Answer: 2 minutes
Step-by-step explanation:
Given the following :
Plane A's descent :
y = -2,500x + 14,000
Plane B's Ascent :
y = 4,000x + 1,000
where y = altitude x = minute
Time to be at the same altitude :
Being at the same altitude means ;
Plane A's descent = Plane B's Ascent
-2,500x + 14,000 = 4,000x + 1,000
-2500x - 4000x = 1000 - 14000
-6500x = - 13000
x = 13000 / 6500
x = 2
x = 2minutes.
Do you know the adjustments for the graph to show the intersecting lines.
Find the area of the shape shown below.
Answer:
28
Step-by-step explanation:
We divide the shape covenientely, like this, and area 1 is 4*4=16
area 2=4*4/2=8
area 3= 2*4/2=4
Area total = Area 1 + Area 2 + Area 3=16+8+4=28
plzzz hellpppppp...........
Answer:
Bearing of R from S = S 45° E or 135°
The bearing of R from Q
= S 66.42° w or 246.42°
Step-by-step explanation:
Distance between R and S
RS²= RP²+PS²
RS²= 15²+15²
RS²=225+225
RS= √450
RS= 21.21
Angle at S
21.21= 15/sins
Sin s= 15/21.21
S= sin^-1 15/21.21.
S= 45°
90+45= 135°
Bearing of R from S = S 45° E or 135°
Distance between R and Q
RQ²= PQ²+PR²
RQ²= 35²+15²
RQ²=1225+225
RQ= √1450
RQ= 38.08
RQ= 15/sinQ
SinQ= 15/38.08
SinQ= 0.40
Q=23.58°
90-23.58 = 66.42°
66.42+180= 246.42°
The bearing of R from Q
= S 66.42° w or 246.42°
Select all that apply. If x^2+b/ax+c/a=0 ; then: The sum of its roots = -b/a? The difference of its roots =-b/a? The product of its roots = c/a?The division of its roots = c/a? I can select multiple.
Answer:
The first and the thirdStep-by-step explanation:
[tex]x^2+\frac bax+\frac ca=0\\\\ ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\qquad\quad x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\\\x_1+x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}+\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-2b}{2a}=\dfrac{-b}a\\\\\\x_1\cdot x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\cdot\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\\\\{}\ \ =\dfrac{b^2-b\sqrt{b^2-4ac}+b\sqrt{b^2-4ac}-(\sqrt{b^2-4ac})^2}{2a}=\dfrac{b^2-(b^2-4ac)}{4a^2}=\\\\{}\ \ =\dfrac{b^2-b^2+4ac}{4a^2}=\dfrac{4ac}{4a^2}=\dfrac{c}{a}[/tex]
[tex]x_1-x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}-\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-2\sqrt{b^2-4ac}}{2a}=\frac{-\sqrt{b^2-4ac}}{a}\\\\\\x_1\div x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}\div\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-b-\sqrt{b^2-4ac}}{2a}\,\cdot\,\frac{2a}{-b+\sqrt{b^2-4ac}}=\\\\=\frac{-b-\sqrt{b^2-4ac}}{-b+\sqrt{b^2-4ac}}=\frac{b+\sqrt{b^2-4ac}}{b-\sqrt{b^2-4ac}}=\frac{b^2+2\sqrt{b^2-4ac}+b^2-4ac}{b^2-b^2+4ac}=\frac{2b^2+2\sqrt{b^2-4ac}-4ac}{4ac}=[/tex]
[tex]=\frac{b^2+\sqrt{b^2-4ac}-2ac}{2ac}[/tex]
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning.
Answer:
A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.
Step-by-step explanation:
Answer:
WHEN U GRAPH WITH A CALCULATOR IT IS MUCH MORE ACCURATE
ESPECIALLY IF THERE R FRACTIONS AND DECIMALS AND THE GRAPHING CALCULATOR GOES ON FOREVER WHERE AS THE GRAPHING PAPER ENDS
Step-by-step explanation:
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
A small cargo plane currently has 140 pounds of cargo aboard. In addition, n boxes weighing 45 pounds each will be brought aboard. Suppose that the total weight of the cargo on board must be less than p pounds. Using the values and variables given, write an inequality describing this.
