Answer:
(a) The time the ball stays in the air is approximately 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters
(c) The maximum altitude of the ball is approximately 26.62 m
Explanation:
The given parameters of the question are;
The initial velocity at which a baseball cannon fires balls, u = 29 m/s
The angle at which the cannon is tilted, θ = 52°
(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;
[tex]2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}[/tex]
Where;
t = The time it takes the baseball to reach maximum height
2·t = The total time of flight = The time the ball stays in the air
θ = The angle at which the ball is tilted = 52°
g = The acceleration due to gravity ≈ 9.81 m/s²
u = The initial velocity = 29 m/s
Therefore, we have;
[tex]2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s[/tex]
The time the ball stays in the air, 2·t ≈ 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;
[tex]Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]
∴ The distance from the cannon at which the ball will hit the ground = R
[tex]Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m[/tex]
The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters
(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;
[tex]H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}[/tex]
Therefore, we have;
[tex]H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m[/tex]
The maximum altitude of the ball ≈ 26.62 m
A spherical conducting shell has charge -5 C. A particle with charge -8 C is placed at the center of the cavity. The charges (in C) on the inner surface and on the outer surface of the shell, respectively, are:
Answer:
Explanation:
The charge of - 5C will be spread on the outer surface of the shell . The presence of - 8C charge at the Centre will create + 8C charge on the inner surface and - 8C charge on the outer surface . The result is that the total charge on the outer surface of the shell will be - 5C + - 8C = - 13C and the inner surface will have charge of + 8C . + 8C charge will be locked to centrally situated - 8C charge and will not be neutralized by negative charge of outer surface .
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
a) 35m/s north
b) 35m/s south
c) 81 m/s north
d) 81 m/s south
Research and define pressure, as it relates to air or water pressure.
Answer:
PRESSURE is a force exerted by the substance per unit area on another substance.
The key difference between water pressure and air pressure is that one is made up of water and the other is made up of air. Both air pressure and water pressure are based on and follow the same physical principals.
Explanation:
How much acceleration does a car need if it is to go a distance of 620 ft. In a time of 20 sec while it is speeding up
Calculate the first and second velocities of the car with three washers attached to the pulley, using the formulas
v1 = 0.25 m / t1, and
v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.
What is the first velocity of the car with three washers at the 0.25 meter mark?
m/s
What is the second velocity of the car with three washers at the 0.50 meter mark?
m/s
Answer:
0.19 and 0.45
Explanation:
edge
The first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.
What is velocity?The velocity of an object is defined as the product of the distance travelled in a given direction and the time required to travel that distance. The velocity is expressed mathematically as,
v = d/t
Here, d represents the travelled distance.
And t is the typical amount of time needed to go the distance.
Given,
The value of the first distance is, d1 = 0.25 m.
The value of the second distance is, d2 = 0.50 m.
Then the first velocity of the car at 0.25 m is,
[tex]v_1 = d_1/t_1\\v_1 = 0.25 / t_1[/tex]
Thus,[tex]t_1[/tex] denotes the first distance's typical time.
The second velocity of the car with three washers at the 0. 50 m mark is
[tex]v_2 = d_2/t_2\\v_2 = 0.50 /t_2[/tex]
Here, [tex]t_2[/tex] stands for the second distance's typical time.
Thus, the first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.
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Light waves travel at 3 × 10 8 m/s. If the light wave has a particular wavelength of 400 nm (400 × 10 –9 m), calculate its frequency.
Answer:
[tex]f=7.5\times 10^{14}\ Hz[/tex]
Explanation:
Given that,
The wavelength of light, [tex]\lambda=400\ nm=400\times 10^{-9}\ m[/tex]
The speed of light, [tex]c=3\times 10^8\ m/s[/tex]
We need to find the frequency of light. We know that,
[tex]c=f\lambda[/tex]
Where
f is the frequency
So,
[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{400\times 10^{-9}}\\\\f=7.5\times 10^{14}\ Hz[/tex]
So, the frequency of light is [tex]7.5\times 10^{14}\ Hz[/tex].
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.
Answer:
Velocidad final, V = 8 m/s
Explanation:
Dados los siguientes datos;
Velocidad inicial, u = 4 m/s
Aceleración, a = 2 m/s²
Tiempo, t = 2 segundos
Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;
V = u + at
Sustituyendo en la fórmula, tenemos;
V = 4 + 2*2
V = 4 + 4
Velocidad final, V = 8 m/s
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
I am soooooooooooo desperate.
