Someone please help me answer these questions

1. What is the walking
Aquarium to the Key West Cemetery?
A
2. What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
3. If you were walking 4 miles per hour how long would it take you
to get from the Aquarium to the Cemetery? (Speed= D/T)
4. If you were to take off in a helicopter from Ft. Zachary State
Historic Site and fly directly to the US Naval Air Station at a constant
speed of 20 miles per hour how long would it take?

Answer:

the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface

Explanation:

Answer:

Gravitational force is the force of attraction in which body having certain mass in the universe attracts every other body which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Answer:

There is no kinetic energy.

Explanation:

Since K=1/2mv^2 where m=2122kg and v=0, clearly the car has no kinetic energy as multiplying by 0 results in 0. If the car were moving, there would be kinetic energy.

Answer:

The answer is "[tex]12682.267\ \ \frac{W}{m^2}[/tex]"

Explanation:

Calculating the mass flow rate of fluid:

[tex]m= \rho AV[/tex]

   [tex]= \rho \frac{\pi}{4} D^2\ V\\\\= 100 \times \frac{\pi}{4} \times (0.0127)^2\times 0.2\\\\=0.0253 \ \frac{kg}{s}\\\\[/tex]

Calculating the amount of heat transfer.

[tex]q =m\timesC_p(T_{m,0}-T_{m,i})[/tex]

  [tex]=0.0253 \times 4000 (75-25)\\\\=0.0253 \times 4000(50)\\\\=0.0253 \times 200,000 \\\\= 5060 \ W[/tex]

Calculating the required value for heat flux:

[tex]q"=\frac{q}{A_s}[/tex]

   [tex]=\frac{q}{\pi DL}\\\\= \frac{5060}{\pi \times 0.0127 \times 10}\\\\= 12682.267 \frac{W}{m^2}\\[/tex]

c.  6.6

The x-component of a vector can be either sinθ or cosθ, depending on which angle you are given.

Cosθ always goes with the side of a right triangle that is adjacent to (touches) the given angle.

The projection of a vector quantity on the x axis of a coordinate system.

If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is

x-component = 8· cosine(34°)

x-component = 8 · (0.829)

x-component = 6.6

Therefore,

6.6  is the length of the x-component of the vector.

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Answer:

Δv/Δt

Explanation:

I beat your game SAW.

Answer:

5.06*10^9

Explanation:

EA = σ(πr²)/εo, where area of the wall A = 2πr², on substituting we have

E(2πr²) = σ(πr^2)/εo

E = σ/(2εo)

What we then do is substitute the values from the question into this formula

E = (8.95*10^-6 C/cm^2)(100^2 cm^2 / m^2) / (2*8.85e-12 C^2/N-m^2)

E = 5.06*10^9 N/C

Therefore, the electric field is calculated to be 5.06*10^9 N/C

A) The electric field in front of the wall is  5.05 * 10⁹ N/C,   Away from the wall

B) No the result does not change as distance from wall varies

C) The electric field in front of the conducting wall is :  10.11 * 10⁹ N/C ,   Away from the wall

Given data :

uniform density of nonconducting thin layer = 8.95 µC/cm² = 8.95 * 10⁻² C/m²

E = [tex]\frac{\alpha }{2*\beta }[/tex]  --- ( 1 )

where :  [tex]\alpha[/tex] =  8.95 * 10⁻² C/m²,   [tex]\beta[/tex]= 8.85 * 10⁻¹² N-m²/C²

back to equation ( 1 )

E = ( 8.95 * 10⁻² ) / (  8.85 * 10⁻¹² ) * [tex]\frac{1}{2}[/tex]

  =  5.05 * 10⁹ N/C,

B) The result from part A does not change as the distance from the wall varies. ( No )

Determining the electric field strength for the conducting wall

E = [tex]\frac{\alpha }{\beta }[/tex]  ----- ( 2 )

where : [tex]\alpha[/tex] =  8.95 * 10⁻² C/m²,  [tex]\beta[/tex] = 8.85 * 10⁻¹² N-m²/C²

E = ( 8.95 * 10⁻² ) / ( 8.85 * 10⁻¹² )

  = 10.11 * 10⁹ N/C

Hence we can conclude that;  The electric field in front of the wall is  5.05 * 10⁹ N/C,   Away from the wall.  No the result does not change as distance from wall varies, and The electric field in front of the conducting wall is :  10.11 * 10⁹ N/C ,   Away from the wall.

