Answer:
100% = 65 Gallons; 70% = 45.5 Gallons
Step-by-step explanation:
The important piece of information here is that 13 gallons of water makes the container 1/5 of the way full, aka 20%. If the question is simply, how many gallons will it hold, then we multiply 13 by 5 to get 100% at 65 gallons. To get the amount held at 7/10, or 70%, we simply multiply 65 with 7/10 to get 45.5 gallons.
Cheers.
Which of the following is the solution to the equation 25^(z + 2) = 125? (6 points) Answer choices are 1) z = 5.5 2) z = 3.5 3) z = −2.5 4) z = −0.5
Step-by-step explanation:
a. z = 5.5
25 ^( 5.5 - 4 ) = 125
25 ^ (1.5) = 125
125 = 125
z = 5.5
PlZzzzz follow me
Translate and solve: 3x less than two times the sum of 2X and one is equal to the sum of 2 and 5
Answer:
The answer is x = 5Step-by-step explanation:
The statement
3x less than two times the sum of 2X and one is written as
2( 2x + 1) - 3x
the sum of 2 and 5 is written as
2 + 5
Equate the two statements
We have
2( 2x + 1) - 3x = 2+5
Expand
4x + 2 - 3x = 7
Simplify
4x - 3x = 7 - 2
We have the final answer as
x = 5Hope this helps you
A bag of marbles contains 4 green marbles, 3 blue marbles, 2 red marbles, and 5 yellow marbles. How many total possible outcomes are there when choosing a marble from the bag?
Answer:
its 14/C
Step-by-step explanation:
i got i right on edg U^U
Answer:
16
Step-by-step explanation:
i did edge test yea dont be imma fake :***
Please help. I’ll mark you as brainliest if correct!
Answer:
Step-by-step explanation:
children=c
adults=a
c+a=359
a=359-c
2.75c+6a=1621
2.75 c+6(359-c)=1621
2.75 c+2154-6c=1621
-3.25 c=1621-2154
-3.25 c=-533
[tex]-\frac{325}{100} c=-533\\-\frac{13}{4} c=-533\\c=-533 \times \frac{-4}{13} =41 \times 4=164 \\children=164\\adults=359-164=195[/tex]
Which of the following values cannot be probabilities? 3 / 5, , , , , , , 2 5 / 3 1.39 − 0.57 1 0 0.04 Select all the values that cannot be probabilities. A. 0 B. 2 C. 3 5 D. − 0.57 E. 0.04 F. 1.39 G. 5 3 H. 1
Question:
Which of the following values cannot be probabilities? 3 / 5, 2, 5 / 3, 1.39, −0.57, 1, 0, 0.04 Select all the values that cannot be probabilities.
A. 0
B. 2
C. 3 / 5
D. − 0.57
E. 0.04
F. 1.39
G. 5 / 3
H. 1
Answer:
B, D, F, G
Step-by-step explanation:
The probability, P(A), of an event A occurring is given by;
0 ≤ P(A) ≤ 1
This means that the probability of an event happening is always between 0 and 1 (both inclusive).
Therefore;
=> 3 / 5 is a valid probability value as;
0 ≤ 3/5 ≤ 1
=> 2 is NOT a valid probability value as 2 is not within the range 0 and 1
=> 5 / 3 is NOT a valid probability value as 5 / 3 = 1.6667 is not withing the range 0 and 1
=> 1.39 is NOT a valid probability value
=> -0.57 is NOT valid. Probability values are not and cannot be negative.
=> 1 is a valid probability value. This just means that the probability that an event will occur is 100% likely.
=> 0 is a valid probability value. This just means that the probability that an event will occur is 0% likely.
=> 0.04 is valid as;
0 ≤ 0.04 ≤ 1
When a force of 36 Newtons is applied to springs S1 and S2, the displacement of the springs is 6 centimeters and 9 cm, respectively. What is the difference between the spring constants of the two springs?
Answer:
200 N/m
Step-by-step explanation:
Rearranging the formula F = kx, you find that k = F/x. For the first spring,
F = 36 N and x = 0.06 m (6 cm). So the spring constant, F/x, is 36N/0.06m = 600 N/m
For the second spring, F = 36 N and x = 0.09 m. F/x = 36N/0.09m = 400 N/m
The difference between these values is 200 N/m, and that's the answer.