Answer:
the answers the correct one is C
Explanation:
In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.
expressed this mathematically is
N = N₀ [tex]e^{- \lambda t}[/tex]
for the average life time
N₀ / 2 = N₀ [tex]e^{- \lambda T_{1/2}[/tex]
T =[tex]\frac{ln 2x}{ \lambda}[/tex]
Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.
when checking the answers the correct one is C
How do you get DC current and AC current? from a generator?
Answer:
They do that by converting rotating mechanical energy into electrical power. Portable generators use an engine—typically running on gasoline, diesel, or propane, to turn an alternator which produces alternating electrical current or AC.
help please
which of the following reacts with most metals to form Hydrogen gas
A.acids
B.Bases
C.acids&bases
Answer:
acid and bases
Explanation:
HOW TO ANSWER THIS QUESTION PLEASE
Answer:
radioactive decay is a random processuse long tongsExplanation:
Quantum theory has taught us that virtually everything to do with the nature of matter in the universe is a random process. The decay of atomic nuclei is something that makes that randomness "visible" with appropriate instrumentation. As such, the rate of decay will vary over the "short" term. Consequently, it is not surprising to see a variation of a few counts in an activity measurement over a period of a few minutes.
__
Safety with respect to radioactive materials involves staying as far away from them as possible. The use of long tongs for handling would be appropriate.
Answer:
Radioactive decay is a long proxyUse long tongs↔ for safety precautions the scientist should used this upon working with radioactive materials in a laboratory.
If you walk for 1.5 hours at an average speed of 4 miles/hr. How far will you have walked?
Light waves Group of answer choices are not electromagnetic radiation. do not require a medium. can not travel in a vacuum. do not travel in straight lines from the source.
Answer:
do not require a medium
Explanation:
Light waves can be regarded as electromagnetic waves and it transverse in nature, no medium material is required to pass through. Light wave can travel through vacuum and it's ray can travel in straight lines even from point source. Light convey energy in perpendicular direction to electric field as well as magnetic field.
Define centre of mass.
Answer:
The center of mass is a position defined relative to an object or system of object
Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
Answer:
Newton's second law of motion?
Two train cars with the same mass (30,000 kg) are traveling in the same direction when they collide.
Train Car A has a velocity of 10 m/s and Train Car B has a velocity of 5 m/s. What is their total
momentum after the collision? Make sure to show all your work and include proper units.
Answer:
25
Explanation:
I just did this
A plastic rod is rubbed with a cloth and becomes positively charged. After charging, the rod is held close to the suspended table-tennis ball shown in Fig. 9.1. The table-tennis ball is covered with metal paint and is uncharged.
Describe what happens to the charges on the metal-painted table-tennis ball as the positively-charged rod is brought close to the ball.
A stationary hockey puck has a mass of 0.27 kg. A hockey player uses her stick to apply a 18 N force over a distance of 0.42 m. How much work does this force do on the puck?
Group of answer choices
7.6 J
-43 J
-7.6 J
28 J
43 J
If a chemical reaction has a AH value of -125 kJ, it would be considered what?
A. an exothermic reaction
B. a reaction that absorbs energy
C. an endothermic reaction
D. A reaction that probably gets cold
exothermic
Explanation:
negative means it's losing energy
PLZ HELP I DONT KNOW THIS ONE
Some ancient objects have been well-preserved in high mountain ranges,
where the concentration of oxygen is low. Otzi the Iceman lived more than
5,000 years ago. Archaeologists found him with his leather pouch, clothes,
and tools perfectly preserved in the ice of the Alps.
Marie's mother lost a leather purse in the yard of their house in Florida, where
the air has more oxygen. Marie found it 30 years later under a tree. It was
rotted and decayed.
Review the information in the data table. What does this information tell you
about the rate of decay reactions relative to the concentration of oxygen?
Answer:
yeah
Explanation:
The information tells you about the rate of decay is that in Florida the reaction occurs more slowly when there is less oxygen in the air.
What is the rate of decay?The reduction in the number of radionuclides per unit time is the rate of decay.
The following table shows that the rate of decay only depends upon the level of oxygen. In Florida concentration of the oxygen in the air is high
Due to this the decay time is less.
The decay time is inversly propotional to the rate of decay. In Florida the rate of decay is high.
Hence the information is that reaction occurs more slowly when there is less oxygen in the air.
To learn more about the rate of decay refer to the link;
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what type of beetle is this?
Find the electric field a distance z above the midpoint between equal and opposite charges,a distance d apart
Answer:
Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex] , E_z =0
Explanation:
To find the electric field of each charge, let's use
E = k q / r²
where the field for a positive charge is outgoing and for a negative charge it is incoming.