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Answer:

a

Explanation:

Answer:

b down

Explanation:

because as she is jumping she is bending her nees so the acceleration is down words

Answer:

b down

Explanation:

Answer:

*Doppler effect by the displacement or towards the red

*The microwave temperature of the universe

Explanation:

The expansion of the universe can be visualized in various facts

* the stars and galaxies are moving away from us, this is observed in the Doppler effect by the displacement or towards the red of the hydrogen lines.

* The microwave temperature of the universe that comes from everywhere, this temperature is the rest of the temperature of an initial great explosion (big ban), for which the expanding universe must cool down.

Answer:

For a converging lens, a ray that passes through the focal point exits the lens parallel to the optical axis (ray 3 in part (a)).

Answer:

This may help

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

Answer:

4.37 * 10^-4 J

Explanation:

Energy stored :

mgΔl / 2

m = mass = 10kg ; g = 9.8m/s² ; r = cross sectional Radius = 1cm = 1 * 10-2 m

Δl = mgl / πr²Y

Y = Youngs modulus = Y=3.5 ×10^10 ; l = Length = 1m

Δl = (10 * 9.8 * 1) / π * (1 * 10^-2)²* 3.5 ×10^10

Δl = 98 / 3.5 * π * 10^6

Δl = 0.00000891267

Energy stored :

mgΔl / 2

(10 * 9.8 * 0.00000891267) / 2

= 0.00043672083 J

4.37 * 10^-4 J

Answer:

A closed system.

Explanation:

The three major types of system are: open, closed and isolated. Open system interacts with its surroundings with respect to its particles and energy. A closed system interacts with its surroundings with respect to energy but not its particles. While an isolated system does not interact with its surroundings in any way.

Therefore, after the jar is sealed, it is an example of a closed system. This is because the emitted gas could not escape into the surroundings, but thermal energy was emitted into its surroundings after the chemical reaction has taken place.

It is a Physical Change, the chemical composition of the sugar is not being changed.

Answer:

hardness, luster, color, streak, specific gravity, cleavage, fracture, and tenacity.

Explanation:

doesn't really need one.

Answer:

momentum=31.5

Explanation:

given,

mass(m)=2.1kg

velocity(v)=15m/s

momentum(p)=?

now,

p=mv

p=15×2.1

p=31.5 kgm/s

e xddd  snoAnswer:n

E

xplanation:s no

Answer:

B. 4700 J

Explanation:

Given the following data;

Mechanical energy = 4900J

Mass = 100kg

Velocity = 2m/s

To find the potential energy;

Mechanical energy = kinetic energy + potential energy

First of all, we would determine the kinetic energy of the object;

K.E = ½mv²

K.E = ½*100*2²

K.E = 50*4

K.E = 200 J

Substituting into the equation, we have;

4900 = 200 + P.E

P.E = 4900 - 200

P.E = 4700 Joules

Answer:

Half: 6 cm^2    Whole: 12 cm^2

Explanation:

First, we know that the edges of the cube are 2 cm long. So there are 6 faces on a cube. We do 2x6=12 cm^2 as our total surface area. Then it asks for each half. So you would divide it by 2 and get 6 cm^2 as your half.

Answer:

25.0

Explanation:

Answer:

17.4 -3.1 = 14.3

Explanation:

answer 14.3

Answer:

03:00        

Explanation:

12 HOUR CLOCK    24 HOUR CLOCK

12:00 AM            00:00

01:00 AM            01:00

02:00 AM            02:00

03:00 AM            03:00

04:00 AM            04:00

05:00 AM            05:00

06:00 AM            06:00

07:00 AM            07:00

08:00 AM            08:00

09:00 AM            09:00

10:00 AM            10:00

11:00 AM              11:00

12:00 PM            12:00

01:00 PM            13:00

02:00 PM            14:00

03:00 PM            15:00

04:00 PM            16:00

05:00 PM            17:00

06:00 PM            18:00

07:00 PM            19:00

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09:00 PM            21:00

10:00 PM            22:00

11:00 PM             23:00

Answer:

B. The thrown ball

Explanation:

because you are giving the ball a higher force causing the acceleration to be higher

Answer:

The answer is 100J.