Find the length of BC
Answer:
The answer is option AStep-by-step explanation:
To find the length of BC we use tan
tan ∅ = opposite / adjacent
From the question
AC is the opposite
BC is the adjacent
So we have
tan 61 = AC / BC
tan 61 = 47/BC
BC = 47/tan 61
BC = 26.05Hope this helps you
A firm just paid an annual dividend of $1.40 and increases that dividend by 2 percent each year. How do you find the price if the firm's stock at year 4 if the discount rate is 13 percent?
Answer:
14.05
Step-by-step explanation:
We have the following:
Current Dividend = D0 = $ 1.40
g = growth rate = 2%
r = discount rate = 13%
Dividend in Year 5
= D5 = D0 * (1 + g) ^ 5
= $ 1.40 * (1 + 2%) ^ 5
= $ 1.40 * (1.02) ^ 5
Firm Stock Price at the end of year 4 = Dividend in Year 5 / (r - g)
= $ 1.40 * (1.02) ^ 5 / (13% -2%)
= $ 1.40 * (1.02) ^ 5 / (0.13 - 0.02)
Therefore, firm stock at the end of year 4 is
P4 = $ 1.40 * (1.02) ^ 5 / (0.13 - 0.02) = 14.05
Which expression is equivalent to 2m^2 - m^2(7-m)+6m^2?
Answer:
[tex]m^3+m^2[/tex]
Step-by-step explanation:
=> [tex]2m^2-m^2(7-m)+6m^2[/tex]
Collecting like terms and expanding the brackets
=> [tex]2m^2+6m^2-7m^2+m^3[/tex]
=> [tex]8m^2-7m^2+m^3[/tex]
=> [tex]m^2+m^3[/tex]
=> [tex]m^3+m^2[/tex]
Use identities to find values of the sine and cosine functions of the function for the angle measure
a. theta, given that cos2theta=28/53 and 0theta < theta < 90degrees
b. 2theta, given sin theta= - sqrt 7 over 5 and cos theta > 0
c. 2x, given tan x=2 and cos x<0
Answer:
Step-by-step explanation:
a) Given cos2theta=28/53 and 0degrees< theta < 90degrees
From cos2theta=28/53
[tex]2\theta = cos^{-1}\frac{28}{53}[/tex]
[tex]2\theta = cos^{-1}0.5283\\ \\2\theta = 58.12\\\\Dividing\ both \ sides\ by \ 2\\\\\frac{2\theta}{2} = \frac{58.12}{2}\\ \\\theta = 29.06^0[/tex]
b) Given
[tex]sin\theta = \frac{-\sqrt{7} }{5} \\\\\theta = sin^{-1} \frac{-\sqrt{7} }{5}\\\\\\\theta = sin^{-1} \frac{-2.6458}{5}\\\\\theta = sin^{-1} -0.5292\\\\\theta = -31.95^0[/tex]
If cos theta [tex]\gneq[/tex] 0, this means we need to look for the quadrant where sin is negative and cos is positive. That will be the fourth quadrant. In the fourth quadrant, theta = 360 - 31.95° = 328.05°
2theta = 2 * 328.05
2theta = 656.1°
c) Given tan x=2 and cos x<0, lets find the angle of x first.
If tan x = 2
x = tan^-1 2
x = 63.4°
Sine cos is less than 0, then we need to find the angle of x where tan is positive and cos is negative. That will be the third quadrant. In the third quadrant, ew value of x = 180+63.4
x = 243.4°
Since we are to find 2x,
2x = 2(243.4)
2x = 486.8°
what is 99/00+44(55)99
Answer:
undefined! one cannot divide by 0
Step-by-step explanation:
Answer:
undefined!
