The main triangular sail on a sailboat is 25 feet tall and 10 feet wide at the bottom. If the sides of another sail are proportional to the main sail, and the bottom of this sail is 8 feet wide, how tall is it?

Step-by-step explanation:

The dimensions are (8-2x) and (10-2x) We will say the depth of the box is x. The equation we use for the volume of the box is V=x(8-2x)(10-2x)

Answer:

part b of the answer is x=1.5 inches

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

data provided in the question

Long = 2 miles

distance = [tex]\frac{2}{11}[/tex]

based on the above information,

We can conclude that

there is not more than one relay as if we divide the 2 by 11 so it comes 0.18 which is greater than 0.1

i.e

0.18 > 0.1

So there is no need for more than one relay i.e to be exchanged between two consecutive mile

Answer:

(5a3b)(2ab)

Expand

That's

15ab( 2ab )

we have the answer as

5y(-y² + 7y - 2)

Expand

That's

Hope this helps you

Answer:

The answer is 0.133

Step-by-step explanation:

All you have to do is take 2/3 as if it was a whole number and divide it by 5, or if you are able to use a calculator, you can just but it in as 2 divided by 3 and then divide 5 by whatever answer you get.

Answer:

Hello! 2/3 divided by 5 in fraction will be 2/15

Step-by-step explanation:

Since we have a 5 we need to change that into a fraction

5 would turn into 1/5

Now you have to multiply both of the fractions to get your answer.

2/3 x 1/5

= 2/15

(So 2/15 will be your answer.)

Hope this helps! :)

Answer:

167.55

Step-by-step explanation:

so it varies jointly so

A-area if cylinder

so

[tex]a \: \alpha \: \pi \: r \: ^{2} h[/tex]

so

[tex]a = k\pi \: r^{2}h[/tex]

where k is the constant

so apply the first set of values to get k=2/3

then substitute the k with the second set of values

Answer: [tex]4\sqrt{3}[/tex] .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

[tex]D=\sqrt{(d-b)^2+(b-a)^2}[/tex]

Distance between points [tex](-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})[/tex].

[tex]D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}[/tex]

Hence, the correct option is [tex]4\sqrt{3}[/tex] .

Answer:

Step-by-step explanation:

i^{11}+i^{16}+i^{21}+i^{26}+i^{31}

[tex]=(i^{2} )^5i+(i^{2} )^8 +(i^{2} )^{10} i+(i^{2} )^{13}+(i^{2} )^{15} i\\=(-1)^5 i+(-1)^8+(-1)^{10} i+(-1)^{13} +(-1)^{15} i\\=- i+1+i-1-i\\=0- i[/tex]

Answer:

BCD

Step-by-step explanation:

Answer: B,C & D

Step-by-step explanation:

Answer:

[tex]\boxed{D = 15/8}[/tex]

Step-by-step explanation:

=> [tex]x^2-\frac{1}{2} x +\frac{1}{2} = 0[/tex]

Comparing it with the standard form of quadratic equation [tex]ax^2+bx+c = 0,[/tex] we get

a = 1, b = -1/2 and c = 1/2

Discriminant = [tex]b^2-4ac[/tex]

[tex]D = (-1/2)^3+4(1)(1/2)\\D = -1/8 + 2\\D = \frac{-1+16}{8} \\D = \frac{15}{8}[/tex]

Answer:

-2

Step-by-step explanation:

your equation is

f(x) = -2x+8

-2x

-2 is the slope

Answer:

The slope is -2

Step-by-step explanation:

Rewriting f(s) as y

y = -2x+8

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = -2x+8

The slope is -2

Answer:

El reloj está marcando:

las 4:00 horas

Step-by-step explanation:

El reloj avanzó a su mismo ritmo pero en sentido contrario a partir de las 6:45

si ahora son las 9:30 el reloj marca:

9:30 = 9horas 30minutos = 9h 30'

6:45 = 6horas 45minutos = 6h 45´

1 hora = 60'

9h 30' = 8h + 60' + 30' = 8h + 90' = 8h 90'

entonces:

 8h 90'

- 6h 45'

= 2h 45

entonces el reloj está marcando 2h 45' menos que la hora en que se dañó.

por tanto:

 6h 45'

- 2h 45'

= 4h 00'

El reloj ahora está marcando las

4 horas en punto.

