PLEASE HELP!! match the correct answers to the words.

The probability that the average coyote weight for a sample of 20 coyotes is less than 13 kg is approximately 13.14%.

we need to know the mean and standard deviation of the coyote weight population. Let's assume that the population mean is μ = 13.5 kg and the population standard deviation is σ = 2 kg.

Since we are measuring a sample of 20 coyotes, we can use the central limit theorem to approximate the distribution of sample means. According to the central limit theorem, if the sample size is large enough (in general, if n > 30), then the distribution of sample means will be approximately normal, regardless of the distribution of the population.

The mean of the sample means will be equal to the population mean (μ) and the standard deviation of the sample means (also known as the standard error) will be equal to σ / √(n), where √(n) is the square root of sample size.

Using this information, we can calculate the z-score for a sample mean of 13 kg as follows;

z = (13 - 13.5) / (2 / √(20)) = -1.118

Next, we can use a standard normal distribution table (or a calculator or software that can calculate normal probabilities) to find the probability that a z-score is less than -1.118. The area to the left of this z-score is approximately 0.1314, or 13.14%.

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Using the fact that the triangles are similar we can see that the value of x is  36

We can see that the triangles are similar due to the same interior angles, then ther is a scale factor k between them.

So we can write:

20*k = 48

k = 48/20 = 2.4

Then:

x = 15*2.4

x = 36

That is the value of x.

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The values of a and C using Law of sines is: a = 23.2 and C = 94°

You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.

You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.

We are given the parameters as:

A = 39°, B = 47°, and b = 27

a/sin A = b/sin B

Thus:

a = (27 * sin 39)/sin 47

a = 23.2

Sum of angles in a triangle is 180 degrees. Thus:

C = 180 - (47 + 39)

C = 94°

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The tickets in the box model should be:
- 1 ticket with a value of $6 (representing a win)
- 4 tickets with a value of -$2 (representing a loss).

In this gambling game, you have a 4 to 1 payout and a 1 in 5 chance of winning.

To create a box model for this scenario, follow these steps:
Identify the possible outcomes:

In this game, there are two possible outcomes:

winning (with a 1 in 5 chance) and losing (with a 4 in 5 chance).
Determine the payout for each outcome:

If a player wins, they receive a 4 to 1 payout on their $2 bet, so they win $8.

However, they also lose the original $2 bet, so the net gain is $6.

If a player loses, they lose their $2 bet.
Assign tickets to the box model based on the probability of each outcome:

Since there is a 1 in 5 chance of winning, there should be 1 ticket representing a win (net gain of $6) and 4 tickets representing a loss (net loss of $2).

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The answer to the trigonometry question in the picture attached is:

   = cos θ / [sin θ * (1 - sin θ)] * (1 + sin θ)

Simplify 1-csc θ as follows:

1 - csc θ = (1 - csc θ)(1 + csc θ) / (1 + csc θ)

= 1 - csc^2 θ / (1 + csc θ)

= 1 - 1/sin^2 θ / (1 + 1/sin θ)

= 1 - sin^2 θ / (sin θ + 1)

= (sin θ - sin^2 θ) / (sin θ + 1)

Simplify 1+csc θ as follows:

1 + csc θ = (1 + csc θ)(1 - csc θ) / (1 - csc θ)

= 1 - csc^2 θ / (1 - csc θ)

= 1 - 1/sin^2 θ / (1 - 1/sin θ)

= 1 - sin^2 θ / (sin θ - 1)

= (sin θ + sin^2 θ) / (sin θ - 1)

Substitute the above simplifications in the expression cos θ/(1-csc θ) * 1+csc θ/(1+ csc θ) to get:

cos θ / (sin θ - sin^2 θ) * (sin θ + sin^2 θ) / (sin θ + 1)

Simplify the expression by canceling out the sin^2 θ terms:

cos θ / (sin θ - sin^2 θ) * (sin θ + sin^2 θ) / (sin θ + 1)