Step-by-step explanation:
Use Green's Theorem to evaluate F · dr. C (Check the orientation of the curve before applying the theorem.)F(x, y) = y cos(x) − xy sin(x), xy + x cos(x) , C is the triangle from (0, 0) to (0, 8) to (2, 0) to (0, 0)
Notice that C has a clockwise orientation. By Green's theorem, we have
[tex]\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\iint_D\left(\frac{\partial(xy+x\cos x)}{\partial x}-\frac{\partial(y\cos x-xy)}{\partial y}\right)\,\mathrm dx\,\mathrm dy[/tex]
where D is the triangule region with C as its boundary, given by the set
[tex]D=\{(x,y)\mid0\le x\le2\land0\le y\le8-4x\}[/tex]
So we have
[tex]\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\int_0^2\int_0^{8-4x}((y+\cos x-x\sin x)-(\cos x-x\sin x))\,\mathrm dy\,\mathrm dx[/tex]
[tex]\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\int_0^2\int_0^{8-4x}y\,\mathrm dy\,\mathrm dx=\boxed{-\dfrac{64}3}[/tex]
I NEED THE ANSWER AS SOON AS POSSIBLE PLEASE!!
Answer:
[tex]\Large \boxed{\sf \ \ 4\sqrt{a^2+b^2} \ \ }[/tex]
Step-by-step explanation:
Hello,
You can use Pythagoras in the 4 right triangles.
For one triangle it comes [tex]\sqrt{a^2+b^2}[/tex].
Then for the polygon it gives [tex]4\cdot \sqrt{a^2+b^2}[/tex].
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Find x round to the nearest tenth
Answer:
83.0
Step-by-step explanation:
We have all three sides and the only thing we're missing is the X angle. And that's okay!
All you have to do is plug in the numbers into each variable. In this case if you are going to solve for X, you should use this equation.
[tex]x^2=y^2+z^2-2yzcosX[/tex]
x = 17ft
y = 8ft
x = 16fi
Then you can algebraically solve for cosX, and then use the inverse of cosx to get the angle.
Find the critical point of the given function and then determine whether it is a local maximum, local minimum, or saddle point.
Answer:
critical point of the given function f(x,y) = x²+y²+2xy is from line y = -x is the critical point of the function f(x0,y0) = 0
and it local minimum.
Step-by-step explanation:
Let the given function be;
f(x,y) = x²+y²+2xy
From above function, we can locate relative minima, maxima and the saddle point
f(x,y) = x²+y²+2xy = (x+y)²
df/dx = 2x+2y = 0 ---- (1)
df/dy =2y+2x = 0 ---- (2)
From eqn 1 and 2 above,
The arbitrary point (x0,y0) from line y = -x is the critical point of the function f(x0,y0) = 0
Then, from f(x,y) >= 0 for arbitrary (x,y) € R^n, the arbitrary point from the line x = -y is local minima of the function f.
Bernard works for a business that sells and repairs tires. He can repair 24 tires in an 8 hour work day. What is Bernard's unit rate for the number of tires repaired in one hour?
Step-by-step explanation:
Unit rate = 24 ÷ 8 = 3 tires
Answer:
Step-by-step explanation:
24 tires/8hours
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Round all answers using one decimal place.
Answer:
The missing side is [tex]B = 6.0\ cm[/tex]
The missing angles are [tex]\alpha = 56.2[/tex] and [tex]\theta = 93.8[/tex]
Step-by-step explanation:
Given
[tex]A = 10\ cm[/tex]
[tex]C = 12\ cm[/tex]
[tex]\beta = 30[/tex]
The implication of this question is to solve for the missing side and the two missing angles
Represent
Angle A with [tex]\alpha[/tex]
Angle B with [tex]\beta[/tex]
Angle C with [tex]\theta[/tex]
Calculating B
This will be calculated using cosine formula as thus;
[tex]B^2 = A^2 + C^2 - 2ACCos\beta[/tex]
Substitute values for A, C and [tex]\beta[/tex]
[tex]B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30[/tex]
[tex]B^2 = 100 + 144 - 240 * 0.8660[/tex]
[tex]B^2 = 100 + 144 - 207.8[/tex]
[tex]B^2 = 36.2[/tex]
Take Square root of both sides
[tex]B = \sqrt{36.2}[/tex]
[tex]B = 6.0[/tex] (Approximated)
Calculating [tex]\alpha[/tex]