Answer:

a) point (2, 1) is when the ball is on it's way down at 2 seconds

b) vertex (1, 2) is the highest the ball goes, which is 2 at 1 second.

c) y-intercept (0, 1) at time zero the ball is starting at a height of 1.

d) Points (0, 1) and (2, 1) are the points at which the ball starts and when it is in the same position from the ground as when it started, which is 1.

e) zero (x-int) is when the ball hits the ground at 2.5 seconds.

Step-by-step explanation:

Answer:

See below

step by step explanation

A. (2 , 1 ) is point on the parabola . It represents that the height of the ball after 2 second have passed.

b. The vertex is at ( 1 , 2 ) . It represent that the maximum height of the ball which is 2 units to at t = 1 second

c. The y - intercept is ( 0 , 1 ) . It represent that the initial height of ball at t = 0 second is 1 unit.

d. Point ( 0 , 1 ) and ( 2 , 1 )

This point represent the set of point having equal height at two different time. It represents how long before the ball reaches the same height from the starting point.

e. The zero or x - intercept is ( 2.5 , 0 )

It represent the time taken by ball before it reaches the ground.

Hope this helps...

Best regards!!

Answer:

33

Step-by-step explanation:

15019 / 53 = 283 R20

53 − 20 = 33

He needs 33 more trees so that every row can have the same number of trees.

Without further context I can't say much other than the radius is perpendicular to the tangent. In other words, the radius and tangent line form a 90 degree angle. This is one particular radius and its not just any radius. The radius in question must have the point of tangency as its endpoint.

The radius, AB  is perpendicular to the tangent line,  BC  so their slopes are negative reciprocals of one another. Because I generated a circle at random for this activity, this conclusion likely applies to any tangent line to a circle. In other words, the tangent line to any circle is perpendicular to the radius at their point of intersection.

Answer:

Since ΔABC is equilateral, ∠ACB = 60°. Since ΔCED is isosceles (we know this because CE = ED from the graph), ∠ECD = ∠EDC from Base Angles Theorem, and since the sum of angles in a triangle is 180°, they measure (180 - 32) / 2 = 74° each. Since BCD is a straight line, it measures 180° so we can write:

60 + x + 74 = 180

134 + x = 180

x = 46°

Answer:

46 degrees

Step-by-step explanation:

Since triangle ABC is equilateral that means each angle in that triangle is 60 degrees.

We also know that for triangle ECD angle C and angle D have to be 74 degrees, because a triangle has 180 degrees in total and the only unique angle is at the top which is 32. So it is 180-32=148, than 148/2=74.

We than know that a half circle is 180 degrees aswell, so we do 180-60=120

120-74=46

Answer:

see explanation

Step-by-step explanation:

Any point that lies on the line is a solution to the equation.

Thus

(0, 1 ), (2, 0 ), (- 2, 2), (4, - 1 ) are all solutions

Answer:

[tex]\boxed{(6, -2)}[/tex]

Step-by-step explanation:

Any of the points that lies on the line is the solution to the equation of the line.

(-2, 2), (0, 1), (2, 0), (4, -1), (6, -2) are all solutions.

Answer:

900

Step-by-step explanation:

a heptagon has 7 sides, so we take the hexagon's sum of interior angles an and add 180 to it's getting us, 720 + 180 = 900 degrees

Answer:

Option C is the correct option

Step-by-step explanation:

Let the points be A and B

A ( 4 , 5 ) ------> ( x1 , y1 )

B ( 10 , 13 ) ------> ( x2 , y2 )

Now, let's find the distance between these points:

[tex] \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]

plug the values

[tex] = \: \sqrt{(10 - 4) ^{2} + {(13 - 5)}^{2} } [/tex]

Calculate the difference

[tex] = \sqrt{ {(6)}^{2} + {(8)}^{2} } [/tex]

Evaluate the power

[tex] = \sqrt{36 + 64} [/tex]

Add the numbers

[tex] = \sqrt{100} [/tex]

Write the number in exponential form with. base of 10

[tex] = \sqrt{ {(10)}^{2} } [/tex]

Reduce the index of the radical and exponent with 2

[tex] = 10 \: units[/tex]

Hope this helps..

