Plz help answer a - d 1. Miguel is playing a game in which a box contains four chips with numbers written on them two of the chips have the number one one chip has the number three and the other chip has the number 5 Miguel must choose to chips if both chips have the same number he wants to dollars if the two chipsy chooses have different numbers he loses $1 (-$1) Look at pictures for the questions

Answer:   (-5, 5)

Step-by-step explanation:

J = (-3, 1)    K = (-8, 11)          ratio 2 : 3    --> 2 + 3  = 5 segments

x-distance from J to K: -8 - (-3) = -5 units

y-distance from J to K: 11 - 1 = 10 units

Divide those distance into 5 segments:

x = -5/5  = -1 unit per segment

y = 10/5 = 2 units per segment

The partition is 2 segments from J:

x = -3 +2(-1)  = -5

y = 1 + 2(2)   = 5

The partition is located at (-5, 5)

Answer:

5

Step-by-step explanation:

Answer:

The angle measures of the trapezoid consists of two angles of 60º adjacent to the bigger base and two angles of 120º adjacent to the smaller base.

Step-by-step explanation:

A trapezoid is a quadrilateral that is symmetrical and whose bases are of different length and in every quadrilateral the sum of internal angles is equal to 360º. The bigger base has the pair of adjacent angles of least measure, whereas the smaller base has the pair of adjancent angles of greatest measure.

Since the sum of the angles adjacent to bigger base is 120º, the value of each adjacent angle ([tex]\alpha[/tex]) is obtained under the consideration of symmetry:

[tex]2\cdot \alpha = 120^{\circ}[/tex]

[tex]\alpha = 60^{\circ}[/tex]

The sum of the angles adjacent to smaller base is: ([tex]\alpha = 60^{\circ}[/tex])

[tex]2\cdot \alpha + 2\cdot \beta = 360^{\circ}[/tex]

[tex]2\cdot \beta = 360^{\circ} - 2\cdot \alpha[/tex]

[tex]\beta = 180^{\circ}-\alpha[/tex]

[tex]\beta = 180^{\circ} - 60^{\circ}[/tex]

[tex]\beta = 120^{\circ}[/tex]

The angle measures of the trapezoid consists of two angles of 60º adjacent to the bigger base and two angles of 120º adjacent to the smaller base.

Answer:

The  class width is  [tex]C_w \approx 13[/tex]

Step-by-step explanation:

From the question we are told that

 The  upper class limits is [tex]max = 121[/tex]

  The  lower class limits is  [tex]min = 14[/tex]

   The number of classes is  [tex]n = 8 \ classes[/tex]

The class width is mathematically represented as  

       [tex]C_w = \frac{max - min}{n }[/tex]

substituting values

       [tex]C_w = \frac{121 - 14}{8 }[/tex]

       [tex]C_w = 13.38[/tex]

      [tex]C_w \approx 13[/tex]

Since

You did not give any options but i will try to answer.

y < -lxl basically means that the value of y is less than the absolute value of x time - 1.

So if x = 2, then y is any number less than -2.

And if x is -3. then y is any number less than -3.

Happy to help!

Answer: x(x-4) = 140 This equation can be solve to find the length.

Step-by-step explanation:

If the width of the rectangle will be 4 less than the length and the length is represented by x then we could have the equation   w=x - 4 for the width and the length is just x. And to find the area of a rectangle we multiply the length by the with so multiply x-4 by x  for it to equal 140 because 140 is the area.

x(x-4) = 140   solve for x

[tex]x^{2}[/tex] - 4x = 140   subtract 140 from both sides  

x^2 - 4x - 140 = 0  find a number that the product is 140 and the sum is -4

                                  -14 and 10 works out.

[tex]x^{2}[/tex] - 14x + 10x - 140 = 0  factor by grouping

x(x -14)  10(x-14) = 0     factor out x-14

(x-14) ( x+10) = 0         set them both equal zero.

x-14= 0      or   x+10 = 0

x = 14      or x= -10  

Since -10 can't represent a distance, the answer is 14.

Check.  

In this case the length is 14  and if the width is 4 less than the length then we will subtract 4 from 14.

14- 4 = 10  so the width is 10.

14 * 10 = 140

Answer:

Step-by-step explanation:

2.8 kilometers farther. Subtract 12.1km for Winchester and 9.3 for Stamford to get 2.8 kilometers.

