pls help me I will give BRANLIEST!!!and follow you back (ー_ー゛)its due in 5minutes
Answers
Answer:
$186.89
Step-by-step explanation:
Let's start by finding the area of the floor.
Area of a trapezium can be found with the formula:
A=(a+b)/2*h
Let's plug our values in.
A=(10+16)/2*7.6
Simplify.
A=26/2*7.6
A=13*7.6
A=98.8
The area of the floor is 98.8 square meters.
Find how many litres of paint are needed.
98.8/1.9=52
He needs 52 liters of paint.
52/5=10.4
He needs 11 5 liter cans of paint.
Each one costs %16.99.
16.99*11=186.89
It would cost $186.89 to buy all the paint he needs.
Related Questions
In one month, the median home price in the Northeast rose from $225,400 to $241,500. Find the percent increase. Round your answer to the nearest tenth of a percent.
Answers
Answer:
7.1%
The percentage increase is 7.1%
Step-by-step explanation:
Percentage increase %∆P is the percentage change in the price.
Percentage increase %∆P = ∆P/Pr × 100%
Where;
∆P = change in sales price = $241,500-$225,400
Pr = regular price = $225,400
Substituting the given values;
%∆P = (241,500-225,400)/225,400 × 100%
%∆P = 7.142857142857% = 7.1%
The percentage increase is 7.1%
22. A parallelogram in which one angle 90° is necessarily:
A. Square
B. rhombus C. rectangle
D.trapezium
Answers
Answer:
C. Rectangle
Step-by-step explanation:
A parallelogram can not have a single 90° angle. This is because the opposite angles of a parallelogram are equal.
Therefore, the two opposite sides are equal.
In a parallelogram, neighboring angles add up to 180°. This therefore implies that all the angles are 90°.
This describes a rectangle.
A chemist is mixing two solutions, solution A and solution B. Solution A is 15% water and solution Bis 20% water. She already has a
beaker with 10mL of solution A in it. How many mL of solution B must be added to the beaker in order to create a mixture that is 18%
water?
Answers
Answer:
15 ml
Step-by-step explanation:
We are told
Solution A = 15% of water
Solution B = 20% of water
Let's assume, the entire solution = 100ml
We are told that in the beaker we have 10 ml of Solution A already
Mathematically,
100 ml = 15%
10 ml = X
100ml × X = 15 × 10
X = 150/ 100
X = 1.5%
Hence in the beaker, we have 1.5% of water from Solution A
We are asked to find how many ml of solution B must be added to make the solution have 18% of water
Let y = number of ml of solution B
Hence
10 ml × 15%(0.15) = 1.5 ml of water - Equation 1
y ml × 20%( 0.20) = 0.20y ml of water ...... Equation 2
Add up the above equation
10ml + y ml ×18% (0.18) = 1.5 + 0.20y
(10 + y)(0.18) = 1.5 + 0.20y
1.8 + 0.18y = 1.5 + 0.20y
Collect like terms
1.8 - 1.5 = 0.20y - 0.18y
0.3 = 0.02y
y = 0.3/0.02
y = 15ml
Therefore,15mL of solution B must be added to the beaker in order to create a mixture that is 18% water
Simplify [tex]$\frac{2\sqrt[3]9}{1 + \sqrt[3]3 + \sqrt[3]9}.$[/tex] $\frac{2\sqrt[3]9}{1 + \sqrt[3]3 + \sqrt[3]9}.$
Answers
Answer:
[tex]3 -\sqrt[2]3[/tex]
Step-by-step explanation:
Given
[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex]
Required
Simplify
Rewrite the given expression in index form
[tex]\frac{2 * 9 ^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 9^{\frac{1}{3}}}[/tex]
Express 9 as 3²
[tex]\frac{2 * 3^2^*^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 3^2^*^{\frac{1}{3}}}[/tex]
[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}}[/tex]
Multiply the numerator and denominator by [tex]1 - 3^{\frac{1}{3}}[/tex]
[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}} * \frac{1 - 3^{\frac{1}{3}}}{1 - 3^{\frac{1}{3}}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) (1 - 3^{\frac{1}{3}})}{(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})(1 - 3^{\frac{1}{3}})}[/tex]
Open the bracket
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2}{3})(3^{\frac{1}{3}})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Simplify the Numerator using Laws of Indices
