Select the topics that a student majoring in atmospheric science would be required to study.

mathematics
political science
physics
climatology
computer programming
physical geography
remote sensing
geographic information systems

Answers

Answer 1

Answer:

whats the answer//

Explanation:

Answer 2

Answer:

A,D,G,H

Explanation:

Mathematics

Climatology

Remote sensing

Geographic information systems


Related Questions

The molecular weight for the compound from the previous question is
64.07 g/mol. What is its molecular formula?

Answers

The molecular formula should have been give to you from ur teacher

2H2O ---> 2H2O + O 2

Answers

Honesty 123/56 (908) - t

How does size affect weight?
(20 points, write at least 5 sentences answer pls thx!)

Answers

Many weight charts have 10 pound increments in each frame size; small, medium, and large. ... Being big-boned or small boned doesn't justify a 20-25 pounds differential from a normal size person. If you are truly convinced you are not overweight just big boned.

Please help me as soon as possible!!! How many grams of H3PO4 are in a 4 L sample of a 17 M solution?

Answers

Answer:

about 6664 grams of hydro phosphoric acid are in a sample of 4 L of 17 M solution

Explanation:

grams of H3PO4 = 4 L | 17 mol   | 98 grams H3PO4

                                      | 1 L        | 1 mol

If energy cannot be created or destroyed, what happens to the kinetic and potential energy?​

Answers

Answer:

According to the law of conservation of energy, energy cannot be created or destroyed, although it can be changed from one form to another. KE + PE = constant. ... As the car coasts down the hill, it moves faster and so it's kinetic energy increases and it's potential energy decreases. hope this helps

Explanation:

Answer:

They cannot be destroyed or created however,

Explanation:

it can only be transformed or transferred from one form to another.

Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.

Answers

Answer:  An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.

Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.

7x[(7+7)divide7]

PLEASE HELP

Answers

Answer:

ik this isnt the answer but mathwa will solve all yours problems

Explanation:

Estimate the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm. [Note: This is a high-field (low-spin) complex.]

Answers

Answer:

The crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm is - 1987.59kJ/mole

Explanation:

Lets calculate -:

 Crystal field stabilization energy -

                    [tex]E=\frac{hc}{\pi }[/tex]

   where h = planks constant = [tex]6.626\times10^-^3^4 Js[/tex]

             c= velocity of light = [tex]3\times10^8m/second[/tex]

           [tex]\pi =wavelength=600nm=600\times10^-^9m[/tex]

           [tex]E=\frac{6.626\times10^-^3^4\times3\times10^8}{600\times10^-^9}[/tex]

                =[tex]0.033\times10^-^1^6 J/ion[/tex]

              = [tex]0.033\times10^-^1^6\times6.023\times10^2^3[/tex]

             = [tex]0.198759\times10^7 J/mole[/tex]  = [tex]1987.59\times10^3J/mole[/tex]

             = [tex]1987.59kJ/mole[/tex]

 Thus , the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) is  1987.59kJ/mole  

           

Solution remained colorless.
During the experimentation, the test tube was gently heated in a Bunsen burner flame for 60 seconds. What was the reason for this specific
procedure?
A)
Heating was done to initiate the combustion of the metal in water.
B)
Heating was done to confirm that no chemical reaction would take
place in acid
0
Heating was done to precipitate the chemical change in each test
tube containing water
D)
Heating helped released the hydrogen contained in water
molecules so students would have a positive H+ test.

Answers

B because the others are not equal and if you add and then get the root it would be b

calculate the percentage mass of calcium chloride, CaCi^2​

Answers

Answer: m-%(Ca) = 40.08 / 110.98

Explanation: molar mass of CaCl2 is 40.08+ 2·35.45 = 110.98

Think you have one mole substance. It contains 40.08 g Ca

Express these temperatures in degrees Fahrenheit and in kelvins. A.-252.97 C B. -40 C C. 1,064 C

Answers

Answer:

A. -423.346 °F, 20.18 K

B. -40°F, 233.15K

C. 1947.2 °F, 1337.15 K

Explanation:

A.

(-252.97 °C × 9/5) + 32 = -423.346 °F

-252.97 °C + 273.15 = 20.18 K

B.