Best regards!!

Answer:

[tex]a_{n}[/tex] = [tex]\frac{1}{2}[/tex] n + 15

Step-by-step explanation:

The n th term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₆ = 18 and d = [tex]\frac{1}{2}[/tex] , then

a₁ + 5d = 18 , that is

a₁ + [tex]\frac{5}{2}[/tex] = 18 ( subtract [tex]\frac{5}{2}[/tex] from both sides )

a₁ = [tex]\frac{31}{2}[/tex]

Thus

[tex]a_{n}[/tex] = [tex]\frac{31}{2}[/tex] + [tex]\frac{1}{2}[/tex] (n - 1) = [tex]\frac{15}{2}[/tex] + [tex]\frac{1}{2}[/tex] n - [tex]\frac{1}{2}[/tex] = [tex]\frac{1}{2}[/tex] n + 15

Answer:

Hey there!

The width is 3 inches, and in real life it would be 90 inches. (3x30)

The length is 5.5 inches, and in real life it would be 165 inches. (5.5x30)

90 inches is 7.5 feet

165 inches is 13.75

13.75 times 7.5 is 103.125, so rounded to the nearest integer, that would be 103 ft^2.

Hope this helps :)

Answer:

The completed proportions are;

ED/A_F = CE/CA = CF/CD

Step-by-step explanation:

The given m∠CED = m∠A

∴ Angle ∠CDE = Angle ∠A_FC, (corresponding angles)

Angle ∠ECD = Angle ∠ACF (reflexive property)

Triangle ΔDCE is similar to triangle ΔACF (Angle Angle Angle (AAA) similarity)

In triangle ΔDCE and triangle ΔACF

m∠A is bounded by CA and A_F

m∠CED is bounded by CE and ED

∠DCE is bounded by CE and DE

∠C is bounded by CA and CF

Based on the orientation of the two triangles, we have

ED is the corresponding side to A_F, CD is the  corresponding side to CF, CE is the corresponding side to CA

Therefore, we have;

ED/A_F = CE/CA = CF/CD.

Answer:

1.  20 tins of milk

2.  Weight of the Carton = 8,4kg ot 8400g

Step-by-step explanation:

Given

Volume of a Tin = 77cm³

Weight of a tin = 5000g

Volume of Empty Carton = 1540cm³

Weight of Empty Carton = 5000g

Calculating the number of tins of milk

To do this, we have to make use of the given volumes;

And this is done as follows;

[tex]Number = \frac{Volume\ of\ Empty\ Carton}{Volume\ of\ a\ Tin}[/tex]

Substitute  77cm³ for Volume of a Tin and 1540cm³ for Volume of an Empty Carton

[tex]Number = \frac{1540cm^3}{77cm^3}[/tex]

[tex]Number = 20[/tex]

Hence, 20 tins of milk will filled the empty carton

Calculating the weight of the Carton after filled with tins of milk

This is calculated as thus;

Total Weight = Weight of Empty Carton + Weight of Tins of Milk

Substitute 5000g for Weight of Empty Carton

Total Weight = 5000g + Weight of Tins of Milk

_________________________________________

Calculating Weight of Tins of Milk

Since 20 tins of milk will fill the empty carton, the

Weight of Tins of Milk = 20 * Weight of 1 Tin of Milk

Weight of Tins of Milk = 20 * 170g

Weight of Tins of Milk = 3400g

_________________________________________

Substitute 3400g for Weight of Tins of Milk

[tex]Total\ Weight = 5000g + 3400g[/tex]

[tex]Total\ Weight = 8400g[/tex]

In Kilograms:

[tex]Total\ Weight = 8.4kg[/tex]

Answer:

Choice A

Step-by-step explanation:

First, let's simplify the equation. We get [tex]\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }[/tex] . Then, we can simplify. We now have [tex]\frac{3^{-3}m^{5} }{6n}[/tex] . To get rid of the negative exponent, we multiply the top and bottom by 3^3 to get [tex]\frac{m^{2} }{6nx3^{3} }[/tex]. Note that the x in the denominator stands for multiplication. 3^3 = 27, so we have [tex]\frac{m^{5} }{6n(27)} = \frac{m^{5} }{162n}[/tex]

Answer:

m^5/ 162 n

Step-by-step explanation:

( 3 m^-2 n) ^-3 / (6mn^-2)

We know a^ -b = 1/ a^b

1 / ( 3 m^-2 n) ^3 *(6mn^-2)

Distribute the power of 3

1 / ( 3^3 m^ -2 ^ 3 n^3) * ( 6m n^-2)

We know a^ b^ c = a^ ( b*c)

1 / ( 27 m^( -2 * 3) n^3) * ( 6m n^-2)

1 / ( 27 m^( -6) n^3) * ( 6m n^-2)

We know a^b * a^c = a^ ( b+c)

1 / ( 27*6 m^( -6+1) n^(3-2))

1/ (162 m^ -5 n^1)

We know a^ -b = 1/ a^b

m^5/ 162 n

Answer:

20

Step-by-step explanation:

use the cos or sin function to solve

Step-by-step explanation:

using 30°

we use cos

using 60

we use Sin

Answer:

Hey there!

We have the angle is equal to half the measure of the arc of 120 degrees. (Just another rule for circles)

7x-10=0.5(120)

7x-10=60

7x=70

x=10

Hope this helps :)

Answer:

x = 10

Step-by-step explanation:

Tangent Chord Angle = 1/2 Intercepted Arc

7x-10 = 1/2 ( 120)

7x -10 = 60

Add 10 to each side

7x -10+10 = 60+10

7x = 70

Divide by 7

7x/7 = 70/7

x = 10

Answer: 16,384

Step-by-step explanation:

The seven marbles have different colours, so we can differentiate them.

Now, suppose that for each marble we have a selection, where the selection is in which jar we put it.

For the first marble, we have 4 options ( we have 4 jars)

For the second marble, we have 4 options.

Same for the third, for the fourth, etc.

Now, the total number of combinations is equal to the product of the number of options for each selection.

We have 7 selections and 4 options for each selection, then the total number of combinations is:

C = 4^7 = 16,384

Answer:

the answer is 16384

Step-by-step explanation:

have a nice day.

Answer:

[tex]\boxed{x = 251.4 cm}[/tex]

Step-by-step explanation:

Part 1: Sketching the triangle

We are given the angle of elevation, 70°, and the distance along the ground, 86 centimeters. Our unknown is a ladder leaning against the building. Buildings are erected vertically, so the unknown side length is the hypotenuse of the triangle.

We can then sketch this triangle out to visualize it (attachment).

Part 2: Determining what trigonometric ratio can solve the problem

Now, we need to refer to our three trigonometric ratios:

[tex]sin = \frac{opposite}{hypotenuse}[/tex]

[tex]cos = \frac{adjacent}{hypotenuse}[/tex]

[tex]tan = \frac{opposite}{adjacent}[/tex]

Visualizing the sketched triangle, we can assign the three sides their terms in correspondence to the known angle -- this angle cannot be the right angle because the hypotenuse is opposite of it.

Therefore, we know our unknown side length is the hypotenuse of the triangle and because the other side is bordering the 70° angle, it is the adjacent side.

By assigning the sides, we can see that we need to use the trigonometric function that utilizes both the hypotenuse and the adjacent side to find the angle. This is the cosine function.

Part 3: Solving for the unknown variable

Now that we have determined what side we need to solve for and what trigonometric function we are going to use to do so, we just need to plug it all into the equation.

