The right isosceles triangle shown is rotated about line k with the base forming perpendicular to k. The perimeter of the triangle is 58 units. Which best describes the resulting three-dimensional shape?

Answer:

4

Step-by-step explanation:

y=mx+b

b=y-intercept.

In this case...

mx=-5<-- this is the slope of the line.

b=4<-- y intercept.

Hope this helps, any further questions, please feel free to ask.

Answer:

We can arrange 4 different colored balls in 24 ways.

Step-by-step explanation:

We have to find the number of ways in which we can arrange 4 different colored balls.

Firstly, we have to decide that either we use Permutation or we use Combination.

A Permutation is used when the order of arranging the numbers matters while on the other hand, a combination is used when the order of arranging the numbers doesn't matter.

So, in our question; the ordering matters to us as a ball which is placed in the first place can't be put again put in other places.

Number of ways of arranging 4 different colored balls = [tex]^{4}P_4[/tex]

                     =  [tex]\frac{4!}{(4-4)!}[/tex]          {[tex]\because ^{n} P_r = \frac{n!}{(n-r)!}[/tex] }

                     =  4! = [tex]4 \times 3 \times 2\times 1[/tex]

                     =  24 ways

Hence, we can arrange 4 different colored balls in 24 ways.

Answer:

If it is warm outside, then it is summer

Step-by-step explanation:

To find the converse, interchange the hypothesis and the conclusion

"If it is summer, then it is warm outside"

If it is warm outside, then it is summer

Answer:

A. If it is warm outside, then it is summer

Step-by-step explanation:

statement "If it is summer, then it is warm outside" : warm=summer

A. If it is warm outside, then it is summer. : warm = summer ✓

B. If it is not warm outside, then it is summer. : not warm = summer x

C. If it is warm outside, then it is not summer. : warm =not  summer x

D. If it is not warm outside, then it is not summer. : not warm = not summer x

Answer:

Data set A best fit by the regression line.

Answer:

Data Set C.

Step-by-step explanation:

Well just even by common sense, the line for "data set A" is not good for the points on the graph

The spinner should land on yellow about 75 times, on red about 50 times, and on blue about 25 times.

Yellow: 3 spaces out of 6, so the probability is 3/6 = 1/2

Red: 2 spaces out of 6, so the probability is 2/6 = 1/3

Blue: 1 space out of 6, so the probability is 1/6

multiplying the probability of each color by 150:

Yellow: 1/2 * 150 = 75 times

Red: 1/3 * 150 = 50 times

Blue: 1/6 * 150 = 25 times

Terefore The spinner should land on yellow about 75 times, on red about 50 times, and on blue about 25 times.

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this is your answer..................

Answer: [tex]2.25\sqrt{3}[/tex]

Not sure what you mean by terms of pi, unless you want us to find the area of the sector, not the triangle.

Step-by-step explanation:

Assuming you mean the area of the triangle...

First draw an altitude from the 120 degree angle to the opposite base.  You will find that the altitude will also be a median.  This forms 2 30-60-90 right triangles.  Thus, the height of the altitude is 1.5 and the base of the triangle is 1.5*root3.  Thus, the base of the triangle is [tex]3\sqrt{3}[/tex] and the height is 1.5.  Thus, the area of the triangle is [tex]2.25\sqrt{3}[/tex]

Answer:

The total loss experienced by Pak kamil is RM74

Step-by-step explanation:

The cost of 10 kg and  6 kg of vegetables = RM 136

The cost of 4 kg fish and 2 kg of vegetables = RM 54

Amount for which the fish was sold = RM8 per kilogram

Amount for which the vegetables was sold = RM0.50 per kilogram

The total mass of the fish = 10 kg + 4 kg = 14 kg

The total mass of the vegetables = 6 kg + 2 kg = 8 kg

The amount for which the meat was sold = 14 kg × RM8/kg = RM112

The amount for which the fish was sold = 8 kg × RM0.50/kg = RM4

RM112 + RM4 = RM116

The total amount for which the fish and vegetable was sold = RM136 + RM54 = RM190

Therefore, the total loss experienced by Pak kamil = RM190 - RM116 = RM74.