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2+1}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Further Simplify
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{3}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^1)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Simplify the denominator
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1}{3}})(3^{\frac{1}{3}}) - (3^{\frac{1}{3}})(3^{\frac{2}{3}})}[/tex]
Further Simplify Using Laws of Indices
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1+1}{3}}) - (3^{\frac{1+2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^{\frac{3}{3}}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^1}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3}}[/tex]
Collect Like Terms
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 - 3+ 3^{\frac{1}{3}} - 3^{\frac{1}{3}}+ 3^{\frac{2}{3}} - 3^{\frac{2}{3}} }}[/tex]
Group Like Terms for Clarity
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(1 - 3) + (3^{\frac{1}{3}} - 3^{\frac{1}{3}}) + (3^{\frac{2}{3}} - 3^{\frac{2}{3}} )}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(- 2)+ (0) + (0)}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{-2}}[/tex]
Divide the fraction
[tex]-(3^\frac{2}{3}) + (3)[/tex]
Reorder the above expression
[tex]3 -3^\frac{2}{3}[/tex]
The expression can be represented as
[tex]3 -\sqrt[2]3[/tex]
Hence;
[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex] when simplified is equivalent to [tex]3 -\sqrt[2]3[/tex]
2x^5-x^2+1=0
can you help me ?
slove it in details
thanks
Answers
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Hi my lil bunny!
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[tex]\boxed{x = 7}[/tex]
Move 1 to the left side of the equation by subtracting it from both sides.
[tex]\sqrt{2x -5 - 2 - 1 = 0 }[/tex]
Subtract 1 from -2.
[tex]\sqrt{2x -5 - 3 = 0 }[/tex]
Add 3 to both sides of the equation.
[tex]\sqrt{2x - 5 = 3}[/tex]
To remove the radical on the left side of the equation, square both sides of the equation.
[tex]\sqrt{2x - 5^3 = 3^2}[/tex]
Simplify each side of the equation.
Multiply the exponents in [tex](( 2x - 5) ^\frac{1}{2})^2[/tex] .
Apply the power rule and multiply exponents, [tex](a^m)^n = a^mn[/tex]
[tex](2x -5)^\frac{1}{2}.2 = 3^2[/tex]
Cancel the common factor of 2.
[tex](2x - 5)^1 = 3^2[/tex]
Simplify.
[tex]2x - 5 = 3^2[/tex]
Raise 3 to the power of 2.
[tex]2x - 5 = 9[/tex]
Solve for x
Move all terms not containing x to the right side of the equation.
Add 5 to both sides of the equation.
[tex]2x = 9 + 5[/tex]
Add 9 and 5.
[tex]2x = 14[/tex]
Divide each term by 2 and simplify.
Divide each term in 2x = 14 by 2.
[tex]\frac{2x}{2} = \frac{14}{2}[/tex]
Cancel the common factor of 2.
[tex]x = \frac{14}{2}[/tex]
Divide 14 by 2.
[tex]x = 7[/tex]
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hope this helped you.
Could you maybe give brainliest..?
❀*May*❀
Answer:
root of f(x) = -0.7419124700395855 to about 16 figures
Step-by-step explanation:
given
f(x) = 2x^5-x^2+1 = 0
The polynomial is prime, so cannot solve by factoring.
Since it is a 5th degree polynomial, it has at least one real root.
Graphing helps locate where roots are, if more than one.
(refer to first graph)
So there is a real root between -1 and 0.
We will use numerical methods to find the root to a good degree of accuracy. The technique applies to any univariable function which is differentiable and continuous near the roots. This requirement is true for all polynomials.
However, we must know approximately where the root is, usually found by graphing.
The formula used is a recursive one, which gives a better approximation (x1) from the initial (x0) one , and can be repeated until the required accuracy is reached.
Here, we see that the slope of the function at the root is quite steep, so convergence will be rapid.
