QUESTION 6 Which of the following is a class A IPv4 address? a. 118.20.210.254 b. 183.16.17.30 c. 215.16.17.30 d. 255.255.0.0

Answer:

a.

Explanation:

Two bytes have 2 times 8 bits is 16 bits.

Max value that can be expressed is 2¹⁶-1 = 65535

Answer:

ADAC uses powershell

Domain Local, Global, and Universal are examples of group scenes

Explanation:

Active directory software is suitable for directory which is installed exclusively on Windows network. These directories have data which is shared volumes, servers, and computer accounts. The main function of active directory is that it centralizes the management of users.

It should be noted thst statements are true about managing through Active Directory are;

Active Directory can be regarded as directory service that is been put in place by  Microsoft and it serves a crucial purpose for Windows domain networks.

It should be noted that in managing through Active, ADAC uses powershell.

Therefore, in active directory Domain Local, Global, and Universal are examples of group scenes .

Learn more about Active Directory  at:

https://brainly.com/question/14364696

Answer:

A. These describe the authority level of workers, fair payment practices, communication channels, and the like.  

Explanation:

As seen in the question above, you have been asked to write the project management plan and know that you need to consider elements such as policies, rules, systems, relationships and standards in the organization. These elements are part of EEF's entry into this process, in addition they are fundamental and indispensable for the description not only of the organizational governance structure, but also describe the management elements that will be adopted and used.

However, there is no way to use them to describe the level of authority of workers, fair payment practices, communication channels and the like, as this is not the function of this.

Answer:

num_ones = amount_to_change % 5

Explanation:

It is given that the cashier has to change the money in the maximum number of 5 dollar bills and remaining as $1 bills.

We have to write a single statement of code to assign the value to variable num_ones to find the value of $1 bills given amount_to_change.

Let us solve this by taking example:

If amount_to_change = $19

Then total number of $5 bills that can be given is 3. And amount that can be given as $5 bills is [tex]\bold{3 \times 5 = \$15}[/tex]

So, the remaining amount i.e. $19 - $15 = $4 will be given as one dollar bills.

Out of these $19, 4 bills of $1 can be found using the Modulus (%) operator.

Modulus operator leaves the remainder i.e.

Output of p % q is the remainder when a number 'p' is divided by 'q'.

19 % 5 = 4

4 is the number of one dollar bills to be given.

So, single line of code for the number of one dollar bills can be written as:

num_ones = amount_to_change % 5

Let us try it for amount_to_change  = $30

We know that 6 number of $5 bills can be used to change the amount of $30 and no one dollar bill required.

num_ones = 30 % 5 = 0 (because 30 is completely divisible by 5 so remainder is 0)

So, the correct statement is:

num_ones = amount_to_change % 5

Answer:

223 8s an order of algorithm faults refrénce fifio 14 suppose in 14 and 123 no need to take other numbers

Answer:

Since the get_seconds function is not given, I'll implement it myself;

The full program (get_seconds and main) written in python is as follows:

def  get_seconds(hour,minute,seconds):

    seconds = hour * 3600 + minute * 60 + seconds

    return seconds

time1 = get_seconds(2,30,0)

time2 = get_seconds(0,45,15)

result = time1 + time2

print(result)

Explanation:

The get_seconds defines hour, minute and seconds as its arguments

This line defines the get_seconds function

def  get_seconds(hour,minute,seconds):

This line calculates the second equivalent of the time passed to the function

    seconds = hour * 3600 + minute * 60 + seconds

This line returns the the calculated seconds equivalent of time

    return seconds

The main starts here

This line calculates the number of seconds in 2 hours and 30 minutes

time1 = get_seconds(2,30,0)

This line calculates the number of seconds in 45 minutes and 15 seconds

time2 = get_seconds(0,45,15)

This line adds both together

result = time1 + time2

This line prints the result

print(result)

Answer:

When using find command in word we can search all of the above

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   const int WEIGHT_MIN   =    0,

             WEIGHT_MAX   =   20,

             DISTANCE_MIN =   10,

             DISTANCE_MAX = 3000;

   float package_weight,

         distance,

         total_charges;

   cout << "\nWhat is the weight (kg) of the package? ";

   cin >> package_weight;

   if (package_weight <= WEIGHT_MIN ||

       package_weight > WEIGHT_MAX)

   {

       cout << "\nWe're sorry, package weight must be\n"

            << " more than 0kg and less than 20kg.\n"

            << "Rerun the program and try again.\n"

            << endl;

   }

   else

   {

       cout << "\nDistance? ";

       cin >> distance;

       if (distance < DISTANCE_MIN ||

           distance > DISTANCE_MAX)

