Answer:
-Transporting water from the roots of the leaves .
-Transporting minerals from the roots to the leaves .
-Support the plant to stay upright.
What evidence is there that the endangered species act is causing harm to species????
Answer:
There is strong and increasing evidence the Endangered Species Act is causing widespread harm to the species it is supposed to protect-to the extent the Act may be doing more harm than good. The Act makes otherwise normal and legal forms of land and resource use illegal, such as farming, home building and cutting timber. The Endangered Species Act’s severe penalties-$100,000 and/or 1 year in jail for harming a single species or even unoccupied habitat that is deemed suitable-turn species in to liabilities. As a result, landowners seek to reduce their liabilities in a number of ways.
Explanation:
what is the importance of mastication during digestion
Mastication is the process by which food is crushed and ground by teeth. It increases the surface area of foods to allow a more efficient break down by enzymes.
A flask containing 100ml of YNB broth was inoculated with approximately yeast cells. The flask was incubated at 37 degrees Celsius (100rpm). Samples were periodically collected and their absorbance (optical density-OD) was measured:
Using the given data (shown in photo) calculate the doubling time of this microorganism (FIRSTLY, you have to determine the exponential phase!)
Answer:
The time it takes for the yeast population to double is 1 hour.
Explanation:
Convert the OD to an approximation of the number of cells present in the broth. Do this by multiplying the OD value with 3 x 10^7.
The exponential phase of growth for the yeast cells is from
time t = 0 hours to time t = 5 hours
Match the membrane structures with their function or characteristics.
14
Membrane Structure
Description
11.
Phosphate heads
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& 00:17:18
12.
Fatty acid tails
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3.
Membrane proteins
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4.
Cholesterol
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v
5.
Glycoproteins
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1 --Click to select
Cell identification
Receptors, transporters
Hydrophobic interior of membrane
Hydrophilic surfaces of membrane
Maintains rigidity
Answer:
Cell identification-Glycoproteins
Receptors, transporters-Membrane proteins
Hydrophobic interior of membrane-Fatty acid tails
Maintains rigidity-Cholesterol
Hydrophilic surfaces of membrane-Phosphate heads
The the above matches indicated the phospholipid bi- layer of cells.This set up ensures that the cells control the movements of substances across its walls or membranes.
The structure also ensures fluidity of the cells which ensures insulation during cold weather. it also prevents the cell from being too rigid under certain condition.
Explanation:
Which is at a higher concentration in acids:
a) H30+ (hydronium)
b) OH (hydroxide)
Answer:
A
Explanation:
Which describes an atom that has fewer neutrons than protons and more electrons than protons? negative compound positive compound positive ion negative ion
Answer:
Negatively charged ion
Explanation:
Negatively charged ions are called anions and they have more electron than than protons and more protons than nuetrons.
When an atom has fewer neutrons than protons and more electrons than protons, such an atom is said to be an anion. Hence, it is negative ion.
Depending on the number of proton and electron, there are 3 types of atoms:
Neutral atoms in which the proton and electron numbers are balancedCation in which the proton number is more than the electron numberAnion in which the electron number is more than the proton numberIn this case, the atom has more electrons than protons and, therefore, is an anion. The excessive electron makes such atom to be negatively charge.
Therefore, an atom that has fewer neutrons than protons and more electrons than protons is a negative ion.
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Why are plant leaves green? Select one: a. They absorb only green wavelengths of light. b. They absorb only yellow and blue wavelengths of light. c. They reflect nearly all wavelengths of light. d. They reflect green wavelengths of light. e. They reflect yellow and blue wavelengths of light.
Answer: Option D.
They reflect green wavelengths of light
Explanation:
Plant leaves are green because they have chlorophyii in their chloroplast. Chloroplast is a organelle that contain the green pigment chlorophyii. The plant contain chlorophyii a and b. The Chlorophyii absorb blue and red wavelengths and other wavelengths are reflected including green are reflected so that the leaves appear green.
An unfertilized egg cell has six chromosomes. After fertilization, how many chromosomes should the zygote have?
