Answer:
[tex] f = 10.7 [/tex]
Step-by-step explanation:
Given ∆DEF,
<F = 36°
DF = e = 15
EF = d = 6
DE = f = ?
f can be found using the Law of Cosine as shown below:
[tex] f^2 = d^2 + e^2 - 2(d)(e)*cos(F) [/tex]
Plug in your values:
[tex] f^2 = 6^2 + 15^2 - 2(6)(15)*cos(36) [/tex]
Evaluate:
[tex] f^2 = 36 + 225 - 180*0.809 [/tex]
[tex] f^2 = 261 - 145.62 [/tex]
[tex] f^2 = 115.38 [/tex]
[tex] f = 10.74 [/tex]
[tex] f = 10.7 [/tex] (to nearest tenth)
How many 5-digit palindromes contain only even digits?
Answer:
400
Step-by-step explanation:
There are 400.
Assuming the number must be at least 10,000, then:
In a 5 digit palindrome, the first and last digits must be the same, and the second and fourth digits must be the same; and:
For the first and last digit there is a choice of 4 digits {2, 4, 6, 8};
For each of these there is a choice of 10 digits {0, 1, ..., 9} for the second and fourth digits;
For each of the above choices these is a choice of 10 digits {0, 1, ..., 9} for the third digit;
Making 4 x 10 x 10 = 400 possible even 5 digit palindromes.
Find the volume of the cuboid which length is 10cm, breadth is 8cm and height is 7cm. Who answers first gets brainliest answer
Answer:
560cm
Step-by-step explanation:
Volume = Length × Breadth × Height
= 10 × 8 × 7
= 560 cm³
Answer:
Step-by-step explanation:
Volume =length x breadth x height
10 x 8 x 7=560cm^3
[tex]( \frac{1 + i}{1 - i} ) {}^{2} [/tex]
Please tell me the answer i need help
Answer:
- 1
Step-by-step explanation:
Given
( [tex]\frac{1+i}{1-i}[/tex] )²
= [tex]\frac{(1+i)^2}{(1-i)^2}[/tex]
= [tex]\frac{(1+i)(1+i)}{(1-i)(1-i)}[/tex] ← expand numerator/ denominator using FOIL
= [tex]\frac{1+2i+i^2}{1-2i+i^2}[/tex] ← simplify using i² = - 1
= [tex]\frac{1+2i-1}{1-2i-1}[/tex]
= [tex]\frac{2i}{-2i}[/tex]
= - 1
quadratic equation grade :9
10 points;)
Answer:
Step-by-step explanation:
put (x+2)/(x-2)=a
a-1/a=5/6
[tex]multiply~by~6a \\6a^2-6=5a\\6a^2-5a-6=0\\6a^2-9a+4a-6=0\\3a(2a-3)+2(2a-3)=0\\(2a-3)(3a+2)=0\\either 2a-3=0,a=3/2 \\\frac{x+2}{x-2} =\frac{3}{2} \\cross~multiply\\3x-6=2x+4\\3x-2x=4+6\\x=10\\[/tex]
[tex]or~3a+2=0\\a=-2/3\\\frac{x+2}{x-2} =-\frac{2}{3} \\3x+6=-2x+4\\3x+2x=4-6\\5x=-2\\x=-2/5[/tex]
2.
put (x+3)/x=a
a+1/a=4 1/4
[tex]a+\frac{1}{a} =\frac{17}{4} \\multiply~by~4a\\4a^2+4=17a\\4a^2-17a+4=0\\4a^2-16a-a+4=0\\4a(a-4)-1(a-4)=0\\(a-4)(4a-1)=0\\either~a-4=0,a=4\\\frac{x+3}{x} =4\\4x=x+3\\4x-x=3\\3x=3\\x=3/3=1\\or\\4a-1=0\\a=1/4\\\\\frac{x+4}{x} =\frac{1}{4} \\4x+16=x\\3x=-16\\x=-16/3[/tex]
Question 7(Multiple Choice Worth 1 points)
(06.02 MC)
The radius of the cone is 5 in and y = 13 in. What is the volume of the cone in terms of n?
40nt in
43n in
O
100nt in
108n in
Hey there! I'm happy to help!
I assume that n is supposed to be π. To find the volume of a cone, you multiply the base by the height and then divide by three.
First, we find the area of the base, which is a circle. To find the area of a circle, you square the radius and multiply by π.
5²=25
And we multiply by π.
25π
Now we multiply by the height.
25π×13=325π
We divide by three.