       {

           cout << "\nWe're sorry, the distance must be\n"       << "within 10 and 3000 miles.\n"

                << "Rerun the program and try again.\n"

                << endl;

       }

       else

       {

            if (package_weight <= 2)

               total_charges = (distance / 500) * 1.10;

           else if (package_weight > 2 &&

                   package_weight <= 6)

               total_charges = (distance / 500) * 2.20;

           else if (package_weight > 6 &&

                   package_weight <= 10)

               total_charges = (distance / 500) * 3.70;

           else if (package_weight > 10 &&

                   package_weight <= 20)

               total_charges = (distance / 500) * 4.80;

           cout << setprecision(2) << fixed

               << "Total charges are $"

               << total_charges

               << "\nFor a distance of "

               << distance

               << " miles\nand a total weight of "

               << package_weight

               << "kg.\n"

               << endl;

       }

   }

Explanation:

Answer:

cell_count = int(input("Enter the value: "))

cell_count *= 10

print(cell_count)

Explanation:

Ask the user to enter a value and set it to the cell_count variable

Multiply the cell_count by 10 and assign it to the cell_count (It can also be written as cell_count = cell_count * 10)

Print the cell_count

Answer:

The answer is to simplify the logic diagrams.

Explanation:

With the help of K-map, we can find the Boolean expression with the minimum number of the variables. To solve the K-map, there is no need of theorems of the Boolean algebra. There are 2 forms of the K-map - POS (Product of Sum) and SOP (Sum of Product), these forms are used according to the requirement. From these forms, the expression can be found.

Answer:

Last name: Duck

Explanation:

explanation is provided in the attached document.

Answer: DHCP (dynamic host configuration protocol)  is a protocol which automatically processes the configuring devices on IP networks.It allows them to to use network services like: NTP and any communication proto cal based on UDP or TCP. DHCP assigns an IP adress and other network configuration parameters to each device on a network so they can communicate with  other IP networks. it is a part of DDI solution.

Explanation:

Answer:

well you could use variables in C and display them

Explanation:

Answer:

Here is the function PrintSongsShorterThan() which prints all the songs from the album shorter than the value of the parameter songDuration.

void Album::PrintSongsShorterThan(int songDuration) const {

unsigned int i;

Song currSong;  

cout << "Songs shorter than " << songDuration << " seconds:" << endl;  

for(int i=0; i<albumSongs.size(); i++){  

currSong = albumSongs.at(i);  

if(currSong.GetDuration()<songDuration){  

currSong.PrintSong();     } } }

Explanation:

I will explain the working of the for loop in the above function.

The loop has a variable i that is initialized to 0. The loop continues to execute until the value of i exceeds the albumSongs vector size. The albumSongs is a Song type vector and vector works just like a dynamic array to store sequences.

At each iteration the for loop checks if the value of i is less than the size of albumSongs. If it is true then the statement inside the loop body execute. The at() is a vector function that is used to return a reference to the element at i-th position in the albumSongs.  So the album song at the i-th index of albumSongs is assigned to the currSong. This currSong works as an instance. Next the if condition checks if that album song's duration is less than the specified value of songDuration. Here the method GetDuration() is used to return the value of duration of the song. If this condition evaluates to true then the printSong method is called using currSong object. The printSong() method has a statement cout << name << " - " << duration << endl;  which prints/displays the name of the song with its duration.

If you see the main() function statement: musicAlbum.PrintSongsShorterThan(210);

The musicAlbum is the Album object to access the PrintSongsShorterThan(210) The value passed to this method is 210 which means this is the value of the songDuration.

As we know that the parameter of PrintSongsShorterThan method is songDuration. So the duration of each song in albumSongs vector is checked by this function and if the song duration is less than 210 then the name of the song along with its duration is displayed on the output screen.

For example if the album name is Anonymous and the songs name along with their duration are:

ABC 400

XYZ 123

CDE 300

GHI 200

KLM 100

Then the above program displays the following output when the user types "quit" after entering the above information.

Anonymous                                                                              

Songs shorter than 210 seconds:                                                                        

XYZ - 123                                                                                                              

GHI - 200                                                                                                              

KLM - 100

Notice that the song name ABC and CDE are not displayed because they exceed the songDuration i.e. 210.

The output is attached.

Answer:

What-If Analysis in Excel allows you to try out different values (scenarios) for formulas. The following example helps you master what-if analysis quickly and easily.

Assume you own a book store and have 100 books in storage. You sell a certain % for the highest price of $50 and a certain % for the lower price of $20.

