Test the claim that the proportion of men who own cats is smaller than 70% at the 0.05 significance level. The null and alternative hypothesis would be:

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

Answer:

Step-by-step explanation:

Let the first number be x

Let the second number be y

For the first equation

2x + 3y = 22

For the second equation

3x + 4y = 31

Multiply the first one by 3 and the second one by 2

That's

First equation

6x + 9y = 66

Second equation

6x + 8y = 62

Subtract the second equation from the first one

That's

6x - 6x + 9y - 8y = 66 - 62

Substitute y = 4 into 2x + 3y = 22

That's

2x + 3(4) = 22

2x = 22 - 12

2x = 10

Divide both sides by 2

Hope this helps you

Answer:

[tex](x + {y}^{2}) = {x}^{2} + 2x {y}^{2} + {y}^{4} [/tex]

Thanks!!!!

Answer:

The percentage of college seniors with "Other" majors is 32%.

Step-by-step explanation:

The total number of college seniors surveyed is, N = 400.

The number of college seniors with "Other" majors is, n = 128.

The percentage of a value of x from N total is given as follows:

[tex]\text{Percentage of}\ x=\frac{x}{N}\times 100\%[/tex]

Compute the percentage of college seniors with "Other" majors as follows:

[tex]\text{Others}\%=\frac{n}{N}\times 100\%[/tex]

              [tex]=\frac{128}{400}\times 100\%\\\\=32\%[/tex]

Thus, the percentage of college seniors with "Other" majors is 32%.

Answer:

(-2,-3)

Step-by-step explanation:

Well in the system,

x−5y=13

4x−3y=1

We need to find x or y in either equation.

Let's do x - 5y = 13 for x.

+5y to both sides

x = 5y + 13

Now we substitute 5y + 13 for y in 4x - 3y = 1.

4(5y + 13) - 3y = 1

20y + 52 - 3y = 1

17y + 52 = 1

-52 to both sides

17y = -51

Divide all by 17

y = -3

Now we can substitute -3 for y in 4x - 3y = 1.

4x - 3(-3) = 1

4x + 9 = 1

-9 to both sides

4x = -8

Divide 4 to both sides

x = -2

Thus,

the solution is (-2,-3).

Hope this helps :)

Answer:

Step-by-step explanation:

x - 5y = 13

4x - 3y = 1

Solve the equation for x

[tex]x - 5y = 13[/tex]

Move '5y' to R.H.S and change it's sign

[tex]x = 13 + 5y[/tex]

Substitute the given value of X into the equation

4x - 3y = 1

[tex]4(13 + 5y) - 3y = 1[/tex]

Solve the equation for y

distribute 4 through the parentheses

[tex]52 + 20y - 3y = 1[/tex]

Collect like terms

[tex]52 + 17y = 1[/tex]

Move constant to R.H.S and change it's sign

[tex]17y = 1 - 52[/tex]

Calculate

[tex]17y = - 51[/tex]

Divide both sides of the equation by 17

[tex] \frac{17y}{17} = \frac{ - 51}{17} [/tex]

Calculate

[tex]y = - 3[/tex]

Now, substitute the given value of y into the equation

x = 13 + 5y

[tex]x = 13 + 5 \times ( - 3)[/tex]

Solve the equation for x

Multiply the numbers

[tex] = 13 - 15[/tex]

Calculate the difference

[tex] = - 2[/tex]

The possible solution of the system is the ordered pair

( x , y )

( x , y ) = ( - 2 , - 3 )

-----------------------------------------------------------------------

Check if the given ordered pair is the solution of the system of equation

[tex] - 2 - 5 \times ( - 3) = 15[/tex]

[tex]4 \times ( - 2) - 3 \times ( - 3) = 1[/tex]

Simplify the equalities

[tex]13 = 13[/tex]

[tex]1 = 1[/tex]

Since all of the equalities are true, the ordered pair is the solution of the system

Hope this helps..

Best regards!!

Answer:

$1137

Step-by-step explanation:

Solution:-

We will define the random variable as follows:

                       X: Monthly social security (OASDI) payments

The random variable ( X ) is assumed to be normally distributed. This implies that most monthly payments are clustered around the mean value ( μ ) and the spread of payments value is defined by standard deviation ( σ ).

