The length of the base of an isosceles triangle is x. The length of a leg is 2x - 2. The perimeter of the triangle is 71. Find

The exponential function f(x) can represent growth or decay

The value of f(14) is 226.07

The given parameters are:

f(-2) = 25 and f(7) = 85

An exponential function is represented as:

f(x) = ab^x

So, we have:

ab^-2 = 25

Also, we have:

ab^7 = 85

Divide both equations.

This gives

b^9 = 3.4

Take the 9th root of both sides

b = 1.15

Recall that:

ab^7 = 85

This gives

a* 1.15^7 = 85

Solve for a

a = 31.95

So, the exponential function is:

f(x) = 31.95 * 1.15^x

Substitute 14 for x

f(14) = 31.95 * 1.15^14

f(14) = 226.07

Hence, the value of f(14) is 226.07

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Answer:

0.5,0.2,0.3

Step-by-step explanation:

divide 60,23,37 by 120

Answer:

D: 699

E: 582.5

F: 116.5

2. 1398

3. 13048

Step-by-step explanation:

Hope this helps!

Answer:

Step-by-step explanation:

The equation factors into

(x^2 + 14x + 49) =16                      Factor

(x + 7)^2 = 16                                 Take the square root of both sides

√(x + 7)^2 = √16

x + 7 = +/- 4

x + 7 = + 4                                      Subtract 7 from both sides

x  = 4 - 7

x = - 3

x + 7 = - 4                                      Subtract 7 from both sides.

x = - 4 - 7

x = - 11

x1 = -11

x2 = - 3

The average daily balance of the transactions given for the billing period will be $1798.

From the complete question, the average daily balance is completed below:

Billing date = 2645.92 × 5 = $13229.6

Repayment on June 6 = $1345.92 × 2 = $2691.84

June 8 = $1381.85

June 9: = $1518.53 × 8 = $12148.24

Gas = $1560.90

Groceries = $1687.37 × 10 = $16873.70

Clothing = $1902.49 × 4 = $7609.96

Total = $53935.19

Therefore, the average daily balance will be:

= $53935 / 30

= $1798

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Answer:

(i) 41-45 mins

(ii) 40 mins

(iii) 75 workers

(iv) Rs10500

Step-by-step explanation:

(i)  The modal class is the class with the highest frequency.

Therefore, from inspection of the frequency table, the modal class is 41-45 mins since if has the highest frequency of 14.

(ii) As the data is grouped, to find an estimate of the mean, assume that every worker takes the value of the class mid-point.  As the data is discrete, there are gaps between the classes, and so we also have to use lower and upper class boundaries to calculate the mid-points.

Class 21-25 : lower 20.5 | upper 25.5 | mid-point 23

Class 26-30 : lower 25.5 | upper 30.5 | mid-point 28

Class 31-35 : lower 30.5 | upper 35.5 | mid-point 33

Class 36-40 : lower 35.5 | upper 40.5 | mid-point 38

Class 41-45 : lower 40.5 | upper 45.5 | mid-point 43

Class 46-50 : lower 45.5 | upper 50.5 | mid-point 48

Class 51-55 : lower 50.5 | upper 55.5 | mid-point 53

Class 56-60 : lower 55.5 | upper 60.5 | mid-point 58

Mean = (sum of frequency x class mid-point) ÷ total frequency

⇒ Mean = (2 x 23 + 5 x 28 + 7 x 33 + 10 x 38 + 14 x 43 + 8 x 48 + 3 x 53 + 1 x 58) ÷ 50

⇒ Mean = 40 mins

(iii)  8 hours = 8 x 60 = 480 mins

Total time ÷ average time to make one doll = 480 ÷ 40 = 12

If the mean time to make a doll is 40 minutes, then one person can make 12 dolls in 8 hours.

Therefore, to calculate the number of workers required to make 900 dolls in 8 hours, divide the total number of dolls needed by 12:

900 ÷ 12 = 75

So 75 workers will be needed to make 900 dolls in 8 hours, given the mean time for a worker to make a doll is 40 mins.

(iv) Overtime is paid in excess of 6 hours.  Therefore, each worker will be working 2 hours overtime.

Total amount of overtime pay = hours x rate x workers

                                                  =  2 x Rs70 x 75

                                                  = Rs10500

Answer: 1/2

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

If you take 20 and divide by 4 you get 5. if you take 16 and also divide by 4, you will get 4.

Answer:

Step-by-step explanation:

BF is the angle bisector of ∠B.

The function that can be find used to find the number of circles needed to make the nth figure in the sequence is (C + 1) + 4.

The sequence can be illustrated through the function (C + 1) + 4 where C is the previous number. For the third picture, the number of circles will be:

= (C + 1) + 4

= 5 + 4

= 9

The fourth term will be:

= 9 + 4

= 13

Therefore, each figure uses 4 circles more than the previous one.

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Answer:

Step-by-step explanation: This function can be used to find the number of circles needed to make the nth figure in the pattern.

Each figure uses 4 more circle(s) than the previous figure because an additional circle is added to the top, bottom, left, and right sides.

the other half i got incorrect.

Answer:

4

Step-by-step explanation:

100 divided by 25 equals 4.