Explanation:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. In this question, the mass is equals to 50kg and the velocity is 2m/s

Now,

25kg×4m/s^2 = 100kgm/s^2 or 100J

so 30.8/13= is 2.369

so round your ans to I dp which is

2.4d/kg

Answer:

a)[tex]|N|=9.83\: N[/tex]  at the top

[tex]|N|=33.37\: N[/tex] at the botton

b) The minimum velocity will be [tex]v=4.43\: m/s[/tex].

Step-by-step explanation:

a) Using the second Newton's law, at the top of the circle we have.

[tex]\Sigma F=ma_{c}[/tex]

The forces at the top are the weight and the normal force.

[tex]W-N=m\frac{v^{2}}{R}[/tex]

[tex]mg-N=m\frac{v^{2}}{R}[/tex]

[tex]N=mg-(m\frac{v^{2}}{R})[/tex]

[tex]N=1.2*9.81-(1.2\frac{6^{2}}{2})[/tex]        

[tex]N=-9.83\: N[/tex]  

[tex]|N|=9.83\: N[/tex]      

At the botton of the circle we have:

[tex]N-W=m\frac{v^{2}}{R}[/tex]

[tex]N-mg=m\frac{v^{2}}{R}[/tex]

[tex]N=1.2*9.81+(1.2\frac{6^{2}}{2})[/tex]  

[tex]|N|=33.37\: N[/tex]

b) If we do the normal force equal to zero we can find the minimum velocity, which means:

[tex]W-0=m\frac{v^{2}}{R}[/tex]

[tex]mg=m\frac{v^{2}}{R}[/tex]

[tex]v=\sqrt{Rg}[/tex]

[tex]v=\sqrt{2*9.81}[/tex]

Therefore, the minimum velocity will be [tex]v=4.43\: m/s[/tex].

I hope it helps you!

Answer:

Erosion is the wearing away if land by forces such as water and wind. It has created things such as mountain peaks, valleys and coastlines.

Answer:

A. 14.14 m/s²

B. 127.26 m/s

C. 572.67 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) of jet = 4250 kg

Force (F) = 60100 N

A. Determination of the acceleration of the jet.

Mass (m) of jet = 4250 kg

Force (F) = 60100 N

Acceleration (a) =?

F = ma

60100 = 4250 × a

Divide both side by 4250

a = 60100 / 4250

a = 14.14 m/s²

B. Determination of the speed of the jet after 9 s.

Initial velocity (u) = 0 m/s

Acceleration (a) = 14.14 m/s²

Time (t) = 9 s

Final velocity (v) =?

v = u + at

v = 0 + (14.14 × 9)

v = 0 + 127.26

v = 127.26 m/s

C. Determination of the distance travelled during the time.

Initial velocity (u) = 0 m/s

Acceleration (a) = 14.14 m/s²

Time (t) = 9 s

Distance travelled (s) =?

s = ut + ½at²

s = (0 × 9) + (½ × 14.14 × 9²)

s = 0 + (7.07 × 81)

s = 0 + 572.67

s = 572.67 m.

Answer:

Kinetic Energy = 36 Joules

Explanation:

Given =

Mass = 2kg

Velocity = 6m/s

Solution =

Kinetic Energy = 1/2 × mv²

Kinetic Energy = 1/2 × 2 × 6 × 6

Kinetic Energy = 36 Joules

The kinetic energy of the string is 36 Joules.

To find the kinetic energy, the values given are

Mass m = 2 kg

speed v = 6m/s

  If an object is in motion, the energy of the object is said to be kinetic energy. The object kinetic energy will be changed unless it has the changes in the mass and speed.

The unit of Kinetic energy is Joules.

Formula for kinetic energy is,

                 K. E = 1/2 mv²

where, K. E - Kinetic energy

          m - mass

          v - velocity

Substituting all the values given,

          K. E = 1/2 ( 2 × 6² )

                 = 1/2 × 2 × 6 × 6

                = 36 J.

So, the kinetic energy of the string is 36 J.

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Answer:

C should be the correct one