The formula is
x1 = x0 - f(x0) / f'(x0), where
x1 = new approximation
x0 = initial (or previous) approximation
f(x0) = value of function when x=x0
f'(x0) = value of derivative of function when x=x0
For the given function
f(x) = 2x^5-x^2+1 = 0
f'(x) = 10x^4-2x = 2x(5x^3-1)
From the graph of f(x), we can take an initial approximation as
x0 = -1
x1 = -1 - (-2)/12 = -5/6
Repeat using x0=-5/6
x1 = -5/6 - ( 2(-5/6)^5 - (-5/6)^2 + 1 ) / (2(-5/6(5(-5/6)^3-1))
= 0.7565596512088784
Repeat again, multiple times
x1 = -0.7423377914518363
x1 = -0.7419128371988212
x1 = -0.7419124700398593
x1 = -0.7419124700395855
x1 = -0.7419124700395855
So we see that the root of f(x) = x1 = -0.7419124700395855 to about 16 figures
Note that the accuracy of the iterations approximately doubles every time.
Find m
A. 82
B. 32
C. 98
D. 107
Answers
Answer: A. 82
Step-by-step explanation:
The measure of <BAD can be found by simply adding 25(<BAC)+57(<CAD) = 82.
[tex]\mathrm{BAD}=\mathrm{BAC}+\mathrm{CAD}=25^{\circ}+57^{\circ}=82^{\circ}[/tex].
Hope this helps.
Determine the settlement set of the following trigonometric equations! cos (x - 1/3π) = cos 1/2π, 0 ≤ x ≤ 2π
Answers
cos (x - π/3) = cos (π/2)
Then we need x - π/3 = π/2
Solving the equation:
x - π/3 = π/2
x = π/2 + π/3
x = 5π/6
Which of the following describes the graph of 2x + 4y < 16? a:solid line, shaded below b:dashed line, shaded above c:dashed line, shaded below d:solid line, shaded above
Answers
Answer: C
Step-by-step explanation:
[tex]2x+4y<16\\=4y<-2x+16\\=y<-\frac{1}{2} x+4[/tex]
Since we are not dividing by a negative at any point during the simplification, the inequality sign won't change.
"<" means that the line will be dashed and shaded below.
Hope this helps!
The description of the inequality is (c) dashed line, shaded below
The inequality is given as:
2x + 4y < 16
The inequality is represented as less than (<)
When the less than sign is used in an inequality, the graph of the inequality would be a dashed line shaded below
Hence, the true statement is (c) dashed line, shaded below
Read more about inequalities at:
https://brainly.com/question/11234618
Please answer in two minutes
Answers
Answer:
Toa
48/55
Step-by-step explanation:
O/A
48/55
Write 59/40 as a decimal
Answers
Answer:
1.475
Step-by-step explanation:
What is the 4th tearm to this?
b(n)=4−6(n−1)
Answers
Answer:
If you wish to find any term (also known as the {n^{th}}n
th
term) in the arithmetic sequence, the arithmetic sequence formula should help you to do so. The critical step is to be able to identify or extract known values from the problem that will eventually be substituted into the formula itself.
Step-by-step explanation:
NEED HELP ASAP WILL AWARD BRAINLIEST!!!!!
Answers
Answer: 69
Step-by-step explanation:
Can anyone help me with this please? And QUICK!
Answers
Answer:
30.6
Step-by-step explanation:
The following data were obtained from the question:
Angle θ = 23°
Opposite = 13
Adjacent = y
The value of y can be obtained by using the following trig ratio:
Tan θ = Opposite /Adjacent
Tan 23° = 13/y
Cross multiply
y × Tan 23° = 13
Divide both side by Tan 23°
y = 13/Tan 23°
y = 30.6
Therefore, the value of y in the diagram above is 30.6
|x–5|=–5 plzz help me
Answers
Answer:
(0-5)=-5
-5-5 = 0
x=0
Step-by-step explanation:
Help please! Thank you
Answers
Step by step
Is
Below
An expression is given -6m+9n-12
Answers
Answer -3(2m-3n+4)
Step-by-step explanation:
calculate EG if a=5 and b=15
Answers
Is y = 75 x + 52 increasing or decreasing.
