Please look at the photo

Answer:

[tex]\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}[/tex]

Step-by-step explanation:

Incomplete question:

[tex]\angle CBD = 53^\circ[/tex]

[tex]\angle CAB = 35^\circ[/tex]

[tex]AB = 75[/tex]

See attachment for complete question

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

[tex]\angle ABC + \angle CBD = 180[/tex] --- angle on a straight line

[tex]\angle ABC + 53= 180[/tex]

Collect like terms

[tex]\angle ABC =- 53+ 180[/tex]

[tex]\angle ABC =127^\circ[/tex]

[tex]\angle ABC + \angle ACB + \angle CAB = 180[/tex] --- angles in a triangle

[tex]\angle ACB + 127 + 35 = 180[/tex]

Collect like terms

[tex]\angle ACB =- 127 - 35 + 180[/tex]

[tex]\angle ACB =18[/tex]

Apply sine rule

[tex]\frac{\sin A}{a} = \frac{\sin B}{b}[/tex]

In this case:

[tex]\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}[/tex]

This gives:

[tex]\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}[/tex]

Step-by-step explanation:

sin18

∘

)

=

x

(sin35

∘

)

Step-by-step explanation:

Incomplete question:

\angle CBD = 53^\circ∠CBD=53

∘

\angle CAB = 35^\circ∠CAB=35

∘

AB = 75AB=75

See attachment for complete question

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

\angle ABC + \angle CBD = 180∠ABC+∠CBD=180 --- angle on a straight line

\angle ABC + 53= 180∠ABC+53=180

Collect like terms

\angle ABC =- 53+ 180∠ABC=−53+180

\angle ABC =127^\circ∠ABC=127

∘

\angle ABC + \angle ACB + \angle CAB = 180∠ABC+∠ACB+∠CAB=180 --- angles in a triangle

\angle ACB + 127 + 35 = 180∠ACB+127+35=180

Collect like terms

\angle ACB =- 127 - 35 + 180∠ACB=−127−35+180

\angle ACB =18∠ACB=18

Apply sine rule

\frac{\sin A}{a} = \frac{\sin B}{b}

a

sinA

=

b

sinB

In this case:

\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}

AB

sinACB

=

x

sinCAB

This gives:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

75

(sin18

∘

)

=

x

(sin35

∘

)

Divide the figure into 3 shapes: 2 rectangles and 1 square

Area of rectangle 1: L * W

L = 5, W = 2

2 * 5 = 10 m^2

Area of rectangle 2: L * W

L = 6 + 2 , W = 3

8 * 3 = 24 m^2

Area of square: s^2

2^2 = 4 m^2

Add all them together

10 + 24 + 4 = 38 m^2

Step-by-step explanation:

Area of the top Horizontal Rectangle =

Length x Width

=

[tex](5 + 3 + 2) \times 2 \\ = 10 \times 2 \\ = 20 {m}^{2} [/tex]

Area of the bottom vertical rectangle =

Length x Width

=

[tex]6 \times 3 \\ = 18 {m}^{2} [/tex]

Total Area = Sum of Area of 2 Rectangles

=

[tex]20 + 18 \\ = 38 {m}^{2} [/tex]

Answer:

600 ft

Step-by-step explanation:

Mark as brainilest

And I'm only 80% sure that is the correct

Answer:

Answer:

1 A 2 A 3 an 4 A 5 Their 6 a, Their 7 they'er 8 there

Step-by-step explanation:

Answer:

Suppose we have a system of two linear equations, this can be written as:

y = a*x + b

y = c*x + d

Now, we have 3 possible cases here.

The solutions of the system are the points where the graphs of the linear equations do intersect.

Then, if for example, we have two parallel lines (two parallel lines never intersect) we have no solutions.

And we know that two lines are parallel if they have the same slope and different y-intercept.

Then the system:

y = a*x + b

y = a*x + c

has no solutions.

If we have both equal lines, then the lines intersect in infinitely many points, meaning that we have infinite solutions, then the system:

y = a*x + b

y = a*x +b

has infinite solutions.

And if the lines intersect only one time we have one solution, and this happens when the slopes are different, so the system:

y = a*x + b

y = c*x + d

has only one solution.

Now, if we have more equations:

y = a*x + b

y = c*x + d

y = k*x + n

We have more equations than variables, then this system only has one solution of the 3 lines intersect at the same point, which is really rare.

One case where we have a solution here is if the 3 equations have the same y-intercept:

y = a*x + b

y = c*x + b

y = d*x + b

where the solution is the point (0, b)

Of course, there are other possible solutions, but these are not as formulaic as this ones.