This will be calculated using cosine formula as thus;
[tex]A^2 = B^2 + C^2 - 2BCCos\alpha[/tex]
Substitute values for A, B and C
[tex]A^2 = B^2 + C^2 - 2BCCos\alpha[/tex]
[tex]10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha[/tex]
[tex]100 = 36 + 144 - 144Cos\alpha[/tex]
Collect Like Terms
[tex]100 - 36 - 144 = -144Cos\alpha[/tex]
[tex]-80 = -144Cos\alpha[/tex]
Divide both sides by -144
[tex]\frac{-80}{-144} = Cos\alpha[/tex]
[tex]0.5556 = Cos\alpha[/tex]
[tex]\alpha = cos^{-1}(0.5556)[/tex]
[tex]\alpha = 56.2[/tex] (Approximated)
Calculating [tex]\theta[/tex]
This will be calculated using cosine formula as thus;
[tex]C^2 = B^2 + A^2 - 2BACos\theta[/tex]
Substitute values for A, B and C
[tex]12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta[/tex]
[tex]144 = 36 + 100 - 120Cos\theta[/tex]
Collect Like Terms
[tex]144 - 36 - 100 = -120Cos\theta[/tex]
[tex]8 = -120Cos\theta[/tex]
Divide both sides by -120
[tex]\frac{8}{-120} = Cos\theta[/tex]
[tex]-0.0667= Cos\theta[/tex]
[tex]\theta = cos^{-1}(-0.0667)[/tex]
[tex]\theta = 93.8[/tex] (Approximated)
Gena wants to estimate the quotient of –21.87 divided by 4.79. Which expression shows the best expression to estimate the quotient using front-end estimation? Negative 21 divided by 4 Negative 21 divided by 5 Negative 20 divided by 4 Negative 20 divided by 5
Answer:
-21/5 = -4.2
Step-by-step explanation:
-21.87 / 4.79 = -4.5657.....
So, the quotients is -4
Now, Let's see who's quotient is equal to think one:
-21/4 = -5.25
-21/5 = -4.2
-40/4 = -5
-20/5 = 4
Answer:
-21/5 = -4.2
Step-by-step explanation:
Imagine working in a freelance developer earning 80 USD per hour how many weeks you will have to take a 12 hour flight on a weekday you can either book a flight for ticket for 11 AM for 900 USD or 11 PM flight or 11 USD there is no Internet boards if you take the day off like you will lose a day of work what would you do
Answer:
pay the 11 AM ticket
Step-by-step explanation:
Note that the flight last for 12 hours, and assuming the freelance developer can still work (have access to the internet) on the airplane throughout the flight, he stand to earn $960 ($80*12), which will still cover the cost of the flight with a profit of $60 ($960-900).
However, if he decides to pay the $11 flight ticket and there is no Internet on boards; there by losing a day of work, he stand to have lost working time which would earn with $900.
Therefore, the best choice is to pay the 11 AM ticket.
Please do either 40 or 39
Answer:
y = 1.8
Step-by-step explanation:
Question 39).
Let the operation which defines the relation between a and b is O.
Relation between a and b has been given as,
a O b = [tex]\frac{(a+b)}{(a-b)}[/tex]
Following the same operation, relation between 3 and y will be,
3 O y = [tex]\frac{3+y}{3-y}[/tex]
Since 3 O y = 4,
[tex]\frac{3+y}{3-y}=4[/tex]
3 + y = 12 - 4y
3 + y + 4y = 12 - 4y + 4y
3 + 5y = 12
3 + 5y - 3 = 12 - 3
5y = 9
[tex]\frac{5y}{5}=\frac{9}{5}[/tex]
y = 1.8
Therefore, y = 1.8 will be the answer.
Suppose you are climbing a hill whose shape is given by the equation z = 1600 − 0.005x2 − 0.01y2, where x, y, and z are measured in meters, and you are standing at a point with coordinates (120, 80, 1464). The positive x-axis points east and the positive y-axis points north. (a) If you walk due south, will you start to ascend or descend?
Answer:
you will start to ascend at the rate of 1.6
Step-by-step explanation:
Walking south, it's the negative part of a coordinate, so the unit vector at this point is; u = (0,-1)
We are told that the equation z = 1600 − 0.005x² − 0.01y²
Therefore, we have;
∇z = ((δ/δx)i + (δ/δx)j)(1600 − 0.005x² − 0.01y²)
This gives;
∇z = -0.005(2x)i - 0.01(2y)j
∇z = <-0.01x - 0.02y>
coordinates are (120, 80, 1464).