Answer:se

Step-by-step explanation:

Answer:

[tex]A. H_o: \mu = 74 ^{\circ} F[/tex]

Step-by-step explanation:

A null hypothesis refers to the hypothesis in which there is no important difference taken place and it is used in statistics and it also does not have any relation between the two measured events or variables  or group association

It can be denoted by

[tex]A. H_o: \mu = 74 ^{\circ} F[/tex]

Therefore the above null hypothesis is the correct answer

Answer:

1/6

Step-by-step explanation:

As we already know that selected bulb is defective the required probability doesn't depend on functional bulbs at all.

The probability, that selected defective bulb is from Box2 is number of defective bulbs in Box 2  divided by total number of defective bulbs.

P(defective in box 2)= N(defective in box 2)/N(defective total)

As we know there is only 1 defective lamp in box 2.

So N(defective in box 2)=1

Total number of defective bulbs is Box1- 2 defective  bulbs,  box2- 1 defective bulbs, box3 - 3 defective bulbs. Total are 6 defective bulbs.

So N(defective total)=6

So P(defective in box 2)=1/6

Answer: :o I FINALLY MADE IT

(5, 2)

x = 5

y = 2

Step-by-step explanation:

First, I graphed both equations.  They meet at the points (5,2) and (2,5).  Because y < 5, the solution is (5, 2)

Hope it helps <3

Answer:

[tex]x=5\\y=2[/tex]

Step-by-step explanation:

[tex]x^2 +y^2 =29[/tex]

[tex]x+y=7[/tex]

Solve for x in the second equation.

[tex]x+y=7[/tex]

[tex]x+y-y=7-y[/tex]

[tex]x=7-y[/tex]

Plug in the value for x in the first equation and solve for y.

[tex](7-y)^2 +y^2 =29[/tex]

[tex]y^2-14y+49+y^2 =29[/tex]

[tex]2y^2-14y+20=0[/tex]

[tex]2(y-2)(y-5)=0[/tex]

[tex]2(y-2)=0\\y-2=0\\y=2[/tex]

[tex]y-5=0\\y=5[/tex]

[tex]y<4[/tex]

[tex]y=2[/tex]

[tex]y\neq 5[/tex]

Plug y as 2 in the second equation and solve for x.

[tex]x+y=7[/tex]

[tex]x=7-y[/tex]

[tex]x=7-2[/tex]

[tex]x=5[/tex]

Answer:

Please check if the answer is a = 4 or not

Answer:

4 plants

Step-by-step explanation:

If betty has $33 dollars and each plant is $8, than 33/8 ≈ 4

(8 * 4 is 32)

She will have one dollar left but she can't buy another plant since that's not enough.

Answer:

4 plants

Step-by-step explanation:

Take the amount of money she has and divide by the cost per plant

33/8

The amount is 4 with 1 dollar left over

4 plants

Answer:  see below

Step-by-step explanation:

[tex]P(x)=\dfrac{2}{3x-1}\qquad \qquad Q(x)=\dfrac{6}{-3x+2}\\[/tex]

P(x) ÷ Q(x)

[tex]\dfrac{2}{3x-1}\div \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\times \dfrac{-3x+2}{6}\\\\\\=\large\boxed{\dfrac{-3x+2}{3(3x-1)}}[/tex]

P(x) + Q(x)

[tex]\dfrac{2}{3x-1}+ \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\bigg(\dfrac{-3x+2}{-3x+2}\bigg)+ \dfrac{6}{-3x+2}\bigg(\dfrac{3x-1}{3x-1}\bigg)\\\\\\=\dfrac{2(-3x+2)+6(3x-1)}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-6x+4+18x-6}{(3x-1)(-3x+2)}\\\\\\=\dfrac{12x-2}{(3x-1)(-3x+2)}\\\\\\=\large\boxed{\dfrac{2(6x-1)}{(3x-1)(-3x+2)}}[/tex]

P(x) - Q(x)

[tex]\dfrac{2}{3x-1}- \dfrac{6}{-3x+2}\\\\\\=\dfrac{2}{3x-1}\bigg(\dfrac{-3x+2}{-3x+2}\bigg)- \dfrac{6}{-3x+2}\bigg(\dfrac{3x-1}{3x-1}\bigg)\\\\\\=\dfrac{2(-3x+2)-6(3x-1)}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-6x+4-18x+6}{(3x-1)(-3x+2)}\\\\\\=\dfrac{-24x+10}{(3x-1)(-3x+2)}\\\\\\=\large\boxed{\dfrac{-2(12x-5)}{(3x-1)(-3x+2)}}[/tex]

P(x) · Q(x)

[tex]\dfrac{2}{3x-1}\times \dfrac{6}{-3x+2}\\\\\\=\large\boxed{\dfrac{12}{(3x-1)(-3x+2)}}[/tex]

Answer:

the smaller is 9 while the digger is 18

Answer:

Step-by-step explanation:

I do not understand your question very well but I think that the state of the glass of the water would be liquid and solid at the same time since the water would not freeze 100% and would be with small pieces of solid and some parts liquid, in terms of temperature, I think that at 5 minutes it would be 5 ° C and at 10 it would be 3-4 ° C the longer it is in the freezer the less its temperature will be

(All of that is my point of view)

Average temperature 30 °

So :

30 ÷ 15 = 2 °

30 ÷ 10 = 3 °

30 ÷ 5 = 6 °

Answer:  width = 2.4 in, length = 5

Step-by-step explanation:

The max area of a right triangle is half the area of the original triangle.

Area of the triangle = (6 x 8)/2  = 24

--> area of rectangle = 24 ÷ 2 = 12

Next, let's find the dimensions.

The length is adjacent to the hypotenuse. Since we know the area is half, we should also know that the length will be half of the hypotenuse.

length = 10 ÷ 2 = 5

Use the area formula to find the width:

A = length x width

12 = 5 w

12/5 = w

2.4 = w

The dimensions of the rectangle with greatest area is length is 3 inch and the width is 4 inch.

Let the length and width of the rectangle be x and y.

Then Area of the rectangle = xy

Now, from the triangle we can conclude that

[tex]\frac{6-x}{y} =\frac{6}{8} \\y=8(\frac{6-x}{6} ).[/tex]

Put the value of y in Area we get

[tex]A(x)=x\frac{8}{6} (6-x)\\A(x)=\frac{8}{6}(6x-x^{2} )\\[/tex]

Differentiating it w.r.t x we get

[tex]A'(x)=\frac{8}{6}(6-2x )\\A''(x)=\frac{8}{6}(0-2 )\\A''(x)=\frac{-8}{3}[/tex]

Put A'(x)=0 for maximum /minimum value

[tex]A'(x)=0\\\frac{8}{6}(6-2x)=0\\x=3[/tex]

Now, [tex]A''(3)=-\frac{8}{3} &lt;0[/tex]

Therefore the area of the rectangle is maximum for x=3 inch

Now,

[tex]y=\frac{8}{6} (6-3)\\y=4[/tex]

Thus the dimensions of the rectangle with greatest area is 3 inch by 4 inch.

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Answer:

$57

Since $71.25 was paid for working 7.5 hours.

That means he was being paid $9.5 per hour.

Which is 71.25÷7.5.

And on tuesday that's 9.5×6 which is $57

Answer:

D. The statement is false. Double blinding is used to decrease the placebo effect.

Step-by-step explanation:

In a double blind study, neither researchers nor the participants know which group is receiving the placebo. If the researchers do not know which group took the medication, they cannot influence the behavior of this group, knowingly or nor, by suggesting how they should behave.

Therefore, a​ double-blind experiment is used to decrease the placebo effect.

Answer:

f(x) = 60(2)ˣ

Step-by-step explanation:

f(x) = a(b)ˣ

After one month:

120 = a(b)¹

After four months:

960 = a(b)⁴

Divide the second equation by the first:

8 = b³

b = 2

Plug into either equation and find a.

120 = a(2)¹

a = 60

Therefore, f(x) = 60(2)ˣ.

Answer:

867.44 ft²

Step-by-step explanation:

The area of the shaded region is A = 196π + 252.

We have the dimensions of the unshaded region are 14ft x 18ft.

We have to find the area of shaded region.

The area of a rectangle is -

A(R) = Length x Breadth = L x B

and the area of Circle is -

A(C) = [tex]\pi r^{2}[/tex]

According to the question -

Dimensions of the unshaded region -

L = 18ft

B = 14ft

Area of the shaded region (A) = Total Area - Area of Rectangle

Total Area = Area of 2 semicircles of radius (7 + 7) 14ft + Area of rectangle of length 18ft and breadth 28ft.

Total Area = ( [tex]2\times \frac{1}{2}\times \pi \times14 \times 14[/tex] ) + ( 18 x 28)

Total Area = 196π + 504

Area of the shaded region (A) = 196π + 504 - 252 = 196π + 252

Hence, the area of the shaded region is A = 196π + 252.

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ANSWER :

6i - (1-i)

Step - by - step explanation:

( 4 + 2i ) - ( 1 - i )

( 4 + 2 × i) - ( 1 - i )

( 6× i ) - ( 1 - i )

= 6i- (1-i)

Hope this helps and pls mark as brainliest :)

Answer:

The value of  annuity is  [tex]P_v = \$ 7929.9[/tex]

Step-by-step explanation:

From the question we are told that

    The periodic payment is  [tex]P = \$ 250[/tex]

     The  interest rate  is   [tex]r = 5\% = 0.05[/tex]

     Frequency at which it occurs in a year is  n = 4 (quarterly )

      The number of years is  [tex]t = 10 \ years[/tex]

The  value of the annuity is mathematically represented as

             [tex]P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ][/tex] (reference EDUCBA website)

 substituting values

             [tex]P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ][/tex]

             [tex]P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ][/tex]

             [tex]P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ][/tex]

            [tex]P_v = \$ 7929.9[/tex]

Answer:

Blue paint=21 ounces

Step-by-step explanation:

3/4 cup=6 ounces

1 cup=8 ounces

3/4 cup of blue paint=6 ounces of blue paint

1 cup of white paint= 8 ounces of white paint

Ava has 28 ounces of white paint

Find the required blue paint

Let the required blue paint=x

Blue paint ratio white paint

6:8=x:28

6/8=x/28

Cross product

6(28)=x(8)

168=8x

x=168/8

x=21 ounces

Answer:

There are 23 people in line at 6:00 A.M

Step-by-step explanation:

When you plug in h=1, we get 23 people

h corresponds with the time 6:00 am, as a result there are 23 people in line

The equation represents how many people will come as the hour increases.

23 represents the initial amount of people in line.

(got this from Khan academy too:))

Answer:

x = 8 ± 2i[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Given

x² - 16x + 60 = - 12 ( subtract 60 from both sides )

x² - 16x = - 72

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 8)x + 64 = - 72 + 64, thus

(x - 8)² = - 8 ( take the square root of both sides )

x - 8 = ± [tex]\sqrt{-8}[/tex] = ± 2i[tex]\sqrt{2}[/tex] ( add 8 to both sides )

x = 8 ± 2i[tex]\sqrt{2}[/tex]

The solution of the given expression is ±2√2i+8

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that

x² - 16x + 60 = - 12

Then subtract 60 from both sides;

x² - 16x = - 72

To complete the square then add ( half the coefficient of the x- term )² to both sides

x² + 2(- 8)x + 64 = - 72 + 64,

(x - 8)² = - 8 ( take the square root of both sides )

x =  ±2√2i+8

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Answer:

See below

Step-by-step explanation:

Proof:

Statements                                    |  Reasons

AD ≅ BC                                         | Given

AD ║ BC                                         | Given

AC ≅ AC                                         |  Reflexive Property

∠DAC ≅ ∠ACB                               | If 2 || lines are cut by a trans., the                                                                       |  alternate interior ∠s are congruent.

ΔADC ≅ ΔBCA                               | S.A.S  Postulate

BA ≅ DC                                         | Corresponding sides of congruent Δs

So, quad. ABCD is a ║gm             | If a quad. has its opposite sides

                                                       | congruent, the quad. is a parallelogram.

It is prove that given quadrilateral is a parallelogram.

            AD ≅ BC      and AD ║ BC              

            AC ≅ AC            

       So that,   ∠DAC ≅ ∠ACB                              

            ΔADC ≅ ΔBCA    

        So that, BA ≅ DC                                        

Hence, opposite sides of given quadrilateral are equal. Therefore, given quadrilateral are parallelogram.

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Answer:

In 10 years she'll have approximately $21865.4 in her account.

Step-by-step explanation:

When an amount is compounded continuously its value over time is given by the following expression:

[tex]v(t) = v(0)*e^{rt}[/tex]

Applying data from the problem gives us:

[tex]v(10) = 12000*e^{(0.06*10)}\\v(10) = 12000*e^{0.6}\\v(10) = 21865.4[/tex]

In 10 years she'll have approximately $21865.4 in her account.

Answer:

21,865.43

previous answer left out the last digit

Step-by-step explanation:

Answer:

after 6 half lives: 210(1/2)^6= 3.28125

Step-by-step explanation:

isotope to be reduced to half its initial mass at first:

210(1/2)=105 half it is original weight

after second life: 210(1/2)^2=105(1/2)=52.5

after third : 210(1/2)^3=52.5/2=26.25

after fourth : 26.25/2=12.125

after fifth : 13.125/2

after 6 half lives: 210(1/2)^6= 3.28125

Answer:

x = 5

Step-by-step explanation:

x = 8 - 3

Thus, x = 5