Answer:

printf(“%d”, i++);

Step-by-step explanation:

Answer:

count += 1

OR

count = count + 1

Step-by-step explanation:

count = 0

numbers = int(input("Enter a number: "))

while number > 0:

    number = number // 10

    count +=1

print("Total number of digits", count)

Answer:C

Step-by-step explanation:332 square in

Answer:

The answer is C, 332 in.2.

Step-by-step explanation:

Just did the unit test on edge. Hope this was able to help, have a good day <3 :)

Given:

The line passes through the points (2,0) and (4,3).

To find:

The point-slope form of the given line.

Solution:

The point slop form of a line is:

[tex]y-y_1=m(x-x_1)[/tex]

Where, m is the slope and [tex](x_1,y_1)[/tex] is the point.

The line passes through the points (2,0) and (4,3). So, the slope of the line is:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\dfrac{3-0}{4-2}[/tex]

[tex]m=\dfrac{3}{2}[/tex]

The slope of the line is [tex]m=\dfrac{3}{2}[/tex] and the point is (4,3). So, the point slope form of the given graphed line is:

[tex]y-3=\dfrac{3}{2}(x-4)[/tex]

Therefore, the point slope form of the given line is [tex]y-3=\dfrac{3}{2}(x-4)[/tex].

Answer:

Two packs of buns and three hotdog packages

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

To find the diameter, use the diameter formula.

d = 2r (r = radius)

In this case, we don't have a radius so to find the radius, use the radius formula.

r = [tex]\sqrt{A/\pi }[/tex] (A = area)

So, r = square root of 132.7/pi

r is approximately 6.5

Now we have the radius so we can find the diameter:

d = 2(6.5)

d = 13

Diameter is 13

The diameter of the circle is 13 cm.

A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the centre.

The formula for the area of a circle is A = πr², where A is the area and r is the radius.

We are given the area of the circle, A = 132.7 cm²

Let's solve for the radius first:

A = πr²

132.7 = πr²

Divide both sides by π:

r² = 42.2

Take the square root of both sides:

r = 6.5

So the radius of the circle is approximately 6.5 cm.

Finally, the diameter is twice the radius:

d = 2r

= 13 cm.

Therefore, the diameter of the circle is approximately 13 cm.

To learn more on Circles click:

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Answer:

the given value x=13 is not a solution of the inequality

Step-by-step explanation:

we first need to solve this inequality (can treat the inequality like a normal equation to solve it)

5x-17 > 62

5x > 79

x>(79/5)

keep in mind that (79/5)=15.8

so x needs to be bigger than 15.8 in order to satisfy this inequality.

since 13<15.8 when x=13 it does not satisfy the inequality

therefore the given value x=13 is not a solution of the inequality

Answer:

167,772,160

Step-by-step explanation:

-Each term is multiplied by 2-

10, 20, 40, 80, 160, 320, 640, 1,280, 2,560, 5,120, 10,240, 20,480, 40,960, 81,920, 163,840, 327,680, 655,360, 1,310,720, 2,621,440, 5,242,880, 10,485,760, 20,971,520, 41,943,040, 83,886,080, 167,772,160

167,772,160 is the 25th term

Answer:

since, v=a(square) ×h

Step-by-step explanation:

v=a(squate)cm×hcm

v=25(square)cm×6cm

v=625cm×6ccm

v=3,750cm(cube)

Answer:

B keeping his debt above 30% of his credit card limit.

Answer:

1. BC=25

2. DC=30

Step-by-step explanation:

In a parallelogram, pairs of opposite sides are always equal. The side opposite of AD is BC, so if AD=25, BC=25. Likewise, if side AB=30, side DC=30. Of course, this is assuming the shape is a parallelogram. If it is not, there is no way of determining the side lengths.

lmk if im wrong, hope this helps :)

Send us a pciture and we will be able to answer

Answer:  

I do not think any option given can make the ploted box and whisker plot.

Step-by-step explanation:

Reason for that is

Most left  part of left side  in your case red point on left side  represents the start of your data ... lowest  number of given data set

Like that   Most right part of right side  in your case red point on right  side  represents the End  of your data  ....means the hightest number of data  

on left side where the box starts it indicates the  lower quartile That is Q1  while  from where the box starts on right side it indicates the upper quartiles Q3 and there will be a line in somewhere in box that  represents  the medians of given data .  

Step-by-step explanation:

#44 y = 180-122 = 58

x = (180-58)/2 = 61

Answer:

a) b ≈ 100

b) m ≈ 30

Step-by-step explanation:

Answer:

pretty sure that's C

Step-by-step explanation:

Step-by-step explanation:

1. Formula for simple interest,

[tex]a = p(1 + rt)[/tex]

where

a = Final amount

p = Principal amount

r = annual interest rate

t = time in years

given p = 1250

r = 4.25/100 (r is a raw number, not percentage, so we need to divide 100 here to get the raw number)

t=4

Substitute values into formula to get a.

