Answer: x= 1/196
Step-by-step explanation:
4. In a simple random sample of 120 women and 150 men from
a population of 150,000, 25% of the women and 37% of the men
are smokers. Suppose you are interested in comparing the
proportion of smokers by sex, compute the Z statistic.
The z-test compares the two sample to determine the existence of a
difference in the two proportion.
The Z-statistic or test of the difference in proportion is approximately -2.106.Reasons:
The given parameter are;
Number of women, n₁ = 120 women
Number of men, n₂ = 150 men
The population size = 150,000
Percentage of women that are smokers in population, [tex]\hat p_1[/tex] = 25%
Percentage of men that are smokers in population, [tex]\hat p_2[/tex] = 37%
The Z statistic is given as follows;
[tex]\displaystyle Z= \mathbf{\frac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p}(1-\hat{p})\left (\frac{1}{n_{1}}+\frac{1}{n_{2}} \right )}}}[/tex]
Number of men = 0.37 × 150 = 55.5
Number of women = 0.25 × 120 = 30
[tex]\displaystyle \hat p = \frac{55.5 + 30}{150 + 120} = \frac{19}{60}[/tex]
Which gives;
[tex]\displaystyle Z=\frac{0.25-0.37}{\sqrt{\frac{19}{60} (1-\frac{19}{60} )\left (\frac{1}{120}+\frac{1}{150} \right )}} \approx -2.106[/tex]
The Z-statistic is approximately -2.106
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3. Your bedroom is 14 feet by 10 feet and your sister's room is 12 feet by 10 feet. If you
are going to paint both rooms the same color and the paint covers 250 square feet per
gallon, how much paint will you need if you are going to paint the walls and ceilings?
Assume the ceiling is 8 ft high.
Step-by-step explanation:
we paint the walls and ceilings.
and we ignore any doors or windows (no information about them).
so, each room has then 5 rectangles : 4 walls and 1 ceiling.
when we say a room is 14 ft × 10 ft, this also means there are 2 sides of 14 ft and 2 sides of 10 ft.
and the area is 14×10 ft².
the area of the ceiling is the same as the area of the floor : 14×10 = 140 ft²
for the walls we have 2 rectangles of 14×8 = 112 ft², and 2 rectangles of 10×8 = 80 ft² (remember, the height of the room is 8 ft).
for the sister's room it is similar.
just a 12×10 = 120 ft² ceiling.
and 2 rectangles of 12×8 = 96 ft² and again 2 rectangles of 10×8 = 80 ft² as walls.
altogether we have then
140 + 112 + 112 + 80 + 80 + 120 + 96 + 96 + 80 + 80 ft²
that is in total
996 ft²
how many gallons of paint do we need for this ?
well, 1 gallon per 250 ft².
so, how often does 250 fit into 996 ?
996 / 250 = 3.984 gallons.
since we get the paint most likely only in quantities of gallons, we need 4 gallons for the paint job.
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows a compounded continuously model, we can determine the amount of substance left in Alexander Litvinenko's body at any given time. If Polonium-210 has a decay rate of .502%, then determine the amount of Polonium-210 left in his body after 40 days. Provide 3 decimal places and units in your answer.
Compounded continuously model are evaluated using exponential functions
There are 8.177 bacteria left after 40 days
The given parameters are:
[tex]\mathbf{a = 10}[/tex] --- the initial number of bacteria
[tex]\mathbf{r = 0.502\%}[/tex] --- the decay rate
[tex]\mathbf{n = 40}[/tex] --- the number of days
The amount of bacteria left each day is calculated using:
[tex]\mathbf{T_n = a \times (1 - r)^n}[/tex]
So, we have:
[tex]\mathbf{T_{40} = 10 \times (1 - 0.502\%)^{40}}[/tex]
Express percentage as decimal
[tex]\mathbf{T_{40} = 10 \times (1 - 0.00502)^{40}}[/tex]
Simplify the expression in bracket
[tex]\mathbf{T_{40} = 10 \times 0.99498^{40}}[/tex]
Evaluate
[tex]\mathbf{T_{40} = 8.1766}[/tex]
Approximate
[tex]\mathbf{T_{40} = 8.177}[/tex]
Hence, there are 8.177 bacteria left after 40 days
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For any nonnegative real number a, (a)2 =
=
O A. a2
O B. va
Ос. а
O D. 1
SUBMIT
Answer:
C
Step-by-step explanation:
For example, if a is equal to 2.
