Please help me wiyh this
In triangle △WXY, XY ≅ WX and m∠X=38 Find m∠W

Answer: m=1/6

Step-by-step explanation:

Answer:

Step-by-step explanation:

Dimensions of the picture:

Area of the picture:

Scale factor = 2.5

Enlarged picture's area:

Option B is correct

The area of the picture after it is enlarged is 250 inches².

Given that,

The length of the rectangle is labeled 5 inches. The width of the rectangle is labeled 8 inches.

A photographer wants to use a scale factor of 2.5 to enlarge a picture.

Based on the above information, the calculation is as follows:

Here, the dimensions of the picture are 5 in and 8 in

Hence, the area of the picture is,

5 × 8 = 40 in²

Since, Scale factor = 2.5

So, the enlarged picture's area would be,

40 × 2.5 ×2.5

= 250 in²

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Answer: It's (A) 12<X

Step-by-step explanation: I chose that one because the line highlighted on the number line, it's bigger than 12!

Answer:

m = 3

Step-by-step explanation:

Pick two points from the table.

(-1, 1) and (1, 7)

Apply the slope formula.

[tex]m=\frac{7-1}{1+1}=\frac{6}{2}=\boxed{3}[/tex]

Hope this helps.

Answer:

She spent 19.82 in all

Step-by-step explanation:

I added them

Given:

Hyperbola with directrices at y = ±2 and foci at (0, 6) and (0, −6).

To find:

The equation of hyperbola.

Solution:

We have, directrices at y = ±2 so this hyparabola is along the y-axis.

The standard form of hyperbola is

[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]      ...(i)

where, (h,k) is center, foci are [tex](h,k\pm c)[/tex] and directrix are [tex]y=k\pm \dfrac{a^2}{c}[/tex].

On comparing foci, we get

[tex](h,k\pm c)=(0,\pm 6)[/tex]

[tex]h=0,k=0,c=6[/tex]

On comparing directrix we get

[tex]k\pm \dfrac{a^2}{c}=\pm 2[/tex]

[tex]\dfrac{a^2}{c}=2[/tex]

[tex]\dfrac{a^2}{6}=2[/tex]

[tex]a^2=12[/tex]

Now,

[tex]a^2+b^2=c^2[/tex]

[tex]12+b^2=(6)^2[/tex]

[tex]b^2=36-12[/tex]

[tex]b^2=24[/tex]

Putting [tex]h=0,k=0,a^2=12,b^2=24[/tex], we get

[tex]\dfrac{(y-0)^2}{12}-\dfrac{(x-0)^2}{24}=1[/tex]

[tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex]

Therefore, the equation of hyperbola is [tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex].

Answer:

the person above has the right answer. I took the test.

Step-by-step explanation:

The person above is correct.

Answer:

208

Step-by-step explanation:

20 × 0 = 0

40 + 40 = 80

125 + 3 = 128

The given expression [tex]40+40-20\times 0+3+125[/tex] is reduced to 208 and this can be determined by using the arithmetic operations.

Given :

Expression - [tex]40+40-20\times 0+3+125[/tex]

The following steps can be used to evaluate the given expression:

Step 1 - Write down the expression.

[tex]=40+40-20\times 0+3+125[/tex]

Step 2 - First, multiply -20 by 0 in the given expression.

[tex]=40+40-0+3+125[/tex]

Step 3 - Now, Add 40 and 40 in the above expression.

= 80 + 3 + 125

Step 4 - Add 80 and 3 in the above expression.

= 83 + 125

Step 5 - Add 83 and 125 in the above expression.

= 208

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Discount amount = price x discount percentage as a decimal:

Discount amount = 62.00 x 0.15 = 9.30

Discount = $9.30

Answer:

$52.70

Step-by-step explanation:

Inequality Answer: 1 + y ≥ 3

I hope this helps, and Happy Holidays! :)

Answer:

sin A= 3/5

sin C= 4/5

cos A= 4/5

cos C= 3/5

Step-by-step explanation:

Please see the attached picture for the full solution.

