Answer:
B
Explanation:
The cochlea is the part of the inner ear involved in hearing. It is a spiral-shaped cavity in the bony labyrinth, in humans making 2.75 turns around its axis, the modiolus.
Answer:
the answer is the cochlea
Explanation:
the eardrum receives the sounds and the cochlea "decifers them" so you know what words people are saying or what sound is playing.
a metal rod has drawing pins stuck to it with wax and is heated at one end...
a)what do you think will happen in this experiment?explain your answer
b)how could this experiment be adapted to compare the codnucting properties of different materials?
1. Give 3 examples of waves that carry small amounts of energy?
ANSWER:
Radio wavesMicro wavesInfrared wavesA. Dashed Line
B. Solid Line
please help its worth 10 points
no links please!
Answer:
which question
The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
Determine the mass of water in the kettle.
Use Figure 10.
Give your answer to 2 significant figures.
Any help would be appreciated
Answer:
0.37 kg
Explanation:
I'm not a professor myself, but this is how I worked it out:
using the graph, after 100 seconds, the temperature is 100 degrees Celsius.
If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:
4200 = 155000/(m x 100)
If we rearrange and solve for m, we get 0.37 kg.
I'm not sure if I have done this correctly, feel free to correct me.
Hope this helps!
By using the specific heat capacity formula, the mass of water in the kettle is 0.47 kg
Give that the energy transferred to the water in 100 seconds was 155 000 J and the specific heat capacity of water = 4200 J/kg °C
From the graph;
The initial temperature of the water at time zero is 22 degree Celsius
The final temperature of the water at time 100s is 100 degree Celsius
Change in temperature (T) = 100 - 22 = 78 degree Celsius
To determine the mass of water in the kettle, use the heat energy formula below
E = mcT
Substitute all the parameters into the equation
155000 = 4200 x 78 M
Make M the subject of the formula
M = 155000/327600
M = 0.47 kg
Therefore, the mass of water in the kettle is 0.47 kg
Learn more here: https://brainly.com/question/15475909
A typical electromagnetic signal from a communications satellite might have an intensity of 0.600 pW/m2 at the surface of the Earth. Your satellite dish collects the energy of the electromagnetic signal from the satellite; then your dish passes that energy to its central receiver, where the signal can be processed by a circuit. The area of a satellite dish can be calculated from pi (3.1416) times the radius squared. If your satellite dish has a radius of 0.28 m, and if it is receiving the signal described above, how much electromagnetic energy is reflected to the central receiver in 2.5 minutes
Answer:
The answer is "22.05 pJ"
Explanation:
Using formula:
[tex]Energy=power\times time\\\\Power=Intensity \times area[/tex]
Calculating Energy:
[tex]=0.147 \times 2.5 \times 60 \times 10^{-12}\\\\=22.05\ pJ[/tex]
When the rock or soil of Earth’s surface is moved to another location by water, ice, or wind
A. Deposition.
B. Weathering
C. Erosion
D. Abiotic
A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one of the revolutions of the block, when the block is at the bottom of its path, point AA, the magnitude of the normal force exerted on the block by the track has magnitude 3.90 NN . In this same revolution, when the block reaches the top of its path, point BB, the magnitude of the normal force exerted on the block has magnitude 0.670 NN . Part A How much work was done on the block by friction during the motion of the block from point AA to point BB
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
A man digs a hole in the soil next to a bush. How does the shovel make work easier for the man digging the hole? Check all that apply. The shovel changes the direction of the force the man applies. The man can apply less force. The man has to apply more force. The force applied by the end of the shovel decreases. The force applied by the end of the shovel increases.
Answer:
Following are the solution to the given points:
Explanation:
The shovel shifts the course of the man's force.
Man can use less power.
The strength at the end of the shovel is growing.
Its shovel is a tool that is used to excavate and transfer its large particles. This streamlines the job for all the men to find the pit.
Its machines modify their method that uses force. Its man must therefore use less force to lift the bulk material.
Answer:
The shovel changes the direction of the force the man applies.
The man can apply less force.
The force applied by the end of the shovel increases.
(a,b,e)
Explanation:
edge 2021
what type of charge will an object have if the object contains less protons than electrons?
Answer:
Hello, I believe it would have a negative charge considering protons have a positive charge while elctrons have a negative charge
Explanation:
Describe the forces that are acting on a person who is standing still on a sidewalk, and identify whether the forces are balanced or unbalanced. Describe how the forces would change if the person started walking.
Answer:
a. i His weight and the normal force on him due to the ground
ii The weight and the normal force are balance
b. There are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.
Explanation:
a. i Describe the forces that are acting on a person who is standing still on a sidewalk
His weight and the normal force on him due to the ground act on him while the person is standing on the sidewalk
ii. identify whether the forces are balanced or unbalanced.