(-40 °C × 9/5) +32 = -40 °F

-40 °C + 273.15 = 233.15 K

C.

(1064 °C ×9/5) + 32 = 1947.2 °F

1064 °C + 273.15 = 1337.15 K

Name each of the following molecular binary compounds:
01. CaCl2 01. hydroiodic acid
02. HI (g) 02. hydrogen monoiodide gas
03. HI (aq) 03. diiodine tetraoxide
04. BH3 04. bromine monofluoride
05. Cl2O6 05. silicon tetrahydride
06. ClF 06. tetraphosphorus hexaoxide
07. P2Cl4 07. disulfur monoxide
08. I2O5 08. carbon monooxide
09. BrF5 09. hydrogen monochloride gas
10. HBr (aq) 10. tetraphosphorus decaoxide
11. IF7 11. dibromine monoxide
12. NF3 12. dinitrogen tetrafluoride
13. H2Se (aq) 13. disilicon hexahydride
14. BrCl 14. tetraarsenic hexaoxide
15. H2Se (g) 15. hydrochloric acid
16. SnO2 16. arsenic trihydride
17. HBr (g) 17. iodine heptafluoride
18. AsF3 18. bromine dioxide
19. N2O3 19. disulfur decafluoride
20. IF5 20. dichlorine heptaoxide

Answers

Answer:

Explanation:

From the given information; we are to assign the correct naming for the molecular binary compounds.

01. CaCl2 → Calcium CHloride

02. HI (g) → Hydrogen mono iodide gas

03. HI (aq) →  Hydroiodic acid

04. BH3 → Borontrihydride

05. Cl2O6 → Dichlorine hexoxide

06. ClF → Chlorine monoflouride

07. P2Cl4 → Phosphorus tetrachloride

08. I2O5 → Diiodine pentaoxide

09. BrF5 → Bromine pentaflouride

10. HBr(aq) → Hydrobromic acid

11. IF7 → Iodine heptaflouride

12. NF3 → nitrogen triflouride

13. H2Se(aq) → hydroselenic acid

14. BrCl → Bromine monochloride

15. H2Se(g) → Hydrogen Selenide

16. SnO2 → Tindeoxide

17. HBr(g) →  Hydrogenbromide gas

18. AsF3 → Arsenic triflouride

19. N2O3 → Dinitrogentrioxide

20. IF4 → Iodine pentafluoride

01. hydroiodic acid  → HI (aq)

02. hydrogen monoiodide gas → HI (g)

03. diiodine tetraoxide → I2O4

04. bromine monofluoride → BrF

05. silicon tetrahydride  → SiH4

06.  tetraphosphorus hexaoxide → P4O6

07. disulfur monoxide → S2O

08. carbon monooxide → CO

09. hydrogen monochloride gas → Hcl

10. tetraphosphorus decaoxide → P4O10

11. dibromine monoxide → Br2O

12. dinitrogen tetrafluoride → N2F4

13. disilicon hexahydride → SiH6

14. tetraarsenic hexaoxide → As4O6

15. hydrochloric acid → HCl (aq)

16.  arsenic trihydride → AsH3

17. iodine heptafluoride → IF7

18. bromine dioxide → BrO2

19. disulfur decafluoride → S2F10

20. dichlorine heptaoxide → Cl2O7

Pictures of every moon

Answers

Answer:

Where?

Explanation:


According to the text, fission occurs when the nucleus
two lighter nuclei.

Answers

The person top of me is wrong

Answer:

Splits into

Explanation:

Because fission reaction is divided into two or more pieces.

If anyone could help I’d appreciate it

Answers

Answer: 2.00 mol

Explanation:

The balanced chemical equation is:

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]  

According to stoichiometry :

2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex]  of [tex]O_2[/tex]

Thus both will act as limiting reagents and will be fully consumed.

2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex]  of [tex]H_2O[/tex]

  Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.

i
CH3-CH2-CO-CH2-CH2-CH3 + H2
Pd​

Answers

Answer:

i don't know but I just want to have coins

How can you determine if elements have the same properties?

Answers

Answer:

You will know if elements have the same properties if they are in the same column (up and down) on the periodic table.