325π/3≈108π
Therefore, the answer is 108π in.
Have a wonderful day! :D
What is the simplified form of y^2+7y+12/y^2-2y-15? Choices:
Answer:
[tex] \frac{y + 4}{y - 5} [/tex]Option C is the correct option
Step-by-step explanation:
[tex] \frac{ {y}^{2} + 7y + 12}{ {y}^{2} - 2y - 15 } [/tex]
Write 7y as a sum
[tex] \frac{ {y}^{2} + 4y + 3y + 12}{ {y}^{2} - 2y - 15} [/tex]
Write -2y as a difference
[tex] \frac{ {y}^{2} + 4y + 3y + 12}{ {y}^{2} + 3y - 5y - 15} [/tex]
Factor out y from the expression
[tex] \frac{y(y + 4) + 3y + 12}{ {y}^{2} + 3y - 5y - 15 } [/tex]
Factor out 3 from the expression
[tex] \frac{y(y + 4) + 3(y + 4)}{ {y}^{2} + 3y - 5y - 15 } [/tex]
factor out y from the expression
[tex] \frac{y(y + 4) + 3(y + 4)}{y(y + 3) - 5y - 15} [/tex]
Factor out -5 from the expression
[tex] \frac{y(y + 4) + 3(y + 4)}{y(y + 3) - 5( y + 3)} [/tex]
factor out y + 4 from the expression
[tex] \frac{(y + 4)(y + 3)}{y(y + 3) - 5(y + 3)} [/tex]
Factor out y + 3 from the expression
[tex] \frac{(y + 4)(y + 3)}{(y + 3)(y - 5)} [/tex]
Reduce the fraction with y + 3
[tex] \frac{y + 4}{y - 5} [/tex]Hope this helps..
Best regards!!
At which value in the domain does f(x)=0? On a coordinate plane, a function goes through the x-axis at (negative 2.5, 0), (negative 0.75, 0), (0, negative 3), and (1, 0).
Answer:
The values in the domain where f(x) = 0 are x = -2.5, x = - 0.75 and x = 1.
Step-by-step explanation:
Since we are given the points (-2.5,0), (-0.75, 0), (0, -3) and (1,0) where the coordinates are in ordered pairs of (x, y) where y = f(x).
To find the values in the domain where f(x) = 0, we look at the ordered pairs given.
We look for the pair in which f(x) = 0.
So f(x) = 0 in (-2.5, 0)
f(x) = 0 in (-0.75, 0)
and f(x) = 0 in (1, 0)
The corresponding values of x in which f(x) = 0 are x = -2.5, x = - 0.75 and x = 1.
So, the values in the domain where f(x) = 0 are x = -2.5, x = - 0.75 and x = 1.
Answer:
C. [tex]x=1[/tex]
Step-by-step explanation:
When x is 1, y is 0.
Help please thanks don’t know how to do this
Answer:
a = 11.71 ; b = 15.56
Step-by-step explanation:
For this problem, we need two things. The law of sines, and the sum of the interior angles of a triangle.
The law of sines is simply:
sin(A)/a = sin(B)/b = sin(C)/c
And the sum of interior angles of a triangle is 180.
45 + 110 + <C = 180
<C = 25
We can find the sides by simply applying the law of sines.
length b
7/sin(25) = b/sin(110)
b = 7sin(110)/sin(25)
b = 15.56
length a
7/sin(25) = a/sin(45)
a = 7sin(45)/sin(25)
a = 11.71
Please help pleaseee give first person to answer brainlest A system of equations is shown below: Equation A: 3c = d − 8 Equation B: c = 4d + 8 Which of the following steps should be performed to eliminate variable d first? A : Multiply equation A by −4. B : Multiply equation B by 3. C : Multiply equation A by 3. D : Multiply equation B by 4.
Answer:
Multiply the first equation by -4
Step-by-step explanation:
Equation A: 3c = d − 8
Equation B: c = 4d + 8
We want to eliminate variable d
Multiply the first equation by -4
-4( 3c = d − 8)
-12c = -4d +32
Add this to the second equation
-12c = -4d +32
c = 4d + 8
================
-11c = 0d + 40
Answer:
A : Multiply equation A by −4
Step-by-step explanation:
3c = d - 8
Multiply the equation by -4.
-12c = -4d + 32
-12c = -4d + 32
c = 4d + 8
Add equations.
-11c = 0d + 40
-11c = 40
The d variable is eliminated.
Solve the following system using substitution.
