteria and Archaea.
What kingdom of Monera ?Some biologists believed it made sense to classify prokaryotes as belonging to their own kingdom, the Monera. That served as the foundation for Richard Whittaker and Lynn Margulis's five-kingdom proposal, which enhanced the Haeckel plan by include a kingdom of fungus.
Protists, protozoa, monera, fungi, and viruses have long been proposed as belonging to different kingdoms, but traditional evolutionists during the majority of the 20th century had given none of them any thought.
Later, the Monera kingdom was split into Eubacteria and Archaebacteria by Carl Woese . Moreover, he divided the five kingdoms into three domains: Eukaryotes, Archaea, and Bacteria.
Find more on Kingdom Monera:
https://brainly.com/question/30621598
#SPJ3
Your question is incomplete. But your complete question is as follows:
When Carl Woese developed the modern system of classification, he broke the previous kingdom of into the two kingdoms of _____ into Bacteria and Archaea.
What is a ‘control’ in an experiment?
A. A version of the experiment that is unchanged to make sure the experimental data is not due to chance.
B. A person who oversees the experiment to make sure it is following proper procedures.
C. The variable controlled by the scientist to affect the dependent variable.
D. The name for the set of independent and dependent variables that will be controlled by the scientist.
need help asap got 1 minute
D. The name for the set of independent and dependent variables that will be controlled by the scientist.
The statement, that describes the ‘control’ in an experiment is "the name for the set of independent and dependent variables that will be controlled by the scientist."
What is a control in experiment?A control is an element in an experiment that remains intact or unaffected by other variables. An experiment or observation aiming to minimise the influence of variables other than the independent variable is referred to as a scientific control. It serves as a standard or point of reference against which other test findings are measured.
In a scientific experiment, an independent variable is the variable that is modified or manipulated in order to assess the effects on the dependent variable. In a scientific experiment, the dependent variable is the variable that is being tested and measured. The designation given to the set of independent and dependent variables that the scientist will regulate.
Hence the correct option is D.
Learn more about control in an experiment here
https://brainly.in/question/19374703
#SJP3
Which of the compounds listed below would you expect to have the highest boiling point? (They all have approximately the same molecular weight)
a. CH_3CH_2OCH_2CH_3
b. Ch-3CH_2CH_2Ch_2CH_3
c. HOCH_2CH_2CH_2OH
d. CH_3CH_2CH_2CH_2OH
e. CH_3CH_2CH_2OCH_3.
Answer:
HOCH₂CH₂CH₂OH Propane-1,3-diol
Explanation:
The boiling point of compound depends up on Hydrogen bonding and vander wall forces. The C option that is alcohol will have higest boiling point assuming that the mass is approximately same (between 60-80) and the boiling point is hight because this is due to extensive intra molecular hydrogen bonding in alcohol .Hence due to hydrogen bonding the molecules are packed close and that increases the boiling point of the molecule.The Answer is option C.
HOCH₂CH₂CH₂OH > CH₃CH₂CH₂CH₂OH > CH₃CH₂CH₂CH₂CH₃ > CH₃CH₂CH₂CH₂CH₃ > CH₃CH₂CH₂OCH₃
Consider the following reaction: NH4I(s) NH3(g) + HI(g) If a flask maintained at 674 K contains 0.138 moles of NH4I(s) in equilibrium with 4.34×10-2 M NH3(g) and 9.39×10-2 M HI(g), what is the value of the equilbrium constant at 674 K?
Answer:
4.08 × 10⁻³
Explanation:
Step 1: Write the balanced reaction at equilibrium
NH₄I(s) ⇄ NH₃(g) + HI(g)
Step 2: Calculate the equilibrium constant
The equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
[tex]K = [NH_3] \times [HI] = 4.34 \times 10^{-2} \times 9.39 \times 10^{-2} = 4.08 \times 10^{-3}[/tex]
Carbon and oxygen combine to form the molecular compound CO2, while silicon and oxygen combine to form a covalent network solid with the formula unit SiO2. Explain the difference in bonding between the two group 4A elements and oxygen. g
Answer:
See explanation below.
Explanation:
Both carbon and silicon are members of group 4A(now group 14) i n the periodic table. Carbon is the first member of the group. CO2 is a gas while SiO2 is a solid. In SiO2, there are single bonds between silicon and oxygen and the geometry around the central atom is tetrahedral while in CO2, there are double carbon-oxygen bonds and the geometry around the central atom is linear. CO2 molecules are discrete and contain only weak vanderwaals forces.
