Answer:
PRESSURE is a force exerted by the substance per unit area on another substance.
The key difference between water pressure and air pressure is that one is made up of water and the other is made up of air. Both air pressure and water pressure are based on and follow the same physical principals.
Explanation:
Can you describe how and why the molecules move from one side to the other?
The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.
The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.
The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.
The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.
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what type of beetle is this?
Calculate the first and second velocities of the car with three washers attached to the pulley, using the formulas
v1 = 0.25 m / t1, and
v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.
What is the first velocity of the car with three washers at the 0.25 meter mark?
m/s
What is the second velocity of the car with three washers at the 0.50 meter mark?
m/s
Answer:
0.19 and 0.45
Explanation:
edge
The first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.
What is velocity?The velocity of an object is defined as the product of the distance travelled in a given direction and the time required to travel that distance. The velocity is expressed mathematically as,
v = d/t
Here, d represents the travelled distance.
And t is the typical amount of time needed to go the distance.
Given,
The value of the first distance is, d1 = 0.25 m.
The value of the second distance is, d2 = 0.50 m.
Then the first velocity of the car at 0.25 m is,
[tex]v_1 = d_1/t_1\\v_1 = 0.25 / t_1[/tex]
Thus,[tex]t_1[/tex] denotes the first distance's typical time.
The second velocity of the car with three washers at the 0. 50 m mark is
[tex]v_2 = d_2/t_2\\v_2 = 0.50 /t_2[/tex]
Here, [tex]t_2[/tex] stands for the second distance's typical time.
Thus, the first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.
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How do you get DC current and AC current? from a generator?
Answer:
They do that by converting rotating mechanical energy into electrical power. Portable generators use an engine—typically running on gasoline, diesel, or propane, to turn an alternator which produces alternating electrical current or AC.
What are two ways fission is used in the real world.
Answer:
germ cleaning
and getting up cooking grease
Explanation:
2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
a) 35m/s north
b) 35m/s south
c) 81 m/s north
d) 81 m/s south
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]
why brittles of a paint brush spread when in water and cling when taken out of water
Answer:
surface tension
Explanation:
because of surface tension in water
An eighth-grade class is studying the motion of objects. They have learned the following concepts about motion.
Motion occurs when there is a change in the position of an object with respect to a reference point.
While the speed of the object may change at various times during a trip the average speed for the trip is found by dividing the total distance by the total time.
The motion of the object can be changed by varying the amount of net force acting on the object or by varying the mass of the object.
The teacher asked students to design investigations to determine how changing the forces acting on an object or the mass of the object would change its motion.
The materials for the investigation included:
1 - toy cart
3 - 10N weights
1 - pulley
2 - meters of string
One group of students decided to design an investigation to determine how different amounts of mass on the toy cart would affect the speed of the toy cart. They set up their investigation as shown below:
The students performed several trials using different masses in the toy cart (M1). They hung a mass shown as (M2) to pull the toy cart as it dropped.
Below is a table they made to record their results.
Which of the following would be a way to test the effect changing the amount of force acting on the object has on the average speed of the object?
Move the cart at various speeds and determine the force at M1
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
Move the cart at various speeds and determine the force exerted by M2
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
How to test the effect of weight on the speed of object?In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.
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PLEASEEEE HELP
Blue light of wavelength 435 nm
enters diamond (n = 2.42). What
is the wavelength of the light in
diamond?
(Unit = nm)
Answer:
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Explanation:
Given:
Blue light of wavelength λ1 = 435 nm
n2 in diamond = 2.42
Find:
Wavelength of light in diamond λ2
Computation:
Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.
So,
n1λ1 = n2λ2
(1)(435) = (2.42)λ2
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Answer:
180
Explanation:
got it right on acellus
If you walk for 1.5 hours at an average speed of 4 miles/hr. How far will you have walked?