Answer/Step-by-step explanation:
3. By substitution method, let's substitute [tex] \frac{2}{3}x- 4 [/tex] for y in the first equation.
Thus,
[tex] \frac{1}{3}x + 2(\frac{2}{3}x- 4) = 1 [/tex]
Solve for x
[tex] \frac{x}{3} + \frac{4x}{3} - 4 = 1 [/tex]
Add 4 to both sides
[tex] \frac{x}{3} + \frac{4x}{3} - 4 + 4 = 1 + 4 [/tex]
[tex] \frac{x}{3} + \frac{4x}{3} = 5 [/tex]
[tex] \frac{x + 4x}{3} = 5 [/tex]
[tex] \frac{5x}{3} = 5 [/tex]
Multiply both sides by 3
[tex] \frac{5x}{3}*3 = 5*3 [/tex]
[tex] 5x = 15 [/tex]
Divide both sides by 5
[tex] x = 3 [/tex]
Now, substitute 3 for x in the equation.
[tex] y = \frac{2}{3}x- 4 [/tex]
[tex] y = \frac{2}{3}(3) - 4 [/tex]
[tex] y = 2 - 4 [/tex]
[tex] y = -2 [/tex]
The solution of the equation is x = 3, y = -2
4. Solving by elimination, let's try to eliminate the x-variable by adding both equation together.
[tex] 3x - 2y = 11 [/tex]
[tex]-3x - y = 4[/tex]
[tex] -3y = 15 [/tex] => [tex] (-3x +(-3x) = 0; -2y +(-y) = -3y; 11 + 4 = 15) [/tex]
Divide both sides by -3 to solve for y
[tex] \frac{-3y}{-3} = \frac{15}{-3} [/tex]
[tex] y = -5 [/tex]
Substitute -5 for y in the first equation to find x
[tex] 3x - 2(-5) = 11 [/tex]
[tex] 3x + 10 = 11 [/tex]
Subtract 10 from both sides
[tex] 3x + 10 - 10 = 11 - 10 [/tex]
[tex] 3x = 1[/tex]
Divide both sides by 3
[tex] \frac{3x}{3} = \frac{1}{3} [/tex]
[tex] x = \frac{1}{3} [/tex]
The solution is [tex] x = \frac{1}{3}, y = -5 [/tex]
An umbrella has 8 ribs which are equally spaced (see fig.). Assuming umbrellato
be a flat circle of radius 45 cm, find the area between the two consecutive ribs of
the umbrella.
Answer:
Yes.
Step-by-step explanation:
You are correct except to the nearest hundredth it is 795.54 cm^2.
Which represents the solution(s) of the system of equations, y + 4 = x2 and y – x = 2? Determine the solution set by graphing.
(–2, 0)
(–2, 0) and (2, 0)
(–2, 0) and (3, 5)
no solutions
Answer:
c
Step-by-step explanation:
c
Answer:
the answer is C ;D
Step-by-step explanation:
(Math never got easier!) No seriously help:)
Answer:
Step-by-step explanation:
cosФ=0 then the angle=π/2=90 degrees
sinФ==1 sin 90=1
12) the original price of the console that Amanda bought :
240+(240*50%)=360 dollars
the price before the tariffs:
360-(360*50^)=180 dollars
Miriam is setting up a fishing game in a kiddie pool for her niece's birthday party. The pool has a circular base with a diameter of 4 feet and a height of 0.75 feet. She wants to fill the pool halfway so there is plenty of space left for the plastic fish. Approximately how many cubic feet of water does she need? 9.4 1.5 2.4 4.7
Answer:
4.7 feet³ of water
Step-by-step explanation:
Diameter of 4 feet
Radius = 2 feet
Height = 0.75 feet
Formula for Volume = 2·[tex]\pi[/tex]·radius·height
But she only wants to fill half, so divide by 2, cancels the 2 in the formula for volume, giving us: [tex]\pi[/tex]·radius·height
[tex]\pi[/tex]·2·0.75 = 4.71 feet³
can someone please help me
Answer:
3x^2 + 3/2 x -9
Step-by-step explanation:
f(x) = x/2 -3
g(x) =3x^2 +x -6
(f+g) (x) = x/2 -3 + 3x^2 +x -6
Combine like terms
= 3x^2 + x/2 +x -3-6
= 3x^2 + 3/2 x -9
A current of 2.5 A delivers 3.5 of charge
1 Ampere = 1 Coulomb of charge per second
2.5 A = 2.5 C of charge per second
Time to deliver 3.5 C of charge = (3.5 C) / (2.5 C / sec)
Time = (3.5 / 2.5) (C / C-sec)
Time = 1.4 sec
A current of 2.5 A delivers 3.5 C of charge in 1.4 seconds.