The weight and the normal force are balance because, the person does not move in the vertical or horizontal direction.
b. Describe how the forces would change if the person started walking.
When the person starts walking, the backward push due to his leg on the ground and the frictional force between his feet and the ground now acts on him in the horizontal direction. The frictional force acts in the forward direction and tends to move him forward. His weight and normal force on his feet still act vertically and are both balanced since he does not move in the vertical direction.
So, there are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.
Please help me with this (20 points)
Answer:
1. troposphere
2. troposphere (still)
3. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere.
4.The stratosphere is where you'll find the very important ozone layer. The ozone layer helps protect us from ultraviolet radiation (UV) from the sun. In fact, the ozone layer absorbs most of the UV radiation the sun sends to us. Life as we know it wouldn't be possible without this layer of protection.
5. It contains the ozone, which protects Earth from the sun's radiation. Why aren't there many meteors in the troposphere? They burn up before they reach the troposphere.
Explanation:
1.The troposphere is the atmospheric layer closest to the planet and contains the largest percentage (around 80%) of the mass of the total atmosphere. Temperature and water vapor content in the troposphere decrease rapidly with altitude.
2.The layer closest to Earth's surface is the troposphere, reaching from about seven and 15 kilometers (five to 10 miles) from the surface. The troposphere is thickest at the equator, and much thinner at the North and South Poles.
3. Explained in the answer.
4. Explained in the answer.
5. Explained in the answer.
The mineral quartz has a chemical formula of SiO2. What is the formal name
for this compound?
Answer:
Silicon Dioxide
Answer:
Silicon dioxide
Explanation:
A KG object has a speed of 24 M/S if it has 14 J of kinetic energy what is the mass
Un acróbata de masa M, se impulsa hacia arriba con una velocidad v0 desde un
trampolín. Mientras sube, a una altura h sobre el trampolín, recoge a un mono entrenado de masa m. ¿Cuál es la altura máxima que alcanzan el mono y el acróbata?
Answer:
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
Explanation:
Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.
Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.
Parte I
La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).
[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)
Donde:
[tex]M[/tex] - Masa del acróbata.
[tex]g[/tex] - Constante gravitacional.
[tex]v_{o}[/tex] - Rapidez inicial del acróbata.
[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.
[tex]h[/tex] - Altura inicial del mono.
Parte II
La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:
[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)
Donde:
[tex]m[/tex] - Masa del mono.
[tex]z[/tex] - Altura máxima del sistema acróbata-mono.
De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]
[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]
[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]
Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]
[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
Give me two examples of a pushing force and two examples of a pulling force:
Answer:
A pushing force example could be a button, like on a keyboard.
Another example would be a piston.
An example of a pulling force could be a lever.
Another example could be rope.
Hope this helps! c:
Identify which method of thermal energy transfer would be fastest through a vacuum, which would be fastest through a gas, and which would be fastest through a solid.
Answer:
vacuum-radiation
gas-convection
solid-conduction
Explanation:
If a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?
Answer:
12 N
Explanation:
Given that a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?
Solution
M = 12 kg
T = 5 s
The formula to use will be
F = ma
Where
Acceleration a = change in velocity/ time
Acceleration a = ( 10 - 5 ) / 5
Acceleration a = 5 / 5
Acceleration a = 1 m/s^2
Substitutes a into the formula above
F = ma
F = 12 × 1
F = 12 N
Therefore, the amount of force applied to increase the speed of the object is 12 N.
Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are
still 4.8 m high, they are traveling at a speed of 8.0 m/s.
a) Calculate the Eg. [write here]
b) Calculate theEk [write here]
c) Calculate the Etotal. [write here)
Answer:
a) Eg = 3,060.72 j
b) Ek = 2,080 j
c) Etotal = 5,140.72 j
Explanation:
The given parameters are;
The mass of the person, m = 65 kg
The height of the person, h = 4.8 m
The speed of the person, v = 8.0 m/s
a) The gravitational potential energy, [tex]E_g[/tex] = m·g·h
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j
Eg = 3,060.72 j
b) The kinetic energy, Ek = 1/2·m·v²
∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j
Ek = 2,080 j
c) The constant total Mechanical Energy, Etotal = Eg + Ek
∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j
Etotal = 5,140.72 j.
What variable do you think made this airplane fly the farthest?
Answer:
How does the weight of the nose on a paper
airplane affect the distance it will travel
when measured in centimeters?
EXPERIMENT CONCLUSION: (Explain whether or
not your data supports, or fails to support your identified
prediction. Explain why, including facts and details!)
The distance did increase when I added 1 paper clip.
However, I was surprised that the distance decreased
when I added a second paper clip. I believe this
happened because the nose of the plane became too
heavy. When the plane was released, the nose of the
plane descended much quicker. I think the plane was
more balanced in weight when only 1 clip was on the
nose.