Answer:

[tex]\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}[/tex]

Step-by-step explanation:

[tex]\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}[/tex] . First multiply 7*-6=-42.

Then do 16*13=208.

Simplify by dividing both by 2.

You get [tex]\frac{-42}{208}=\frac{-21}{104}[/tex].

Your final simplified answer is [tex]\frac{-21}{104}[/tex]

I hope this helps!

Answer:

(0,-3)

Step-by-step explanation:

Answer:

3 ≤ n < 15

 1-2. not n

3-4. yes n

5-6. yes n

 7-8. yes n

9-10. yes n

11-12. yes n

13-14. yes n

15-16. not n

Step-by-step explanation:

Everything on this side is less than, < but everything on this side is greater.

Everything on this side could be equal or less, ≤ but everything on this side is

not.

I'm had a hard time with the number line, but imagine a line going through the periods and there being a dot where the yes ns end, and start.

Intervals has each point represent more than one number making the line shorter.

Answer:

Excess of income over expenditure is ₹1,185,500.

Step-by-step explanation:

Note: The data in this question are merged together. They are therefore sorted before answering this question. See the attached pdf file for the sorted question.

The question is now answered as follows:

Question: Prepare Income and Expenditure A/c. for the year ending 31-03-2014.

Answer and explanation:

Note: See the attached excel file for the Income and Expenditure A/c. for the year ending 31-03-2014.

Both receipts and payments account and income and expenditure account are prepared by not-for-profit organizations such as charity organizations, human right campaign, clubs, etc.

Receipts and payments account is an account gives a summary of all the cash transitions, cash received and paid, that the organization engaged in during a particular period. It is similar to the cash book prepared by profit making organizations. The receipts and payments account is prepared in or to determine the balance of cash in hand or at bank or bank overdraft at the end of the period.

Income and expenditure account is an account gives a summary of all incomes and expenses of an organization during a particular period. It is similar to the trading and profit and loss account prepared by profit making organizations. The income and expenditure account is prepared in order to determine whether there is a surplus or a deficit balance during the period.

In order to solve this problem, we will need a little more information, for example, we need to know what the functions are. Let's say the problem looks like this:

Use the drawing tool(s) to form the correct answer on the provided number line. Consider the functions below.

[tex]f(x)=|3x|-3[/tex]

and

[tex]g(x)=-x^{2}+8x-5[/tex]

Represent the interval where both functions are increasing on the number line provided.

Answer:

See attached picture

Step-by-step explanation:

Since this problem is posted on the algebra section of Brainly, I assume we will need to make use of an algebraic approach to solve this. Basically, the idea is to graph the functions and find the x-values for which both functions increas. In order to graph the functions, we will need to build a table with points for each of the functions. In order to graph the functions you need to pick the x-values you wish and evaluate them in the given functions. (See attached pictures)

Once you got the desired points, you can plot them in the coordinate axis and find the x-values for which both graphs will be increasing. If we take a close look at the graphs we can see the f(x) graph increases in the interval:

(0,∞)

and the g(x) graph increases in the interval:

(-∞,4)

so the interval in which both graphs are increasing will be the region where both intervals cross each other, which will be (0,4)

so that's the interval we draw on our number line. (see attached picture.

Answer:

see photos

Step-by-step explanation:

Plato/Edmentum

Hey there! I'm happy to help!

To find the volume of a cylinder, you multiply the base by the height and then divide by three. The volume of a cone is the same as the volume of a cylinder with the same dimensions divided by three.

So, since a cone's volume is 1/3 of that of a cylinder, we just divide 72 by 3!

72/3=24

Therefore, the volume of the cone is 24 feet cubed.

Have a wonderful day! :D

Answer: its 24.