In a school, 25% of the teachers teach basic math. If there are 50 basic math teachers, how many teachers are there in a school?
Answer:
200 teachers
Step-by-step explanation:
If 25% is a fourth of the teacher staff, and this value is fifty, to find out how many teachers there are you just have to multiply by 4 to find out the 100%. So this means that 50*4= 200
Answer:
Total teachers = 200
Step-by-step explanation:
Let x be the total teachers in school
Basic Maths teachers = 25 % of x
Basic Maths Teachers = 50
=> 25% of x = 50
=> [tex]\frac{25}{100} x = 50[/tex]
=> [tex]\frac{x}{4} = 50[/tex]
Multiplying both sides by 4
=> x = 200
Please Help! Two lines, A and B, are represented by the following equations: Line A: y = x − 1 Line B: y = −3x + 11 Which of the following options shows the solution to the system of equations and explains why? (3, 2), because the point does not lie on any axis (3, 2), because one of the lines passes through this point (3, 2), because the point lies between the two axes (3, 2), because both lines pass through this point
Answer:
The last choice (3,2), because both lines pass through this point.
Step-by-step explanation:
For a point to be a solution to a system of linear equations, both equation's lines have to pass through that same point.
Answer: (3, 2), because both lines pass through this point
Step-by-stepexplanation:
This can be solved by substitution. The graph will show the same result.
Please answer this question now
Answer:
[tex] Area = 538.5 m^2 [/tex]
Step-by-step Explanation:
Given:
∆XVW
m < X = 50°
m < W = 63°
XV = w = 37 m
Required:
Area of ∆XVW
Solution:
Find side length XW using Law of Sines
[tex] \frac{v}{sin(V)} = \frac{w}{sin(W)} [/tex]
W = 63°
w = XV = 37 m
V = 180 - (50+63) = 67°
v = XW = ?
[tex] \frac{v}{sin(67)} = \frac{37}{sin(63)} [/tex]
Cross multiply
[tex] v*sin(63) = 37*sin(67) [/tex]
Divide both sides by sin(63) to make v the subject of formula
[tex] \frac{v*sin(63)}{sin(63)} = \frac{37*sin(67)}{sin(63)} [/tex]
[tex] v = \frac{37*sin(67)}{sin(63)} [/tex]
[tex] v = 38 [/tex] (approximated to nearest whole number)
[tex] XW = v = 38 m [/tex]
Find the area of ∆XVW
[tex] area = \frac{1}{2}*v*w*sin(X) [/tex]
[tex] = \frac{1}{2}*38*37*sin(50) [/tex]
[tex] = \frac{38*37*sin(50)}{2} [/tex]
[tex] Area = 538.5 m^2 [/tex] (to nearest tenth).
Which expression is equivalent to x^2 • x^3?
Answer:
x^5
Step-by-step explanation:
x^2 . x^3
x^(2+3)
x^5
In a fiftness class, there was a warm up of 14 press-ups. Anyone unable to do 14 or more recives a punishment. Jessica can do 10 press-ups without ever failing, however, the chances of her successfully doing each subsequent press-up halves. Whats the probality of her receiving a punishment? A. 1 in 8 B. 1 in 1024 C. 15 in 16 D. 1023 in 1024
Answer:
The correct option is;
C. 15 in 16
Step-by-step explanation:
The given information are;
The number of press-ups required = 14 press-ups
The number of press-ups Jessica is sure to do = 10 press-ups
The chance of Jessica doing subsequent press-ups after 10 halves each time
The consequence of not completing the 14 press-ups = Punishment
The probability that Jessica does goes on to do 11 press-ups = 1/2
The probability that Jessica does goes on to do 12 press-ups = 1/2×1/2
The probability that Jessica does goes on to do 13 press-ups = 1/2×1/2×1/2
The probability that Jessica does goes on to do (completes) 14 press-ups = 1/2×1/2×1/2×1/2 = 1/16
Therefore;
Since the probability that Jessica does not receive a punishment because she completed the 14 push-ups is 1/16, we have;
The probability that Jessica does not complete the 14 press-ups and receives a punishment = 1 - 1/16 = 15/16 which is 15 times out of 16 or 15 in 16.