A block of density 8.9g/cm³ measures 5cm by 2cm, Given that the force of gravity is 10N/kg. Determine the maximum pressure
Answer:
Maximum pressure = 4450 N/m²
Explanation:
We'll begin by calculating the volume of the block. This can be obtained as follow:
Volume (V) = 5 cm × 3 cm × 2 cm
V = 30 cm³
Next, we shall determine the mass of the block. This can be obtained as follow:
Density = 8.9 g/cm³
Volume = 30 cm³
Mass =?
Density = mass /volume
8.9 = mass / 30
Cross multiply
Mass = 8.9 × 30
Mass = 267 g
Next, we shall covert 267 g to Kg.
1000 g = 1 Kg
Therefore,
267 g = 267 g × 1 Kg / 1000
267 g = 0.267 Kg
Thus, the mass of the block is 0.267 Kg
Next, we shall determine the force.
Force of gravity (g) = 10 N/Kg
Mass (m) = 0.267 Kg
Force (F) =?
F = mg
F = 0.267 × 20
F = 2.67 N
Next, we shall determine the minimum area since we are trying to obtain the maximum pressure. This can be obtained as follow:
Minimum area = 3 cm × 2 cm
Covert each measurement to metre (m) by dividing each measurement by 100
Minimum area = 0.03 m × 0.02 m
Minimum area = 0.0006 m²
Finally, we shall determine the maximum pressure. This can be obtained as follow:
Force (F) = 2.67 N
Minimum area = 0.0006 m²
Maximum pressure =?
Maximum pressure = Force /minimum area
Maximum pressure = 2.67 / 0.0006
Maximum pressure = 4450 N/m²
David put a plant in a black box as shown. The box also had a black lid to cover the front. David only opened the box to add water to the plant. The plant stayed in the box for 10 days. When David took the plant out of the box on the tenth day, the plant was dead. Why did the plant dead only after ten days in the box?
Answer:
the plant died because of lack of sunlight
Explanation:
A plant gets its food from the photosynthesis process, which combines CO₂ and H₂0 into carbohydrates, the two substances are in the box, but for this they need energy from sunlight.
CO₂ + H₂O + Sunlight /chlorophyll → (CH₂0)ₙ + O₂
the extra oxygen is released into the atmosphere.
Therefore the plant died because of lack of sunlight
PLZZ IF ANYONE KNOWS SCIENCE HELP ME PLZ I this is so confusing :(
ill liderally make a question with 50 and a brainliest since you helped me ;-;
Answer:
i think it would be either b or c because....
Explanation:
"The desert biome is best adapted for aloe because aloe plant usuallly grows in open area under sunlight exposure where the intensity of sunlight is very high. Its grows in very rocky, dry and open areas."
tic energy
15.The energy changes that take place when a stone falls freely from rest to
the ground can be orderly arranged as
A. Kinetic energy → Potential energy
B. Sound energy → Potential energy
C. Potential energy
→ Sound energy
D. Potential energy
16.A ductile material is that which
→ Sound energy
→ Heat.
→ Kinetic energy → Heat.
→ Kinetic energy → Heat.
→ Kinetic energy → Heat energy
→ Sound.
Answer:
15. potential- kinetic -potential
16. I don't understand
Ductile materials are materials that can be drawn into wire e.g copper
Answer:
15.A
Explanation:
a falling objects posses kinetic energy whiles objects at rest has potential energy
what is the most dense type of stars?
Answer:
A neutron star is the most intensely dense object in all the universe. Of course, the argument can be made that a black hole is the most dense, but considering that a black hole is technically beyond the event horizon, it is neutron stars that get the top spot for the being the ‘most dense’.
Explanation:
:) please mark me as brainliest, thanks
When two different species compete for resources, it is______ competition.
Answer:
it is a interspecific competition
Explanation:
i just took a test with this question
GIVING BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 23pts-
2-Write True(T) if the sentence is true. Write False(F) if the sentence is
false.
Momentum is a measure of the motion of a body equal to the product of its
mass and acceleration due to gravity.
Impulse is defined as the force times the time interval.
The tendency of an object to resist a change in motion is called Force
If the speed of an object is doubled, its momentum is multiplied by 2
Sudden change in momentum in a collision, results in a large force that can
cause injury.
Safety features of modern cars ensures that energy is not absorbed when vehicles
stop:
Crumple zones are built into cars to increase the duration of crashes.
What is the frequency of a wave with a period of 8s?
What is inertia and how can you increase an object's inertia?
Answer:
Explanation:
Inertia is the property of a body by virtue of which it opposes any agency that attempts to put it in motion or, if it is moving, to change the magnitude or direction of its velocity.
The more mass, the more inertia. If you increase the mass of the object then you increase the inertia.
Answered by the ONE & ONLY #QUEEN
HOPED THIS HELPED!!