Answer:
The inequality that represents this situation is: [tex]140 + 45*n < p[/tex]
Step-by-step explanation:
Since the plane already had 140 pounds on board and "n" boxes will be loaded on it, then the weigh of each box multiplied by the number of box should be the extra cargo on the plane. This extra cargo added to the previous load must be less than the limit of cargo the plane can take as shown below:
[tex]140 + 45*n < p[/tex]
Hi how to solve this simultaneous equation
Answer:
[tex]\large \boxed{\sf \ \ x=\pm8 \ \ or \ \ x=\pm2 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
First of all, we can assume that x and y are different from 0, as we cannot divide by 0.
And from the first equation we can write y as a function of x as below.
[tex]y=\dfrac{16}{x}[/tex]
And then, we replace it in the second equation to get.
[tex]\dfrac{x}{\frac{16}{x}}+\dfrac{\frac{16}{x}}{x}=\dfrac{17}{4}\\\\<=> \dfrac{x^2}{16}+\dfrac{16}{x^2}=\dfrac{17}{4}\\\\\text{*** We multiply by }16x^2 \text{ both sides ***}\\\\x^4+16*16=\dfrac{17*16}{4}x^2\\\\x^4-68x^2+3600=0\\\\\text{*** The product of the zeroes is 3600 = 64*4 and the sum is 64+4=68 ***}\\\\\text{*** So we can factorise *** }\\\\x^4-64x^2-4x^2+3600=x^2(x^2-64)-4(x^2-64)=(x^2-64)(x^2-4)=0\\\\x^2=64=8^2 \ \ or \ \ x^2=4\\\\x=\pm8 \ \ or \ \ x=\pm2\\[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Please answer this in two minutes
Answer:
[tex] s = 14.1 [/tex]
Step-by-step explanation:
Given:
<S = 31°
SQ = r = 9
SR = q = 21
s = ?
To find s, use the Law of Cosines:
s² = r² + q² - 2rs*cos(S)
[tex] s^2 = 9^2 + 21^2 - 2*9*21*cos(31) [/tex]
[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]
[tex] s^2 = 522 - 324.02 [/tex]
[tex] s^2 = 197.98 [/tex]
[tex] s = 14.1 [/tex] (nearest tenth)
Answer the problem below
Answer:
D. 4z^3
Step-by-step explanation:
First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3
Hope this helps, if you want me to explain more, feel free to ask questions.
Have a good day! :)
Answer:
4 z^3
Step-by-step explanation:
( 64 z^9) ^ 1/3
Rewriting 64 as 4^3
( 4^3 z^9) ^ 1/3
We know that ( ab) ^c = a^c * b^c
4^3 ^ 1/3 z^9 ^ 1/3
We know that a^ b^c = a^ ( b*c)
4^(3 * 1/3) z^ (9 * 1/3)
4 ^ ( 1) z^ ( 3)
4 z^3
Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem?
Answer:
The additional information required to prove ΔDEF ~ ΔPQR is the value of the ratio DE/PQ which has to be equal to three-halves for ΔDEF to be similar to ΔPQR
Step-by-step explanation:
Given DF/PR = FE/RQ = 3/2
The Side Side Side, SSS, similarity theorem states that where there are two triangles that have corresponding sides that are proportional to each other, the two triangles are said to be similar
Given ΔDEF and ΔPQR, have sides DF/PR = FE/RQ, to prove that ΔDEF and ΔPQR, then the additional information required is the ratio of the third sides of the triangles which is DE/PQ.
If DE/PQ = Three-halves, the two triangles ΔDEF and ΔPQR are similar, if not, that is DE/PQ ≠ Three-halves, then the two triangles ΔDEF and ΔPQR are not similar.
Answer:
D: DE/PQ = 3/2
Step-by-step explanation:
Did it on edge 2020
Help please! Thanks
Answer:
E. 0
Step-by-step explanation:
There isn't any guarantee that there are any people that have their birthdays in the same month based on what you're given, so your answer would be 0.
An exponential growth function has a base that is____one?
Please help
Answer:
greater than
Step-by-step explanation:
An exponential growth function has a base that is__greater than__one.
If the base is less than one, it will be a decay function.
Note: the above assumes an exponent greater than one as well.
Paul has four paper strips of the same length. He glues two of them together with a 4 cm overlap, and the new strip is 36 cm long. He wants to make a 30 cm long strip with the other two strips. How long should the overlap be?