[tex]a = 1250(1 + (\frac{4.25}{100})(4)) \\ = 1250(1 + 0.17) \\ = 1250(1.17) \\ = 1462.50dollars[/tex]

Let's use the simple interest to calculate Henry's final amount first.

p = 5000

r = 4.2/100

t = 4

[tex]a = 5000(1 + ( \frac{4.2}{100} )(4)) \\ = 5000(1 + 0.168) \\ = 5000(1 .168) \\ = 5840 \: dollars[/tex]

To calculate the interest paid, just use the final amount minus the principal amount

[tex]a - p = 5840 - 5000 \\ = 840dollars[/tex]

Now we will do the exact same method for Ingrid.

p = 5,000

r = 3.9/100

t = 6

[tex]a = 5000(1 + ( \frac{3.9}{100} )(6)) \\ = 5000(1 + 0.234) \\ = 5000(1.234) \\ = 6170 \: dollars[/tex]

[tex]a - p = 6170 - 5000 \\ = 1170dollars[/tex]

Difference in interest between 2 of them =

Interest of Ingrid Loan - Interest of Henry Loan

= 1170 - 840

= $330

Answer:

18.18%

Step-by-step explanation:

66 - 54 = $12

% change - 12/66 * 100

simplify - 12/66 --> 2/11

2/11 * 100

200/11

18.18%

Answer:

x= 30, y= 90

Step-by-step explanation:

Let the smaller number be x and the greater number be y.

Given that the sum of the 2 numbers is 120,

x +y= 120 -----(1)

The greater number is 3 times the smaller number:

y= 3x -----(2)

Substitute (2) into (1):

x +3x= 120

Simplify:

4x= 120

x= 120 ÷4 (÷4 on both sides)

x= 30

Substitute x= 30 into (2):

y= 3(30)

y= 90

Answer:

Let the first number be x

Then the second number will be 3 × x = 3x

According to the question

3x + x = 120

4x = 120

Taking 4 to RHS

x = 120/4

x = 30

Number are

x = 30

3x = 3(30) = 90

[tex] \\ [/tex]

Answer: 4

Step-by-step explanation:

u+3=7

u=7-3

u=4

Answer:

8

Step-by-step explanation:

After 30 minutes Emily and Jennifer charged an equal amount

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

Let us find charges for emily and Jennifer

For Emily

The line passing through points (0, 6) and (6, 8)

Slope =2/6=1/3

y intercept is 6

6=b

Equation is y=1/3x+6

Now let us find for Jennifer (0, 4) and (5, 6)

m=2/5

y intercept is 4

Equation is y=2/5x+4

Now equation both equations

1/3x+6=2/5x+4

1/3x-2/5x=4-6

x(1/3-2/5)=-2

x(5-6)/15=-2

-x/15=-2

x=30

Hence, after 30 minutes Emily and Jennifer charged an equal amount

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Step-by-step explanation:

[tex]y = -\frac{2}{3}x + 4[/tex]

[tex]y = \frac{1}{3}x - 2[/tex]

Since both equations are set equal to [tex]y[/tex], we can take the right-hand side of each equation and set them equal to each other to solve for [tex]x[/tex]:

[tex]-\frac{2}{3}x + 4 = \frac{1}{3}x - 2[/tex]

[tex]-\frac{2}{3}x - \frac{1}{3}x = -2 - 4[/tex]

[tex]-x = -6[/tex]

[tex]x = 6[/tex]

Now we can plug this value into either equation to solve for [tex]y[/tex]:

[tex]y = \frac{1}{3}x - 2[/tex]

[tex]y = \frac{1}{3}(6) - 2[/tex]

[tex]y = 2 - 2[/tex]

[tex]y = 0[/tex]

So the solution to the system of equations is [tex](6, 0)[/tex]

Answer: radius is is 12.

Step-by-step explanation:

Explanation: A circle with equation of the form x2+y2=r2 will have radius r=√144=12 .

Sorry, I'm not sure on the bottom part

We know,

The general equation for circle is –

[tex] { \boxed{\bf{\rm \red {(x \: - \: a)² \: + \: (y \: - \: b)² \: = \: r²}}}} [/tex]

[tex] \bf (a, \: b) \: = \: center \: coordinates [/tex]

[tex] \bf r \: = \: radius [/tex]

[tex] \bf a \: = \: 0 \: , \: b \: = \: 0 \: , \: r \: = \sqrt{144} \: = \: 12 [/tex]

[tex] \bf Center \: coordinates \: = \: (0, \: 0) [/tex] [Answer]

[tex] \bf Radius \: = \: 12 [/tex] [Answer]

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NOTE – Refer the above attachment.

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