The cosine function is provided: [tex]cos( \alpha) = \frac{adjacent}{hypotenuse}[/tex], where [tex]\alpha[/tex] is the angle. We just need to plug in our values and solve for our unknown side; the hypotenuse.

[tex]cos (70) = \frac{86 cm}{x}[/tex], where x is the unknown side/the hypotenuse.

[tex]x * cos (70) = \frac{86 cm}{x} * x[/tex] Multiply by x on both sides of the equation to eliminate the denominator and make the unknown easier to solve for.

[tex]\frac{xcos (70)}{cos(70)} = \frac{86 cm}{cos(70)}[/tex], Evaluate the second fraction because the first one cancels down to just the unknown, x.

[tex]\frac{86}{cos(70)} = 251.4[/tex], round to one decimal place.

Your final answer is [tex]\boxed{x=251.4cm}[/tex].

Answer:

[tex]Angle = 54[/tex]

Step-by-step explanation:

Given

Kano = 45;

Kwara  = 410;

Ogun = 105;

Ondo = 126;

Oyo = 154

Total Distribution = 840

Required

Determine the angle subtended by Ondo (in a pie chart)

The general formula to calculate subtended angle in a Pie chart is;

[tex]Angle = 360 * \frac{Frequency}{Total\ Frequency}[/tex]

In this case of Ondo

Frequency = 126

Total Frequency = Total Distribution = 840

Substitute these values in the given formula;

[tex]Angle = 360 * \frac{126}{840}[/tex]

[tex]Angle = \frac{360 *126}{840}[/tex]

[tex]Angle = \frac{45360}{840}[/tex]

[tex]Angle = 54[/tex]

Hence, the angle subtended by Ondo is 54

Answer:

Examine the system of equations.

–2x + 3y = 6

–4x + 6y = 12

Answer the questions to determine the number of solutions to the system of equations.

What is the slope of the first line?  

✔ 2/3

What is the slope of the second line?  

✔ 2/3

What is the y-intercept of the first line?  

✔ 2

What is the y-intercept of the second line?  

✔ 2

How many solutions does the system have?  

✔ infinitely many

The equations are a multiple of the other, therefore, by the multiplicative

property of equality, the equations are equivalent.

Response:

The given system of equations are;

-2·x + 3·y = 6

-4·x + 6·y = 12

Required:

The slope of the first line.

Solution:

The slope of the first line is given by the coefficient of x when the equation is expressed in the form; y = m·x + c.

Therefore, from -2·x + 3·y = 6, we have;

3·y = 2·x + 6

[tex]y = \dfrac{2}{3} \cdot x + \dfrac{6}{3} = \dfrac{2}{3} \cdot x + 2[/tex]

[tex]y =\dfrac{2}{3} \cdot x + 2[/tex]

[tex]\underline{The \ slope \ of \ the \ first \ equation \ is \ \dfrac{2}{3}}[/tex]

Required:

The slope of the second line;

Solution:

The equation of the second line, -4·x + 6·y = 12, can be expressed in the form;

[tex]y =\dfrac{4}{6} \cdot x + \dfrac{12}{6} = \dfrac{2}{3} \cdot x + 2[/tex]

[tex]y = \mathbf{\dfrac{2}{3} \cdot x + 2}[/tex]

[tex]\underline{The \ slope \ of \ the \ second \ equation \ is \ therefore \ \dfrac{2}{3}}[/tex]

Given that the equation have the same slope and the same y-intercept, the equations are equations of the same line, therefore;

Learn more about the solutions of a system of equations here:

https://brainly.com/question/15356519

Answer:

10

Step-by-step explanation:

[tex]\left(x-h\right)^{2}+\left(y-k\right)^{2}=r^2[/tex]

[tex]\left(x-6\right)^{2}+\left(y-0\right)^{2}=r^2\\[/tex]

We used (2,-3)

[tex]\left(2-6\right)^{2}+\left(-3-0\right)^{2}=25[/tex]

[tex]r^2=25\\[/tex] , so [tex]r = 5[/tex]

But this one is asking for the diameter, and to find it. It's simply 2r.

2*5 = 10