The percentage price of an article is 30000 and its price after the discount is 27600. What will the percentage of the discount be ?​

Answers

Answer 1

the answer for this would be 20 percent


Related Questions

Approximate the temperature of the water after 6 intervals

Answers

obviously 56%*f degrees fare height

pls answer the blanks

Answers

Answer:

mention the blanks please...if u mention iam ready to answer

please answer this question​

Answers

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Before answering the given question, you should know the difference between polygon and regular polygon.

Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles. Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

There are different types of polygon based on the sides :-

A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.

Let's Begin :-

I have thought to make a 4 side polygon that is quadrilateral.

Steps of construction :-

Step - 1 :- Draw a 5 cm line AB horizontally Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD Step - 4 :- Now, join the line AD Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.

Result :- All the angles are equal that is 90° each.

Conclusion :- The above figure is square as it is having equal sides and angles.

Now, we have to find the sum of the angles of the polygon :-

Here,

All angles are equal in measure 90°

Therefore,

The sum of the angles of the given polygon

[tex]\sf{ = 90{\degree} + 90{\degree} + 90{\degree} + 90{\degree} }[/tex]

[tex]\sf{ = 180{\degree} + 90{\degree} + 90{\degree} }[/tex]

[tex]\sf{ = 270{\degree} + 90{\degree} }[/tex]

[tex]\sf{ = 360{\degree} }[/tex]

Hence, The sum of the angles of the above polygon is 360° .

Find the length of a diameter.
22 mm
A diameter of the circle is_____mm

Answers

Answer:

44 mm

Step-by-step explanation:

radius = 22 mm

diameter = 2 * radius = 44 mm

44 mm would be the diameter.

The diameter = radius x2

Hope this helps!!

Write each expression without the absolute value symbol.
PLEASE HELP

Answers

Step-by-step explanation:

| x - 19 + 11 | = | x - 8 |

look at the picture.

The expression without the absolute value symbol is:

|x - 8| = x - 8, if x > 8

|x - 8| = 0, if x = 8

|x - 8| = 8 - x, if x < 8

What is an expression?

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

|(x - 19) + 11|

This can be written as,

= |x - 19 + 11|
= |x - 8|

Now,

|x - 8| = x - 8, if x > 8

|x - 8| = 0, if x = 8

|x - 8| = 8 - x, if x < 8

Thus,

The expression without the absolute value symbol is:

|x - 8| = x - 8, if x > 8

|x - 8| = 0, if x = 8

|x - 8| = 8 - x, if x < 8

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PLEASE HELP!

The scatter plot shows the number of years of experience, x, and the
amount charged per hour, y, for each of 25 dog sitters in Texas.

(a) Write an approximate equation of the line of best fit for the data. It doesn't have to be the exact line of best fit.

(b) Using your equation from part (a), predict the amount charged per hour by a dog sitter with 18 years of experience.

Answers

Answer:

(a) [tex]\sf y=\dfrac{11}{20}x+7[/tex]

(b) $16.90

Step-by-step explanation:

Part (a)

Add a line of best fit (see attached).

Find two points on the line:  (7, 0) and (20, 18)

Use these points to find the slope of the line:

[tex]\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{18-7}{20-0}=\dfrac{11}{20}[/tex]

Use the found slope and one of the points in the point-slope form of the linear equation to find an equation for the line of best fit:

[tex]\sf\implies y-y_1=m(x-x_1)[/tex]

[tex]\sf\implies y-7=\dfrac{11}{20}(x-0)[/tex]

[tex]\sf\implies y=\dfrac{11}{20}x+7[/tex]

Part (b)

Substitute x = 18 into the equation and solve for y:

[tex]\sf\implies y=\dfrac{11}{20}(18)+7=\$16.90[/tex]

A circular "No Parking" road sign has a diameter of 26 inches. Which measurement is closest to the area of the sign in square inches? 81.64 in.² 163.28 in.² 530.66 in.² 2,122.64 in.²

Answers

Answer:

530.66 in²

area of circle: πr²

diameter: 26 in

radius : diameter/2 = 26/2 = 13 in

area: πr² ⇒ π(13)² ⇒ 530.66 in²

Answer:

pretty sure its 530.66 in.²

Step-by-step explanation:

I am not sure how to do for this question! Pls help

Answers

Answer:

wheres the question

Step-by-step explanation:

??????

You were elected the student council president for the next year at your school. After vacation is over, you have to plan a school carnival for the new school year. You are studying last year’s event and know that 210 people attended last year’s school carnival. The total amount of money collected for tickets was $710. Prices were $5 for regular admission, $3 for students, and $1 for children. The number of regular tickets sold was 10 more than twice the number of children’s tickets sold. Determine how many of each kind of ticket were sold.