Answer:
12 chromosomes, because the basic (haploid) number of chromosomes is 6 (n: 6)
Explanation:
The unfertilized egg contains a basic (haploid) number of chromosomes (n), being in this case 6. In humans, for example, the gamete haploid cells have a basic n content of 23 chromosomes, while in somatic cells this DNA amount is duplicated (2n), being therefore 46 chromosomes that are organized into 22 pairs of autosomal chromosomes and two sex chromosomes (X and Y).
Why is the Calvin cycle considered a dark reaction
Answer:
because it's the part that doesn't need energy from the sun to happen. The Calvin cycle takes place within the stroma of the chloroplast.
Explanation:
Answer:
The Calvin cycle can occur in the absence of light.
The Calvin cycle requires ATP and NADPH.
Explanation: See Above
Part C Having correctly established the F2 ratio in Part B, now predict the F2 phenotypic ratio of a "dihybrid" cross involving two independently assorting genes, A and W, for this cross. WWWWAAAA x wwwwaaaa The F2 ratio would be: ____ dominant W and dominant A individuals : ____ dominant W and recessive a individuals : ____ recessive w and dominant A individuals : ____ recessive w and recessive a individuals Enter your answer as four numbers separated by colons (example: 9:3:3:1).
Answer:
The F2 ratio would be: 1:0:0:0 dominant W and dominant A individuals : 1:1:0:0 dominant W and recessive a individuals : 1:1:0:0 recessive w and dominant A individuals : 1:1:0:0 recessive w and recessive a individuals
Explanation:
All the progeny resulting from this cross will be of an identical genotype (WWwwAAaa) since the parent genotype is homozygous dominant being crossed with homozygous recessive. The phenotypic ratio in this case is 1:0:0:0, indicating that all offspring express the dominant trait and are carriers of the recessive trait.
Students have expressed a protein according to the BASIL protocols. They collected a pre-induction sample, a post-induction sample, and a sample following an affinity column purification. The samples were analyzed by SDS-PAGE followed by Coommassie Blue staining. Which lane corresponds to which sample?
Answer:
The first lane with the protein band is the post-induction sample, i.e., the lane with the sample of interest.
Explanation:
Antibody binding is specific and will only bind to whichever protein it has been produced for particularly, which in this case would be the post induction sample.
Mario performed an experiment to determine if photosynthesis was affected by the amount of light that a plant received. The data from his experiment are shown in the table below. Amount of light (hours) Number of plants Average volume of oxygen produced (mL) 1 4 0.50 6 4 2.0 10 4 5.0 What could he have done to increase the validity of his data? Reduce the number of plants. Remove the 1 hour group. Add a 0 hours control. Measure the oxygen in liters.
Answer:
Add a 0 hour control
Explanation:
In an experiments, a control is what serves as a guide to measure the amount of change.
An experiment is made up of independent and dependent variable
the dependent variable is the variable to be measured that is varied and in this case its the number of light while the independent variable stands alone and been depended on by dependent variable. For more precision, the varied variable should have an experimental control that will serve as a check to know if indeed the varied number of light is of significance or not. If the control is having higher average performance than the experimental variable then it shows the control is more preferably but when the performance of the variable is higher than the control then its indicates that either one or some of the variable or all are equally better than the control and can be used.
Answer:
Add a 0 hour control
Explanation:
i did the test
to encourage a yellow pigmentation, micrococcus luteus has to be incubated at a. 0 degrees C b. 25 degree C c. 37 degree C d. 100 degree C
Answer:
C. 37 degree C
Explanation:
Micrococcus luteus is a pathogenic Bacteria and has similar features with Staphylococcus aureus. It usually found in the body in the respiratory tracts and cutaneous parts of the body. They rarely cause disease except if an individual has a weak immune system.
Due to the Bacteria thriving well in the body of humans, the optimal incubation rate is usually 37 degree C which is the same body temperature of humans and it aids the yellow pigmentation of the bacteria
Advantages of attached algae
Answer:
Algae is a non flowering plant and found in very most and wet areas.
The Importance of algae include mopping up of the Carbon dioxide present in waterbodies and producing some amount of oxygen to the water through photosynthesis and this helps in the survival of sea animals.