x + 3y = 42
2x - y= 14
Answer:
x=12,y=10
Step-by-step explanation:
Step: Solve x+3y=42
x+3y=42
x+3y+−3y=42+−3y(Add -3y to both sides)
x=−3y+42
Step: Substitute−3y+42forxin2x−y=14:
2x−y=14
2(−3y+42)−y=14
−7y+84=14(Simplify both sides of the equation)
−7y+84+−84=14+−84(Add -84 to both sides)
−7y=−70
Divide both sides by -7
y=10
Step: Substitute10foryinx=−3y+42:
x=−3y+42
x=(−3)(10)+42
x=12(Simplify both sides of the equation)
Hope this Helps:)
-Ac<3-
abby owns a square plot of land. she knows that the area of the plot is between 2200 and 2400 square meters. which of the following answers is a possible value for the side length of the plot of land?
Answer:
48
Step-by-step explanation:
The formula for the area of a square is A = s². Plug in each value and see if is in between 2200 and 2400.
A = s²
A = (46)²
A = 2116
A = s²
A = (48)²
A = 2304
A = s²
A = (50)²
A = 2500
A = s²
A = (44)²
A = 1936
The only value that fits in between 220 and 2400 is 48.
WILL MARK BRAINLIEST
Answer:
A
Step-by-step explanation:
A high school wants to sell postage stamps with the school logo on them. The fundraising group have purchased 500 sheets of stamps at $16/sheet plus $50 to create the image. They plan to sell each sheet for $20. a) Write an equation that represents the cost of obtaining the stamps. b) Write an equation that represents the income from sales. c) For each equation, set up a table of values. d) Graph each equation on the same set of coordinate axis. e) What is the minimum number of sheets the group must sell so they don't lose any money? f) How much profit will they make if they sell 500 sheets?
Answer:
a) Cost
[tex]C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050[/tex]
b) Sales income
[tex]S(q)=20q\\\\S(500)=20\cdot 500 = 10,000[/tex]
c) Table of values
[tex]\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right][/tex]
d) Attached
e) Breakeven point = 12.5 sheets
f) Profit at 550 sheets = $1,950
Step-by-step explanation:
a) We have a fixed cost for the image, at $50.
We also have a variable cost of $16 a sheet.
The purchased quantity is 500 sheets.
Then, the cost function is:
[tex]C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050[/tex]
b) The price for each sheet is $20, so the income from sales are:
[tex]S(q)=20q\\\\S(500)=20\cdot 500 = 10,000[/tex]
c) Table of values
[tex]\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right][/tex]
d) Attached
e) The minimum number of sheets the group must sell so they don't lose any money is the breakeven point (BEP) and can be calculated making the income sales equal to the cost:
[tex]S(q)=C(q)\\\\20q=50+16q\\\\(20-16)q=50\\\\4q=50\\\\q=50/4=12.5[/tex]
f) This profit can be calculated as the difference between the sales income and the cost:
[tex]P(500)=S(500)-C(500)\\\\P(500)=20\cdot 500-(50+16\cdot 500)=10,000-8,050=1,950[/tex]
The given number of 500 sheets of stamps purchased at $16/sheet with
a plan to sell each sheet for $20 gives the following values;
(a) Cost, C = 50 + 16·q
(b) Income, R = 20·q
(c) Please find the included table of values and the attached graph
(e) Approximately 403 sheets
(f) $1,950
Which method can be used to derive the equations?
(a) The cost per sheet of stamp = $16/sheet
The cost to create the image = $50
Amount at which they plan to sell each sheet, P = $20
Therefore
Cost of obtaining the stamps, C = 50 + 16·q(b) The income from sale, R = Number of units sold × P
Which gives;
R = 20·q(c) The table of values are therefore;
C = 50 + 16·q
[tex]\begin{array}{|c|c|c|}q&C=50+16 \times q\\0&50\\1&66\\2&82\\3&98\\4&114\\5&130\\6&146\\7&162\\8&178\\9&194\\10&210\\11&226\\12&242\\13&258\\14&274\end{array}\right][/tex]
R = 20·q
[tex]\begin{array}{|c|c|c|}q&R = 20 \times q\\0&0\\1&20\\2&40\\3&60\\4&80\\5&100\\6&120\\7&140\\8&160\\9&180\\10&200\\11&220\\12&240\\13&260\\14&280\end{array}\right][/tex]
Please find attached the required graph created with MS Excel
e) The minimum number of sheets the group must sell is given as follows;
The cost of the sheets purchased = 50 + 16 × 500
Which gives;
At point of profitability; Income = Cost
50 + 16 × 500 = 20·[tex]q_{min}[/tex]
[tex]q_{min} = \dfrac{50 + 16 \times 500}{20} =402.5 \approx \mathbf{403}[/tex]
The minimum number the sheets they must sell, [tex]q_{min}[/tex] ≈ 403 sheets(f) The profit made by selling 500 sheets is; 20·q - (50 + 16·q)
Where;
q = 500
Which gives;
20 × 500 - (50 + 16 × 500) = 1,950
The profit made from selling 500 sheet = $1,950
Learn more about graphs of functions here:
https://brainly.com/question/22150463
Find the missing side. Round your answer to the nearest tenth.
