Mathematics College

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For the class picnic, 25 liters of punch were purchased. 6 liters were left over. How many gallons of punch were used at the picnic? (1 liter is approximately 0.26 gallons)

Answers

Answer 1

Answer:

Gallons of punch used = 4.94 gallons

Step-by-step explanation:

Given that:

Liters of punch purchased = 25 liters

Liters of punch left over = 6 liters

Liters of punch used = 25 - 6 = 19 liters

According to the given statement;

1 liter = 0.26 gallons

19 liters = 0.26*19 gallons

19 liters = 4.94 gallons

Hence,

Gallons of punch used = 4.94 gallons

Related Questions

Solve x4 - 11x2 + 18 = 0.

Answers

Answer:

x=√2, x=-√2, x= 3 and x=-3

Step-by-step explanation:

We need to solve the equation x^4 - 11x^2+18=0  

We can replace x^4 = u^2 and x^2 = u

So, the equation will become

u^2 -11u+18 = 0

Factorizing the above equation:

u^2 -9u-2u+18 =0

u(u-9)-2(u-9)=0

(u-2)(u-9)=0

u=2, u=9

As, u = x^2, Putting back the value:

x^2 =2 , x^2 =9  

taking square roots:

√x^2 =√2 ,√x^2=√9  

x=±√2 , x = ±3

so, x=√2, x=-√2, x= 3 and x=-3

Answer:

The second answer is correct.

Step-by-step explanation:

Mark brainliest if correct please

Asphere has a radius of 27 inches. A horizontal plane passes through the center of the sphere.
Part 1 out od 2
Describe the cross section formed by the plane and the sphere.

Answers

9514 1404 393

Answer:

  circle of radius 27 inches

Step-by-step explanation:

Anywhere a plane cuts a sphere, the cross section is a circle. When the plane includes the center of the sphere, the circle has the same radius the sphere has.

The cross section is a circle of radius 27 inches.

Luis solves the following system of equations by elimination.
5s+ 3t = 30
2s+3t=-3
What is the value of s in the solution of the system?

Answers

the value of s is 11

X^9/7 convert from exponent form to radical form

Answers

Answer:

[tex]x^{\frac{9}{7}} = \sqrt[7]{x^9}[/tex]

Step-by-step explanation:

You can solve this by realising that the denominator of a fractional exponent can be expressed as the base of a radical.

Note also that the order does not matter.  You could also express it as

[tex]\sqrt[7]{x}^9[/tex]

The reason this works is that you're effectively breaking the exponent into fractions.  The first answer is the equivalent of:

[tex](x^9)^{1/7}[/tex]

and the second would be:

[tex](x^{1/7})^9[/tex]

In both cases, the exponents would be multiplied, giving the same result.

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