[tex] \sqrt{2} {}^{2} = 2[/tex]
The answer is still the given number a.
The solution of the expression √a² is,
⇒ a
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
The expression is,
⇒ √a²
Where, 'a' is nonnegative real number.
Now, We can simplify as;
⇒ √a²
⇒ √ a × a
⇒ a
Thus, The solution of the expression √a² is,
⇒ a
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The sum of two numbers is 15 and the difference is 4. Let the two numbers be x and y.
Write down a pair of simultaneous equations involving x and y. Solve the equations.
Answer:
x=9.5 and y=5.5
Step-by-step explanation:
x+y=15
x-y=4
add
2x=19
x=9.5
y=15-9.5
y=5.5
x=9.5 and y=5.5
what is 2x-3 when x=1
Find the slope of the line that passes through:
(6,7) and (4,2)
Answer:
5/2
Step-by-step explanation:
Slope = Change in y/Change in x
Slope = 2 - 7/4 - 6
Slope = -5/-2
Slope = 5/2
-Chetan K
The table below shows the size of the graduating classes for to high schools.
I think It's B. I'm not really sure thought.
Answer:
2017
Step-by-step explanation:
Adams high school Butler High school
628, 625, 622, 619, 616, 613, 436, 449, 462, 475, 488, 501
common difference = 625 - 628 = -3 common difference = 449-436 = 13
we can continue series like this
613 - 3 = 610 [2011] 501 + 13 = 514
610 - 3 = 607 [2012] 514 + 13 = 527
607 - 3 = 604 [2013] 527 + 13 = 540
604 - 3 = 601 [2014] 540 + 13 = 553
601 - 3 = 598 [2015] 553 + 13 = 566
598 - 3 = 595 [2016] 566 + 13 = 579
595 - 3 = 592 [2017] 579 + 13 = 592
I assume when they will become equal
so it is 2017
calculate lim F(X)
[tex] {x }^{2} + 1 - 3 \frac{ ln(x) }{x} [/tex]
[tex]Hiya![/tex]
Sokka is here to help!!
Here's the step:
[tex]x^2+1-3\frac{In(x)}{x}[/tex]
[tex]Mutiply[/tex] [tex]by:[/tex] [tex]3[/tex]
[tex]. \frac{In(x)}{x} :\frac{3In(x)}{x}[/tex]
[tex]= x^2+1-\frac{3In(x)}{x}[/tex]
ANSWER:
[tex]= x^2+1-\frac{3In(x)}{x} .[/tex]
Hopefully, this helps you!!
[tex]Sokka[/tex]
Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets.
What is the minimum number of games that Enzo could have played?
Answer:
Enzo must have played 11 games.
Step-by-step explanation:
Since Enzo earns 5 tickets from every game and Beatriz wins 11 tickets from each game, we have to find the LCM (Least Common Multiple) since they earned the same amount of tickets when they stopped.
The LCM of 11 and 5 is 55.
To see how many games they both played we have to divide the amount of tickets they earn each time from the LCM (55).
Since Enzo earns 5 tickets from each game and both Enzo and Beatrice earned 55, Enzo must've played 11 games.
(If that makes sense lol)
find measurement 1 and 4
Answer:
the info they gave us is to suppose that angle 6 is = 126°
step 1:
We know that angle 8 = angle 6 = 126°
Why? — when a circle (360°) is split by 2 lines that intersect, there will be 2 equal pairs of angles formed
step 2:
angle 2 = angle 8 = 126°
Why? — they’re alternate angles
step 3:
angle 4 = angle 2
Why? — when a circle (360°) is split by 2 lines that intersect, there will be 2 equal pairs of angles formed
step 4:
angle 1 = 180-126 (angle 4) = 54°
Why? — total angles in a straight line = 180°
Key Term:
Alternate angles:
Alternate angles are angles that occur on opposite sides of the transversal line and have the same size. Alternate angles are equal: We can often spot interior alternate angles by drawing a Z shape: There are two different types of alternate angles, alternate interior angles and alternate exterior angles.
I need help with this math problem
Answer: The drill will reach -915 feet after 18 days.
The water level in a lake was monitored and was noted to have changed -2 1/3 inches in one year. The next year it was noted to have changed -1 5/6 inches. What was the total change in the water level over the two years?
