Question 8 of 10
A T-shirt vendor is thinking about changing the number of T-shirts he brings to
an event. To make sure he doesn't run out, he plans to bring more of the size
most likely to be sold.
The table shows the number of T-shirts of each size sold at his last event and
the number he had for sale.
Sold
Number for sale
180
Small
126
Medium
220
270
284
315
Large
X-Large
95
135
Which size should he bring more of?
A. Small
B. Medium
C. Large
D. X-Large

Answer:

X= 618079825.9

Y= 6.18 crystals

Step-by-step explanation:

It takes Lily a crystal to raise 999 zombies.

It will take her x crystals to Raise 617461746174 zombies

Mathematically

One crystal= 999 zombies

X = 617461746174

X=( 617461746174*1)/999

X= 617461746174/999

X= 618079825.9

Again

It took one crystal to raise 999 zombies

It will take y crystal to raise 6174 zombies

Mathematically

One = 999

Y =( 6174*1)/999

Y= 6.18 crystals

Answer:

14,7

Step-by-step explanation: if it is being divided by 2 it is 14 and 7

Answer:

[tex]\boxed{x=\frac{4\pm\sqrt{2}}{2}}[/tex]

Step-by-step explanation:

Part 1: Rewriting equation to match ax² + bx + c = 0 (quadratic function)

The given equation is not written in quadratic form. To rewrite the equation:

To overcome this difficulty, follow these mathematical steps:

[tex]2x^2=8x-7\\2x^2-8x=-7\\2x^2-8x+7=0[/tex]

Subtract 8x from both sides of the equation to rearrange it to the left side. Then, add 7 to rearrange it as well. Finally, set the three values on the left of the equation equal to zero.

Part 2: Using the quadratic formula

The quadratic formula is defined as [tex]\boxed{x=\frac{-b\pm\sqrt{b^2-4ac} }{2a} }[/tex].

Using the parent quadratic function, the values are easy to find in the given equation. [tex]\boxed{a=2, b=-8, c=7}[/tex]

Substitute these values into the quadratic formula and solve for x.

[tex]x=\frac{8\pm\sqrt{(-8)^2-4(2)(7)}}{2(2)} \\\\x=\frac{8\pm\sqrt{64-4(14)}}{4}\\\\x=\frac{8\pm\sqrt{64-56}}{4} \\\\x=\frac{8\pm\sqrt{8}}{4}\\\\x= 2\pm\frac{\sqrt{8}}{4}\\ \\x=2\pm\frac{\sqrt{2}}{2}[/tex]

Part 3: Solving for x with the values from the quadratic formula

Now that x is set equal to the simplified version of the equation, the operations have to be followed through with.

This equation will have two zeros/roots to solve for by setting x equal to zero.

Operation 1: Addition

[tex]x=2+\frac{\sqrt{2} }{2}\\\\x=\frac{4+\sqrt{2}}{2}[/tex]

Operation 2: Subtraction

[tex]x=2-\frac{\sqrt{2}}{2}\\ \\x=\frac{4-\sqrt{2}}{2}[/tex]

Because both values are the exact same (minus the operations), the roots can be simplified even further to one value:

[tex]\boxed{x=\frac{4\pm\sqrt{2}}{2}}[/tex]

Answer:

[tex] s = 14.1 [/tex]

Step-by-step explanation:

Find s using the Law of Cosines:

m < S = 31°

SR = q = 21

SQ = r = 9

QR = s = ?

Thus,

[tex] s^2 = r^2 + q^2 - 2(r)(q)*cos(S) [/tex]

[tex] s^2 = 9^2 + 21^2 - 2(9)(21)cos(31) [/tex]

[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]

[tex] s^2 = 522 - 324.0216 [/tex]

[tex] s^2 = 197.9784 [/tex]

[tex] s = \sqrt{197.9784} [/tex]

[tex] s = 14.07 [/tex]

[tex] s = 14.1 [/tex] (to the nearest tenth)

Answer:

see explanation

Step-by-step explanation:

1) 6c + 15(1) = 75

6c = 60

c = 10 packs of cupcakes

2) 6c + 15(7) = 75

6c + 105 = 75

6c = -30

c = -5, since he bought more brownies than needed, he does not need to buy any cupcakes.