The normal distribution is defined by two parameters mean ( μ ) and standard deviation ( σ ) as follows:

                       X ~ Norm ( μ , σ^2 )

We will define the normal distribution for (OASDI) payments as follows:

                       X ~ Norm ( μ , 116^2 )

We are to determine the mean value of the distribution by considering the area under neat the normal distribution curve as the probability of occurrence. We are given that 1/4 th of payments lie above the value of $1214.87. We can express this as:

                      P ( X > 1214.87 ) = 0.25

We need to standardize the limiting value of x = $1214.87 by determining the Z-score corresponding to ( greater than ) probability of 0.25.

Using standard normal tables, determine the Z-score value corresponding to:

                     P ( Z > z-score ) = 0.25 OR P ( Z < z-score ) = 0.75

                     z-score = 0.675

- Now use the standardizing formula as follows:

                     [tex]z-score = \frac{x - u}{sigma} \\\\1214.87 - u = 0.675*116\\\\u = 1214.87 - 78.3\\\\u = 1136.57[/tex]

Answer: The mean value is $1137

Answer:

Where is the table

Step-by-step explanation:

I cant answer without it

Answer:

If I set my alarm to read 8:10 when it is really 8:00 (i.e., it is 10 minutes fast) and the alarm goes off each day when it reads 8:10, it will be reliable but not valid.

Step-by-step explanation:

If I set my alarm to wake me earlier than I need to be woken, it might be in order to give me enough time to adjust to the alarm, and be awake enough to get out of bed before the normal time I need to be out of bed. This method is very reliable, as there is a very little probability of me waking up late, since I have a 10 minutes head start everyday to get out of bed. The problem is that this method is not valid, since I now actually wake earlier than I am supposed to. The extra 10 minutes can actually lead to a disorientation with time.

Answer:

0, 22, 44, 66

Step-by-step explanation:

Given the equation for the model, [tex] d = 11t [/tex] , you can complete the table above by simply plugging in each value of "t" has given in the table to solve for "d".

*When t (seconds) = 0, distance (feet) would be:

[tex] d = 11(0) [/tex]

[tex] d = 0 [/tex]

*When t (seconds) = 2, distance (feet) would be:

[tex] d = 11(2) [/tex]

[tex] d = 22 [/tex]

*When t (seconds) = 4, distance (feet) would be:

[tex] d = 11(4) [/tex]

[tex] d = 44 [/tex]

*When t (seconds) = 6, distance (feet) would be:

[tex] d = 11(6) [/tex]

[tex] d = 66 [/tex]

Answer:

Step-by-step explanation:

If [tex]\sum a_n[/tex] is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

[tex]\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho[/tex]

If [tex]\rho[/tex] < 1, the series converges absolutely

If [tex]\rho > 1[/tex], the series diverges

If [tex]\rho = 1[/tex], the test fails.

Given the series [tex]\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}[/tex]

To test for convergence or divergence using ratio test, we will use the condition above.

[tex]a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}[/tex]

[tex]\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\[/tex]

[tex]\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\[/tex]

aₙ₊₁/aₙ =

[tex]\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\[/tex]

note that any constant dividing infinity is equal to zero

[tex]|\frac{1+2/\infty+1/\infty^2}{5}|\\\\[/tex]

[tex]\frac{1+0+0}{5}\\ = 1/5[/tex]

[tex]\rho = 1/5[/tex]

Since The limit of the sequence given is less than 1, hence the series converges.

Answer:

d. 5250 pounds

Step-by-step explanation:

25 lbs per day

There are 30 days in april

25 lbs/ day * 30 days

1 tiger would eat 750 lbs

There are 7 tigers

7 * 750 =5250 lbs

Answer:

D. 5250 pounds

Step-by-step explanation:

What you need to do is multiply 25 pounds by 30 because there are 30 days in the month of April.

25 x 30 = 750

Then multiply that amount by seven because there are 7 tigers.

750 x 7 = 5250

Answer:

Time taken = 6 sec (Approx)

Step-by-step explanation:

Given:

Total distance = 1/12 mi = 0.083333

Speed of train = 50 mph = 50 / 3600 = 0.01388889 mps

Find:

Time taken

Computation:

Time taken = Total distance / Speed

Time taken = Total distance / Speed of train

Time taken = 0.0833333 / 0.01388889

Time taken = 6 sec (Approx)

Answer:

B. edge 2021

B. is correct for the next one too.

Step-by-step explanation:

B. is the correct answer for the first one
B. is also the correct answer for the second one

Answer:

Step-by-step explanation:

3x+4y = 17 _______ equation 1

-4x -7y= -18 _______ equation 2

muliply by 4 in equation 1

12x + 16y = 68 ______ equation 3

multiply by 3 in equation 2

-12x - 21y = -54 ________ equation 4

add equation 3 & 4

- 5y = 14

y = - 14/5

substitute y in equation 1

3x + 4 (-14/5) =17

3x = 17+ (56/5)

3x =( 85 + 56) / 5

3x = 141/5

x = 47/5

hence (a,b) = (47/5, -14/5)

Answer: He should reject the null hypothesis.