= cos θ / (sin θ - sin^2 θ) * (1 + sin θ) / (sin θ + 1)

Simplify further by factoring out common terms in the numerator and denominator:

cos θ / (sin θ - sin^2 θ) * (1 + sin θ) / (sin θ + 1)

= cos θ * (1 + sin θ) / [(sin θ - sin^2 θ) * (sin θ + 1)]

Finally, simplify the expression by factoring out a sin θ term from the denominator:

cos θ * (1 + sin θ) / [(sin θ - sin^2 θ) * (sin θ + 1)]

= cos θ * (1 + sin θ) / [sin θ * (1 - sin θ) * (sin θ + 1)]

= cos θ / [sin θ * (1 - sin θ)] * (1 + sin θ)

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We have identified three parent functions that exhibit 180-degree rotational symmetry around the point (0,0): the constant function f(x) = 0, the odd power functions f(x) = x²ⁿ⁺¹ for any integer n, and the tangent function f(x) = tan(x) on the interval (-π/2, π/2).

A function f(x) exhibits 180-degree rotational symmetry around the point (0,0) if and only if f(-x) = -f(x) for all x. To see why, consider rotating the graph of f(x) by 180 degrees around the origin.

Using this criterion, we can identify the parent functions that have 180-degree rotational symmetry around the point (0,0). These functions are:

The constant function f(x) = 0. This function is symmetric about the origin, and any rotation around the origin preserves this symmetry.

The odd power functions f(x) = x²ⁿ⁺¹ for any integer n. These functions are also symmetric about the origin, and any rotation around the origin preserves this symmetry. To see why, note that f(-x) = (-x)²ⁿ⁺¹ = -x²ⁿ⁺¹ = -f(x) for all x.

The tangent function f(x) = tan(x) on the interval (-π/2, π/2). This function has vertical asymptotes at x = π/2 and x = -π/2, but these do not affect its rotational symmetry around the origin.

To see why, note that f(-x) = tan(-x) = -tan(x) = -f(x) for all x in the interval (-π/2, π/2).

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Answer:

Opposite and Adjacent

Step-by-step explanation:

Tanegnt is a function where you take the side lengths of the opposite side from the angle and the adjacent sides of the angle. opp/adj is the commonly used formula.

Answer:

C and D

Step-by-step explanation:

cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{4}{5}[/tex] ⇒ C

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{3}{5}[/tex] ⇒ D

The next three terms of the sequence.

(a) The sequence alternates between a run of "1"s and a run of "0"s.

Specifically, the nth term is 1 if the number of "1"s in the first n-1 terms is

odd, and 0 if the number of "1"s in the first n-1 terms is even.

(b) The nth term is[tex]\lfloor (n+1)/2\rfloor[/tex] if n is odd, and n/2 if n is even.

(c) The nth term is[tex]2^{(n-1)/2}[/tex] times the parity (i.e., 0 or 1) of n.

(d) The nth term is [tex]3\cdot 2^{n-1}[/tex].

(e) The nth term is 15-7(n-1).

(f) The nth term is the sum of the first n positive integers minus 3, i.e.,

[tex]1+2+3+\cdots+n-3.[/tex]

To determine the next three terms of each sequence, we simply apply the rule or formula given above. For example, for sequence (a), the next three terms are 0, 1, 1, since the next term is 0 (since there are an even number of 1's so far), followed by two 1's (since there are now an odd number of 1's).

For sequence (b), the next three terms are 9, 10, 10, since the next term is 9 (since the next term in the pattern is odd), followed by two 10's (since the next two terms in the pattern are even). And so on for the other sequences.

(a) The sequence alternates between a run of "1"s and a run of "0"s.

Specifically, the nth term is 1 if the number of "1"s in the first n-1 terms is

odd, and 0 if the number of "1"s in the first n-1 terms is even.

(b) The nth term is[tex]\lfloor (n+1)/2\rfloor[/tex] if n is odd, and n/2 if n is even.