Answer:

6c+15b=75

1)If the treasurer buys 1 package of brownie bites

6(1)+15b=75

15b=75-6

b=69/15=4.6 ( means the treasure needs to buy 5 packages).

2): If the treasurer buys 7 packages of brownie bites,

6c+15(7)=75

6c+105=75

c=-30/6=-5( you can not buy negative amount)

the treasure does not need to buy, because brownies are enough and more.

Answer:

[tex]\boxed{D = 15.8\ units}[/tex]

Step-by-step explanation:

The coordinates are (0,9) and (-8,-4)

Distance Formula = [tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

D = [tex]\sqrt{(-8-0)^2+(-4-9)^2}[/tex]

D = [tex]\sqrt{(-8)^2+(-13)^2}[/tex]

D = [tex]\sqrt{81+169}[/tex]

D = [tex]\sqrt{250}[/tex]

D = 15.8 units

Answer:

15.3

Step-by-step explanation:

The coordinates are (0,9) and (-8,-4)

Distance of two points formula:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Plug in the values.

[tex]D=\sqrt{(-8-0)^2+(-4-9)^2}[/tex]

[tex]D=\sqrt{(-8)^2+(-13)^2}[/tex]

[tex]D=\sqrt{64+169}[/tex]

[tex]D=\sqrt{250}[/tex]

[tex]D= 15.264338...[/tex]

[tex]D \approx 15.3[/tex]

[tex] {3x}^{2} - 4x - 12 = 0[/tex]

[tex]a = 3[/tex]

[tex]b = - 4[/tex]

[tex]c = - 12[/tex]

Formula:

[tex] \boxed{x = \dfrac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }[/tex]

Replacing:

[tex]x = \dfrac{ -( - 4) \pm \sqrt{ { (- 4)}^{2} - 4(3)( - 12)} }{2(3)} [/tex]

Option: C).

Answer:

B.

Step-by-step explanation:

Well we know that

[tex]224=2^{5} *7[/tex]

so we can get the 2 outside of the radical

[tex]x^{11} =(x^{5} )^{2} *x[/tex]

and we can get the x^2 outside too.

[tex]y^8=y^5*y^3[/tex]

and we also can get y outside.

so we have:

[tex]2x^{2}y\sqrt[5]{7xy^3}[/tex]

Answer: f(x) = -3x^2 + 3x - 2

Explain: x of vertex: [tex]x[/tex] = [tex](-\frac b{2}{a} )[/tex]  = [tex]-\frac{3}{-6} = \frac{1}{2}[/tex]

y of vertex: y = [tex]f (\frac{1}{2} ) = - \frac{3}{4} + \frac{3}{2} -2=-\frac{5}{4}[/tex]

y-intercept: y = -2

x-intercept: y = 0

D = b[tex]^[/tex]^2 - 4ac = 9 - 24 = - 15 <0. There are no real roots (no x-intercepts) because D<0.

Since a <0, parabola opens downward. The parabola is below the x-axis

Answer:

The correct answer is D.

Step-by-step explanation:

Giving the following information:

R = 90x

Total cost= 35x + 17,000

x= is the number of units produced and sold

Now, we know that:

Unitary variable cost= 35

Fixed costs= 17,000

Selling price per unit= 90

To calculate the break-even point in units, we need to use the following formula:

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 17,000 / (90 - 35)

Break-even point in units= 309 units

Answer:

108

Step-by-step explanation:

To find x, you need the geometric mean. First, find the second part of 225 by doing 225 - 144 = 81. Now, to find geometric mean, do 81 x 144 = 11,664; [tex]\sqrt{11,664} = 108[/tex].

The missing length in the right triangle as given in the task content is; 108.

It follows from the complete question that the triangle given is a right triangle and the missing length can be calculated as;

First, find the second part of 225 by

225 - 144 = 81.

Now, to find geometric mean,

81 × 144 = x²

11,664 = x²

x = 108

Thus, The missing length in the right triangle as given in the task content is; 108.