Thus;
∇z(120, 80, 1464) = <-0.01(120), - 0.02(80)> = <-1.20, -1.60>
D_uf = <-1.20, -1.60> × <0, - 1>
D_uf = 0 + 1.6
D_uf = 1.6
So, you will start to ascend at the rate of 1.6
-2x(x+3)-(x+1)(x-2)=
Answer:
-3x^2 -5x +2
Step-by-step explanation:
-2x(x+3)-(x+1)(x-2)=
Distribute
-2x^2 -6x -(x+1)(x-2)
Foil
-2x^2 -6x -(x^2 -2x +x -2)
Combine like terms
-2x^2 -6x -(x^2 -x -2)
Distribute the minus sign
-2x^2 -6x -x^2 +x +2
Combine like terms
-2x^2 -x^2 -6x +x +2
-3x^2 -5x +2
Answer:
[tex]\huge\boxed{-2x(x+3)-(x+1)(x-2)=-3x^2-5x+2}[/tex]
Step-by-step explanation:
[tex]-2x(x+3)-(x+1)(x-2)[/tex]
Use the distributive property: a(b + c) = ab + ac
and FOIL: (a + b)(c + d) = ac + ad + bc + bd
[tex]=(-2x)(x)+(-2x)(3)-\bigg[(x)(x)+(x)(-2)+(1)(x)+(1)(-2)\bigg]\\\\=-2x^2-6x-\bigg(x^2-2x+x-2\bigg)=-2x^2-6x-x^2-(-2x)-x-(-2)\\\\=-2x^2-6x-x^2+2x-x+2[/tex]
Combine like terms:
[tex]=(-2x^2-x^2)+(-6x+2x-x)+2=-3x^2+(-5x)+2\\\\=-3x^2-5x+2[/tex]
42.
You were given the four numbers below and were asked to find the sum
of the first two numbers, the difference between the last two numbers,
the quotient when the sum is divided by the difference and the product
when the quotient is multiplied by 8. What is the final answer?
6458 2994
7013
6945
Answer:
1112
Step-by-step explanation:
6458 + 2994 = 9452
7013 - 6945 = 68
9452/68 = 139
139 * 8 = 1112
Find the common difference of the arithmetic sequence. 4, 10, 16, 22, . . .
Answer:
6
Step-by-step explanation:
10 - 4 = 6
16 - 10 = 6
22 - 16 = 6
Answer:6
Step-by-step explanation:
1) 10-4=6
2) 16-10=6
3) 22-16=6
Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary.
1.26 0.98 1.07 0.97 1.28 0.89 1.14 0.58 1.42 0.59 0.96
Answer:
Five-number summary in ascending order: [tex] 0.58, 0.89, 0.98, 1.26, 1.42 [/tex]
Step-by-step Explanation:
The number summary, in ascending order, includes the minimum value, maximum value, median value, upper quartile and lower quartile.
To find each of the above values, first, order the data set in ascending order. Our values given, when ordered, would be:
0.58, 0.59, 0.89, 0.96, 0.97,| 0.98|, 1.07, 1.14, 1.26, 1.28, 1.42
1.The minimum value (the least value or lower value in the given data set).
From the ordered data set, minimum value = 0.58
2. The maximum value is the highest value in the data set = 1.42
3. Median value is the middle value of the data set. The middle value is the 6th value = 0.98.
The median value divides the data set into lower and upper region, as shown below.
0.58, 0.59, 0.89, 0.96, 0.97,|0.98|, 1.07, 1.14, 1.26, 1.28, 1.42
4. Lower Quartile (Q2) is the middle value of the lower region = 0.89, as shown below,
0.58, 0.59, [0.89], 0.96, 0.97,|0.98|, 1.07, 1.14, 1.26, 1.28, 1.42
5. Upper Quartile (Q3) is the middle value of the upper region = 1.26, as shown below.
0.58, 0.59, 0.89, 0.96, 0.97,|0.98|, 1.07, 1.14, [1.26], 1.28, 1.42
: this is the middle value of lower region, after our median divides the data set into two.