Step-by-step explanation: When using P-Values to decide if you accept or not the alternative hypothesis, compare the p-value with the chosen significance level (α).

In the Mayor's survey:

p-value = 0.04

α = 5% or 0.05

If the p-value is less than α, reject the null hypothesis and accept the alternative. If p-value is greater than or equals α, fail to reject the null hypothesis and don't accept the alternative.

Analysing the Mayor's survey:

p-value = 0.04 < α = 0.05

In conclusion, the Mayor should reject the null hypothesis and accept that the proportion of voters who are aged 18 to 20 is not equal to 10%, i.e., accept the alternative hypothesis: [tex]H_{a}[/tex]: p≠0.10

Answer:

There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.

Step-by-step explanation:

The summary of the statistics from the information given is ;

At 90% confidence interval, 25​% dreaded​ Valentine's Day and the margin of error for the survey was 3.6 percentage points

SO;

[tex]C.I = \hat p \pm M.O.E[/tex]

[tex]C.I = 0.25 \pm 0.036[/tex]

C.I = (0.25-0.036 , 0.25+0.036)

C.I = (0.214, 0.286)

The 90% confidence interval for the proportion of the adult citizens of the nation that dreaded Valentine’s day is 0.214 and 0.286.

There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.

Answer:

11% of the Total the entire voting population

Step-by-step explanation:

Let's bear in mind that the total number of sample candidates is equal to 600.

But out of 600 only 66 preffered candidate A.

The proportion of sampled people to that prefer candidate A to the total number of people is 66/600

= 11/100

In percentage

=11/100 *100/1 =1100/100

=11% of the entire voting population

Answer:

[tex]\boxed{(1, -3)}[/tex]

Step-by-step explanation:

[tex]y+3=2 (x-1)[/tex]

Put equation in slope-intercept form.

[tex]y=mx+b[/tex]

[tex]y=2(x-1)-3[/tex]

[tex]y=2x-2-3[/tex]

[tex]y=2x-5[/tex]

Let x = 1

[tex]y=2(1)-5[/tex]

[tex]y=2-5[/tex]

[tex]y=-3[/tex]

The point (1, -3) lies on the line.

Answer:

[tex]\large \boxed{\sf \ \text{2 feet, 4 seconds, 258 feet } \ }[/tex]

Step-by-step explanation:

Hello,

To know the height of the baseball when it is hit we have to compute h(0), as t = 0 is when the baseball is hit into the air.

[tex]h(0)=-16\cdot 0^2+128 \cdot 0+2=2[/tex]

So, the answer is 2 feet.

h(x) is a parabola which can be written as [tex]ax^2+bx+c[/tex], it means that the vertex is the point (-b/2a,h(-b/2a)).

The baseball reached its maximum height after

   [tex]\dfrac{-b}{2a}=\dfrac{-128}{-2*16}=\boxed{4 \text{ seconds}}[/tex]

And the maximum height of the baseball is h(4).

[tex]h(0)=-16\cdot 4^2+128 \cdot 4+2=-256+512+2=\boxed{258 \ \text{feet}}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer: Yes

Step-by-step explanation:

See explanations in the attached document

Answer:

2/5

Step-by-step explanation:

(7-5)/(6-1)

Step-by-step explanation:

Check that attachment

Hope it helps :)

Hey! :)

________ ☆ ☆_________________________________________

Answer:

There are six trigonometric ratios, which will be under “Explanation”

Step-by-step explanation:

Trigonometric ratios are a measurements of a right triangle.

Here are the all the six trigonometric ratios.

1. cotangent (cot)

2. cosecant (csc)

3. cosine (cos)

4. secant (sec)

5. sine (sin)

6. tangent (tan)

Hope this helps! :)

_________ ☆ ☆________________________________________

By, BrainlyMember ^-^

Good luck!

