Answer:
weight = float(input("Enter the weight of the package: "))
distance = float(input("Enter the distance to be sent: "))
weight_charge = 0
if weight <= 2:
weight_charge = 0.25
elif 2 < weight <= 10:
weight_charge = 0.3
elif 10 < weight <= 20:
weight_charge = 0.45
elif 20 < weight <= 50:
weight_charge = 1.75
if int(distance / 100) == distance / 100:
d = int(distance / 100)
else:
d = int(distance / 100) + 1
total_charge = d * weight_charge
print("The charge is $", total_charge)
Explanation:
*The code is in Python.
Ask the user to enter the weight and distance
Check the weight to calculate the weight_cost for 100 miles. If it is smaller than or equal to 2, set the weight_charge as 0.25. If it is greater than 2 and smaller than or equal to 10, set the weight_charge as 0.3. If it is greater than 10 and smaller than or equal to 20, set the weight_charge as 0.45. If it is greater than 20 and smaller than or equal to 50, set the weight_charge as 1.75
Since those charges are per 100 miles, you need to consider the distance to find the total_charge. If the int(distance / 100) is equal to (distance / 100), you set the d as int(distance / 100). Otherwise, you set the d as int(distance / 100) + 1. For example, if the distance is 400 miles, you need to multiply the weight_charge by 4, int(400/100) = 4. However, if the distance is 410, you get the int(400/100) = 4, and then add 1 to the d for the extra 10 miles.
Calculate the total_charge, multiply d by weight_charge
Print the total_charge
During TCP/IP communications between two network hosts, information is encapsulated on the sending host and decapsulated on the receiving host using the OSI model. Match the information format with the appropriate layer of the OSI model.
a. Packets
b. Segments
c. Bits
d. Frames
1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer
Answer:
a. Packets - Network layer
b. Segments - Transport layer
c. Bits - Physical layer
d. Frames - Data link layer
Explanation:
When TCP/IP protocols are used for communication between two network hosts, there is a process of coding and decoding also called encapsulation and decapsulation.
This ensures the information is not accessible by other parties except the two hosts involved.
Operating Systems Interconnected model (OSI) is used to standardise communication in a computing system.
There are 7 layers used in the OSI model:
1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer
6. Presentation layer
7. Application layer
The information formats given are matched as
a. Packets - Network layer
b. Segments - Transport layer
c. Bits - Physical layer
d. Frames - Data link layer
Consider an entity set Person, with attributes social security number (ssn), name, nickname, address, and date of birth(dob). Assume that the following business rules hold: (1) no two persons have the same ssn; (2) no two persons have he same combination of name, address and dob. Further, assume that all persons have an ssn, a name and a dob, but that some persons might not have a nickname nor an address.
A) List all candidate keys and all their corresponding superkeys for this relation.
B) Write an appropriate create table statement that defines this entity set.
Answer:
[tex]\pi[/tex]
Explanation:
What is media framing?
Answer:
media frame all news items by specific values, facts, and other considerations, and endowing them with greater apparent for making related judgments
Explanation:
What are the two basic functions (methods) used in classical encryption algorithms?
substitution and transport
You've created a new programming language, and now you've decided to add hashmap support to it. Actually you are quite disappointed that in common programming languages it's impossible to add a number to all hashmap keys, or all its values. So you've decided to take matters into your own hands and implement your own hashmap in your new language that has the following operations:
insert x y - insert an object with key x and value y.
get x - return the value of an object with key x.
addToKey x - add x to all keys in map.
addToValue y - add y to all values in map.
To test out your new hashmap, you have a list of queries in the form of two arrays: queryTypes contains the names of the methods to be called (eg: insert, get, etc), and queries contains the arguments for those methods (the x and y values).
Your task is to implement this hashmap, apply the given queries, and to find the sum of all the results for get operations.
Example
For queryType = ["insert", "insert", "addToValue", "addToKey", "get"] and query = [[1, 2], [2, 3], [2], [1], [3]], the output should be hashMap(queryType, query) = 5.
The hashmap looks like this after each query:
1 query: {1: 2}
2 query: {1: 2, 2: 3}
3 query: {1: 4, 2: 5}
4 query: {2: 4, 3: 5}
5 query: answer is 5
The result of the last get query for 3 is 5 in the resulting hashmap.
For queryType = ["insert", "addToValue", "get", "insert", "addToKey", "addToValue", "get"] and query = [[1, 2], [2], [1], [2, 3], [1], [-1], [3]], the output should be hashMap(queryType, query) = 6.
The hashmap looks like this after each query:
1 query: {1: 2}
2 query: {1: 4}
3 query: answer is 4
4 query: {1: 4, 2: 3}
5 query: {2: 4, 3: 3}
6 query: {2: 3, 3: 2}
7 query: answer is 2
The sum of the results for all the get queries is equal to 4 + 2 = 6.