Since the electric field is a vector magnitude, let's add its components at the point z
X axis
Eₓ = E₁ₓ + E₂ₓ
Eₓ = 2 E₁ₓ
Z axis
E_z = E_{1z} -E_{2z}
E_z= 0
Let's find the expression for the electric field
the distance from the charge to the test point, using the Pythagorean theorem is
r² = (x-0) ² + (0-z) ²
E = [tex]k \frac{q}{x^2 + z^2}[/tex]
with trigonometry we can find its components
cos θ = E₁ₓ / E
E₁ₓ = E cos θ
we substitute
Eₓ = 2 E cos θ
where the cosine
cos θ = x / r
Ex = [tex]2 k \frac{q}{x^2 + z^2} \ \frac{x}{\sqrt{x^2 + z^2} }[/tex]
Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex]
E_z = 0
A force of 20 N acts upon a 5000g block. Calculate the acceleration of the object
Answer:
a = 4 m/s²
Explanation:
Given: 5000 g, 20N
To find: Acceleration (a)
Solution: Firstly, convert 5000g to kilograms
1000g = 1kg
∴ 5000g = 5kg if divided by 1000
A = F ÷ m
= 20 ÷ 5
= 4 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
A toy train moves round a circular track of radius 0.50 m.
How many radians has the trained turned through in moving 1.4 m along a track?
Answer:
2.8 radians
Explanation:
[tex]s = r \beta \\ 1.4 = 0.50 \beta \\ \beta = 2.8 \: rad[/tex]
Need help pls. It is for acellus
Answer:
The height of the water column = 1.62405[tex]\overline{30}[/tex] × 10⁻¹ m
Explanation:
The air cavity in the Coke bottle = 0.220 m deep
The fundamental (frequency) it plays when water is added to shorten the column and it is blown across the top, f = 528 Hz
The given speed of sound in air, v = 343 m/s
We note that the air cavity in the coke bottle is equivalent to a tube closed at one end
The fundamental frequency for a tube closed at one end, 'f', is given as follows;
f = v/(4·L) = v/λ
Where;
L = The height of the water column
λ = The wavelength of the wave
∴ 4·L = v/f = (343 m/s)/(528 Hz) = 0.6496[tex]\overline{21}[/tex] m
∴ L = 0.6496[tex]\overline{21}[/tex] m/4 = 0.162405[tex]\overline{30}[/tex] m
The height of the water column = 1.62405[tex]\overline{30}[/tex] × 10⁻¹ m.
Answer:
0.058
Explanation:
got it right on acellus
A spring has an unstretched length of
12.0 cm. Its stiffness k is 8 N/cm. What load is
needed to stretch the spring to a length of 15.0 cm?
Answer:
24 N
Explanation:
Given,
Unstretched length or original length , x1 = 12cm
Stiffness constant, k = 8 N/cm
Load required to take spring to a length , x2 of 15cm
Recall the relation :
F = Ke
Where, e = extension
e = x2 - x1
e = (15 - 12) = 3
F = ke
F = 8 N/cm * 3cm
F = 24 N/cm*cm
F = 24 N
Hence, required load = 24 N
An eighth-grade class is studying the motion of objects. They have learned the following concepts about motion.
Motion occurs when there is a change in the position of an object with respect to a reference point.
While the speed of the object may change at various times during a trip the average speed for the trip is found by dividing the total distance by the total time.
The motion of the object can be changed by varying the amount of net force acting on the object or by varying the mass of the object.
The teacher asked students to design investigations to determine how changing the forces acting on an object or the mass of the object would change its motion.
The materials for the investigation included:
1 - toy cart
3 - 10N weights
1 - pulley
2 - meters of string
One group of students decided to design an investigation to determine how different amounts of mass on the toy cart would affect the speed of the toy cart. They set up their investigation as shown below:
The students performed several trials using different masses in the toy cart (M1). They hung a mass shown as (M2) to pull the toy cart as it dropped.
Below is a table they made to record their results.
Which of the following would be a way to test the effect changing the amount of force acting on the object has on the average speed of the object?
Move the cart at various speeds and determine the force at M1
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
Move the cart at various speeds and determine the force exerted by M2
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
How to test the effect of weight on the speed of object?In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.
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hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N
Answer:
i'll answer your question but follow me first
What are two ways fission is used in the real world.
Answer:
germ cleaning
and getting up cooking grease
Explanation:
Work done depends on
A. Force
B. Displacement
C. Both force and displacement
D. Neither force nor displacement
Answer:
C. Both force and displacement
Explanation:
Hope this helps