The nth term of a sequence is 3n^2/2

9514 1404 393

Answer:

  circle of radius 27 inches

Step-by-step explanation:

Anywhere a plane cuts a sphere, the cross section is a circle. When the plane includes the center of the sphere, the circle has the same radius the sphere has.

The cross section is a circle of radius 27 inches.

Answer:

x=√2, x=-√2, x= 3 and x=-3

Step-by-step explanation:

We need to solve the equation x^4 - 11x^2+18=0  

We can replace x^4 = u^2 and x^2 = u

So, the equation will become

u^2 -11u+18 = 0

Factorizing the above equation:

u^2 -9u-2u+18 =0

u(u-9)-2(u-9)=0

(u-2)(u-9)=0

u=2, u=9

As, u = x^2, Putting back the value:

x^2 =2 , x^2 =9  

taking square roots:

√x^2 =√2 ,√x^2=√9  

x=±√2 , x = ±3

so, x=√2, x=-√2, x= 3 and x=-3

Answer:

The second answer is correct.

Step-by-step explanation:

Mark brainliest if correct please

Answer:

[tex]x^{\frac{9}{7}} = \sqrt[7]{x^9}[/tex]

Step-by-step explanation:

You can solve this by realising that the denominator of a fractional exponent can be expressed as the base of a radical.

Note also that the order does not matter.  You could also express it as

[tex]\sqrt[7]{x}^9[/tex]

The reason this works is that you're effectively breaking the exponent into fractions.  The first answer is the equivalent of:

[tex](x^9)^{1/7}[/tex]

and the second would be:

[tex](x^{1/7})^9[/tex]

In both cases, the exponents would be multiplied, giving the same result.