Read more on missing length;

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Answer:

m<R=48.2 to the nearest tenth

Step-by-step explanation:

1. sin(m<T)=2/3

m<T=arcsin(2/3)=41.81 degrees

m<R=180-90-m<T=180-90-41.81=48.19 degrees

Answer:

6 ft and 8 ft

Step-by-step explanation:

let x be the length of one leg then (x + 2) is the other leg.

Using Pythagoras' identity in the right triangle, that is

x² + (x + 2)² = 10² ← expand left side and simplify

x² + x² + 4x + 4 = 100 ( subtract 100 from both sides )

2x² + 4x - 96 = 0 ( divide all terms by 2 )

x² + 2x - 48 = 0 ← in standard form

(x + 8)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 6 = 0 ⇒ x = 6

But x > 0 ⇒ x = 6

Thus the 2 sides are 6 ft and x + 2 = 6 + 2 = 8 ft

Answer:

For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:

[tex] arctan(tan(\frac{2\pi}{3}))[/tex]

Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:

[tex]  arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]

Step-by-step explanation:

For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:

[tex] arctan(tan(\frac{2\pi}{3}))[/tex]

Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:

[tex]  arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]

Answer:

The answer is option 2.

Step-by-step explanation:

First, you have to find the length of CD using Tangent Rule, tanθ = opposite/adjacent:

[tex] \tan(θ) = \frac{oppo.}{adj.} [/tex]

[tex]let \: θ = 48[/tex]

[tex]let \: oppo. = cd[/tex]

[tex]let \: adj. = ad = 110[/tex]

[tex] \tan(48) = \frac{cd}{110} [/tex]

[tex]cd = 110 \tan(48)[/tex]

[tex]cd = 122.17 \: feet[/tex]

Next, you have to find the length of BC using Sine Rule:

[tex] \sin(θ) = \frac{oppo.}{hypo.} [/tex]

[tex]let \: θ = 65[/tex]

[tex]let \: oppo. = cd = 122.17[/tex]

[tex]let \: hypo. = bc[/tex]

[tex] \sin(65) = \frac{122.17}{bc} [/tex]

[tex]bc = \frac{122.17}{ \sin(65) } [/tex]

[tex]bc = 134.8 \: feet \: (near.tenth)[/tex]

Answer:

[tex]\boxed{134.8 \: \mathrm{ft}}[/tex]

Step-by-step explanation:

Let’s take triangle ACD.

Find length CD.

tan θ = [tex]\frac{opposite}{adjacent}[/tex]

tan (48) = [tex]\frac{CD}{110}[/tex]

110 tan (48) = CD

CD ≈ 122.167

Let’s take triangle BCD.

Find length BC.

sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

sin (65) = [tex]\frac{122.167}{BC}[/tex]

BC = [tex]\frac{122.167}{sin(65)}[/tex]

BC ≈ 134.796

Answer:

Step-by-step explanation:

We know that the bull's eye target has a diameter of 20 centimeters, which equals 200 milimeters.

So, we find the area

[tex]A_{target}= \pi (100mm) ^{2} =(3.14)(10000) mm^{2} =31,400 mm^{2}[/tex]

Therefore, the right answer is B.

Answer:

D. 31,400mm^2

Step-by-step explanation:

Answer:

Our set of data is:

A. their first choice (12 people)

B their second choice (7 people)

C their third choice (3 people)

D their last choice (3 people)

The total number of people is:

12 + 7 + 3 + 3 = 25.

You already know the number of people for each situation, but let's calculate the percentage:

1st choice: The first choice of 12 people winned, and the total number of people is 25.

Now, 25 is our 100%, then 12 is equivalent to x;

Then we have

12*100% = 25*x

x = (12/25)*100% = 48%

This is:

The quotient between

Second choice:

Same reasoning as above, here the percentage is:

(7/25)*100% = 28%

Third choice:

Same reasoning as above, here the percentage is:

(3/25)*100% = 12%

Fourth/Last choice:

Same reasoning as above, here the percentage is:

(3/25)*100% = 12%

Answer:

He should expect to be stopped a total of 16 times

Step-by-step explanation:

What the question is saying is that out of every 5 intersections, he would be stopped at 2.