A construction worker uses a board and log as a lever to lift a heavy rock. He applies a force of 20 N without the use
of the lever, however with the lever, he applies a force of 10 N. What is the mechanical advantage?
Answer:
vz vc
Explanation:
v b
HOW TO ANSWER THIS QUESTION PLEASE
Answer:
radioactive decay is a random processuse long tongsExplanation:
Quantum theory has taught us that virtually everything to do with the nature of matter in the universe is a random process. The decay of atomic nuclei is something that makes that randomness "visible" with appropriate instrumentation. As such, the rate of decay will vary over the "short" term. Consequently, it is not surprising to see a variation of a few counts in an activity measurement over a period of a few minutes.
__
Safety with respect to radioactive materials involves staying as far away from them as possible. The use of long tongs for handling would be appropriate.
Answer:
Radioactive decay is a long proxyUse long tongs↔ for safety precautions the scientist should used this upon working with radioactive materials in a laboratory.
A micro element that is essential for the formation of haemoglobin
Iron ( Fe ) is a micro element that is essential for the formation of haemoglobin.
Hemoglobin has two components-
Haem - The iron partGlobin - The proteinaceous partWhy friction is called necessary evil?
Explanation:
Frictional force causes a lot of losses in general upkeep and wear and tear of machinery. Hence it is considered as a evil. But almost all crucial tasks cannot be carried out without the presence of friction. ... Hence it is considered as a necessary evil .
Explanation:
Frictional force causes a lot of losses in general upkeep and wear and tear of machinery. Hence it is considered as a evil. But almost all crucial tasks cannot be carried out without the presence of friction. ... Hence it is considered as a necessary evil .
A dentist uses a small concave mirror to locate a cavity in a patient's tooth. The focal length of the mirror is 2.00 cm. If the mirror is held 1.60 cm from the tooth, how many times bigger will the image be? (In other words, what is the magnification?)
Answer:
m = 4.0
Explanation:
For this exercise in geometric optics we will use the equation of the constructor
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and image, respectively.
In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]
let's calculate
[tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6
[tex]\frac{1}{q}[/tex] = -0.125
q = -8 cm
the magnification is
m = - q / p
m = 8/2
m = 4.0
Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
Answer:
Newton's second law of motion?
A 8.57-m ladder with a mass of 21.4 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 258 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.63 rad/s2 about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder
Answer:
[tex]1311.5\ \text{Nm}[/tex]
Explanation:
l = Length of ladder = 8.57 m
m = Mass of ladder = 21.4 kg
F = Force on ladder = 258 N
[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Net torque is given by
[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]
The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].
A car is moving along a road. What force between the tyres and the road makes the car stop? Tick the correct box. Air Resistance, Gravity, Friction or weight?
Answer:All the forces are acting. The force due to which the car stops that is between road and tire is "friction".
Explanation:
Light waves Group of answer choices are not electromagnetic radiation. do not require a medium. can not travel in a vacuum. do not travel in straight lines from the source.
Answer:
do not require a medium
Explanation:
Light waves can be regarded as electromagnetic waves and it transverse in nature, no medium material is required to pass through. Light wave can travel through vacuum and it's ray can travel in straight lines even from point source. Light convey energy in perpendicular direction to electric field as well as magnetic field.
Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]
let's calculate
v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]
v = 17.30 m / s
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
I am soooooooooooo desperate.
Answer:
the answers the correct one is C
Explanation:
In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.
expressed this mathematically is
N = N₀ [tex]e^{- \lambda t}[/tex]
for the average life time
N₀ / 2 = N₀ [tex]e^{- \lambda T_{1/2}[/tex]
T =[tex]\frac{ln 2x}{ \lambda}[/tex]
Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.
when checking the answers the correct one is C
Two train cars with the same mass (30,000 kg) are traveling in the same direction when they collide.
Train Car A has a velocity of 10 m/s and Train Car B has a velocity of 5 m/s. What is their total
momentum after the collision? Make sure to show all your work and include proper units.