(c) The nth term is[tex]2^{(n-1)/2}[/tex] times the parity (i.e., 0 or 1) of n.

(d) The nth term is [tex]3\cdot 2^{n-1}[/tex].

(e) The nth term is 15-7(n-1).

(f) The nth term is the sum of the first n positive integers minus 3, i.e.,

[tex]1+2+3+\cdots+n-3.[/tex]

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Answer:

x=2

Step-by-step explanation:

x^4=16

x=[tex]\sqrt[4]{16}[/tex]

x=[tex]2[/tex]

f(x) = {x, if x < 0

x^2, if x >= 0

This function is defined by two pieces: the formula x for x < 0, and the formula x^2 for x >= 0. The "jump" or change in formula occurs at x = 0.

A) From the given graph we see that, step function has 4 pieces. B) The step function is composed of 3 intervals: (0, 1), [1, 2), [2, 3), and [3, ∞). C) Point is not included in a function, it is indicated by an open circle.

A function that is defined by various equations or formulae on various intervals or portions of its domain is known as a piecewise function. To put it another way, a piecewise function is a function made up of several functions that have been "stitched" together.

A piecewise function is defined on a particular interval or collection of intervals for each piece. A "jump" or change in the formula used to describe the function is commonly indicated by vertical lines that separate the intervals when different parts of the function are described.

A) From the given graph we see that, step function has 4 pieces.

B) The step function is composed of 3 intervals: (0, 1), [1, 2), [2, 3), and [3, ∞).

C) When a point is not included in a function, it is indicated by an open circle; when a point is included in a function, it is indicated by a closed circle.

D) Because each input (weight) translates into exactly one output (postage cost), this is a function. In other words, no two weights that are different from one another have the same shipping price.

E) Because each piece of this piecewise function can be represented by a linear equation of the form y = mx + b, where m and b are constants, the pieces of this piecewise function are linear.

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Weight cannot be represented as a function of height.

No, the weight of Karim's friends cannot be represented as a function of their height.

To represent weight as a function of height, there should be a consistent relationship between the height and weight values.

However, from the given data, we can see that for the same height, there are different weight values, and for the same weight, there are different height values.

This indicates that there is no one-to-one relationship between height and weight, and hence weight cannot be represented as a function of height.

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The formula for the general term of the arithmetic sequence is:

a) an = -10 + (n-1) * 6 and first-term = -10

b) an = -10 + (n-1) * 6 and first-term = 6

c) an = 36 + (n-1) * (-5) and first-term = 36

An arithmetic sequence is a sequence of numbers in which each term (after the first) is obtained by adding a fixed number called the common difference, d, to the preceding term. The first term of an arithmetic sequence is denoted by 'a'. The general formula for an arithmetic sequence is:

a, a + d, a + 2d, a + 3d, ...

where 'a' is the first term, 'd' is a common difference, and each term after the first is obtained by adding 'd' to the preceding term.

a) To find the common difference, we subtract any term from the term that comes after it. For example, we can subtract -10 from -4, or 2 from 8, and we get:

-4 - (-10) = 6

8 - 2 = 6

Since both of these subtractions give us the same result, we know that the common difference is d = 6. To find the first term, we can use any term and subtract the product of the common difference and its position in the sequence minus 1. For example, we can use the second term -4 and its position 2 to get:

a = -4 - (2-1) * 6 = -10

Therefore, the formula for the general term of the sequence is:

an = -10 + (n-1) * 6

b) The common difference between consecutive terms is -2 because each term is 2 less than the term before it. To find the first term, we can use any term and add the product of the common difference and its position in the sequence minus 1. For example, we can use the second term 8 and its position 2 to get:

a = 8 + (2-1) * (-2) = 6

Therefore, the formula for the general term of the sequence is:

an = 6 + (n-1) * (-2)

c) The common difference between consecutive terms is -5 because each term is 5 less than the term before it. To find the first term, we can use any term and add the product of the common difference and its position in the sequence minus 1. For example, we can use the second term 31 and its position 2 to get:

a = 31 + (2-1) * 5 = 36

Therefore, the formula for the general term of the sequence is:

an = 36 + (n-1) * (-5)

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Answer:

The answer is 7 pens

Answer: there is only one number

Answer:

Solo hay un número primo que se puede escribir como suma de dos números primos y también como diferencia de dos números primos.