Answer:

sam will take the 75 pollywog pralines and divide them into the three bags

75÷3 =25

Answer:

120°

Step-by-step explanation:

m<ABD+m<DBC=m<ABC

61°+59°=120°

hope this helped!

Answer:

We conclude that the value of m∠ABC = 120°

Step-by-step explanation:

Given

m∠ABD = 61°

m ∠DBC = 59°

To Determine

m∠ABC = ?

It is clear that the value of m∠ABC can be determined by adding m∠ABD and m∠DBC because m∠ABC the segment BD divides the angle m∠ABC into two adjacent angles m∠ABD and ∠DBC.

Therefore,

m∠ABC = m∠ABD + m∠DBC

             = 61° + 59°            ∵ m∠ABD = 61°, m ∠DBC = 59°

             = 120°

Therefore, we conclude that the value of m∠ABC = 120°

Answer:

50

Step-by-step explanation:

Answer: the answer is 50

Step-by-step explanation:

Answer:

12%

Step-by-step explanation:

We can get SI of 3 years = 12005 - 9800 = 2205

SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]

Principal = 12005 - 3675 = 6125

So Rate = (100*3675)/(6125*5) = 12%

===================================================

Explanation:

Make sure your calculator is in radian mode. Use your calculator to find that tan(5pi/8) = -2.41421 which is approximate.

Since the value is negative, this means the answer is between choices C and D. You can use your calculator to compute those expressions given and you should find it matches with choice D.

----------------------

Further explanation:

We can apply the half angle identity for tangent like so

[tex]\tan\left(\frac{x}{2}\right) = \pm \sqrt{\frac{1-\cos(x)}{1+\cos(x)}}\\\\\\\tan\left(\frac{5\pi/4}{2}\right) = -\sqrt{\frac{1-\cos(5\pi/4)}{1+\cos(5\pi/4)}}\\\\\\\tan\left(\frac{5\pi}{8}\right) = -\sqrt{\frac{1-\left(-\frac{\sqrt{2}}{2}\right)}{1+\left(-\frac{\sqrt{2}}{2}\right)}}\\\\\\[/tex]

Simplifying further, we get

[tex]\tan\left(\frac{5\pi}{8}\right) = -\sqrt{\frac{1+\frac{\sqrt{2}}{2}}{1-\frac{\sqrt{2}}{2}}}\\\\\\\tan\left(\frac{5\pi}{8}\right) = -\sqrt{\frac{2+\sqrt{2}}{2-\sqrt{2}}}\\\\\\[/tex]

In the last step, I multiplied top and bottom of the outer fraction by 2 to clear out the denominators of the inner fractions.

Answer:

Answer D

Step-by-step explanation:

on edge 2023

Answer:

Solution in photo

Step-by-step explanation:

Answer:

Average rate of change for the function [tex]f(x)= x^2-x-1[/tex] over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: [tex]f(x)= x^2-x-1[/tex]

The formula used to find average rate of change is:

[tex]Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}[/tex]

We have, a = -1 and b = 1

Finding f(b) when b=1

[tex]f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1[/tex]

Now, finding f(a), when a= -1

[tex]f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1[/tex]

Now, putting values and finding average rate of change

[tex]Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1[/tex]

So, average rate of change for the function [tex]f(x)= x^2-x-1[/tex] over the interval -1<x<1 is -1

Answer:

I think is The little (D) -12.4.

Answer:

True, True, False.

Step-by-step explanation:

A) Rise/Run is 8/1

B) 8 dollars are earned every hour

C) Correct equation is y=8x

Answer:

let the third proportion be x.

then 8,12 and x are in proportion

then 8:12=12:x

8x=12×12

x=144/8=18

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

80 x (7 / 10) = 56

9514 1404 393

Answer:

  12 m

Step-by-step explanation:

The distances of interest are the sides of a right triangle whose right angle is at Bruce. The hypotenuse of the triangle is the Teacher-Ruth distance. The unknown side (x) can be found using the Pythagorean theorem:

  x² + 9² = 15²

  x² = 225 -81 = 144

  x = √144 = 12

Bruce and Ruth are 12 meters apart.

Answer:

He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6

Step-by-step explanation:

8·11= 88

11-5= 6