Answers

70 regular, 110 student, and 30 children tickets were sold.

The number of regular tickets are 70, the number of student tickets are 110 and the number of children tickets are 30.

What is a linear system of equations?

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

Given that, you are studying last year’s event and know that 210 people attended last year’s school carnival.

The number of regular tickets sold was 10 more than twice the number of children’s tickets sold.

Let the number of children tickets be x.

Then, number of regular tickets be 2x+10

Let the number of student tickets be y.

You are studying last year’s event and know that 210 people attended last year’s school carnival.

x+2x+10+y=210

3x+y=200 --------(I)

The total amount of money collected for tickets was $710.

Now, 5(2x+10)+3y+x=710

10x+50+3y+x=710

11x+3y=660 --------(II)

Substitute y=200-3x in equation (II), we get

11x+3(200-3x)=660

11x+600-9x=660

2x=60

x=30

Substitute x=30 in equation (I), we get

3(30)+y=200

y=110

Number of regular tickets =2x+10

= 70

Therefore, the number of regular tickets are 70, the number of student tickets are 110 and the number of children tickets are 30.

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if tan=5/12
Find sinx/cosx+tanx

Answers

Answer:

[tex] \frac{10}{12} [/tex]

Step-by-step explanation:

given,

tanX = 5/12

sinX/cosX + tanX

= tanX + tanX ( sinX/cosX = tanX)

= 5/12 + 5/12

=

[tex] \frac{10}{12} [/tex]

Step-by-step explanation:

[tex] \tan(x) = \frac{5}{12} \\ \hookrightarrow \: \frac{p}{b} = \frac{5}{12} [/tex]

As,

[tex] \hookrightarrow \: \frac{ \sin(x) }{ \cos(x) } = \tan(x) [/tex]

Now,

[tex] \hookrightarrow \: \frac{ \sin(x) }{ \cos(x) } + \tan(x) \\ \hookrightarrow \: \tan(x) + \tan(x) \\ \hookrightarrow \: \frac{5}{12} + \frac{5}{12} \\ \hookrightarrow \frac{5 + 5}{12} \\ \hookrightarrow \frac{10}{12} [/tex]

How many times does 8 go into the 12 1/2?

Answers

Answer:

1.5625

Step-by-step explanation:

rround to 2

If HI = IJ = 14 and GH = 12, what is HJ?​

Answers

Answer:

24 units

Step-by-step explanation:

Missing drawing but assumed that:

HI and IJ are equal sides of the isosceles triangle HIJIG is the perpendicular bisector of same triangle

Since G is the midpoint of HJ, we have:

GH = GJ = 12

So

HJ = 2*GH = 2*12 = 24

Answer:

24 units

Step-by-step explanation:

IJ = 14 and GH = 12

Gh=gj=12

Hj=2gh

2*12=24

-5X^2 + 3X = -3X^2 + 3X - 50  solve for x ​

Answers

[tex]-5x^2+3x = -3x^2 +3x -50\\\\\implies 5x^2-3x^2 +3x-3x -50 =0\\\\\implies 2x^2 -50 =0\\\\\implies x^2 -25 = 0\\\\\implies x^2 = 25\\\\\implies x = \pm5\\\\\text{Hence}~ x = 5~ \text{or}~ x = -5[/tex]

Answer:

X = 5, —5

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

100.2and 19.400 which is greater​

Answers

Answer:

19.400

Step-by-step explanation:

19.400 equals out to 42769.67886386625

There is exactly 1 pair of parallel sides. 6 3 9

Answers

Answer:

Step-by-step explanation:

The given properties of one pair of parallel sides in the four sided

quadrilateral, indicates that the shape is a trapezium.

Response:

The area of the shape is 35 square unit

Parallel sides=6 and 9Height=3

Area of trapezoid

1/2(Sum of parallel sides)(Height)1/2(6+9)(3)1/2(15(3))12(45)22.5units^2

(7 point)
13. Amir posts on social media frequently, while Naomi posts rarely. Their number of posts over
the last six days are given in the table below. Compare the spreads of the data sets using both
range and IQR
Amir Naomi
15
2
12
4
14
10
16
2
15
3
19
0

Answers

The number of social media post of Noami has a greater spread when compared to that of Amir.

What is the range and intequartile range of the social media posts?

Range is the difference between the highest and lowest values of a set of observations

Range = highest value - lowest value

The range of Amir's social media posts = 19 - 15 = 4 The range of Noami's social media posts = 10 - 0 = 10

The inter quartile range is the difference between the third quartile and the first quartile of a data set.

IQR = Q3 - Q1

The IQR of Amir's social media posts: 7

The IQR of  Naomi's social media posts = 10

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Answer:

Naomi"s data set has more spread since her range is 10 and her IQR is 3.