Answers
Answer:
Increasing if X is positive decreasnig if X is negative
Step-by-step explanation:
Answer:
increasing
Step-by-step explanation:
positive slope of 75 so line goes up to the right
what does 30b/6b equal? (30b divided by 6b)
Answers
Answer:
5
Step-by-step explanation:
Given
[tex]\frac{30b}{6b}[/tex]
Cancel the b on the numerator/ denominator.
Also the 30 and 6 can both be cancelled by 6 , thus
[tex]\frac{30b}{6b}[/tex] = [tex]\frac{30}{6}[/tex] = 5
Answer:
[tex]\boxed{5}[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{30b}{6b}[/tex]
[tex]\sf Simplify[/tex]
[tex]\displaystyle \frac{30}{6} \times \frac{b}{b}[/tex]
[tex]5 \times 1[/tex]
[tex]=5[/tex]
if OA= 3 & AB= 2 what is the ratio of the circumference of the smaller circle to the circumference of the larger circle
Answers
Answer:
(B) 3/5
Step-by-step explanation:
In the figure above, both circles have their centers at point O. Point A lies on segment OB. If OA = 3 and AB = 2, what is the ratio of the circumference of the smaller circle to the circumference of the larger circle?
(A) 2/3
(B) 3/5
(C) 9/16
(D) 1/2
(E) 4/9
Answer: The circumference of a circle is the perimeter of the circle, that is it is the arc length of the circle. The circumference of a circle is given as:
Circumference = 2 π r. Where r is the radius of the circle.
The radius of the bigger circle = length of OB = OA + AB = 3 + 2 = 5
Circumference of the bigger circle = 2 π (5) = 10π
The radius of the smaller circle = length of OA = 3
Circumference of the smaller circle = 2 π (3) = 6π
The ratio of the circumference of the smaller circle to the circumference of the larger circle = circumference of the smaller circle / circumference of the larger circle = 6π / 10π = 3/5
find the value of x in the triangle shown below
Answers
Answer:
46°
Step-by-step explanation:
We can tell that this triangle is an isosceles triangle because 2 of it's sides are the same, therefore, two of it's angles are the same.
Looking at it, we can assume that the two angles not defined (x and the other one) are the two angles that are the same because they look similar.
Now, the angles of all triangles add up to 180°. So, we can subtract 88° from 180 to see what the two angles add up to.
[tex]180-88=92[/tex]
So both of these angles add up to 92 degrees. Since there are two, we divide 92 by 2.
[tex]92 \div 2 = 46[/tex]
Hope this helped!
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answers
Answer:
4x-2
Step-by-step explanation:
4x(3x+5)-2(3x+5)
(4x-2)(3x+5)
you can see that 4x-2 is a factor
Simplify $(1-3i)(1-i)(1+i)(1+3i)$
Answers
[tex](1-3i)(1-i)(1+i)(1+3i)=\\(1^2-(3i)^2)(1^2-i^2)=\\(1+9)(1+1)=\\10\cdot2=20[/tex]
Answer:
[tex]\huge\boxed{(1-3i)(1-i)(1+i)(1+3i)=20}[/tex]
Step-by-step explanation:
[tex](1-3i)(1-i)(1+i)(1+3i)\\\\\text{use the commutative property}\\\\=(1-3i)(1+3i)(1-i)(1+i)\\\\\text{use the associative property}\\\\=\bigg[(1-3i)(1+3i)\bigg]\bigg[(1-i)(1+i)\bigg]\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=\bigg[1^2-(3i)^2\bigg]\bigg[1^2-i^2\bigg]\\\\=\bigg(1-9i^2\bigg)\bigg(1-i^2\bigg)\\\\\text{use}\ i=\sqrt{-1}\to i^2=-1\\\\=\bigg(1-9(-1)\bigg)\bigg(1-(-1)\bigg)\\\\=\bigg(1+9\bigg)\bigg(1+1\bigg)\\\\=(10)(2)\\\\=20[/tex]
You want to buy a new sweater. The regular price was
$48 dollars. The sale price was $34. What was the
percent of discount to the nearest percent?