Espero haber ayudado :D

An equation that represents a function that relates the value of Ethan’s car in dollars, g(t), and the time in years since he bought the car.

[tex]g(t) = P * e^{(-rt)[/tex]

Assuming that Ethan's car depreciates in value over time, a commonly used function to model such depreciation is an exponential decay function of the form:

[tex]g(t) = P * e^{(-rt)[/tex]

where:

[tex]g(t) = P * e^{(-rt)[/tex]

where P, r, and t are specific values based on the purchase price and depreciation rate of Ethan's car, as well as the time that has passed since he bought it.

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The prompt on measurement of rooms and surface area is given below. Note that the total surface area of the room is 752 ft².

Therefore, the total surface area of the room is 96 + 96 + 160 + 160 + 120 + 120 = 752 square feet.

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The probability that a rainfall event exceeds the mean by more than 2 standard deviations is approximately 0.0498.

a. The exponential distribution with a mean of 2.725 hours can be expressed as λ = 1/2.725. Using this parameter, we can calculate the probabilities as follows:

P(X ≥ 2) = [tex]e^{(-λ2) }= e^{(-1/2.7252)[/tex] ≈ 0.4800

P(X ≤ 3) = 1 - [tex]e^{(-λ3)} = 1 - e^{(-1/2.7253)[/tex] ≈ 0.6674

P(2 ≤ X ≤ 3) = [tex]e^{(-λ2)} - e^{(-λ3)} = e^{(-1/2.7252)} - e^{(-1/2.7253)}[/tex] ≈ 0.1474

b. The standard deviation of an exponential distribution is equal to the mean, so 2 standard deviations above the mean would be 2*2.725 = 5.45 hours. The probability that a rainfall event exceeds this duration can be calculated as follows:

P(X > 5.45) =[tex]e^{(-λ5.45)} = e^{(-1/2.7255.45)}[/tex] ≈ 0.0498

Therefore, the probability that a rainfall event exceeds the mean by more than 2 standard deviations is approximately 0.0498.

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Complete Question:

Suppose that rainfall duration follows an exponential distribution with mean value 2.725 hours.

a. What is the probability that the duration of a particular rainfall event is at least 2 hours? At most 3 hours? Between 2 and 3 hours? (.4800, .6674, .1474)

b. What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations? (.0498)

The correct option a. may.The data shown in the may histogram is more centered around a high peak.

A graph called a histogram is used to show the frequency distribution of a small number of data points for a single variable.

For the given two histograms,

May has the peak value for the frequency of day at 14.

July has the peak value for the frequency of day at 10.

Thus, The data shown in the may histogram is more centered around a high peak.

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Complete question-

which data set is more centered around a high peak??

a. may

b. july

c. neither

d. both

The diagram for the question is shown.

The value of z is 14.

What is the fraction?

A fraction is a mathematical representation of a part of a whole, where the whole is divided into equal parts. A fraction consists of two numbers, one written above the other and separated by a horizontal line, which is called the fraction bar or the vinculum.

To solve for z, we can start by cross-multiplying the fractions, which gives:

5z = 14 * 25

Simplifying the right side, we get:

5z = 350

Finally, we can solve for z by dividing both sides by 5:

z = 70/5

Simplifying the right side, we get:

z = 14

Therefore, the value of z is 14.

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The complete question:

Solve for the value of z: 14/5 = z/25

When we compare this to the options provided, we can see that the equation is: a. y = -x²/2+x+1. The answer is (a) y = -x²/2+x+1.