Explanation:

Ex: Lithium and a hydrogren has the same properites bcause they are both on the same line/column. Columns are up and down the table and rows are left and right. Hope this helps

How many Protons, Electrons and Neutrons does Helium-6 have?

Answers

Answer:

12 neutrons

2 protons

2 electrons

Answer:

Hello There!!

Explanation:

Helium 6 has:

-two protons

-two electrons

-two neutrons

hope this helps,have a great day!!

~Pinky~



Choose the best answer

1. Gas A diffuses twice as fast as another gas B. If the density of the gas A is 2, the molecular mass of
(a)2
(b) 4
(c) 8
(d) 16​

Answers

i think it is

(b) 4

:) hope its correct :)

Mg(s) + 2HCl (aq) -----> MgCl2 (aq) + H2

You have 6.00 g HCl and 4.8 g Mg.
What is the limiting reaction

Answers

Answer:

HCl is the limiting reactant

Explanation:

To find the limiting reactant of a reaction we must find the moles of each one as follows:

Moles Mg (Molar mass: 24.305g/mol)

4.8g Mg * (qmol / 24.305g) = 0.20 moles Mg

Moles HCl (Molar mass: 36.46g/mol)

6.00g HCl* (1mol / 36.46g) = 0.165 moles HCl

Based on the chemical reaction, for a complete reaction of 0.20 moles of Mg are necessaries:

0.20 moles Mg * (2mol HCl / 1mol Mg) = 0.40 moles HCl

As there are just 0.165 moles of HCl:

HCl is the limiting reactant

write the value of atmosphere pressure at sea level .​

Answers

Answer:

standard sea- level pressure,by definition,equals 760 mm of Mercury,14.70 pounds per square inch, 1,013.25x10³ dynes per square centimetre, 1,013.25 millibars,one standard atmosphere,or 101.325 kilopascale

Here's your answer

l hope it's helpful for u....

What is the concentration of a solution with a
volume of 2.5 liters containing 660 grams of
calcium phosphate Ca3(PO4)2 ?

Answers

Answer:

660gx Imol = 2.1278 mol 310.189 2.5L 1.85 m).

Explanation:

The number of moles of 660 grams of calcium phosphate is 2.127. Then the molarity of the solution of 2.5 liter volume is 0.85 M.

What is molarity ?

Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute particles to the volume of solution in liters. Hence, its unit is mol/L or molar.

The molarity of a solution is a colligative quantity as well as temperature dependent.

Given,

molar mass calcium phosphate,  Ca₃(PO₄)₂  =310.18 g/mol

Then,

no.of moles of calcium sulphate in 660 g = 660 g/310.18 g/mol = 2.127 moles

volume of solution = 2.5 L

Molarity = no.of moles of solute/ volume of solution in L

M = 2.127 moles/ 2.5 L

   = 0.85 M.

Therefore, the molarity of the given solution is 0.85 molar.

Find more on molarity:

brainly.com/question/8732513

#SPJ6

calculate the ph of one solution containing 0.1 M formic acid and 0.1 M sodium formate before and after the addition of 1mL of 5 M Naoh. how much could the Ph change if the NaOh were added to 1 L of pure water

Answers

Answer:

Pka of formic acid (HCOOH)= 3.75

pH= PKa +log [ Sodium formate/ formic acid] = 3.75

NaOH reacts with HCOOH as HCOOH (aq) + NaOH(aq) --> NaCHO2 (aq) and H2O (l)

Moles of HCOOH= 0.1*1= 0.1 moles

Moles of NaOH= 5*1/1000= 0.005 moles

HCOOH is in excess and the excess is = 0.1 - 0.005 = 0.095

Moles of sodium formate = 0.005 + 0.1 = 0.105 moles of HCOOH= 0.095

volume after mixing = 1 + 5 /1 000=1.005

Concentrations : HCOOH= 0.095/1.005 sodium formate= 0.105/1.005

pH= 3.75+log (0.105/0.095)=3.85

When NaOH is added, molarity is , 1*5= 1000*M

M= 5/1000=0.005

The pH remains the same. Only the molarity of NaOH changes.