It also helps in pollution control and degradation of hard toxic substances.
They also serve as source of food of sea animals.
During a rainstorm water is running down a hill composed of solid rock. The water then reaches an area of the hill with unsaturated soil and gentler slope. What will the effect be?
Answer:
erosion will occur in that part of the hill.
Explanation:
Rainstorm refers to the rainfall which occurs with storm. The rainstorm is responsible for erosion of the soil where there is a slop which removes the upper layer of the soil and water comes to downward in the form of mud flood which destroy everything. At the hill, rainstorm will occur which does not causes erosion due to rocky surface but when this water goes to those areas where soil is present. This water takes that soil with itself downward and erosion of the soil will occur.
Make a prediction: During the first trial, you will not be able to see how many people have the disease until the end. If no students are immune, how many do you think will have the disease at the end? __________ out of 20
Answer:
all 20
Explanation:
It is impossible to know how many individuals will have the disease at the end without knowing other factors such as the condition where the subjects are being held, trial specifications and safety measures, etc. Based on the information provided, the best prediction that can be made is that all 20 subjects will have the disease. This is because since none of them are immune the disease will spread between the patients/subjects through contact or testing equipment.
Answer:
I put 17 and it didn't say it was wrong.
Explanation:
thread like structure form body of fungus called....?
Answer:
The answer is Hyphae
Explanation:
The body of fungi is very simple known as mycelium
Answer:
Most fungi grow as thread-like filaments called hyphae. A mass of hyphae make up the body of a fungus, called a mycelium.
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Explanation:
Anterior lobe of pituitary gland is
Answer:
The anterior lobe makes up about 80% of the pituitary gland. It regulates growth, metabolism, and reproduction through the hormones that it produces.
Explanation:
The production of these hormones is either stimulated or inhibited by chemical messages sent from the hypothalamus to the pituitary.
4. EXPERIMENT: 3ml of starch solution is placed into two test tubes (#1 and #2). Lugol's solution is
added to tube #1. Benedict's solution is added to tube #2 and the tube is incubated at 37 C degrees
for 30 minutes.
What color is seen in tube #1?
In tube #2?
Explain these results:
Answer:
Tube 1- blue-black colour
Tube 2- blue colour
Explanation:
Lugol's solution was first prepared by a French Physician, Jean Guillaume August Lugol. It was formerly used as a tuberculosis therapy and it consists of iodine and potassium iodide. It is still used as medication for iodine deficiency and also as an antiseptic.
Benedict's solution is used to test for reducing sugars.
Starch is known to react with iodine to form a blue-black starch-iodide complex. Hence, when a solution of Lugol's reagent is added to the starch, a blue-black colouration is observed due to the formation of the starch iodide complex.
Starch does not react with Benedict's solution because the reducing moieties in starch are not free. When starch reacts with Benedict's solution, even at 37°C, the solution remains blue because the starch ahas not been hydrolysed in order to enable reaction with Benedict's solution.
Why is study of wheat genome is difficult task?
Answer:
Due to large size of genome.
Explanation:
The study of wheat genome is difficult task because of its large size. The genome of wheat comprise of 15 billion DNA bases. The wheat genome is three times bigger in size as compared to the genome of mammoth. Mammoth is an extincted specie of elephant which were the biggest land animal at that time. So due to large genome size of wheat, the scientists takes more time to complete its sequencing (order of nucleotide in the DNA).
Which best describes homeostasis
A woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has codominant alleles M and N. If both children are of blood type M, list all of the possible parental phenotypes
Answer:type A
Explanation:
Possible parental phenotypes could be mother with blood type A Rh positive and MN or MM while the father will have blood type B Rh negative and MN or MM type.
What is blood typing in humans?Blood typing is a method to tell what type of blood group or blood an individual has. Blood typing is done so a person can safely donate hos or her blood or receive a blood transfusion from another person. It is also done to see if a person have a substance called as the Rh factor on the surface of the red blood cells.
Blood typing in humans is an example of codominance and multiple allelism. Blood group A and B are codominant and O is recessive allele. Rh negative is recessive over Rh positive blood group. A third gene for the MN blood group is codominant, in which M and N are codominant.