Answer:
Step-by-step explanation:
In a right triangle, the sides forming the right angle also determine the angle opposite one of the sides.
Tan(29) =26/x Multiply both sides by x
x tan(29) = 26 Divide by tan(29)
x = 26/tan(29) Find tan(29)
x = 26/0.5543 Divide
x= 46.9
The table shows the number of flowers in four bouquets and the total cost of each bouquet. A 2-column table with 4 rows. The first column is labeled number of flowers in the bouquet with entries 8, 12, 6, 20. The second column is labeled total cost (in dollars) with entries 12, 40, 15, 20. What is the correlation coefficient for the data in the table? –0.57 –0.28 0.28 0.57
Answer:
The correct option is;
0.28
Step-by-step explanation:
The given data values are;
x, f(x)
8, 12
12, 40
6, 15
20, 20
Where;
x = The number of flowers in the bouquet
f(x) = The total cost (in dollars)
The equation for linear regression is of the form, Y = a + bX
The formula for the intercept, a, and the slope, b, are;
[tex]b = \dfrac{N\sum XY - \left (\sum X \right )\left (\sum Y \right )}{N\sum X^{2} - \left (\sum X \right )^{2}}[/tex]
[tex]a = \dfrac{\sum Y - b\sum X}{N}[/tex]
Where:
N = 4
∑XY = 1066
∑X = 46
∑Y = 87
∑X² = 644
(∑X)² = 2116
b = (4*1066 - 46*87)/(4*644 - 2116) = 0.5696
a = (87 - 0.5696*46)/4 = 15.1996
The standard deviation of the x- values
[tex]S_X = \sqrt{\dfrac{\sum (x_i - \mu)^2}{N} }[/tex]
[tex]\sum (x_i - \mu)^2}[/tex] = 115
N = 4
Sx =√(115/4)
Sx = 5.36
[tex]S_Y = \sqrt{\dfrac{\sum (y_i - \mu_y)^2}{N} }[/tex]
[tex]\sum (y_i - \mu_y)^2}[/tex] = 476.75
N = 4
Sy =√(476.75/4)
Sy= 10.92
b = r × Sy/Sx
Where:
r = The correlation coefficient
r = b × Sx/Sy = 0.5696*5.36/10.92 = 0.2796 ≈ 0.28
The correct option is 0.28.
Answer:
C on edge
Step-by-step explanation:
Help please!!!!!thxxxx
Answer:
144
Step-by-step explanation:
An angle of a regular pentagon is of 180(5-2)/5=108°
and that all the sides are equal so angle MNL=108/3=36
then MNK=180-MNL=180-36=144
I don't know if you understand this but it's hard to work without more points :)
Give the digits in the tens place and the tenths place.
12.05
A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of miles and a standard deviation of miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires?
Complete question is;
A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 34,000 miles and a standard deviation of 2500 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires?
Answer:
The mechanics worded guarantee that the tyre will be replaced if it lasts less than or equal to 30796 miles.
Step-by-step explanation:
Let X = Life expectancy of the automobile tire
For the normal distribution, we are given;
μ = 34000
σ = 2700
Let y miles be the minimum miles of the tyres which the mechanic guarantees that he will replace if it's last less than that.
Now, since the mechanic is willing to replace approximately 10% of the tires, y would be such that:
P(X ≤ y) = 0.1
Using the z formula, we have;
P[(X - μ)/σ) ≤ [(y - μ)/σ] = 0.1
Thus;
P(Z ≤ ([y - μ]/σ) = 0.1
From z-distribution table the Z-score at 0.1 is approximately -1.2816
This is P(Z ≤ -1.2816)
Thus;
[y - μ]/σ = -1.2816
(y - 34000)/2500 = -1.2816
y - 34000 = -1.2816 × 2500
y - 34000 = -3204
y = 34000 – 3204
y = 30796
So, we conclude that the mechanic will guarantee that the tyre will be replaced if it lasts less than or equal to 30796 miles.