Step-by-step explanation:

Answer:

R = 21.8° to the nearest tenth

Step-by-step explanation:

To find Angle R we use tan

tan ∅ = opposite / adjacent

From the question

The opposite is 2

The adjacent is 5

So we have

tan R = 2/5

R = tan-¹ 2/5

Hope this helps you

Answer:

(2,1)

Step-by-step explanation:

Well first we single out y or x in one of the equations,

we’ll use 2x + y = 5 and single out y.

2x + y = 5

-2x to both sides

y = -2x + 5

So we can plug in -2x + 5 into y in 2x - 2y = 2.

2x - 2(-2x + 5) = 2

2x + 4x - 10 = 2

combine like terms,

6x - 10 = 2

Communicarice property

+10 to both sides

6x = 12

divide 6 to both sides

x = 2

If x is 2 we can plug 2 in for x in 2x + y = 5.

2(2) + y = 5

4 + y = 5

-4 to both sides

y = 1

(2,1)

Thus,

the solution is (2,1).

Hope this helps :)

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

Answer:

370 mm²

Step-by-step explanation:

The area of this figure can be calculated by taking the whole figure as a full rectangle, and consider the part that is cut out from the middle of the shape as another rectangle.

Find the area of the cut-out part and subtract from the area of the full rectangular shape to get the area of the composite figure.

=>Area of full rectangular shape:

Length = 30 mm

Width = 15 mm

Area = L * B = 30*15 = 450 mm²

=>Area of the cut-out Rectangle part:

Length = 10 mm

Width = 8 mm

Area = 10*8 = 80 mm²

=>Area of composite figure = 450 mm² - 80 mm² = 370 mm²

Answer: 42w

Step-by-step explanation:

Subtracting a negative is like adding.

Answer:

(3,2)

Step-by-step explanation:

Just took the test

Answer:

Step-by-step explanation:

given data

mean = 1.9 hours

standard deviation = 0.3 hours

solution

we get here first  random movie between 1.8 and 2.0 hours

so here

P(1.8 < z < 2 )

z = (1.8 - 1.9) ÷ 0.3

z = -0.33

and

z = (2.0 - 1.9) ÷ 0.3

z = 0.33

z = 0.6293

so

P(-0.333 < z < 0.333 )

=  0.26

so random movie is between 1.8 and 2.0 hours long is 0.26

and

A movie is longer than 2.3 hours.

P(x > 2.3)

P( [tex]\frac{x-\mu }{\sigma}[/tex]  > [tex]\frac{2.3-\mu }{\sigma}[/tex] )

P (z  > [tex]\frac{2.3-1.9 }{0.3}[/tex]  )

P (z  > 1.333  )

= 0.091

so chance a movie is longer than 2.3 hours is 0.091

and

length of movie that is shorter than 94% of the movies is

P(x > a ) = 0.94

P(x <  a ) = 0.06

so

P( [tex]\frac{x-\mu }{\sigma }[/tex] <  [tex]\frac{a-\mu }{\sigma }[/tex] )

[tex]\frac{a-1.9 }{0.3 } = -1.55[/tex]

a = 1.43

so length of the movie that is shorter than 94% of the movies about 1.4 hours.

Answer:

crystal size and rock texture     D

Step-by-step explanation:

:)

Hence, the option (D) is the correct answer i.e., crystal size and rock texture.

What is the texture?

The texture is defined as a tactile quality of an object's surface. It appeals to our sense of touch, which can evoke feelings of pleasure, discomfort, or familiarity.

The texture of an igneous rock is dependent on the rate of cooling of the melt slow cooling allows large crystals to form, fast coolng yields small crystals.

Hence, the option (D) is the correct answer i.e., crystal size and rock texture.

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Answer:

i believe a=105, b=29, and c=45

Answer:

Sine angle of <ACB = 38.68°

Step-by-step explanation:

Hello,

To solve this problem, we need a good representation of the sides and the angle.