A parabola's equation can take many different forms, such as vertex form, standard form, or intercept form, depending on its particular shape and orientation.

The parabola's typical vertex form equation is y = a(x - h)² + k

We must locate the vertex form of the parabola in order to get its equation, which is:

y = a(x - h)² + k

Using to determine the vertex

h = -b/2a

To begin, we can locate the vertex:

(-1,0) (1,1.5) (3,0) (-2, -3) (4,-3) (-3,-6) (5,-6)

In order to average the x-values of the two sets of x-intercepts, the vertex must be halfway between the parabola's x-intercepts:

h = (-1 + 3)/2 = 1

The vertex and another point can then be used to find the value of "a":

y = a(x - 1)² + k

Using the point (4, -3):

-3 = a(4 - 1)² + k

-3 = 9a + k

Using the point (1, 1.5):

1.5 = a(1 - 1)² + k

1.5 = k

k = 1.5 is substituted into the second equation:

-3 = 9a + 1.5

-4.5 = 9a

a = -0.5

y = -0.5(x - 1)² + 1.5

When we multiply the equation, we get:

y = -0.5x² + x + 1

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1. The equation she was supposed to solve was sin(x) = cos(2x), but she mistakenly added an extra "= 0" term.

2. The correct answers are x = π/6 and x = 5π/6.

To find the correct answers, we will solve the correct trigonometric equation sin(x) = cos(2x).

Since cos(2x) = 1 - 2sin²(x), the equation becomes:

sin(x) = 1 - 2sin²(x)

Now we can rewrite this equation as a quadratic equation in sin(x):

2sin²(x) + sin(x) - 1 = 0

This equation can be solved using the quadratic formula:

sin(x) = [-b ± sqrt(b² - 4ac)] / 2a

where a = 2, b = 1, and c = -1:

sin(x) = [-1 ± sqrt(1² - 42(-1))] / (2*2)

sin(x) = [-1 ± sqrt(9)] / 4

sin(x) = (-1 ± 3) / 4

There are two possible solutions for sin(x):

sin(x) = 1/2

sin(x) = -1

For sin(x) = 1/2, we have:

x = π/6, 5π/6

For sin(x) = -1, there is no solution in the interval 0 < x < 2π because the sine function does not reach -1 within this range.

So the correct answers are x = π/6 and x = 5π/6.

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Answer:see below

Step-by-step explanation:

10.600

11.80000

12.17

13.48

14.4000

21. 1km=100m;0.5km=500m;0.1km=100m

22.50m=5000cm; 5m=500cm; 0.5m=50cm

This means that we can be 95% confident that the true population means examination score falls within this range based on the sample data.

The confidence interval estimate of the population means examination score can be calculated using the sample mean and the margin of error. The margin of error depends on the level of confidence and the sample size.

For example, if a sample of 100 applications provided a sample mean score of 80, and a 95% confidence level is used, the confidence interval estimate of the population mean examination score would be:

Margin of error = (critical value) x (standard error)

The critical value for a 95% confidence level with 99 degrees of freedom is 1.984. The standard error can be calculated using the formula:

Standard error = (standard deviation) / sqrt(sample size)

If the standard deviation of the examination scores is known, it can be used in the formula. If not, the sample standard deviation can be used as an estimate.

Assuming a sample standard deviation of 10, the standard error would be:

[tex]Standard\  error = \frac{10} { \sqrt{(100)}} = 1[/tex]

Therefore, the margin of error would be:

Margin of error = 1.984 x 1 = 1.984

The confidence interval estimate of the population means examination score would be:

80 ± 1.984, or between 78.016 and 81.984.

This means that we can be 95% confident that the true population means examination score falls within this range based on the sample data.

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The 95% confidence interval for the population mean examination score would be between 72.23 and 77.77, to the

nearest whole number.

To determine the confidence interval estimate of the population mean examination score based on a sample mean

provided to the nearest whole number, we need to know the sample size and the level of confidence.