QUESTION 6 Consider the following reaction between the diatomic and monatomic forms of iodine: I2 (g) <-> 2I (g) When 0.095 M I2 is initially placed in a previously empty container and sealed, the system slowly reaches equilibrium. When equilibrium is reached, it is found that there is an equilibrium concentration of 0.0055 M of the monatomic form of iodine. Calculate the (unitless) equilibrium constant Kc. Round your answer to two sig figs, and express it in scientific notation.

Answers

Answer: The equilibrium constant is [tex]3.3\times 10^{-4}[/tex]

Explanation:

Initial concentration of [tex]I_2[/tex] = 0.095 M  

The given balanced equilibrium reaction is,

                            [tex]I_2(g)\rightleftharpoons 2I(g)[/tex]

Initial conc.          0.095 M       0 M

At eqm. conc.     (0.095-x) M   (2x) M

Given : 2x = 0.0055

x = 0.00275

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[l]^2}{[I_2]}[/tex]  

Now put all the given values in this expression, we get :

[tex]K_c=\frac{(0.0055)^2}{(0.095-0.00275)}[/tex]

[tex]K_c=\frac{(0.0055)^2}{0.09225}=0.00033[/tex]

Thus the equilibrium constant is [tex]3.3\times 10^{-4}[/tex]

1/5 divided by 3/4 fraction

Answers

Answer:

4/15

Explanation:

we can write out an equation by doing (1/5 ÷ 3/4) and then switch the sign to multiplication and we can keep the first fraction the same (in this case 1/5) and then we flip the second fraction BUT when we flip the second fraction upside-down we have to change the symbol to multiplication (1/5x4/3)

then after that all we do is multiply the denominators and numerators :)

1 x 4 = 4

_______

5 x 3 = 15

answer would be 4/15

What is the molality of a solution containing 18.2 g HCl and 250. g of water?

Answers

Answer:

m=2.0mol/kg

Explanation:

Hello there!

In this case, according to the formula to compute molality, which requires moles of solute (HCl) and kilograms of solvent (water), we first compute the moles of the former with its molar mass as shown below:

[tex]n=\frac{18.2g}{36.46g/mol}= 0.50mol[/tex]

And then the kilograms of water:

[tex]\frac{250.g}{1000g/kg} =0.250kg[/tex]

Finally, the molality turns out to be:

[tex]m=\frac{0.50mol}{0.250kg}\\\\m=2.0mol/kg[/tex]

Best regards!

Which of the different components of smog depicted in the graph are most likely released from automobile exhaust?
A
A and B
B
B and C
с
A, B, and C
D
B, C, and D

Answers

Answer:

B, B and C

Explanation:

The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.

What is Smog?

This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.

(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.

Read more about Smog here  https://brainly.com/question/14029972

Fission and fusion are alike in many ways. However, one difference is
A)
Fusion forms dangerous nuclear waste that is difficult to dispose whereas
fission does not.
Eliminate
B)
Fission is a controllable chain reaction and fusion is not.
Fusion results in a greater product mass whereas fission does not.
D)
Raw materials for fission are cheaper and easy to get.

Answers

Explanation:

Fusion vs Fission

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium. Both reactions release energy which, in a power plant, would be used to boil water to drive a steam generator, thus producing electricity.

Answer:

B

Explanation:

i did this

Uranium, an important component of both nuclear weapons and nuclearreactors, has two major isotopes, U-238, which has a half-life of approximately billion years, and U-235, which has a half-life of approximately million years. Both were present in equal amounts at the time of thecreation of the Earth, billion years ago. How many years after the creationof the Earth had the amount of radiation from uranium decayed to half theamount present at the time of the creation of the Earth

Answers

Answer:

Hello your question is poorly written below is the well written question

Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of  approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5  billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth

Answer : 140 billion years

Explanation:

Given that :

U-238   h1/2 = 4.5 billion years

U-235   h1/2 = 700 million years

At the beginning both Isotopes where present in equal amount

Determine the T years before the amount of Uranium decays to Half

T =   ?    N'2 = N1 / 2

we know that N = No ( 1/2 )^h   where h = time / half-life time

attached below is the detailed solution of the given problem

is oxygen a beginning substance or ending substance?​

Answers

it’s a beginning substance i think
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