Answer:
The total change in water level over the past 2 years is [tex]\displaystyle -4 \frac{1}{6}[/tex].
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightFractions
Proper and ImproperNumbers
Least Common Multiple (LCM)Step-by-step explanation:
Step 1: Define
Identify
Year 1 water change: [tex]\displaystyle -2 \frac{1}{3}[/tex]
Year 2 water change: [tex]\displaystyle -1 \frac{5}{6}[/tex]
Step 2: Find Total Water Change
[Set up] Add yearly water changes: [tex]\displaystyle -2 \frac{1}{3} + -1 \frac{5}{6}[/tex][Fractions] Convert to improper: [tex]\displaystyle \frac{-7}{3} - \frac{11}{6}[/tex][Fraction] Rewrite [LCM]: [tex]\displaystyle \frac{-14}{6} - \frac{11}{6}[/tex][Order of Operations] Subtract: [tex]\displaystyle \frac{-25}{6}[/tex][Fraction] Convert to proper: [tex]\displaystyle -4 \frac{1}{6}[/tex]What is the sum of the two expressions? (3/7x+4)+(1/7x-2)
Combine the like terms:
3/7x + 1/7x = 4/7x
4 + -2 = 4-2 = 2
Answer: 4/7x + 2
Find the missing number.Write your answer on your answer sheet.
3/5÷2/6= 3/5÷6/2=
[tex] \huge \bf \color{gold} \frac{3}{5} \div \frac{2}{6} = [/tex]
[tex] \tt \frac{3}{5} \times \frac{6}{2} = [/tex]
[tex] \tt \frac{18 \div 2}{10 \div 2} = [/tex]
[tex] \tt \frac{9}{5} = [/tex]
[tex] \boxed {\color{blue}{ 1 \frac{4}{5}}}[/tex]
THE RESULT IS 1 4/5
Answer:
The solution is 9/5 and 1/5
Step-by-step explanation:
3/5÷2/6
= 3/5×6/2
= 3/5×3
= 9/5
3/5÷6/2
= 3/5×2/6
= 3/5×1/3
= 1/5
Find the angle measures. Justify your responses.
m
a
21
34
b
65
7/8
Given: a 1b, m_2=3x +20°,
m27=2x -10°
Find: m3, m26
mZ3 =
=
m26=
=
Answer:
m∠3 = 2x - 10° and m∠6 = 3x + 20
m∠3 = 58° ; m ∠6 = 122°
Step-by-step explanation:
a ║ b
m∠2 = m∠6 If ║ cut by a transversal, then corresponding angles
are ≅ and =
m∠7 = m∠3 If ║ cut by a transversal, then corresponding angles
are ≅ and =
m∠2 = 3x + 20 Given
m∠7 = 2x - 10 Given
m∠6 + m∠3 = 180° If ║ cut by a transversal, then each pair of same-side
interior angles (also called consecutive interior angles
are supplementary (sum = 180°) .
3x + 20 + 2x - 10 = 180°
5x + 10 = 180°
5x = 170°
x = 34°
Answer: m∠3 = 2x - 10° and m∠6 = 3x + 20
m∠3 = 2(34) - 10 ; m∠6 = 3(34) + 20
m∠3 = 58° ; m ∠6 = 122°
The side of an equilateral triangle is 12. Its area is
Select one:
a. 72
b. 48
c. 144
d. 36 square root 3
A≈62.35
..................
Work out the length x. 14cm, 7cm , right angle triangle
The given triangle is a right angled triangle. So we can use the pythagorean theorem to solve this.
Hypotenuse = 14 cm
Altitude = 7 cm
Base = x cm
Using pythagorean theorem,
Hypotenuse² = Base² + Altitude²
14² = x² + 7²
14² - 7² = x²
196 - 49 = x²
147 = x²
√147 = x
12.124 = x (approx.)
_________
Hope it helps ⚜
What is the value of x?
14(6x−2)=x−2
A)-3
B)2
C)-7
D)-9
14(6x-2)=x-2
84x-28=x-2
84x-x= 28-2
83x = 26
x = 26/83
there are no corect answer below
ok done. Thank to me :>
(7 x 10^-6)(7 x 10^-6) pls help <:D
we have (7 x 10^-6)(7 x 10^-6) = (7 x 10^-6)^2 = 49 x 10^-3 = 0.049
ok done. Thank to me :>
18.which the venn diagram illutrates A-B?