Answers
Answer:
29%
Step-by-step explanation:
48-34 = 14 dollar saving
14/48 = 29.17 % = 29% saving
Answer:
29%
Step-by-step explanation:
48-34= 14 dollar saving
14/48 = 29.17% = 29% saving
If y is a positive integer, for how many different values of y is RootIndex 3 StartRoot StartFraction 144 Over y EndFraction EndRoot a whole number? 1 2 6 15
Answers
Answer:
2 possible values
Step-by-step explanation:
The given expression is:
[tex]\sqrt[3]{\frac{144}{y} }[/tex]
In order for this to result in a whole number, 144/y must be a perfect cube, the possible perfect cubes (under 144) are:
1, 8, 27, 64, 125
The values of y that would result in those numbers are:
[tex]y=\frac{144}{1}=144 \\y=\frac{144}{8}=18 \\y=\frac{144}{27}=5.333\\y=\frac{144}{64}=2.25\\y=\frac{144}{125}=1.152[/tex]
Only two values of y are integers, therefore, there are only two possible values of y for which the given expression results in a whole number.
Answer:it’s b
Step-by-step explanation:
Just took quiz on edge 2020
PLEASE HELP ASAP!!!
Answers
Answer:
Step-by-step explanation:
Any time you have compounding more than once a year (which is annually), unless we are talking about compounding continuously, you will use the formula
[tex]A(t)=P(1+\frac{r}{n})^{(n)(t)}[/tex]
Here's what we have:
The amount after a certain time that she has in the bank is 4672.12; that's A(t).
The interest rate in decimal form is .18; that's r.
The number of times the interest compounds is 12; that's n
and the time that the money is invested is 3.5 years; that's t.
Filling all that into the formula:
[tex]4672.12=P(1+\frac{.18}{12})^{(12)(3.5)}[/tex] Simplifying it down a bit:
[tex]4672.12=P(1.015)^{42}[/tex] Raise 1.015 to the 42nd power to get
4672.12 = P(1.868847115) and divide to get P alone:
P = 2500.00
She invested $2500.00 initially.
Please can someone help me
Answers
Answer:
706.86 cm
Step-by-step explanation:
=4pi(r^2)
=12.56(r^2)
=12.56(7.5^2)
=12.56(56.25)
=706.86
Can somebody plz help me [-5+(-7)]^2-(7+3)^2
Answers
Answer:
[tex]\boxed{44}[/tex]
Step-by-step explanation:
[tex][-5+(-7)]^2-(7+3)^2[/tex]
Resolving Parenthesis
[tex](-5-7)^2-(10)^2\\(-12)^2-100\\144-100[/tex]
=> 44
Answer:
[tex]\boxed{44}[/tex]
Step-by-step explanation:
[tex][-5+(-7)]^2-(7+3)^2[/tex]
Solve for brackets first.
[tex][-12]^2-(10)^2[/tex]
Solve the exponent or power.
[tex]144-100[/tex]
Subtract the numbers.
[tex]=44[/tex]
Will give the brains of me brains and my brains and maby ur brain to u how many brains can i give u if u ask this quetion right?
Answers
Answer:
$10.5 dollars
Step-by-step explanation:
Keep your brains.
Using the data given:
(18+4+12+8)÷4=
42÷4=
$10.5 dollars
Find the vertical asymptote of f(x)=2x^2+3x+6/x^2-1 I'm having trouble with this one, seems simple tho I just don't want to make a stupid mistake,,, And here are the choices:
Answers
Answer:
x = - 1, x = 1
Step-by-step explanation:
Given
f(x) = [tex]\frac{2x^2+3x+6}{x^2-1}[/tex]
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
x² - 1 = 0 ← difference of squares
(x - 1)(x + 1) = 0
x - 1 = 0 ⇒ x = 1
x + 1 = 0 ⇒ x = - 1
x = - 1 and x = 1 are vertical asymptotes