Answer:
10 cm overlap required to make a 30 cm long strip.
Step-by-step explanation:
Given:
Four paper strips of the same length.
Two of them glued together with a 4 cm overlap to make a new strip which is 36 cm long.
To find:
Overlap required to make a strip which is 30 cm long = ?
Solution:
First of all, let us understand the concept of overlap.
Please refer to the attached image.
Let length of each strip be [tex]x[/tex] cm.
Given that there is 4 cm overlap resulting in new strip of length 36 cm.
The overlapping length is counted only once as clear from the figure attached.
So, Let us try to find the equation:
[tex]x +(x-4) = 36\\\Rightarrow 2x=40\\\Rightarrow x = 20\ cm[/tex]
i.e. each strip length is 20 cm.
Now, let us assume, an overlap of 'y' cm is to be made to make a new strip of 30 cm.
The equation will be:
[tex](20-y)+20 =30\\\Rightarrow y = 40-30\\\Rightarrow y = 10\ cm[/tex]
The length of ZX is 2 units. What is the perimeter of triangle XYZ? 5 + + 2 units 5 + 3 units 5 + + 2 units 10 + 2 units
Answer:
B) 5 + 3√5 units
Step-by-step explanation:
The length of ZX is 2√5 units. What is the perimeter of triangle XYZ?
A) 5 +√3 + 2 √5 units
B) 5 + 3√5 units
C) 5 + √6 + 2√5 units
D) 10 + 2√5 units
From the diagram attached, point X is at (-1, 4), Y(3, 1), Z(1, 0).
The distance between two point
[tex]O(x_1,y_1)\ and\ A(x_2,y_2)\ is\ given\ as:\\\\OA=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
The lengths of the sides of the triangle are:
[tex]|XY| = \sqrt{(3-(-1))^2+(1-4)^2}=\sqrt{25} =5\ unit\\ \\|XZ|= \sqrt{(1-(-1))^2+(0-4)^2}=\sqrt{20} =2\sqrt{5} \ unit\\\\|YZ|= \sqrt{(1-3)^2+(0-1)^2}=\sqrt{5} \ unit[/tex]
The perimeter of the triangle is the sum of all the sides, i.e.
Perimeter = |XY| + |YZ| + |XZ| = 5 + 2√5 + √5 = 5 + 3√5
Answer:
B
Step-by-step explanation:
y=-2x-21 determine the intercepts of the line (,) (,) ASAPPPP
Answer:
x intercept (10.5,0)
y intercept (0, -21)
Step-by-step explanation:
y=-2x-21
there are two intercept for a line
x intercept, the point of given equation of line which lies on x axis.
For x intercept corodinate of y is o
Thus, value x intercept is form (x,0)
putting these value in y=-2x-21, we find x intercept
0=-2x-21
2x = 21
x = 21/2 = 10.5
Thus, x intercept (10.5,0)
Y intercept, the point of given equation of line which lies on y axis.
For Y intercept coordinate of x is o
Thus, value y intercept is form (0,y)
putting these value in y=-2x-21, we find y intercept
y = -2*0 -21
y = -21
Thus, y intercept (0, -21)
Drag the tiles to the correct boxes to complete the pairs.
This table gives Information about vehicles sold at a dealership in a month.
Gasoline Diesel
18
5
Hatchback
Sedan
15
12
SUV
3
7
Analyze this data, and match each percentage to the description It represents. Round your answers to the nearest whole number.
30%
44%
21%
8%
42%
78%
the percentage of hatchbacks that run on gasoline
the percentage of diesel vehicles that are hatchbacks
tum. All rights reserved.