Now, for forty times in which he passes through an intersection , we want to know the number of times in which he would be stopped

In this case we only need to multiply the probability by the number of times in which he passes an intersection and that would be 2/5 * 40 = 16 times

Answer:

16

Step-by-step explanation:

Answer:

So possibilities of zeroes are:

Positive       Negative       Imaginary

   1                    1                   2

   3                   1                   0

Zeroes = -1.4549, 1.2658, 0.34457-1.0503i, 0.34457+1.0503i.  

Step-by-step explanation:

Note: Descartes' Rule of Signs is used to find the signs of zeroes not the exact value.

The given function is

[tex]f(x)=4x^4-2x^3-3x^2+6x-9[/tex]

Degree of polynomial is 4 so number of zeroes is 4.

There are three sign changes, so there are either 3 positive zeros or 1 positive zero.

Now, put x=-x in f(x).

[tex]f(-x)=4(-x)^4-2(-x)^3-3(-x)^2+6(-x)-9[/tex]

[tex]f(-x)=4x^4+2x^3-3x^2-6x-9[/tex]

There is one variation in sign change, so there is 1 negative zero.

So possibilities of zeroes are:

Positive       Negative       Imaginary

   1                    1                   2

   3                   1                   0

Using graphing calculator the zeroes of given function are -1.4549, 1.2658, 0.34457-1.0503i and 0.34457+1.0503i.  

Answer:

39 students

Step-by-step explanation:

let x represent the number of students taking both current event and foreign language

there are : 70 eight grader taking current event and 54 taking foreign

70+54-x=93

-x=93-124

x= 31 students taking both

number of eighth graders take only a current events class and not a foreign language class: 70-31=39 students

Answer:

f( x ) = 4( [tex]2^x[/tex] )

Step-by-step explanation:

If we vertically stretch a graph by a factor of 4, the " exponential slope " extending from the x - axis, should increase by a factor of 4 as well.

Therefore, the previous function is expressed by the following ...

f( x ) = [tex]2^x[/tex] ... then this new function should be -

f( x ) = 4( [tex]2^x[/tex] )

The equation of this new function is f( x ) = 4( [tex]2^x[/tex] )

Answer:

The ratio between Roberto and David is 3:11

Step-by-step explanation:

If Roberto were to have 18 cards when we start, then David would have 24. Roberto has 3/4 the amount that David has. Then Roberto gives half of his cards (9) to David. Roberto now has 9 cards and David has 33.

The ratio of Roberto's cards to David's cards will be 3:11.

Algebra is the study of graphic formulas, while logic is the interpretation among those signs.

The number of Roberto's baseball cards is 3/4 the number of David's cards. If Roberto gives 1/2 of his cards to David.

If Roberto were to have 18 cards when we start, then David would have 24.

Roberto has 3/4 the amount that David has. Then Roberto gives half of his cards (9) to David. Roberto now has 9 cards and David has 33.

The ratio between Roberto and David is 3:11

More about the Algebra link is given below.

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Answer:

38.5°

Step-by-step explanation:

Given that the height of the building is 8 yard and the distance between Jonathan and the building is 10 yards.

The sun is at the top of the building, let the distance between Jonathan laying on the ground and the top of the building be x. Using Pythagoras:

x² = 10² + 8²

x² = 100 + 64

x² = 164

x = √164 = 12.86 yards

For a triangle with sides a, b, c and their respective opposite angles A, B, and C. The sine rule is given as:

[tex]\frac{a}{sin(A)} =\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex]

Let the angle that the sunlight hit the ground be y°. The andle between the building and the ground is 90°. Therefore using sine rule:

[tex]\frac{8}{sin(y)}=\frac{12.86}{sin(90)}\\\\sin(y)=\frac{8*sin(90)}{12.86}\\\\sin(y)=0.622\\\\y=sin^{-1}0.622\\\\y = 38.5^0[/tex]

Answer:

B. 1296 in.^2

Step-by-step explanation:

The rectangles are similar, and sides ST and YZ are corresponding sides.

The linear scale factor is k = YZ/ST = 24/8 = 3

The area scale factor is k^2 = 3^2 = 9

A = 144 sq in. * k^2 = 144 sq in. * 9 = 1296 sq in.