Again, silicon bonds to oxygen via its 3p orbital while carbon bonds to oxygen via a 2p orbital. As a result of this, there will be less overlap between the pi orbitals of silicon and that of oxygen. This is why tetrahedral bonds are formed with oxygen leading to a covalent network solid rather than the formation of a silicon-oxygen pi bond. A covalent network solid is known to be made up of a network of atoms of the same or different elements connected to each other continuously throughout the structure by covalent bonds.
In SiO2, each silicon atom is surrounded by four oxygen atoms. Each corner is shared with another tetrahedron. SiO2 forms an infinite three dimensional structure and melts at a very high temperature.
Describe the difference between ionic and molecular compounds. Give an example of each. Check all that apply. Check all that apply. A molecular compound is formed between a metal and a nonmetal (or polyatomic ions), and is held together through the attraction of opposite charges. An example is KCl. An ionic compound is usually formed between two or more nonmetals, and is held together through the sharing of electrons between atoms. An example is SO2. An ionic compound is formed between a metal and a nonmetal (or polyatomic ions), and is held together through the attraction of opposite charges. An example is KCl. A molecular compound is usually formed between two or more nonmetals, and is held together through the sharing of electrons between atoms. An example is SO2. An ionic compound is formed between two or more metals, and is held together through the attraction of opposite charges. An example is Na2Al.
Answer:
An ionic compound is formed between a metal and a nonmetal (or polyatomic ions), and is held together through the attraction of opposite charges. An example is KCl. A molecular compound is usually formed between two or more nonmetals, and is held together through the sharing of electrons between atoms. An example is SO2.
Explanation:
When we talk about ionic bonds, the first thing that must come to mind is the electrostatic attraction between oppositely charged ions. Hence, we know that metals form cations and nonmetals form anions, thus metals could transfer electrons to nonmetals to facilitate the formation of ionic bonds. Ionic bonds could also be formed by the combination of metals with polyatomic ions such as CaCO3. Always keep it in mind that ionic bonds are characterized by electrostatic attraction between any pair of oppositely charged ions.
Molecular compounds are formed by sharing of electrons between nonmetals. We find covalent or polar covalent bonds in molecular compounds such as SO2.
If the vinegar were measured volumetrically (e.g., a pipet), what additional piece of data would be needed to complete the calculations for the experiment?
Answer:
the density if vinegar will also be needed
Explanation:
Because this is an experiment of volumetric analysis
Hydrogen bonding between polyamide chains plays an important role in determining the properties of a nylon such as nylon 6,6. Draw the structural formulas for two adjacent chains of nylon 6,6, and show where hydrogen-bonding interactions could occur between them.
Answer:
See figure 1
Explanation:
In the structure of nylon 6,6 we have amide groups. In this functional group, We have a nitrogen bond to hydrogen, so in this bond, we will have a dipole, due to the electronegativity difference. Nitrogen has more electronegativity than hydrogen, therefore a positive dipole would be generated in the hydrogen atom. Additionally, in the carbonyl group (C=O) due to the oxygen, we will have also a dipole, in this case, a negative dipole because the oxygen atom has more electronegativity (compare with carbon).
When we put two strings of nylon 6,6 the positive dipole will interact with the negative dipole and vice-versa and we will obtain the "hydrogen bonds".
See figure 1
I hope it helps!
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of CO2 and 0.01961 mol of H2O. The empirical formula of the compound was found to be C3H6O2. Show how this was calculated.
What does the empirical formula tell you about the compound?
The molar mass of the actual compound was found to be 222.27g/mol. Find the molecular formula of this compound. What does the molecular formula tell you about the compound?
Can you see what type of functional group this compound could have?
Answer:
See explanation.
Explanation:
Hello,
In this case, we can show how the empirical formula is found by following the shown below procedure:
1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:
[tex]n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC[/tex]
2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:
[tex]n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH[/tex]
3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:
[tex]m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO[/tex]
4. Compute the moles of oxygen by using its molar mass:
[tex]n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO[/tex]
5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:
[tex]C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1[/tex]
6. Search for the closest whole number (in this case multiply by 2):
[tex]C_3H_6O_2[/tex]
Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:
[tex]M=12*3+1*6+16*2=74g/mol[/tex]
Which is about three times in the molecular formula, for that reason, the actual formula is:
[tex]C_9H_{18}O_6[/tex]
It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.
Best regards.