Answer:
Option B is correct answer
What is the slope of any line that is perpendicular to the line that contains the points (8,8) and (12,12)
Answer: 1
Step-by-step explanation:
12-8=4
12-8=4
4 over 4 is 1
if it perpendicular then it's the opposite reciprocal
hope that help
A hummingbird lives in a nest that is 12 meters high in a tree. The hummingbird flies 15
meters to get from its nest to a flower on the ground. How far is the flower from the base of
the tree?
Answer:
The flower is 9 meters from the base of the tree.
Step-by-step explanation:
Use the Pythagorean theorem to solve. We are given the length of one leg and the length of the hypotenuse of a right triangle.
[tex]a^{2} +b^{2} =c^{2}[/tex]
where a and b are the legs, and c is the hypotenuse.
Plug in the given values and solve:
[tex]x^{2} +12^{2} =15^{2} \\x^{2} +144=255\\x^{2} =81\\x=9[/tex]
The flower is 9 meters from the base of the tree.
5) Placido pulls a rope attached to a wagon through a pulley at a rate of q m/s. With dimension as in Figure 5:
(a) Find a formula for the speed of the wagon in terms of q and the variable x in the figure.
(b) Find the speed of the wagon when x=0.6 if q=0.5 m/s.
The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.
[tex](a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}[/tex]
(b) When x = 0.6 and q = 0.5 m/s, the speed of the wagon is approximately 0.243 m/s.
Reasons:
(a) The distance from the cart to the pulley, r is given by Pythagoras's
theorem as follows;
r = √((3 - 0.6)² + x²) = √(2.4² + x²)
The speed of the wagon = [tex]\mathbf{\dfrac{dx}{dt}}[/tex]
The speed of the rope, q = [tex]\mathbf{\dfrac{dr}{dt}}[/tex]
By chain rule, we have;
[tex]\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}[/tex]
[tex]\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}[/tex]
Therefore;
[tex]\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}[/tex]
[tex]\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}[/tex]
(b) The speed of the wagon when x = 0.6 if q = 0.5 m/s is given as follows;
[tex]\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243[/tex]
The speed of the wagon when x = 0.6 and q = 0.5 m/s, [tex]\dfrac{dx}{dt}[/tex] ≈ 0.243 m/s
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what is 1/5 divided by 9?
Answer:
9/5
Step-by-step explanation:
Just divide the 9 by 1 so it'll be 9/5 hope it helps
Simple Arcs and Sectors question attached. First person to answer correctly gets 50 points. Good Luck!!
Step-by-step explanation:
a=12/56°
b=14/65°
c=238°
At a sale this week, a desk is being sold for $285.60. This is 34% of the original price.
What is the original price?
well, let's say the original price is "x", which namely 100% of the price of the product, we also know that 285.60 is 34% of that.
[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 285.60&34 \end{array}\implies \cfrac{x}{285.60}=\cfrac{100}{34}\implies \cfrac{x}{285.60}=\cfrac{50}{17} \\\\\\ 17x=14280\implies x = \cfrac{14280}{17}\implies x = 840[/tex]
Which distance formula or formulas show(s) a joint variation?
Answer:
II and III only
Step-by-step explanation:
One variable quantity is said to vary jointly as a number of other variable quantities, when it varies directly as their product.
Can some please help me I will mark u brilliant
Question 2: -4/3
Question 3: -7/20
The annual number of burglaries in a town rose by 50% in 2012 and fell by 10% in 2013. hence the total number of burglaries increased by 40% over the two year period.
a. by what percent has the number of burglaries actually changed in the two-year period?
b. by what percent would the crime have to decrease in the second year in order for the change over the two-year period to actually be a 40% increase?
The percentage change in the number of burglaries over the two-year period is 35% .
The change in burglaries over the two-year period to have a 40% increase is 6.7%.
Let's assume that the annual number of burglaries in 2011 is 1000. After the 50% increase in 2012, the number of burglaries would be: 1000(1.50) = 1500.
The number of burglaries after the 10% reduction in 2013 would be: 1500(.90) = 1350
The change in burglaries over the two-year period = (1350 / 100) - 1 = 35%
In order to determine how much burglaries would have to reduce in order to have a 40% change in burglaries, this formula would be used
(x - 1000) / 1000 = 0.40
x - 1000 = 400
x = 1400
The change in burglaries over the two-year period to have a 40% increase = (1400 / 1500) - 1 = 6.7%
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