Answer:

Step-by-step explanation:

Given the half like of a material to be 8.3 hours and the amount of iron-52 left after t hours is modeled by the equation [tex]A(t) = A_0 a^{t}[/tex], we can get A(t) as shown;

At t = 8.3 hours, A(8.3) = 1/2

Initially at t = 0; A(0) = 1

Substituting this values into the function we will have;

[tex]\frac{1}{2} = 1 * a^{8.3}\\\\Taking \ the \ log \ of\ both \ sides;\\\\log(\frac{1}{2} ) = log(a^{8.3} )\\\\log(\frac{1}{2} ) = 8.3 log(a)\\\\\fr-0.30103 = 8.3 log(a)\\\Dividing\ both\ sides\ by \ 8.3\\\\\frac{-0.30103}{8.3} = log(a)\\\\log(a) = - 0.03627\\\\a =10^{-0.03627} \\\\a = 0.919878 (to\ 6dp)[/tex]

Answer: The rule of complements is apprising us that, the person selected will.eithwr have a type B blood or will not have a type B blood

Step-by-step explanations:

Find explanations in the attachment

Answer:

6.96x10^-3

Step-by-step explanation:

0.00696

We move the decimal point to between 6 and 9

since the number with the decimal point should be between 0 and 9.

Then we count the numbers.

6.96x10^-3.

Hope this helps. ❤❤❤

Answer: 6.96 * 10^(-3)

Step-by-step explanation:

In scientific notation, you multiply a number that has a value in the ones place and no value in the tens place by 10 raised to an exponent.

Hope it helps <3

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

[tex]SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000[/tex]

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

[tex]\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}[/tex]

                               [tex]=\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907[/tex]

Use Excel's NORMSINV{0.907} function to find the Z-score.

z = 1.322

Compute the optimal production quantity for the card as follows:

[tex]\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\[/tex]

                                               [tex]=8000+(1.322\times 1000)\\=8000+1322\\=9322[/tex]

Thus, the optimal production quantity is 9,322 cards.

Answer:

(a) C = 80 a = 5.938cm c = 9.097cm

(b) unsure

(c) b= 22.147cm

A = 48.16 degrees

C = 22.82 degrees

Note angle sum higher than 180 due to rounding inaccuracies

Step-by-step explanation:

(a) <C == 180 - (40 + 60) == 80 (Interior angles on triangle have sum of 180 degrees)

side a = (8*sin(40))/sin(60) == 5.938cm by law of sines

side c = (8*sin(80))/sin(

60) == 9.097cm by law of sines

(b) unsure

(c) b^2 = 17^2 + 11^2 - 2(17)(11)cos(104) --> Law of cosines

b^2 = 289 + 121 - 2(187)cos(104)

b^2 = 400 - -90.479

b^2 = 490.479

b = 22.147 cm

sin(A)/17cm = sin(104)/22.147cm

A = arcsin((17/22.147)*sin(104))

A = 48.16 degrees

sin(C)/11cm = sin(104)/22.147cm

C = arcsin((11/22.147)*sin(104))

C = 28.82 degrees

Answer:

57

Step-by-step explanation:

f(15)=4(15)-3

f(15)=60-3

f(15)=57

Hope that helps, tell me if you need more help

Answer:

57

Step-by-step explanation:

If you plug 15 into the equation, you get f(15)=4(15)-3

60-3

57

:)

Answer:

A...............................

Answer:

Answer is 24288.

Step-by-step explanation:

Given that there are 18 senior and 22 junior partners.

To find:

Number of ways of selecting at least one junior partner to form a committee of 3 partners.

Solution:

At least junior 1 member means 3 case:

1. Exactly 1 junior member

2. Exactly 2 junior member

3. Exactly 3 junior member

Let us find number of ways for each case and then add them.

Case 1:

Exactly 1 junior member:

Number of ways to select 1 junior member out of 22: 22

Number of ways to select 2 senior members out of 18: 18 [tex]\times[/tex] 17

Total number of ways to select exactly 1 junior member in 3 member committee: 22 [tex]\times[/tex] 18 [tex]\times[/tex] 17 = 6732

Case 2:

Exactly 2 junior member:

Number of ways to select 2 junior members out of 22: 22 [tex]\times[/tex] 21

Number of ways to select 1 senior member out of 18: 18

Total number of ways to select exactly 2 junior members in 3 member committee: 22 [tex]\times[/tex] 21 [tex]\times[/tex] 18 = 8316

Case 3:

Exactly 3 junior member:

Number of ways to select 3 junior members out of 22: 22 [tex]\times[/tex] 21 [tex]\times[/tex] 20 = 9240

So, Total number of ways = 24288