Please solve Question 10

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

Answer:

the speed is higher in the PERIHELIUM

Explanation:

As stated in your statement, Kepler's second law says that a vector from the sun to the planet also sweeps equal in equal times. This is a consequence that the sun-planet system is isolated, therefore the angular momentum is conserved.

            L = r x p = m r x v

where m is the planet mass   and the Sun is considered fixed

Let's analyze this expression, if the anglar momentum  is a constant when r is less (perihelion) the speed must increase, so that the product remains fixed

So the speed is higher in the PERIHELIUM

Answer:

It’s C

Explanation:

Answer:

its the area method

Explanation:

i did it on edge nuity and i got it correct.

Answer:

40 Kpa

Explanation:

150 cm2 = 0.015 m2

[tex]p \: = \frac{mg}{ a} = 40000[/tex]

Answer:

24 hours. 365 days

Explanation:

Answer:

ok  a good rest of your day

Explanation:

Answer:

 m = 4.0

Explanation:

For this exercise in geometric optics we will use the equation of the constructor

         [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and image, respectively.

In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]

let's calculate

         [tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6

         [tex]\frac{1}{q}[/tex] = -0.125

         q = -8 cm

the magnification is

        m = - q / p

        m = 8/2

        m = 4.0

Answer:

[tex]1311.5\ \text{Nm}[/tex]

Explanation:

l = Length of ladder = 8.57 m

m = Mass of ladder = 21.4 kg

F = Force on ladder = 258 N

[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Net torque is given by

[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]

The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].

The density of this cement sample is equal to [tex]2727.27\;kg/m^3[/tex]

Given the following data:

To calculate the density of this cement sample​:

First of all, we would determine the volume of the rectangular block.

[tex]Volume = length \times width \times height\\\\Volume = 1.1 \times 2 \times 2.5\\\\Volume = 5.5 \;m^3[/tex]

Now, can calculate the density of this cement sample:

Mathematically, the density of a substance is given by the formula;

[tex]Desnity =\frac{Mass}{Volume}[/tex]

Substituting the values into the formula, we have;

[tex]Density=\frac{15000}{5.5} \\\\Density =2727.27\;kg/m^3[/tex]

Read more: https://brainly.com/question/18320053

Note: 1.1 m, 2 m, 2.5 m are the figures provided from a rectangular block of cement.

Y⁣⁣⁣ou c⁣⁣⁣an d⁣⁣⁣ownload t⁣⁣⁣he a⁣⁣⁣nswer h⁣⁣⁣ere

bit.[tex]^{}[/tex]ly/3a8Nt8n

Answer:

The name given to the underwater mountains in the middle of oceans is;

Mid-ocean ridges

Explanation:

Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.

The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.

Answer:

445N

Explanation:

F=mg

m=44.5kg

g=10m/s2

F=44.5 * 10

=445N

The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.

The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.

The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.

The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.

Learn more about molecules here:-https://brainly.com/question/26044300

#SPJ1

Answer:

Answer:

incomplete question, resistor must be there

Explanation:

Answer:

All the planets in the Solar System orbit the Sun. When planets orbit the Sun, they don’t move around in a perfect circle. They all follow an 'elliptical path', meaning it looks more like an oval.

Explanation:

Answer:no planets orbit the sun in a perfect circle because they travel in a slightly elliptical orbit

Explanation:

Answer:

The answer is "perpendicular and distance".

Explanation:

The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.

The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.

Answer:

0.66 degrees

Explanation:

The computation of the angle of the third dark interference is shown below:

The condition of the minima is

Path difference = (2n +1) × [tex]\lambda[/tex]÷ 2

For third minima, n = 2

Now

xd ÷ D = (2 × 2 + 1) × [tex]\lambda[/tex]÷ 2

d tan Q_3 = 5[tex]\lambda[/tex] ÷ 2

tan Q_3 = 5[tex]\lambda[/tex] ÷ 2d

Q_3 = tan^-1 × (5[tex]\lambda[/tex] ÷2d)

= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)

= 0.66 degrees

Answer:

1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move

2. Mike

Explanation:

According to Newton's second law of motion, force is proportional to te rate of change of momentum produced

Mathematically, we can write the above law as follows;

F = m × a

Where;

F = The force acting on the object

m = The mass of object in motion

a = The acceleration of the object

1. The given parameters in the question are;

The weight of Tim = 311 Newtons (70 lbs.)

The weight of Mike = 50 Newtons (50 lbs.)

The minimum force required to pull the wagon to constant speed = The weight of the wagon

With the assumption that the wagon has very little weight, we have

Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a

Given that mass is proportional to weight, we can write;

Force from mike, Tim on the wagon F₁ = 311 N × a₁

Similarly when they switched places, we have;

Force from Tim, Mike on the wagon  = F₂ = 50 N × a₂

Therefore, for the same force, F₁ = F₂ = F, we have;

a₁ = F₁/(311 N) = F/(311 N)

a₂ = F₂/(50 N) = F/(50 N)

By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁

The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move

2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we  are also given that F₃ > F₁

By Newton's second law of motion, we have;

a₃ = F₃/(50 N) and a₁ = F₁/(50 N)

From F₃ > F₁, we have;

F₃/(50 N) > F₁/(50 N)

Therefore;

a₃ > a₁

The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike

Therefore, Mike is on the wagon when it has the greatest acceleration.

Answer:

False. Temperature is independent of volume

Answer: the answer False sorry if its wrong

Explanation: have a nice day\night buddy

Answer:

Thrust = 200 N

Explanation:

The engine thrust can be found by using the following formula:

[tex]Thrust = mv[/tex]

where,

m = mass flow rate of the fuel = 0.05 kg/s

v = velocity of ejected gases = 4000 m/s

Therefore, using the given values in the equation, we get:

[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]

Thrust = 200 N

Answer:

Wavelength of light wave = 0.6 m

Explanation:

Given:

Frequency of wave = 5 x 10⁸

Speed of light = 3 x 10⁸ m/s

Find:

Wavelength of light wave

Computation:

The size of a wave form is its spatial duration, or the duration in which the wave's form repeats.

Wavelength of light wave = Speed of light / Frequency of wave

Wavelength of light wave = [3 x 10⁸] / [5 x 10⁸]

Wavelength of light wave = 0.6 m

Answer:

The range is 17.32 m

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Initial velocity (u) = √2g

Acceleration due to gravity (g) = 10 m/s²

Range (R) =?

The range can be obtained as follow:

R = u²Sine2θ /g

R = (√2g)²Sine 2θ / g

R = 2g² × Sine (2×30) / g

R = 2g × Sine 60

R = 2 × 10 × 0.8660

R = 17.32 m

Therefore, the range is 17.32 m

Answer:

what is your exact question.

Answer:

vz vc

Explanation:

v b

Answer:

v = 17.30 m / s

Explanation:

For this exercise we will use Newton's second law

at the bottom of the loop and stopped

           ∑ F = 0

           N-W = 0

           N = W

            W = 770 N

the mass of the body is

            W = mg

             m = W / g

            m = 770 / 9.8

            m = 78.6 kg

on top of the loop and moving

           ∑ F = m a

           N + W = m a

note that the three vectors go in the same vertical direction down

the centripetal acceleration is

           a = v² / r

we substitute

           N + W = m v² / r

           v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]

let's calculate

          v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]

          v = 17.30 m / s

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

Answer:

surface tension

Explanation:

because of surface tension in water