See attached document for better illustration.

Assuming it's a right angled triangle,

AC = hypothenus

AB = opposite

BC = adjacent

AC = 40

BC = 25

AB = 25

From trigonometric ratios

Sinθ = opposite/ hypothenus

Sinθ = AB / AC

Sinθ = 25 / 40

Sinθ = 0.625

θ = sin⁻¹0.625

θ = 38.68°

Sine angle of <ACB = 38.68°

Answer:

total rotation = 90 clockwise.

Step-by-step explanation:

Rotation from B to negative y-axis = 45 degrees because B(-3,-3)

Rotation from negative y-axis to B' = 45 degrees because B(-3,3)

Therefore total rotation = 45+45 = 90 clockwise.

Answer:

40 m

Step-by-step explanation:

The perimeter of the flat, orange shape is the sum of all the sides that forms a boundary around the shape.

The shape is made up of 4 triangles having 2 equal side lengths each, which surrounds the center square.

Each side length of the triangle, that forms a boundary round the shape = 5 m.

There are 8 of this equal side length.

Perimeter = 8(5m) = 40 m

Answer:

x = 1

Step-by-step explanation:

Using the rules of logarithms

log [tex]x^{n}[/tex] ⇔ n log x

[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]

Given

3[tex]log_{2}[/tex] (2x) = 3

[tex]log_{2}[/tex] (2x)³ = 3

(2x)³ = 2³

8x³ = 8 ( divide both sides by 8 )

x³ = 1 ( take the cube root of both sides )

x = 1

Answer:

x=1 is the correct answer

Step-by-step explanation:

got it right on edge!!!!

Answer:

c. 108

Step-by-step explanation:

Given

Shape of container: Cube

Initial dimension of the container = 6ft by 6ft by 6ft

Initial Number of boxes = 4

Required

Calculate the number of boxes when the dimension is tripled

The first step is to calculate the initial volume of the box;

[tex]Volume = Length * Length * Length[/tex]

[tex]Volume = 6ft * 6ft * 6ft[/tex]

[tex]Volume = 216ft^3[/tex]

This implies that the container can contain 4 small boxes when its volume is 216;

Represent this as a ratio;

[tex]4 : 216[/tex]

The next step is to calculate the volume when the dimension is tripled;

[tex]New\ Length = Old\ Length * 3[/tex]

[tex]New\ Length = 6ft* 3[/tex]

[tex]New\ Length = 18ft[/tex]

Hence;

[tex]Volume = 18ft * 18ft * 18ft[/tex]

[tex]Volume = 5832ft^3[/tex]

Let the number of boxes it can contain be represented with x

Similarly, represent this as a ratio

[tex]x : 5832[/tex]

Equate both ratios;

[tex]4 : 216 = x : 5832[/tex]

Convert ratios to fractions

[tex]\frac{4}{216} = \frac{x}{5832}[/tex]

Multiply both sides by 5832

[tex]5832 * \frac{4}{216} = \frac{x}{5832} * 5832[/tex]

[tex]5832 * \frac{4}{216} = x[/tex]

[tex]\frac{5832 *4}{216} = x[/tex]

[tex]\frac{23328}{216} = x[/tex]

[tex]108 = x[/tex]

[tex]x = 108[/tex]

Hence, the maximum number of boxes it can contain is 108

Answer:

x^2 +4x + y^2 -2y +1 =0

Step-by-step explanation:

First we need to find the radius

Since the y coordinate is the same, the radius is the difference in the x coordinate -2 - (-4) = -2+4 = 2

A circle can be written in the form

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x--2)^2 + (y-1)^2 = 2^2

(x+2)^2 + (y-1)^2 = 4

FOIL ing

x^2 +4x+4  + y^2 -2y +1 = 4

Combining like terms

x^2 +4x + y^2 -2y +5 -4 =0

x^2 +4x + y^2 -2y +1 =0

Answer and Step-by-step explanation:

Answer:

x^2 +4x + y^2 -2y +1 =0

Step-by-step explanation:

First we need to find the radius

Since the y coordinate is the same, the radius is the difference in the x coordinate -2 - (-4) = -2+4 = 2

A circle can be written in the form

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x--2)^2 + (y-1)^2 = 2^2

(x+2)^2 + (y-1)^2 = 4

FOIL ing

x^2 +4x+4  + y^2 -2y +1 = 4

Combining like terms

x^2 +4x + y^2 -2y +5 -4 =0

x^2 +4x + y^2 -2y +1 =0

Answer:

(a) The probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is 0.3336.

(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 ​minutes is 0.0582.

(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is 0.0055.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) The population mean must be more than 72​, since the probability is so low.

Step-by-step explanation:

We are given that a geyser has a mean time between eruptions of 72 minutes.

Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.

(a) Let X = the interval of time between the eruptions

So, X ~ N([tex]\mu=72, \sigma^{2} =23^{2}[/tex])

The z-score probability distribution for the normal distribution is given by;

                            Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean time = 72 minutes

           [tex]\sigma[/tex] = standard deviation = 23 minutes

Now, the probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is given by = P(X > 82 min)

       P(X > 82 min) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{82-72}{23}[/tex] ) = P(Z > 0.43) = 1 - P(Z [tex]\leq[/tex] 0.43)

                                                           = 1 - 0.6664 = 0.3336

The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.

(b) Let [tex]\bar X[/tex] = sample mean time between the eruptions

The z-score probability distribution for the sample mean is given by;

                            Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean time = 72 minutes

           [tex]\sigma[/tex] = standard deviation = 23 minutes

           n = sample of time intervals = 13

Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P([tex]\bar X[/tex] > 82 min)

       P([tex]\bar X[/tex] > 82 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{82-72}{\frac{23}{\sqrt{13} } }[/tex] ) = P(Z > 1.57) = 1 - P(Z [tex]\leq[/tex] 1.57)

                                                           = 1 - 0.9418 = 0.0582

The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.

(c) Let [tex]\bar X[/tex] = sample mean time between the eruptions

The z-score probability distribution for the sample mean is given by;

                            Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean time = 72 minutes

           [tex]\sigma[/tex] = standard deviation = 23 minutes

           n = sample of time intervals = 34

Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P([tex]\bar X[/tex] > 82 min)

       P([tex]\bar X[/tex] > 82 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{82-72}{\frac{23}{\sqrt{34} } }[/tex] ) = P(Z > 2.54) = 1 - P(Z [tex]\leq[/tex] 2.54)

                                                           = 1 - 0.9945 = 0.0055

The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 ​minutes, then we conclude that the population mean must be more than 72​, since the probability is so low.

Answer:

Step-by-step explanation:

From the given data

mean, u = 72

Standard deviation [tex]\rho[/tex] = 23

A) Probability that a randomly selected time interval between eruptions is longer than 82​minutes

[tex]P (x > 82) = P[\frac{x-u}{\rho} > \frac{82-72}{23}]\\\\P (x > 82) = P[z > 0.43]\\\\P (x > 82) = 0.3336[/tex]

B)

[tex]P (x > 82) = P[\frac{x-u}{\frac{\rho}{\sqrtn}} > \frac{82-72}{\frac{23}{\sqrt{13}}}]\\\\P (x > 82) = P[z > 1.5676]\\\\P (x > 82) = 0.0594[/tex]

C)

[tex]P (x > 82) = P[\frac{x-u}{\frac{\rho}{\sqrtn}} > \frac{82-72}{\frac{23}{\sqrt{34}}}]\\\\P (x > 82) = P[z > 2.5351]\\\\P (x > 82) = 0.0057\\\\[/tex]

D) If the mean is less than 82minutes, then the probability that the sample mean of the time between eruptions is greater than 83 minutes decrease because the variability in the sample mean decrease as the sample size increases

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