(i really hope this is what u needed)

Answer:

Network.

Explanation:

Availability is an essential part of network security, and user behavior analysis and application analysis provide the data needed to ensure that systems are available.

Availability in computer technology ensures that systems, applications, network connectivity and data are freely available to all authorized users when they need them to perform their daily routines or tasks. In order to make network systems available regularly, it is very essential and important to ensure that all software and hardware technical conflicts are always resolved as well as regular maintenance of the systems.

A network administrator can monitor the network traffics and unusual or unknown activities on the network through the user behavior analysis and data gathered from the application analysis to ensure the effective and efficient availability of systems.

Answer:

C. DAT-1

Explanation:

Chain of custody is applied when examining digital evidence and checking for proof that no alterations have been made to the document. It ensures that the original piece of digital evidence which could be in text, image, video, or other electronic formats, is preserved and protected from alterations. Hashing algorithms which are mathematical computations that help to condense files are applied during this procedure.

Common hashing algorithms applied, include;  the message digest 4, secure hashing algorithms 1, 2, 256, 224, 512, etc. The message digest 4 is used to evaluate why a particular piece of evidence was handled by an individual. This is further authenticated by examining the fingerprint.

Answer:

//import the Random class

import java.util.Random;

//Begin class definition

public class CoinFlipper {

   //The main method

    public static void main(String []args){

       //Create an object of the Random class

       Random ran = new Random();

       System.out.println("Result");    

       //Use the object and the number of times for simulation

       //to call the flipCoin method

       flipCoin(ran, 25);

    } //End of main method

    //Method to flip coin

    public static void flipCoin(Random ran, int nooftimes){

        //Create a loop to run as many times as specified in variable nooftimes

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}   //End of class definition

====================================================

Sample Output:

Result

1

1

1

2

1

2

2

1

2

1

1

2

1

2

1

1

1

2

1

1

1

2

2

1

2

========================================================

Explanation:

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments.

The sample output from the execution of the code is also given above.

The code is re-written as follows without comments.

import java.util.Random;

public class CoinFlipper {

    public static void main(String []args){

       Random ran = new Random();

       System.out.println("Result");    

       flipCoin(ran, 25);

    }

    public static void flipCoin(Random ran, int nooftimes){

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}

Answer:

1. Yes

2. No

Explanation:

1 Note that the term BIOS (Basic input and Output System) refers to instructions that controls a computer device operations. Thus, devices that shows up in BIOS should be in device manager.

2. Not all devices listed in devcie manager of a computer system will be listed in BIOS.

Answer:

The networks are intelligent and send packets at the highest speed and most efficiently.

Explanation:

Alcatel-Lucent was founded in 1919, it was a French global telecommunications equipment manufacturing company with its headquarter in Paris, France. Alcatel-Lucent provide services such as telecommunications and hybrid networking solutions deployed both in the cloud and on properties.

Alcatel-Lucent’s High Leverage Network (HLN) increases bandwidth and network capabilities while reducing the negative impact on the environment. This high leverage network can handle large amounts of traffic more efficiently because the networks are intelligent and send packets at the highest speed and most efficiently. HLN are intelligent such that it delivers increased bandwidth using fewer devices and energy.

Generally, when the High Leverage Network (HLN) is successfully implemented, it helps telecommunications companies to improve their maintenance costs, operational efficiency, enhance network performance and capacity to meet the bandwidth demands of their end users.

Answer:

I am writing a Python program.

def phonebook(names, numbers):  #method phonebook that takes two parameters i.e a list of names and a list of phone numbers

   dict={}  #creates a dictionary

   for x in range(len(names)):  # loop through the names

       dict[names[x]]=numbers[x]  #maps each name to its phone number

   return dict #return dictionary in key:value form i.e. name:number

#in order to check the working of this function, provide the names and numbers list and call the function as following:

names = ['Jackie', 'Joshua', 'Marguerite']

numbers = ['404-555-1234', '678-555-5678', '770-555-9012']

print(phonebook(names, numbers))

Explanation:

The program has a function phonebook() that takes two parameters, name which is a list of names and numbers that is a list of phone numbers.

It then creates a dictionary. An empty dictionary is created using curly brackets. A dictionary A dictionary is used here to maps a names (keys) phone numbers (values) in order to create an unordered list of names and corresponding numbers.

for x in range(len(names)):  

The above statement has a for loop and two methods i.e. range() and len()

len method is used to return the length of the names and range method returns sequence of numbers just to iterate as an index and this loops keeps iterating until x exceeds the length of names.

dict[names[x]]=numbers[x]

The above statement maps each name to its phone number by mapping the first name with the first  umber, the second name with the second number and so on. This mapping is done using x which acts like an index here to map first name to first number and so on. For example dict[names[1]]=numbers[1]  will map the name (element) at 1st index of the list to the number (element) at 1st index.

return dict retursn the dictionary and the format of dictionary is key:value where key is the name and value is the corresponding number.