Answer:
The percentage of hatchbacks that run on gasoline: 78%
The percentage of diesel vehicles that are hatchbacks: 21 %
Step-by-step explanation:
The given table represents the following:
Hatchbacks that run on Gasoline = 18
Hatchbacks that run on Diesel = 5
Total number of hatchbacks = 23
Sedan that run on Gasoline = 15
Sedans that run on Diesel = 12
Total number of sedans = 27
SUVs that run on Gasoline = 3
SUVs that run on Diesel = 7
Total number of SUVs = 23
Total number of gasoline vehicles = 36
Total number of Diesel vehicles = 24
To find:
the percentage of hatchbacks that run on gasoline
the percentage of diesel vehicles that are hatchbacks
Solution:
[tex]\text{Percentage of hatchbacks that run on gasoline = } \dfrac{\text{Number of hatchbacks on gasoline}}{\text{Total number of hatchbacks}}\times 100\\\Rightarrow \text{Percentage of hatchbacks that run on gasoline = } \dfrac{18}{23}\times 100 \approx 78\%[/tex]
[tex]\text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{\text{Number of hatchbacks that run on diesel}}{\text{Total number of diesel vehicles}}\times 100\\\Rightarrow \text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{5}{24}\times 100 \approx 21\%[/tex]
So, the answer is:
The percentage of hatchbacks that run on gasoline: 78%
The percentage of diesel vehicles that are hatchbacks: 21%
Answer:
I used a calculator and this is what can up with
Step-by-step explanation:
2.
The roots of the equation x2-3x - m(m + 3) = 0,
where m is a constant, are
(a) m, m + 3
(b) -m, m + 3
(c) m,- (m+3) (d) -m, -(m + 3)
(AI 2011)
Answer:
(b) -m, m + 3
Step-by-step explanation:
x² − 3x − m(m + 3) = 0
x² − 3x = m(m + 3)
x² − 3x + 9/4 = m(m + 3) + 9/4
(x − 3/2)² = m(m + 3) + 9/4
(x − 3/2)² = m² + 3m + 9/4
(x − 3/2)² = (m + 3/2)²
x − 3/2 = ±(m + 3/2)
x − 3/2 = m + 3/2, -m − 3/2
x = m + 3, -m
two bags and four hats cost $100 in all. three bags and seven hats cost $164 in all. what is the cost of 1 hat?
Answer:
Bags = 22
Hat = 14
22 x 2 = 44
14 x 4 = 56
So the first part is true
3 x 22 = 66
7 x 14 = 98
So the second part is true
14 is the answer
It's trial and error
Step-by-step explanation:
Eparture time of a car is 0540 hours and it traveled for 45 minutes before it reached its destination. At what time did the car arrived at its destination : *
Answer:
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6.
Step-by-step explanation:
Departure time = 0540 Hours means 5: 40 am or 40 minutes past 5 in the morning.
Now add 45 mins
Hours : Minutes
5: 40
+ 45
5 : 85
But 1 hour contains 60 minutes so 85 - 60 gives 25 minutes . those 60 minutes = 1 hour are carried over the hours and added .
Hours : Minutes
1
5: 40
+ 45
6 : 25
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6 in the morning.
2 There are x fish in a pond.
Omar puts 5 more fish in the pond.
How many fish are in the pond now?
Answer:
x+5
Step-by-step explanation:
We are adding fish
There were x and then we added 5
There are now
x+5
Answer:
x+5
Step-by-step explanation:
since there are x fish, adding five more would make it x+5
In one U.S. city, the taxi cost is $3 plus $0.60 per mile. If you are traveling from the airport, there is an additional charge of $5.50 for tolls. How far can you travel from the airport by taxi for $26.50?
the airport by taxi for $26.50?
Answer:
30 milesStep-by-step explanation:
How far can you travel from the airport by taxi for $26.50 ?($26.5 - $3 - $5.50) : $0.6/m =
= $18 : 0.6$/m
= 30 miles
How does the period of f(x)= cos(2x) relate to the period of the parent function cos x?
Answer:
Both have the same period which is 2π
Step-by-step explanation:
The local ice cream shop offers 3 different types of cones and 15 different flavors of ice cream. How many possible ice cream cones (one scoop) can a customer order? a 40 b 18 c 45 d 35
Answer:
45
Step-by-step explanation:
There are 3 cones and 15 flavors
Multiply the number of cones by the number of flavors
3*15
45
There are 45 possible combinations
32 is an example of A. an algebraic equation B. a numerical expression C. a numerical equation D. an algebraic expression Reset
ayuda plis nosé donde estoy q Brainli es este
ayuda
Answer:
hmm I'm not sure but i think it's B. a numerical expression
Sowwy if this didn't help :c
Irving cannot remember the correct order of the five digits in his ID number. He does remember that the ID number contains the digits 1, 4, 3, 7, 6. What is the probability that the first three digits of Irving's ID number will all be odd numbers?