Step-by-step explanation:

Range                   IQR

12,14,15,15,16,19    16-14=2

0,2,2,4,5,10           5-2=3

19-12=7  10-0=10

Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.

Answers

Answer:

Step-by-step explanation:

3. Use Cosine law to find the  length of the unknown side (PR)

q² = p² +  r² - 2prCos Q

q is the opposite side of ∠Q;  

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² -  2* 33*67 Cos 19°

    = 1089 + 4489 - 4422 * 0.95

     = 1089 + 4489 - 4200.9

    = 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

[tex]\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}[/tex]

Sin P = 0.3

[tex]P = Sin^{-1} 0.3\\[/tex]

P = 17.5°

∠R = 180 - (19 + 17.5)

    = 143.5°

The time it takes me to wash the dishes is uniformly distributed between 7 minutes and 16 minutes. What is the probability that washing dishes tonight will take me between 8 and 15 minutes?

Answers

Answer as a fraction = 7/9 which is exact

Answer in decimal form = 0.778 which is approximate

=========================================================

Explanation:

The time gap from 8 to 15 is 15-8 = 7 minutes.

The time gap from 7 to 16 is 16-7 = 9 minutes.

Divide those differences: 7/9 = 0.778 approximately

The 7's go on forever, but rounding at some point will bump the last 7 to an 8.

find x and y. use proper postulates or theorems to justify your answer

Answers

Answer:

x = 110 & y = 28

Step-by-step explanation:

The top and bottom lines are both intersected by a transversal. Because of this, we can say the 100-degree angle is equivalent to the (x-10) angle due to the Corresponding Angles Theorem.

If 100 = x -10 then you add 10 to both sides to get x = 110 degrees.

Then, using the Same Side Exterior Angles Postulate, you can conclude that the 100-angle and the (2y + 24) angle are supplementary, meaning they add up to 180 degrees.

So, 100 + (2y + 24) = 180.

Subtract 100 from both sides to get 2y + 24 = 80

Then subtract 24 from both sides to get 2y = 56

And divide both sides by 2 to get y = 28 degrees.

Find measure of <1. (The figure may not be drawn to scale)

Answers

Answer:

t = 55

Step-by-step explanation:

The figure is a  straight line and the sum of angles that make a straight line is 180 degrees

90 + t+ 35 = 180

125+t = 180

Subtract 125 from each side

125 +t-125 = 180-125

t = 180-125

t = 55

Which function should be used when evaluating the function at x = -1?
S -x2 + 8x if x < -1
p(x) =
*x? - 4 if x 2-1
O p (x) = {x? - 4
O p(x) = -x2 + 8x

Answers

WE WILL SOLVE THIS EQUATION USING PEMDAS.

PARENTHESES, EXPONENTS, MULTIPLICATION, ADDITION, AND SUBTRACTION.

This recipe makes 4 pancakes.
Sanjay follows the recipe but wants to make 12 pancakes.
How much of each ingredient does he need?

Recipe: Makes 4
135 g flour
1 teaspoon (tsp) baking powder
2 tablespoons (tbsps) sugar
130 ml milk
1 egg
2 tablespoons (tbsps) oil

Answers

Answer:

405g of flour, 3 teaspoons baking powder, 6 tablespoons sugar, 390ml of milk and 3 eggs and 6 tablespoons of oil

Step-by-step explanation:

She wants to triple the recipe, so she must multiply each amount of each ingredient by three:

135 × 3 = 405

1 × 3 = 3

2 × 3 = 6

130 × 3 = 390

1 × 3 = 3

2 × 3 = 6


7. The area of the parallelogram is 450 m2. What is
the height?
A. 25 m
B. 36 m
C. 50 m
D. 72m

Answers

The answer is 36 sq. ft. Find the area of the following parallelograms. Example 3. Base = 7 meters, Height = 3.5 meters. First, write

h = height of the parallelogram. a = side of the parallelogram (AD) x = any angle between the sides of the parallelogram (∠DAB or ∠ADC) d1 = diagonal of the parallelogram (p)
...
Area = ½ × d1 × d2 sin (y)

Observations of the center of the Milky Way show the presence of a super massive black hole with a mass of 4.6 x 106 solar masses. Compute the Schwarzschild radius of this supermassive black hole. Give your answer in units of astronomical units (AU). At what distance does Mercury orbit from the Sun in AU? If we swapped out the Sun for this super massive black hole, would the event horizon extend beyond the orbit of Mercury? Be sure to show your calculations. 1 AU = 1.5 x 108 km.

Answers

The Schwarzschild radius of the black hole depends on its mass

The Schwarzschild radius of this supermassive black holeis 0.091 AU

How to determine the Schwarzschild radius?