The screenshot of the program and its output is attached.

Answer:

The number of execution can't always be determines

Explanation:

The following points should be noted

Variable d relies on variable x (both of double data type) for its value

d is calculated as

[tex]d = \sqrt{x}^2 - x[/tex]

Mere looking at the above expression, the value of d should be 0;

However, it doesn't work that way.

The variable x can assume two categories of values

The range of the above values depend on the system running  the application;

When variable x assumes a small value,

[tex]d = \sqrt{x}^2 - x[/tex] will definitely result in 0 and the loop will terminate immediately because [tex]\sqrt{x}^2 = x[/tex]

When variable x assumes a large value,

[tex]d = \sqrt{x}^2 - x[/tex] will not result in 0  because their will be [tex]\sqrt{x}^2 \neq x[/tex]

The reason for this that, the compiler will approximate the value of [tex]\sqrt{x}^2[/tex] and this approximation will not be equal to [tex]x[/tex]

Hence, the loop will be executed again.

Since, the range of values variable x can assume can not be predetermined, then we can conclude that the number of times the loop will be executed can't be determined.

Answer:

Hello your question lacks the required options here are the options

answer : source IP and destination port

Explanation:

The information that is used in an attempt to identify the local destination address is the source IP and destination port

source IP is simply the internet protocol address of a device from which an IP packet is sent to another device while destination port are the ports found in a destination device that receives IP packets from source ports  they are found in many internet applications  

Answer: 1 is A

2 is D

Explanation:

Answer:

Can be executed on multiple platforms.

Explanation:

A program is portable if it is not platform dependent. In other words, if the program is not tightly coupled to a particular platform, then it is said to be portable. Portable programs can run on multiple platforms without having to do much work. By platform, we essentially mean the operating system and hardware configuration of the machine's CPU.

Examples of portable programs are those written in;

i. Java

ii. C++

iii. C

Answer:

315 Mbps

Explanation:

Given data :

30 frames per second

resolution = 1280 * 1024

what transmission rate is required can be calculated as

frames per second = rendered frames / number of seconds passed

30 = 30 / 1

Transmission rate = the rate at which the images are transmitted from source to destination =315 Mbps without data compression

Explanation:

Microsoft Access is an information management tool that helps you store information for reference, reporting, and analysis. Microsoft Access helps you analyze large amounts of information, and manage related data more efficiently than Microsoft Excel or other spreadsheet applications.

A real-life example of a Microsoft Access Query is a table that stores the names of new customers at a supermarket.

Microsoft Access is a database management software application designed and developed by Microsoft Inc., in order to avail its end users an ability to create, store and add data to a relational database.

In Microsoft Access, the options that are available on the File tab include the following:

Opening a database.

Selecting a template.

Creating a new database.

In conclusion, a database is an element in Microsoft Access which is an ideal data source and a query would always obtain, generate, or pick information from it.

Read more on Microsoft Access here: brainly.com/question/11933613

#SPJ2

Answer:

c. a key found on Windows-oriented computer keyboards.

Explanation:

Hope it helps.

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

Following are the modified program to the given question:

Program Explanation:

Program:

import re #import package

def compare_strings(string1, string2):#defining a method compare_strings that takes two parameters

   string1 = string1.lower().strip()#defining a variable string1 that converts and holds string value into lower case  

   string2 = string2.lower().strip()#defining a variable string1 that converts and holds string value into lower case

   punctuation = r'[^\w\s]'#defining a variable that holds value

   string1 = re.sub(punctuation, '', string1)#using the variable that calls the sub method that checks parameter value with punctuation variable value  

   string2 = re.sub(punctuation, '', string2)#using the variable that calls the sub method that checks parameter value with punctuation variable value  

   return string1 == string2#using return keyword that check string1 value equal to string2

print(compare_strings("Have a Great Day!", "Have a great day?")) # calling method that prints the return value

print(compare_strings("It's raining again.", "its raining, again")) # calling method that prints the return value

print(compare_strings("Learn to count: 1, 2, 3.", "Learn to count: one, two, three.")) # calling method that prints the return value

print(compare_strings("They found some body.", "They found somebody.")) # calling method that prints the return value

Output:

Please find the attached file.

Learn more:

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