Please help due in 10 minutes

Answer:  [tex]\frac{8x^3}{27y^6}[/tex]

This is the fraction 8x^3 all over 27y^6

On a keyboard, we can write it as (8x^3)/(27y^6)

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Explanation:

The exponent tells you how many copies of the base to multiply with itself.

We'll have three copies of [tex]\left(\frac{2x}{3y^2}\right)[/tex] multiplied with itself due to the cube exponent on the outside.

So,

[tex]\left(\frac{2x}{3y^2}\right)^3 = \left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2x*2x*2x}{(3y^2)*(3y^2)*(3y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{(2*2*2)*(x*x*x)}{(3*3*3)*(y^2*y^2*y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{9y^6}\\\\[/tex]

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Or another approach you could take is to cube each component of the fraction. The rule I'm referring to is [tex]\left(\frac{a}{b}\right)^c = \frac{a^c}{b^c}[/tex]

Applying that rule will lead to:

[tex]\left(\frac{2x}{3y^2}\right)^3 = \frac{(2x)^3}{(3y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2^3*x^3}{3^3*(y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^{2*3}}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^6}\\\\[/tex]

Either way you should get 8x^3 all over 27y^6 as one fraction.

Answer:

He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6

Step-by-step explanation:

8·11= 88

11-5= 6

Answer:

True, True, False.

Step-by-step explanation:

A) Rise/Run is 8/1

B) 8 dollars are earned every hour

C) Correct equation is y=8x

Answer:

12%

Step-by-step explanation:

We can get SI of 3 years = 12005 - 9800 = 2205

SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]

Principal = 12005 - 3675 = 6125

So Rate = (100*3675)/(6125*5) = 12%

[tex]\Large\boxed{\tt Answer: 5\frac{2}{3} }[/tex]

[tex]\tt Step-by-step~explanation:[/tex]

We can solve this by dividing both numbers by four.

[tex]\tt 8\div4=2\\12\div4=3\\\frac{2}{3}[/tex]

We then add that to 5 to get our answer.

Given:

Twice the sum of x and 3 is decreased by 13.

To find:

The expression for the given statement.

Solution:

The sum of x and 3 is (x+3).

Twice the sum of x and 3 is two times of (x+3), i.e., 2(x+3)

Negative sign is used of decrease.

Decreased by 13 is represented by -13.

Using these representation, we get

Twice the sum of x and 3 is decreased by 13: [tex]2(x+3)-13[/tex]

Therefore, the required expression is [tex]2(x+3)-13[/tex].

Answer:

m = 3

Step-by-step explanation:

Pick two points from the table.

(-1, 1) and (1, 7)

Apply the slope formula.

[tex]m=\frac{7-1}{1+1}=\frac{6}{2}=\boxed{3}[/tex]

Hope this helps.

Answer:

4x−7+6y+2x+x+16−3x

=4x+−7+6y+2x+x+16+−3x

Combine Like Terms:

=4x+−7+6y+2x+x+16+−3x

=(4x+2x+x+−3x)+(6y)+(−7+16)

=4x+6y+9

Answer:

=4x+6y+9

Answer:

sin A= 3/5

sin C= 4/5

cos A= 4/5

cos C= 3/5

Step-by-step explanation:

Please see the attached picture for the full solution.

Answer:

D

Step-by-step explanation:

This is equivalent to t < 4.

clearly this is not part of the set.

Answer:

0

Step-by-step explanation:

The minimum number of cavities a patient had was 0 cavities.

Answer:

0

Step-by-step explanation:

The smallest number that indicates cavity is '0' therefore it is the minimum number of cavities

Answer:

-3r + 13

Step-by-step explanation:

11r - 14r - 3 + 16

add like terms

-3r + 13

Given:

Hyperbola with directrices at y = ±2 and foci at (0, 6) and (0, −6).

To find:

The equation of hyperbola.

Solution:

We have, directrices at y = ±2 so this hyparabola is along the y-axis.

The standard form of hyperbola is

[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]      ...(i)

where, (h,k) is center, foci are [tex](h,k\pm c)[/tex] and directrix are [tex]y=k\pm \dfrac{a^2}{c}[/tex].

On comparing foci, we get

[tex](h,k\pm c)=(0,\pm 6)[/tex]

[tex]h=0,k=0,c=6[/tex]

On comparing directrix we get

[tex]k\pm \dfrac{a^2}{c}=\pm 2[/tex]

[tex]\dfrac{a^2}{c}=2[/tex]

[tex]\dfrac{a^2}{6}=2[/tex]

[tex]a^2=12[/tex]

Now,

[tex]a^2+b^2=c^2[/tex]

[tex]12+b^2=(6)^2[/tex]

[tex]b^2=36-12[/tex]

[tex]b^2=24[/tex]

Putting [tex]h=0,k=0,a^2=12,b^2=24[/tex], we get

[tex]\dfrac{(y-0)^2}{12}-\dfrac{(x-0)^2}{24}=1[/tex]

[tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex]

Therefore, the equation of hyperbola is [tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex].