The Schwarzschild radius (r) is calculated using:

[tex]r_s = \frac{2GM}{c^2}[/tex]

Where:

G =  Gravitational constant = 6.67408 × 10-11 m3 kg-1 s-2

M = Mass of the object = 4.6 x 10^6 solar masses

c = Speed of light = 299792458 m / s

Express the mass in Kg

M = 4.6 x 10^6 * 9.2 * 10^18 = 9.15 * 10^36 kg

Substitute the above values in the equation

[tex]r_s = \frac{2 * 6.67408 * 10^{-11} * 9.15 * 10^36}{299792458 ^2}[/tex]

Evaluate the expression

[tex]r_s = 13589425339.6[/tex] m

Express as km

[tex]r_s = 13589425.3396[/tex] km

Expressas AU

[tex]r_s = \frac{13589425.3396}{1.5 * 10^8}[/tex]

Evaluate the quotient

[tex]r_s = 0.09059616893[/tex]

Approximate

[tex]r_s = 0.091\ AU[/tex]

Hence, the Schwarzschild radius of this supermassive black holeis 0.091 AU

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Help picture below problem 3

Answers

angle ksp+61=108(being straight angle)

or,angle ksp=180-61

angle ksp=119

help is super appreciated this should probably be fast
2. Determine the y – intercept, zeros, the equation of the axis of symmetry and vertex of each quadratic
relation.
y = (x − 3)(x+3)

Answers

[tex]\\ \rm\rightarrowtail y=(x-3)(x+3)=x^2-9[/tex]

Zeros are x intercepts

(3,0) U(-3,0)

#2

Y intercept=-9

#3

Axis of symmetry=x=0

#4

Vertex=(0,-9)

Answer:

Given quadratic equation:  y = (x - 3)(x + 3)

Zeros (x-intercepts)

The zeros of a quadratic equation are the points where the graph of the quadratic equation crosses the x-axis.  So the x-intercepts (zeros) are when y = 0

⇒ (x - 3)(x + 3) = 0

⇒ (x - 3) = 0  so  x = 3

⇒ (x + 3) = 0  so  x = -3

Therefore, the x-intercepts are at (3, 0) and (-3, 0).

y-intercept

The y-intercept is the point where the graph crosses the y-axis.  So the y-intercept is when x = 0

⇒ (0 - 3)(0 + 3) = -9

Therefore, the y-intercept is at (0, -9)

Vertex

Expand the equation so that it is in standard form y = ax² + bx + c:  

⇒ y = x² - 9

x-value of vertex is -b / 2a ⇒ -0 / 2 = 0

substitute the found value of x into the equation to find y:

⇒ y = (0)² - 9 = -9

Therefore, the vertex is (0, -9)

Axis of symmetry

Axis symmetry of a quadratic equation is x = a where a is the x-value of the vertex.

Therefore, the axis of symmetry is x = 0

Which of the following is true for the function y = log3(x)?
It is the inverse of the function y = x3.
It is the inverse of the function y = 3x.
It is the reciprocal of the function y = x3.
It is the reciprocal of the function y = 3x.

Answers

Answer:

B

Step-by-step explanation:

ED

Point G is on line segment FH. Given FG = 7 and GH = 2, determine the length
FH.

Answers

If FG= 7 GH= 2 and the point G is on the line FH then FH = 2 + 7
So the length of FH = 9

Point G is on line segment FH. Given FG = 7 and GH = 2, the length of line segment FH is 9 units.

The length of line segment FH can be determined by adding the lengths of its two parts, FG and GH.

This is based on the property that the whole length of a line segment is equal to the sum of its parts.

Given that FG = 7 and GH = 2,

we can find the length of FH as follows:

FH = FG + GH

FH = 7 + 2

FH = 9

So, the length of line segment FH is 9 units.

This is a basic principle in geometry where the total length of a segment can be calculated by adding the lengths of its individual parts.

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B.A ECO
(b) Prices of three commodities A, B and Crised by 4096, 60% and 90% respectively.
Commodity A is six times more important than Qy and B is three times more important than
C. what is the mean fise of these three commodities?

Answers

gagi i mean hi you I can get over it and white combo for the trial of

Q. If A is a square matrix such that A² = A, then write the value of 7 A −(I + A)³, where I is an identity matrix.​

Answers

Since [tex]A^2=A[/tex], we have

[tex](I + A)^2 = I^2 + IA + AI + A^2 = I + A + A + A = I + 3A[/tex]

[tex](I + A)^3 = (I + A) (I + 3A) = I^2 + 3IA + AI + 3A^2 = I + 3A + A +  3A = I + 7A[/tex]

Then the target expression is

[tex]7A - (I + A)^3 = 7A - (I + 7A) = \boxed{-I}[/tex]

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