0.58, 0.59, 0.89, 0.96, 0.97,|0.98|, 1.07, 1.14, 1.26, 1.28, 1.42
Therefore, the five-number summary in ascending order is as follows: [tex] 0.58, 0.89, 0.98, 1.26, 1.42 [/tex]
Min = 0.58
Q1 = 0.89
Median = 0.98
Q3 = 1.26
Max = 1.42
A box plot has been constructed using the five-number summary. Check the attachment below.
The min value is represented by the whisker that starts from your left and connects to the rectangular box.
The max value is indicated at the extreme end of the other whisker that you have from the end of the rectangular box to your far right.
The median value is indicated by the vertical line that divides the rectangular box into 2.
The lower quartile is indicated at the beginning of the rectangular box, while the upper quartile is located at the end of the rectangular box.
TWhich equation has the same solution as this equation. X^2 - 8x + 12 = 0
x² - 8x + 12 = 0
First of all we need to find the roots
Δ = b² - 4.a.c
Δ = (-8)² - 4 . 1 . 12
Δ = 64 - 4. 1 . 12
Δ = 16
Has 2 real roots
x = (-b +- √Δ)/2a
x' = (--8 + √16)/2.1
x'' = (--8 - √16)/2.1
x' = 12 / 2
x'' = 4 / 2
x' = 6
x'' = 2
So our equation can be solved with x = 6 and x = 2, therefore we can create two other equations with the same roots
x - 6 = 0
and
x - 2 = 0
Answer:
(x – 4)2 = 4
Step-by-step explanation:
Find the slope of the line that passes through (1, 14) and (4,9)
Which two numbers in the points represent y values? Select both in the
list
Answer:
14 and 9
Step-by-step explanation:
Y values are always the second number in the parenthesis. The X value is the first one. I like to think of Y being dependent on X, so X goes first, then Y.
Which of the following functions best describes this graph ?
Answer:
answer D
Step-by-step explanation:
Lets have a look to the graph and to the each of given functions.
As we can see in graph it intersects X in points (-3;0) and (-6;0) that means the function has the roots x1=-3 and x2=-6
Function A has the roots x1=+3 and x2=+6 => doesn' t fit
Function B has only 1 root x=2 , so can be factorized y=(x-2)^2 => doesn' t fit
Function C has 2 roots x1=4 and x2=-5 => doesn' t fit
Function D can be factotized as y=(x+6)*(x+3) so has 2 roots x1=-6 x2=-3 => exactly what we need!!!
We can also notice that the coefficient near x² is equal to 1 and is positive.
That means the legs of the graph directed up,- this is exactly like in our graph. It gives us extra argument why we choose D.
helpppppppppppppppppppppp i will give star thanks bralienst
Answer:
90/x=70/100 that's my answer
[tex]90 \x = 70 \100[/tex]
Answer:
90/x = 70/100
Step-by-step explanation:
Is means equals and of means multiply
90 = 70% *x
Changing to decimal form
90 = .70x
Changing to fraction form
90 = 70/100 *x
Divide each side by x
90/x = 70/100
Find the mean and standard deviation for each binomial random variable:
Answer: a) Mean = [tex]=37.80[/tex]
Standard deviation=[tex]=1.9442[/tex]
b) Mean = [tex]56.00[/tex]
Standard deviation=[tex]4.0988[/tex]
c) Mean = [tex]=24[/tex]
Standard deviation=[tex]2.4495[/tex]
Step-by-step explanation:
To compute Mean and standard deviation , we use following formula:
Mean = [tex]n\pi[/tex]
Standard deviation=[tex]\sqrt{n\pi(1-\pi)}[/tex]
a. [tex]n=42,\ \pi=0.90[/tex]
Mean = [tex]42\times0.90=37.80[/tex]
Standard deviation=[tex]\sqrt{42(0.90)(0.10)}=\sqrt{3.78}\approx1.9442[/tex]
b. [tex]n=80,\ \pi=0.70[/tex]
Mean = [tex]80\times0.70=56.00[/tex]
Standard deviation=[tex]\sqrt{80(0.70)(0.30)}=\sqrt{16.8}\approx4.0988[/tex]
c. [tex]n=32,\ \pi=0.75[/tex]
Mean = [tex]32\times0.75=24[/tex]
Standard deviation=[tex]\sqrt{32(0.75)(0.25)}=\sqrt{6}\approx2.4495[/tex]