Answer:

the person above has the right answer. I took the test.

Step-by-step explanation:

The person above is correct.

Step-by-step explanation:

Given that,

For 4 weeks in June, Cameron biked 3 1/4 miles each week and swam 2 1/2 miles each week.

For 3 weeks in July, he biked 4 3/4 miles each week and swam 3 1/2 miles each week.

We need to find how much greater was the total distance Cameron bike and swim in July compared to the total distance he bike in swim in June.

In July, total distance is ,

[tex]4\dfrac{3}{4}\times 3+3\dfrac{1}{2}\times 3\\\\= \dfrac{19}{4}\times 3+\dfrac{7}{2}\times 3\\\\=24.75\ \text{miles}[/tex]

In June, total distance is :

[tex]=4\times 3\dfrac{1}{4}+4\times 2\dfrac{1}{2}\\\\=\dfrac{13}{4}\times 4+\dfrac{5}{2}\times 4\\\\=23\ \text{miles}[/tex]

Hence, in June total distance is 23 miles and in July total distance is 24.75 miles.

Step-by-step explanation:

20x² = y - 24

y = 20x² + 24

For y to have the least possible value, x² have to be the least possible, which is 0.

Since -3 <= x <= 2 includes x = 0, this is allowed.

Hence least possible value of y

= 20(0)² + 24 = 24.

Answer:

24

Step-by-step explanation:

-3---> 20(-3)^2=y-24 ----> y=204

-2---> 20(-2)^2=y-24 ----> y=104

-1---> 20(-1)^2=y-24 ----> y=44

0---> 20(0)=y-24 ----> y=24

1---> 20(1)^2=y-24 ----> y=44

2---> 20(2)^2=y-24 ----> y=104

Answer:

x = - 2

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= x² - 2x + 6x + 4

= x² + 4x + 4

Equating to zero

x² + 4x + 4 = 0 ← left side is a perfect square

(x + 2)² = 0, thus

x + 2 = 0 ( subtract 2 from both sides )

x = - 2

Answer:

d 4x^2 + 24x - 8

Step-by-step explanation:

Perimeter of the rectangle = 2x² - 5 + 12x + 1 + 2x² - 5 + 12x + 1

                                            = (2x²+ 2x²) + (12x+ 12x) + (- 5 + 1 - 5 + 1)

                                            = 4x² + 24x - 8

Answer:

its the first one

Step-by-step explanation:

Answer:

Length = 22 ; width = 10

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Perimeter = 64 feets

Length = 2 + (2*width)

Let :

Length = l ; width = w

Perimeter = 2((2 + (2w)) + w)

64 = 2(2 + 3w)

64 = 4 + 6w

64 - 4 = 6w

60 = 6w

w = 60/6

w = 10

Width = 10

Length = 2 + (2*width) = 2 + (2*10) = 2 + 20 = 22

Answer

the first one is the answer and none of the above

Step-by-step explanation:

Answer:

Step-by-step explanation:

1/2

Answer:

178 miles

Step-by-step explanation:

Let Eric has driven d miles.

As the rate of charge of driving the truck = 76 cents /mile

So, the charge of driving the truck for d miles = 76d cents= $0.76d

The base fee of the truck was $16.95.

Total money paid at the time of returning the truck = $152.23

So, 16.95+0.76d=152.23

0.76d= 152.23-16.95=135.28

d=135.28/0.76

d=178

Hence, he drives 178 miles.

Answer:

50

Step-by-step explanation:

Answer: the answer is 50

Step-by-step explanation:

Answer:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

Step-by-step explanation:

Given

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

Reflection: [tex]y = x[/tex]

Required

Determine the coordinates of G'H'I'

The following applies when a line A is reflected over [tex]y = x[/tex]

[tex]A = (x,y)[/tex]

[tex]A' = (y,x)[/tex]

i.e, we simply swap the positions of x and y

So, for:

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

The reflections are:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

See attachment

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Explanation:

Think of x as a placeholder for a number. For me, I tend to think of it as a box. It's handy that the letter x is part of box, to help make that connection better. We have some box and inside the box goes a number.

If we multiply 5 by whatever is in the box, we can write it like [tex]5*\square[/tex]

Then let's say we fill that box with the value 7. We would then have [tex]5*\boxed{7}[/tex]

If we put 3 in the box instead we'll have [tex]5*\boxed{3}[/tex] and so on

Unfortunately the box symbol isn't something we could easily write on a keyboard, so we go with x instead to make life simpler.

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So far we've shown that "5 times a number" turns into 5*x or just 5x.

From here we subtract off 3 to get 5x-3 as the final answer. Whatever the result of 5x is, we subtract off 3.

The answer would not be 3-5x since this means "subtract 5x from 3". The order of subtraction matters. In general, A-B is not the same as B-A.

Discount amount = price x discount percentage as a decimal:

Discount amount = 62.00 x 0.15 = 9.30

Discount = $9.30

Answer:

$52.70

Step-by-step explanation: