Question 3. A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the +z-direction. The a magnetic field is uniform and has components Bx = -0.242T, By= -0.985, and B2=-0.336. a. Find the components of the magnetic force on the wire? b. What is the magnitude of the net magnetic force on the wire? ​

Answers

Answer 1

a.

The components of the force are Fx = 2.2163 N, Fy = -0.5445 N and Fz = 0 N

The force on a current carrying conductor in a magnetic field is given by F = iL × B where i = current = 9.00 A, L = 25.0 cmk = 0.25 mk (since the conductor is along the z-direction). B = magnetic field. Since B has component Bx = -0.242T, By= -0.985, and Bz = -0.336, B = -0.242i + (-0.985j) + (-0.336)k = -0.242i - 0.985j - 0.336)k.

So, F = iL × B

F = 9.00 A{(0.25 m)k × [-0.242Ti + (-0.985Tj) + (-0.336T)k]T}

F = 9.00 A{(0.25 m)k × (-0.242T)i + (0.25 m)k × (-0.985Tj) + (0.25 m)k × (-0.336T)k]}

F = 9.00 A{-0.0605mT)k × i + (-0.24625 mT)k × j + (-0.084 m)k × k]}

F = 9.00 A{-0.0605mT)j + (-0.24625 mT) × -i + (-0.084 mT) × 0]}

F = 9.00 A{-0.0605mT)j + (0.24625 mT)i + 0 mT]}

F = -0.5445 AmT)j + (2.21625 AmT)i + 0 AmT]}

F = -0.5445j + 2.21625i + 0 k

F = (2.2163i - 0.5445j + 0 k) N

So, the components of the force are Fx = 2.2163 N, Fy = -0.5445 N and Fz = 0 N

b.

The magnitude of the net force on the wire is 2.282 N

The net force F = √(Fx² + Fy² + Fz²)

F = √[(2.2163 N)² + (-0.5445 N)² + (0 N)²)

F = √[(4.912 N)² + 0.2964 N)² + (0 N)²)

F = √[5.2084 N)²

F = 2.2822 N

F ≅ 2.282 N

So, the magnitude of the net force on the wire is 2.282 N

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Related Questions

What state of matter is jelly?

Answers

Answer:

Hey mate.....

Explanation:

This is ur answer.....

Solids

Jelly is a colloid where colloidal particles are solids which are dispersed in the liquid. Jelly is a fluid which can not be considered as a particular one kind of state. It is in the category of 'gel' which is a colloidal form.

Hope it helps!

Brainliest pls!

Follow me! ;)

A father (75 kg) was standing watching TV, minding his own business when one of his kids (20 kg) approached him at 2m/s heading at 0 degrees and jumped onto his back. Another kid (15 kg) approached him at 3m/s heading at 45 degrees to the first kid and also jumped on him at exactly the same time. Immediately after impact, in what direction did the group go (measured in degrees with respect to the first kid)

Answers

Answer:

Explanation:

Conservation of momentum

Let's say the first child was headed north

North momentum

75(0) + 20(2) + 15(3sin45) = (75 + 20 + 15)vn

vn = 0.6529 m/s

East momentum

75(0) + 20(0) + 15(3cos45) = (75 + 20 + 15)ve

ve = 0.28927 m/s

θ = arctan(0.28927/0.6529)

θ = 23.896...

θ = 24° east of north

Which item is not a solid-state component?

an integrated circuit
a vacuum tube
a diode
a transistor

Answers

Answer:

a vacuum tube is NOT a solid state component

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavier fragment slides 5.60 mm before stopping. How far does the lighter fragment slide

Answers

Answer:

M1 + M2 = 0   total momentum before explosion = momentum after explosion where M1 is the lighter fragment

M1 V1 + 7 M1 V2 = 0

V2 = -V1 / 7      

The lighter fragment will slide 7 times as far - 39.2 mm because it must have 7 times as much velocity - assuming the distance slid is proportional to the original velocity

A ball is thrown up into the air. When it gets to the very top,
what kind of energy does it have?

Answers

At the highest attitude, the  velocity of  the ball is 0 m/s, so the kinetic energy is 0 as well.

Hence the answer is potential energy because it doesn't depend on velocity .

Two airplanes taxi as they approach the terminal. Plane 1 taxies with a speed of 13 m/s due north. Plane 2 taxies with a speed of 8.5 m/s in a direction 20 ∘ north of west.
Part A
What is the magnitude of the velocity of plane 1 relative to plane 2?
Part B
What is the direction of the velocity of plane 1 relative to plane 2?
Part C
What are the magnitude of the velocity of plane 2 relative to plane 1?

Answers

Answer:

Explanation:

Plane 2 is moving north at

8.5sin20 = 2.9 m/s

Plane 2 is moving west at

8.5cos20 = 8.0 m/s

Part A

v = √((13 - 2.9)² + 8.0²) = 12.876... 13 m/s

Part B

θ = arctan((13 - 2.9) / 8.0) = 51.617... 52° N of E

Part C

13 m/s  52° S of W

relative velocity magnitude is independent of reference frame

A circular coil having 60 turns has a radius of 75 mm. What current must exist in the coil
to produce a magnetic field of 300 μT at the center of the coil?

Answers

Answer:

Explanation:

Step 1 of 4

CONCEPT:

The mathematical expression for magnetic field B at center of a coil:

Here,  is the current in the coil, N is the number of turns of the coil, is the permeability of the free space and  is radius of the coil.

Rearrange above equation for current in the coil.

Peregrine falcons, which can dive at 200 mph (90 m/s), grab prey birds from the air. The impact usually kills the prey. Suppose a 480 g falcon diving at 75 m/s strikes a 240 g pigeon, grabbing it in her talons. We can assume that the slow-flying pigeon is stationary. The collision between the birds lasts 15 ms.

Answers

Answer:

What is the average force of collision?

Explanation:

The velocity of the combined mass after impact is found by conservation of momentum

0.480(75) + 0.240(0) = (0.480 + 0.240)v

v = 50 m/s

An impulse results in a change of momentum

FΔt = mΔv

F = mΔv/Δt

for the pigeon

F = 0.240(50 - 0)/0.015

F = 800 N

for the falcon

F = 0.480(50 - 75)/0.015

F = -800 N

The final speed(v) of the Peregrine falcons and pigeon is 50 m/s

The objective of this question is to determine the final speed(v) of the Peregrine falcons and pigeon

From the information given:

the mass of the falcon m_f = 480 gthe speed of the falcon v_f = 75 m/sthe mass of the pigeon m_p = 240 gthe collision time = 15 ms = 0.015 s

According to the conservation of momentum, we can say that the totality of momentum before and after the collision is the same. As such;

[tex]\mathbf{m_fv_f = (m_f+m_p) v}[/tex]

[tex]\mathbf{480 g \times 75 m/s = (480 + 240) \ g \times v}[/tex]

[tex]\mathbf{v = \dfrac{480 g \times 75 m/s}{(480 + 240) \ g}}[/tex]

[tex]\mathbf{v = \dfrac{36000 \ m/s}{ 720}}[/tex]

v = 50 m/s

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A skater is spinning with his arms outstretched. He has a 2 lb weight in each hand. In an attempt to change his angular velocity he lets go of both weights (by just opening his grip). Does he succeed in changing his angular velocity

Answers

Answer:

No

Explanation:

Changing momentum of any kind requires work. Work is a force acting over a distance. While holding the weights at arms length and spinning will create a force (centripetal), there is no radial distance change incurred. Releasing the weights will reduce the force to zero, still no work done and no change in angular momentum.

If he was holding the weights at arms length while spinning and he pull his hands to his chest, there now exists both the centripetal force and a distance in the direction of that force (inward radial) this work will result in an increase in angular velocity as moment of inertia has decreased with the work done.

No, the skater doesn't succeed in changing his angular velocity.

Conservation of angular momentum

The final angular velocity of the skater is determined by applying the principle of conservation of angular momentum as shown below;

Li = Lf

[tex]Ii\omega _i = I_f \omega _f[/tex]

where;

Ii is the initial moment of inertia of the skaterIf is the final moment of inertia of the skaterωi is the initial angular speed of the skaterωf is the final angular speed of the skater

When the skater holds the weight, the momnet of inertia of both arms is the same. Also when the skater drops the weight, the moment of inertia of both arms is still the same. Thus, at any instant, the moment of inertia of the two arms is the same.

To change the angular speed, the initial and final moment of inertia of the two arms must be different. Thus, the skater doesn't succeed in changing his angular velocity.

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If you drop your keys from the tallest building in San Antonio, how fast will

they be falling after 3 seconds?

9.8 m/s

0 14,7 m/s

29.4 m/s

44,1 m/s

Answers

Hi there!

We can use the equation:

v = at, where in this instance:

v = velocity (m/s)

a = acceleration due to gravity (m/s²)

t = time (s)

g ≈ 9.8 m/s², so:

v = 9.8(3) = 29.4 m/s

E TRUE OR FALSE: Write the word TRUE if the statement is correct, and FALSE if it is not. (3 points each). Write your answer on a separate sheet of paper. 1. Most EM waves has the same speed. 2. EM waves travel at the speed of 4x108 m/s. 3. Electromagnetic waves are transverse waves consisting of changing electric fields and changing magnetic fields. 4. Electromagnetic waves transfer energy through a vacuum. 5. A wave is a disturbance that transfers energy .what the answer?

Answers

Answer:

TRUE

FALSE

TRUE

TRUE

TRUE

TRUE

Explanation:

1. Most EM waves has the same speed. True

2. EM waves travel at the speed of 4x108 m/s. False

3. Electromagnetic waves are transverse waves consisting of changing electric fields and changing magnetic fields. True

4. Electromagnetic waves transfer energy through a vacuum. True

5. A wave is a disturbance that transfers energy. True

Can someone PLEASE help me??

Answers

Id say the second answer (high efficiency, produce more heat) as the more light, the more waste (heat) ,but I would still check just to be sure because I may be wrong.

An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.​

Answers

Answer:

The distance traveled before takeoff is 1720 m

Explanation:

Given:

a = + 3.2 m/s²

t = 32.8 s

Vᵢ = 0 m/s

To Find:

d = ?

Now,

d = Vᵢ × t + 0.5 × a × t²

d = (0 m/s) × (32.8 s) + 0.5 × (3.20 m/s²) × (32.8 s)²

d = 1720 m

Thus, The distance traveled before takeoff is 1720 m

-TheUnknownScientist 72

Just need the answer

Answers

Answer:

1.  1, 2, 4 all show some form of refraction as the bending of a light ray when passing from one media to another.

Explanation:

Number 4 is the most accurate as it also shows some light being reflected and the bending of the refracted light ray in the correct direction for going from a medium of low refractive index (air) into a higher refractive index material (crown glass)

A solar collector for a hot water system absorbs solar radiation at the rate of 660 W/m^2
. Its collecting area is 3.8m^2 . Cold water at 15degrees enters the collector. What volume of
water per minute at an output temperature of 60 degrees can this collector deliver?

Answers

This question involves the concepts of the law of conservation of energy and specific heat capacity.

This collector can deliver "7.96 x 10⁻⁴ m³/min" of water at an output temperature of 60°C.

According to the law of conservation of energy:

Solar Energy = Energy Required to raise the temperature of the water

Solar Power = Energy Required to raise the temperature of the water

[tex]IA=\frac{mC\Delta T}{t}\\\\\frac{m}{t}=\frac{IA}{C\Delta}[/tex]

where,

[tex]\frac{m}{t}[/tex] = mass flow rate = ?

I = solar radiation = 660 W/m²

A = Area = 3.8 m²

ΔT = change in temperature = 60°C - 15°C = 45°C

C = specific heat capacity = 4200 J/kg.°C

Therefore,

[tex]\frac{m}{t}=\frac{(660\ W/m^2)(3.8\ m^2)}{(4200\ J/kg.^oC)(45^oC)}\\\\\frac{m}{t}=(0.0133\ kg/s)(\frac{60\ s}{1\ min})\\\\\frac{m}{t}=0.796\ kg/min[/tex]

Now, the volume flow rate will be:

[tex]\frac{V}{t}=\frac{(\frac{m}{t})}{(density\ of\ water)}=\frac{(0.796\ kg/min)}{(1000\ kg/m^3)}\\\\\frac{V}{t}=7.96\ x\ 10^{-4}\ m^3/min[/tex]

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The attached picture explains the law of conservation of energy.

How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 390 m/s

Answers

Answer:

Explanation:

½(75)v² = ½(0.008)390²

        v² = (0.008)390²/75

        v² = 16.224

         v = 4.027...

         v = 4.0 m/s

Find the time it takes for an object dropped from a building and reaches a final velocity of 20 m/s downward?

I need the formula

Answers

Answer:

Explanation:

v = at

t = v/a

t = 20 m/s / 9.8 m/s²

t = 2.0408163...

t = 2.0 s

2 W' is the symbol of a) antimony b) gold c) polonium d) tungsten​

Answers

Answer:

D. Tungsten

Explanation:

W - Wolfram

What is the angle of incidence when incident ray is reflected backwards along the same path

Answers

Answer:

The angle of incidence = The angle of reflection

Explanation:

For instance, the formula is <i = <r which means if the surface is smooth then the reflacted anglw will be equal according to the normal (dotted 90°) line.

Upon being reflected backwards the angle of incidence is simply the same, except from the other side

What is speed of sound in air?​

Answers

Answer:

speed of sound, speed at which sound waves propagate through different materials. In particular, for dry air at a temperature of 0 °C (32 °F), the modern value for the speed of sound is 331.29 metres (1,086.9 feet) per second

PLEASE HELP!

A 2457 kg car moves with initial speed of 18 ms-?. It is stopped in 62 m by its brakes.
How much work is done by the brakes?

Answers

Answer:

Explanation:

The work of the brakes will equal the initial kinetic energy of the car

Fd = ½mv²

F = mv²/2d

F = 2457(18²) / (2(62))

F = 6,419.903...

F = 6.4 kN

What is the formula of [tex]\underline{force}[/tex]in physics?

Answers

The formula of force is F = ma.

Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N).  Force is a vector quantity

Types of force

Friction forcePushPullUpthrustTensional force.

⇒ The formula of force is

F = ma................ Equation 1

⇒ Where:

F = forcem = mass of the bodya = acceleration

Hence, the formula of force is F = ma.

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Before looking at the formula, Lets understand what is force?

Force:- Force can be defined as the cause of motion of an object. Force can change the shape, direction and velocity of an object.

It's SI unit is Newton

The formula used to find force is:

[tex] \sf \nrightarrow \: F=m×a[/tex]

Where,

F is forceM is mass of the bodyA is acceleration

Equation in words:- Force applied on an object is directly proportional or equal to the product of the mass of object and the acceleration of object.

Wrte down the effect of humidity and temperature in the speed of sound....​

Answers

Explanation:

the speed of sound is affected by temperature and humidity

why does air pressure decrease with increasing altitude?

Answers


Answer:
The weight of the air above is smaller

Explanation:

As altitude increases, the amount of gas molecules in the air decreases. The air becomes less dense than air nearer to sea level. This is what people mean by “thin air”. Thin air exerts less pressure than air at a lower altitude.

Children in a tree house lift a small dog in a basket 3.85 m up to their house. If it takes 201 J of work to do this, what is the combined mass of the dog and basket

Answers

Answer:

Explanation:

The work will equal the increase in potential energy.

PE = mgh

m = PE/gh = W/gh = 201/(9.81(3.85)) = 5.32 kg

Please help me as quick as possible!!!!!!! Please, please please!!!!!!

Answers

Answer:

23

Explanation:

3x-4

Assume that two cars have the same kinetic energy, but that the red car has twice the speed of the blue car. We then know that the red car has ____ mass as the blue car.

Answers

Answer:

equal

Explanation:

How do humans obtain the carbon and energy they use in their bodies?

A. by breathing in carbon dioxide from the atmosphere

B. by consuming plants or other animals

C. by absorbing energy from sunlight

D. by absorbing carbon found in the soil

Answers

Answer:

B. . by consuming plants or other animals

An above ground swimming pool of 30 ft diameter and 5 ft depth is to be filled from a garden hose (smooth interior) of length 100 ft and diameter 5/8 inch. If the pressure at the faucet to which the hose is attached remains at 55 psi, how long will it take to fill the pool

Answers

This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.

It will take "5.1 hours" to fill the pool.

First, we will use the formula for the dynamic pressure to find out the flow speed of water:

[tex]P=\frac{1}{2}\rho v^2\\\\v=\sqrt{\frac{2P}{\rho}}[/tex]

where,

v = flow speed = ?

P = Dynamic Pressure = 55 psi[tex](\frac{6894.76\ Pa}{1\ psi})[/tex] = 379212 Pa

[tex]\rho[/tex] = density of water = 1000 kg/m³

Therefore,

[tex]v=\sqrt{\frac{2(379212\ Pa)}{1000\ kg/m^3}}[/tex]

v = 27.54 m/s

Now, we will use the formula for volume flow rate of water coming from the hose to find out the time taken by the pool to be filled:

[tex]\frac{V}{t} = Av\\\\t =\frac{V}{Av}[/tex]

where,

t = time to fill the pool = ?

A = Area of the mouth of hose = [tex]\frac{\pi (0.015875\ m)^2}{4}[/tex] = 1.98 x 10⁻⁴ m²

V = Volume of the pool = (Area of pool)(depth of pool) = A(1.524 m)

V = [tex][\frac{\pi (9.144\ m)^2}{4}][1.524\ m][/tex] = 100.1 m³

Therefore,

[tex]t = \frac{(100.1\ m^3)}{(1.98\ x\ 10^{-4}\ m^2)(27.54\ m/s)}\\\\[/tex]

t = 18353.5 s = 305.9 min = 5.1 hours

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Swim swim swim swim swim swim swim swim swim swim swim swim.

Answers

Swim swim swim faster ‍♂️
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