Assuming a normal distribution and a level of confidence of 95%, we can use the following formula to calculate the

confidence interval estimate:

Confidence interval = sample mean +/- (critical value) x (standard error)

The critical value can be found using a t-distribution table or a calculator, based on the sample size and degrees of

freedom (n-1). For a sample size of 30 or more, we can use the z-score instead of the t-score.

The standard error is the standard deviation of the sample divided by the square root of the sample size.

For example, if a sample of 50 applications provided a sample mean of 75, and the standard deviation was 10, the

standard error would be 10/sqrt(50) = 1.41.

Assuming a level of confidence of 95%, the critical value for a sample size of 50 and degrees of freedom of 49 would be 1.96.

Therefore, the confidence interval estimate would be:

75 +/- 1.96 x 1.41 = 75 +/- 2.77

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The probability that no more than 4 of the next 10 households that a student visits will purchase a raffle ticket is 1%.

Probability refers to the likelihood or chance of a particular event occurring, and it is usually expressed as a number between 0 and 1. An event with a probability of 0 is impossible, while an event with a probability of 1 is certain.

For example, if you toss a fair coin, the probability of getting heads is 0.5, and the probability of getting tails is also 0.5. If you roll a fair six-sided die, the probability of rolling a 6 is 1/6, and the probability of rolling any other number is also 1/6. Based on the information, the correct option is C.

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To determine if each ordered pair is a point of intersection between the line x - y = 6 and the circle y² - 26 = -x², we need to substitute the values of x and y in both equations and see if they are true for both.

For the ordered pair (1, -5):

x - y = 6 becomes 1 - (-5) = 6, which is true.

y² - 26 = -x² becomes (-5)² - 26 = -(1)², which is false.

Therefore, (1, -5) is not a point of intersection.

For the ordered pair (1, 5):

x - y = 6 becomes 1 - 5 = -4, which is false.

y² - 26 = -x² becomes (5)² - 26 = -(1)², which is true.

Therefore, (1, 5) is a point of intersection.

For the ordered pair (5, -1):

x - y = 6 becomes 5 - (-1) = 6, which is true.

y² - 26 = -x² becomes (-1)² - 26 = -(5)², which is false.

Therefore, (5, -1) is not a point of intersection.

So the answer is:

(1,-5) - No

(1,5) - Yes

(5,-1) - No

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Answer:

75%

Step-by-step explanation:

We are given that Sara bought a chest for $42, and then sold it for $73.50.

Recall that when finding by how much something was marked up, you should use the following formula:

(new price-original price)/(original price)

Let's substitute the values, like so:

[tex]\frac{73.50-42}{42}=\\\\ \frac{31.50}{42}[/tex]

Now, set up a proportion to find what this fraction is as a percentage:

[tex]\frac{31.5}{42} =\frac{x}{100} =\\42x=3150=\\x=75[/tex]

So, the price was marked up by 75%.

Answer:

Step-by-step explanation:

5989.87

Answer:

4028

Step-by-step explanation:

Answer:

4028

Step-by-step explanation:

You need to subtract 9,755 from 13,783 on a calculator and you get your answer.hope it helps

The statement that is true about Evan's expression is that it represents a linear function of the amount of medicine in his bloodstream, where the initial amount is 100 milligrams and the rate of change is -0.4 milligrams per minute.

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

The expression 100 - 0.4m represents the amount of medicine in Evan's bloodstream after m minutes, where the amount of medicine decreases by 0.4 milligrams each minute.

The coefficient of the variable m (-0.4) represents the rate of change of the amount of medicine in Evan's bloodstream per minute. It tells us that for every one minute that passes, the amount of medicine in his bloodstream decreases by 0.4 milligrams.

The constant term (100) represents the initial amount of medicine in Evan's bloodstream before the medicine starts to decrease.

Therefore, the statement that is true about Evan's expression is that it represents a linear function of the amount of medicine in his bloodstream, where the initial amount is 100 milligrams and the rate of change is -0.4 milligrams per minute.

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