Answer: 1/10
Step-by-step explanation:
given:
numbers contained in the i.d
1,4,3,7,6
1. permutations of 5 possible outcome
T = 5
= 5 * 4 * 3 * 2 *1
= 120 times.
2. permutations of 3 odd numbers
( 1,3 and 7 )
T = 3
= 3 * 2 * 1 * 2 * 1
= 12
probability of of first three digits being odd numbers
P = 12 / 120
= 1 / 10
Answer: The probability is 0.10
Step-by-step explanation:
The ID number has five digits, and the digits can be 1, 4, 3, 7 and 6, and I will assume that each digit appears only once.
Then if we want to calculate the probability that the first 3 digits will be odd is:
Suppose that we have 5 slots, we want that in the first two slots to have odd numbers.
In our set, we have only 3 odd numbers {1, 3 and 7}
Then if we want an odd number in the first digit, we have 3 options
If we want an odd number in the second digit, we have two options (because we already selected one in the first selection)
If we want an odd number in the first digit, we have only one option.
For the fourth digit we have one of the two remaining even options, so we have 2 options.
For the fifth digit, we have only one digit.
The number of combinations is equal to the product of the number of options in each selection:
c = 3*2*1*2*1 = 12
Now, the total number of combinations is:
For the first digit we have 5 options
for the second digit we have 4 options.
for the third digit we have 3 options.
for the fourth digit we have 2 options.
for the fifth digit we have 1 options.
The number of combinations is:
C = 5*4*3*2*1 = 120.
Then the probability that the first 3 digits are odd numbers, is equal to the quotient between number of combination that start with 3 odd digits and the total number of combinations:
P = c/C = 12/120 = 0.10
What the correct answer now
Answer:
388.6 yd²
Step-by-step explanation:
the missing angle in triangle is 180 - 32 - 38 = 110
Law of sines: 31/sin 38 = VT/sin 32
VT = 26.68
area = 1/2ab sinC
A = 1/2 (31)(26.68) sin 110
388.6 yd²
[tex] \sqrt[3]{y} = a(c + \frac{1}{x})[/tex]
Greetings from Brasil...
Here we don't have much to go
∛Y = A.(C + 1/X)
∛Y = (AC + A/X)
raising both members to the cube.....
(∛Y)³ = (AC + A/X)³
from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³
Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³
Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]
This is probably pretty easy, I could solve all the other ones but I got stuck on this one.
Answer:
78
Step-by-step explanation:
Let x be the score on the next test
We are averaging 6 tests and want an average of 75
( 82+91+38+78+83+x) /6 = 75
Multiply each side by 6
( 82+91+38+78+83+x) = 75*6
( 82+91+38+78+83+x) =450
Combine like terms
x+372 = 450
Subtract 372 from each side
x+372-372 = 450-372
x =78
Brad walked a total of 24 kilometers by making 6 trips to school. After 21 trips to school, how many kilometers will Brad have walked in total? Solve using unit rates.
Answer:
84 km... Mark me as BRAINLIEST
Step-by-step explanation:
Refer to the pic...
Hope it helped you!
Step-by-step explanation:
Since it takes 6 trips to cover 24 km -
1 trip = 24/6
Therefore 1 trip is -
4 km
Now, the distance for 21 trips is -
21*4 = 84
Therefore, Brad has walked -
84 km
HOPE YOU FIND THIS HELPFUL
Which function is graphed below?
Answer:
The answer is f(x) = -sin(x) as you can see in the graph below
Step-by-step explanation:
WILL GIVE BRAINLIEST A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched. Graphon the coordinate plane.
Answer:
[tex]h=64t-4.9t^{2}[/tex]
Please refer to the attached graph.
Step-by-step explanation:
Given that
Initial velocity of rocket = 64 and is launched vertically.
To find:
Quadratic equation in time to represent the height of rocket in feet.
Solution:
Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.
Initial velocity, u = 64 feet/s
The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.
Formula for distance traveled is given as:
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Here Let us represent s by 'h'
a = -g = 9.8 m/[tex]s^2[/tex]
Let us put the known values in the formula:
[tex]h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2[/tex]
It is a quadratic equation, the equation represents the graph of a parabola.
Please refer to the attached graph.
Value of height is 0 at 0 second and ~13 seconds