Input/Output
[execution time limit] 4 seconds (py3)
[input] array.string queryType
Array of query types. It is guaranteed that each queryType[i] is either "addToKey", "addToValue", "get", or "insert".
Guaranteed constraints:
1 ≤ queryType.length ≤ 105.
[input] array.array.integer query
Array of queries, where each query is represented either by two numbers for insert query or by one number for other queries. It is guaranteed that during all queries all keys and values are in the range [-109, 109].
Guaranteed constraints:
query.length = queryType.length,
1 ≤ query[i].length ≤ 2.
[output] integer64
The sum of the results for all get queries.
[Python3] Syntax Tips
# Prints help message to the console
# Returns a string
def helloWorld(name):
print("This prints to the console when you Run Tests")
return "Hello, " + name
Answer:
Attached please find my solution in JAVA
Explanation:
long hashMap(String[] queryType, int[][] query) {
long sum = 0;
Integer currKey = 0;
Integer currValue = 0;
Map<Integer, Integer> values = new HashMap<>();
for (int i = 0; i < queryType.length; i++) {
String currQuery = queryType[i];
switch (currQuery) {
case "insert":
HashMap<Integer, Integer> copiedValues = new HashMap<>();
if (currKey != 0 || currValue != 0) {
Set<Integer> keys = values.keySet();
for (Integer key : keys) {
copiedValues.put(key + currKey, values.get(key) + currValue);
}
values.clear();
values.putAll(copiedValues);
currValue = 0;
currKey = 0;
}
values.put(query[i][0], query[i][1]);
break;
case "addToValue":
currValue += values.isEmpty() ? 0 : query[i][0];
break;
case "addToKey":
currKey += values.isEmpty() ? 0 : query[i][0];
break;
case "get":
copiedValues = new HashMap<>();
if (currKey != 0 || currValue != 0) {
Set<Integer> keys = values.keySet();
for (Integer key : keys) {
copiedValues.put(key + currKey, values.get(key) + currValue);
}
values.clear();
values.putAll(copiedValues);
currValue = 0;
currKey = 0;
}
sum += values.get(query[i][0]);
}
}
return sum;
}
Consider the following method.
public int locate(String str, String oneLetter)
{
int j = 0;
while(j < str.length() && str.substring(j, j+1).compareTo*oneLetter < 0)
{
j++;
}
return j;
}
Which of the following must be true when the while loop terminates?
a. j == str.length()
b. str.substring(j, j+1) >= 0
c. j <= str.length() || str.substring(j, j+1).compareTo(oneLetter) > 0
d. j == str.length() || str.substring(j, j+1).compareTo(oneLetter) >= 0
e. j == str.length() && str.substring(j, j+1).compareTo(oneLetter) >= 0
Answer:
All
Explanation:
From the available options given in the question, once the while loop terminates any of the provided answers could be correct. This is because the arguments passed to the while loop indicate two different argument which both have to be true in order for the loop to continue. All of the provided options have either one or both of the arguments as false which would break the while loop. Even options a. and b. are included because both would indicate a false statement.
g n this program, you will prompt the user for three numbers. You need to check and make sure that all numbers are equal to or greater than 0 (can use an if or if/else statement for this). You will then multiply the last two digits together, and add the result to the first number. The program should then start over, once again asking for another three numbers. This program should loop indefinitely in this way. If the user enters a number lower than 0, remind the user that they need to enter a number greater than or equal to 0 and loop the program again.
Answer:
In Python:
loop = True
while(loop):
nm1 = float(input("Number 1: "))
nm2 = float(input("Number 2: "))
nm3 = float(input("Number 3: "))
if (nm1 >= 0 and nm2 >= 0 and nm3 >= 0):
result = nm2 * nm3 + nm1
print("Result: "+str(result))
loop = True
else:
print("All inputs must be greater than or equal to 0")
loop = True
Explanation:
First, we set the loop to True (a boolean variable)
loop = True
This while loop iterates, indefinitely
while(loop):
The next three lines prompt user for three numbers
nm1 = float(input("Number 1: "))
nm2 = float(input("Number 2: "))
nm3 = float(input("Number 3: "))
The following if condition checks if all of the numbers are greater than or equal to 0
if (nm1 >= 0 and nm2 >= 0 and nm3 >= 0):
If yes, the result is calculated
result = nm2 * nm3 + nm1
... and printed
print("Result: "+str(result))
The loop is then set to true
loop = True
else:
If otherwise, the user is prompted to enter valid inputs
print("All inputs must be greater than or equal to 0")
The loop is then set to true
loop = True