Answer:

$850.69824

Step-by-step explanation:

Answer:

$850.70 (nearest cent)

Step-by-step explanation:

Simple interest formula:   A = P(1 + rt)

where:

Given:

Substituting given values into the formula, and solving to find A:

⇒ A = 6604.8(1 + 0.0322 · 4)

       = 6604.8(1.1288)

       = $7455.50 (nearest cent)

Therefore, to find the amount of interest earned, subtract the principal from the final amount:

⇒ I = A - P

     = 7455.50 - 6604.80

     = $850.70 (nearest cent)

[tex]\qquad\qquad\huge\underline{{\sf Answer}} \huge♨[/tex]

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~

[tex]\qquad \sf  \dashrightarrow \:3y = 90 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 90 \degree \div 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 30 \degree [/tex]

Now, Let's use Angle sum property of Triangle to solve for z :

[tex]\qquad \sf  \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z = 180 \degree - (50 \degree + 90\degree)[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z = 180 \degree - (140\degree)[/tex]

[tex]\qquad \sf  \dashrightarrow \:4z = 40 \degree[/tex]

[tex]\qquad \sf  \dashrightarrow \:z = 40 \degree \div 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:z = 10 \degree [/tex]

I hope you understood the procedure, you can ask me in comments if you have any doubts.

Answer:

45

Step-by-step explanation:

Have a great day!

#EquestrianLion

Answer:

1 liter

Step-by-step explanation:

x2by 100%8hdofux27675 868*uhf

Answer:

3(C + 5) = 7

Step-by-step explanation:

Let C = unknown number

The sum of a number and 5:

C + 5

Three times the sum of a number and 5:

3(C + 5)

Three times the sum of a number and 5 is 7:

3(C + 5) = 7

To solve

Use the distributive law:  a(b + c) = ab + ac

⇒ 3C + 15 = 7

Subtract 15 from both sides:

⇒ 3C = -8

Divide both sides by 3:

⇒ C = -8/3

So

The expression is

On solving

Answer:

[tex]x = -5 \pm \sqrt{26}[/tex]

Step-by-step explanation:

[tex]x^2+10x-1=0\\\\\implies x^2+2\cdot 5 x +5^2-5^2-1=0\\\\\implies (x+5)^2-25-1=0\\\\\implies (x+5)^2 -26=0\\\\\implies (x+5)^2 = 26\\\\\implies x +5 = \pm\sqrt{26}\\\\\implies x = -5 \pm \sqrt{26}[/tex]

Answer:

[tex]y = 5[/tex]

Step-by-step explanation:

Given function:

[tex]y=\dfrac{5x}{x+6}[/tex]

[tex]\implies y=5 \left( \dfrac{x}{x+6}\right)[/tex]

[tex]\textsf{As }x \rightarrow +\infty, \ \dfrac{x}{x+6} \rightarrow1[/tex]  

[tex]\implies y\rightarrow5[/tex]

[tex]\textsf{As }x \rightarrow -\infty, \ \dfrac{x}{x+6} \rightarrow1[/tex]  

[tex]\implies y\rightarrow5[/tex]

As [tex]x[/tex] approaches infinity and negative infinity, [tex]y[/tex] approaches 5 (but never gets there).    Therefore, the horizontal asymptote is [tex]y=5[/tex]

Answer:

1 gallon / 600 sq ft

Step-by-step explanation:

As we can see, we are given that 600 sq ft uses one gallon to cover, therefore one gallon covers 600 sq ft (just vice versa of what's given).

The notation just means

(f/g)(-4) = f(-4) / g(-4)

If f(x) = x² + 2 and g(x) = 1 - 3x, then

f(-4) = (-4)² + 2 = 16 + 2 = 18

g(-4) = 1 - 3 (-4) = 1 + 12 = 13

and so

(f/g)(-4) = 18/13

Answer:

1

Step-by-step explanation:

Choose two points on the line:  (-5, 0) and (0, 5)

Let the first point [tex](x_1,y_1)[/tex] = (-5, 0)

Let the second point [tex](x_2,y_2)[/tex] = (0, 5)

Use the gradient formula:

[tex]\textsf{gradient}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{5-0}{0-(-5)}=1[/tex]

----------------------------------------------------------------------------------------------------

If you want to find the equation of the line, use the point-gradient form of a linear equation:  [tex]y-y_1=m(x-x_1)[/tex]

(where [tex]m[/tex] is the gradient and [tex](x_1,y_1)[/tex] is a point on the line)

Substituting the values into the formula:

[tex]\implies y-0=1(x-(-5))[/tex]

[tex]\implies y-0=x+5[/tex]

[tex]\implies y=x+5[/tex]

Therefore, the equation of the line is y = x + 5

Answer:

A

Step-by-step explanation:

Remember domain is input and range is output.

Input: All real numbers

Output: [0, infinity)

A

Answer:

The reflection coordinates of JKL would be:

J (3,7)

K (2,3)

L (-1,5)

The reflection coordinates of MNP would be:

M (8,-6)
N (2,-4)
P (8,-4)

Step-by-step explanation:

Answer:

I plotted it out on the graph and here it is:

Answer:

B. 90 in²

Area of white triangle

3×4/2

12/2 = 6 in²

Area of blue triangle

12×16/2

192/2= 96in²

96in² - 6in² = 90 in²