In the given question, both the children are of blood type M. In this case, M and N are codominant over each. Therefore, the possible parental combinations can be MN × MN or MM × MN.
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freshwater biomes have
Answer:
c. A salinity of less than 1%
Explanation:
what is the function of guard cells?
Answer:
Guard cells are adapted to their function by allowing gas exchange and controlling water loss within the leaf. The size of the stomatal opening is used by the plant to control the rate of transpiration and therefore limit the levels of water loss from the leaf. This helps to stop the plant from wilting .
Explanation:
Explanation:
regulates the entry of materials needed for the process of photosynthesis. can contain chloroplast which can also make them a site of photosynthesis
The organelle located near the nucleus in the cytoplasm that divides and migrates to the opposite poles during mitosis; is involved in the formation of the mitotic spindle.
A. Lysosome
B. Vacuole
C. Cell membrand
D. Centrosome
Answer:
D
Explanation:
The centrosome where they are paired structures lying at right angles to one another. In this context they are possibly involved in spindle assembly during mitosis.
What’s the definition of CER
Answer:
Claim evidence reasoning
Explanation:
Court witnesses are asked "to tell the truth, the whole truth, and nothing but the truth." Research shows, however, that eyewitness accounts of crimes often are unreliable because even the most conscientious witnesses misremember details of what they observed. What other factors that might affect the "truth" a court witness presents?
Answer:
Check explanation
Explanation:
The testimony presented by an eyewitness is unreliable for a number of reasons, a few of which are listed below:
1. The witness may give false details about the incident out of fear or pressure.
2. The witness may misidentify a convict and ruin an innocent person's life by putting them in jail.
3. Events are not stored perfectly in one's memory, as research has shown, making eye witness accounts inaccurate.
uses of gene cloning in the production of human insulin
Answer:
what's gone cloning tho?
somebody help me please
Answer:
1. evolution
2. variation
3. competition
4. natural selection
Explanation:
A scientist is trying to determine the population size of western fence lizards (Sceloporus occidentalis) in the Sycamore Canyon Park in Riverside using the mark-recapture method. During her first sampling event, she caught and marked 50 lizards which she then released back into the population. A week later she caught a total of 45 lizards, 7 of which were marked. What is the estimated population size of the western fence lizard?
Answer:
approximately 321
Explanation:
Using the mark recapture method formula, we can estimate the population size of the western fence lizard from this.
N = (M*C)/R
Where N is the estimated pop size
M is the first capture marked
C is the total second capture
R is the marked recaptured
Thus, N = (50*45) / 7
N =2250/7 = approximately 321
The mark-recapture method is an indirect method to estimate population sizes. In this example, the estimated population size of the western fence lizard is N = 321.42 individuals.
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There are different methods to study population density.
There are direct methods and indirect methods.
Among these last ones, we might find the Mark-Recapture technique.
The Mark-Recapture technique assumptions are
A closed population during the sampling season, with no mortality nor natality. Random distribution of individuals in the population, All the individuals have the same probability of being sampled.Marks in the individual last the whole sampling season, Marks do not affect the individuals or their behavior.The method consists of
1) Capturing a first sample of individuals belonging to the population under study, in this case, lizard's population.
2) Marking the captured individuals and releasing them again.
3) Taking a second sample where a new capture is done
4) Counting the number of individuals that are already marked. These marked individuals belong to the first sample.
5) Calculating the population size by using the Lincoln Index or any other index.
The Lincolns Index estates that to estimate the total number of individuals in this population, N, the following equation must be considered:
N = (n1 x n2) / m
1) The initial sample has n1 number of individuals
2) The second sample has n2 number of individuals
4) The number of already marked individuals is m
5) The total number of individuals in the population is N
In the exposed example,
n1 = 50 lizardsn2 = 45 lizardsm = 7 lizardsN = (n1 x n2) / m
N = ( 50 x 45 ) / 7
N = 2250 / 7
N = 321.428 ≅ 321.42 individuals
The estimated population size of the western fence lizard is N = 321.42 individuals.
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