Answer:
25
Explanation:
I just did this
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.
Answer:
Velocidad final, V = 8 m/s
Explanation:
Dados los siguientes datos;
Velocidad inicial, u = 4 m/s
Aceleración, a = 2 m/s²
Tiempo, t = 2 segundos
Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;
V = u + at
Sustituyendo en la fórmula, tenemos;
V = 4 + 2*2
V = 4 + 4
Velocidad final, V = 8 m/s
1. Which term is the name given to the underwater mountains in the
middle of oceans? *
mid-ocean crust
mid-ocean mountas
mid-ocean ridges
mid-ocean basins
Answer:
The name given to the underwater mountains in the middle of oceans is;
Mid-ocean ridges
Explanation:
Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.
The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.
ASAP PLEASE HELP WITH THIS 1.Mike and tim are outside with a wagon time weight 311 Newtons(70lbs) and gets in the the wagon and mike,who weights 50 Newtons(50lbs),pulls it. As mike pulls it, he accelerates until reaching a constant speed. After stopping, Mike and Tim switch places . Tim now pulls mike in the wagon, accelerating from stop to a constant velocity. Now, Tim may be bigger then mike but mike was riding in the wagon when it had the greatest acceleration during start up? Why? Use Newtons second law of motion to explain.
2. Now Sare comes along, and she is the exact same size as Mike. However, she is even stronger then mike When she pulls mike in the wagon, she pulls with a greater force than when mike pulls her. Now who is in the wagon when it has the greatest acceleration? Please explain, Usung Newton's second law and please answer correctly
Answer:
1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move
2. Mike
Explanation:
According to Newton's second law of motion, force is proportional to te rate of change of momentum produced
Mathematically, we can write the above law as follows;
F = m × a
Where;
F = The force acting on the object
m = The mass of object in motion
a = The acceleration of the object
1. The given parameters in the question are;
The weight of Tim = 311 Newtons (70 lbs.)
The weight of Mike = 50 Newtons (50 lbs.)
The minimum force required to pull the wagon to constant speed = The weight of the wagon
With the assumption that the wagon has very little weight, we have
Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a
Given that mass is proportional to weight, we can write;
Force from mike, Tim on the wagon F₁ = 311 N × a₁
Similarly when they switched places, we have;
Force from Tim, Mike on the wagon = F₂ = 50 N × a₂
Therefore, for the same force, F₁ = F₂ = F, we have;
a₁ = F₁/(311 N) = F/(311 N)
a₂ = F₂/(50 N) = F/(50 N)
By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁
The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move
2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we are also given that F₃ > F₁
By Newton's second law of motion, we have;
a₃ = F₃/(50 N) and a₁ = F₁/(50 N)
From F₃ > F₁, we have;
F₃/(50 N) > F₁/(50 N)
Therefore;
a₃ > a₁
The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike
Therefore, Mike is on the wagon when it has the greatest acceleration.
A spherical conducting shell has charge -5 C. A particle with charge -8 C is placed at the center of the cavity. The charges (in C) on the inner surface and on the outer surface of the shell, respectively, are:
Answer:
Explanation:
The charge of - 5C will be spread on the outer surface of the shell . The presence of - 8C charge at the Centre will create + 8C charge on the inner surface and - 8C charge on the outer surface . The result is that the total charge on the outer surface of the shell will be - 5C + - 8C = - 13C and the inner surface will have charge of + 8C . + 8C charge will be locked to centrally situated - 8C charge and will not be neutralized by negative charge of outer surface .
The model shows how the Sun fuses two nuclei of hellum-3 into beryllium-6. Since beryllium-6 is unstable, it will decay into smaller nuclei.
What additional product completes the model?
O A Helium-4
OB Helium-8
o C Carbon-4
OD Carbon-8
Answer:
A
Explanation:
I took the test
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
[tex]Thrust = mv[/tex]
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]
Thrust = 200 N