Answer: B. 1296 in.^2

Answer:

4)1,296in^2

5)510.4ft

Step-by-step explanation:

4)

24/8=3 This is the dilation

144/8=18 This is the side length for QRST

18*3=54 The side length for WXYZ

24*54=1296 The area of WXYZ

5)

319*8/5 Your fence with a scale factor of 8/5

319*1.6 Changing 8/5 into fraction form

319*1.6=510.4 The length of the friend's fence.

Hope this helps. I could not see the end of the last question so I am sorry if it is not written properly.

Have a good day!

Answer: 40/41

Step-by-step explanation:

The cosine can be represented as adjacent/hypotenuse.  Thus, the cosine of C is 40/41

Answer:

Solution,

BC = 40

AC = 41

Now,

[tex]cos \: theta \: = \frac{adjacent}{hypotenuse} [/tex]

[tex]cos \: c \: = \frac{bc}{ac} [/tex]

Plugging the values

[tex]cos \: c \: = \frac{40}{41} [/tex]

Hope this helps..

Good luck on your assignment..

Answer:

D.

Step-by-step explanation:

To find the equation of g(x), we can substitute the point into each of the equations.

A. g(x) = (1/4x)^2

1 = (1/4 * 2)^2

1 = (1/2)^2

1 = 1/4

This statement is false, so this is not the equation.

B. g(x) = 1/2 * x^2

1 = 1/2 * (2)^2

1 = 1/2 * 4

1 = 2

This statement is false, so this is not the equation.

C. g(x) = 2x^2

1 = 2 * 2^2

1 = 2 * 4

1 = 8

This statement is false, so this is not the equation.

D. g(x) = (1/2x)^2.

1 = (1/2 * 2)^2

1 = 1^2

1 = 1

This statement is true, so this is your answer.

Hope this helps!

Answer: y = 2x+1

Step-by-step explanation:

It is the only line with (1,3) as a solution.  A slower algebraic way to solve this would be to plug in 1 for x and 3 for y, then, out of the equations in which it works, plug in -2 for x and -3 for y.  The equation that remains true for both points is the answer.

Hope it helps <3

Answer:

[tex]\boxed{y = 2x + 1}[/tex]

Step-by-step explanation:

The line passes through (1, 3).

The solution of the line is the points it crosses.

x = 1

y = 3

Plug x as 1 and y as 3 in the equation.

y = -2x + 1

3 = -2(1) + 1

3 = -2 + 1

3 = -1 False

Plug x as 1 and y as 3 in the equation.

y = 2x + 1

3 = 2(1) + 1

3 = 2 + 1

3 = 3 True

Plug x as 1 and y as 3 in the equation.

y = x - 1

3 = 1 - 1

3 = 0 False

Plug x as 1 and y as 3 in the equation.

y = -x + 1

3 = -(1) + 1

3 = -1 + 1

3 = 0 False

Answer:

Her Verticle ramp support was 5.5 ft tall.

Step-by-step explanation:

In this type of question, you would need to use the saying "soh cah toa".

Soh Cah Toa is a saying that people use for Sin, Cosine, and tagent. Each of those mean

Sine: opposite/hypotenuse Cosine: Adjacent/hypotenuse and Tagent: Opposite/Adjacent

In this specific question to figure out how tall or high her support is or needs to be have to 20 degree  angle off the ground, you will need to use Sin which is opposite over Hypotenuse or x/16

To find the answer in your calculator you would do:

Sin(20)=x/16

First thing you do is the get the x on one side by itself so you would multiply 16 on both sides giving you:

16 × Sin(20)= x

You would then follow to put Sin(20) in your calculator giving you 0.34202014332

After that you multiply that number by 16

5.47232229321

Rounding to the nearest tenth you get answer:

5.5

Answer:

T=10

Step-by-step explanation:

Answer:

t=10

Step-by-step explanation:

you multiply each side by 2.5 so 4*2.5= 10

Answer:

The answer is option B.

Explanation:

A rule that uniquely associates elements of one set A with the elements of another set B and each element in set A maps to only one element in set B.

Each element from X is related to only one element in Y. But it is okay for two different elements in X to be related to the same element in Y. So its  still a function. Let suppose

{ (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c.