Answer:
12.3 °C
Explanation:
Q=m*Cp*ΔT-->
1150=45*2.07*ΔT-->
ΔT=1150/93.15-->
ΔΤ=12.3 °C
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?
A) Θ decrease
B) Θ increase
C) Θ remains the same
D) distant between spheres increases
Answer:
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)
Explanation:
please click the heart and rate excellent and brainleist to ❤☺️☻♨️♨️☻☺️❤
Give a definition of the positive work.
Answer and I will give you brainiliest
Explanation:
The work that leads towards the open mindness of people without any discrimination that contribute to a moral development is positive work
what is the process that creates wind.
Answer:
Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.
plz mark me as brainliest.
Two identical particles, each with a mass of 4.5 mg and a charge of 30 nC, are moving directly toward each other with equal speeds of 4.0 m/s at an instant when the distance separating the two is equal to 25 cm. How far apart will they be when closest to one another?
Answer:
r₁ = 20.5 cm
Explanation:
In this exercise we can use the conservation of energy
the gravitational power energy is always attractive, the electrical power energy is repulsive if the charges are of the same sign
starting point.
Em₀ = U_g + U_e + K = [tex]-G \frac{m_1m_2}{r} +k \frac{q_1q_2}{r} - 2 ( \frac{1}{2} m v^2)[/tex]
the two in the kinetic energy is because they are two particles
final point. When it is detained
Em_f = U_g + U_e = [tex]-G \frac{m_1m_2}{r_1} + k \frac{q_1q_2}{r_1}[/tex]
the energy is conserved
Em₀ = em_f
the charges and masses of the two particles are equal
[tex]-G \frac{m^2}{r} + k \frac{q^2}{r} + m v^2 = - G \frac{m^2}{r_1} + k \frac{q^2}{r_1}[/tex]
sustitute the values
-6.67-11 (4.5 10-3) ² / 0.25 - 9, 109 (30 10-9) ² / 0.25 + 4.5 10-3 4² = - 6.67 10- 11 (4.5 10-3) ² / r1 -9 109 (30 10-9) ² / r1
-5.4 10⁻¹⁵ + 3.24 10⁻⁵ - 7.2 10⁻⁵ = -1.35 10⁻¹⁵ / r₁ + 8.1 10⁻⁶ / r₁
We can see that the terms that correspond to the gravitational potential energy are much smaller than the terms of the electric power, which is why we depress them.
3.24 10⁻⁵ - 7.2 10⁻⁵ = 8.1 10⁻⁶ / r₁
-3.96 10⁻⁵ = 8.1 10⁻⁶ / r₁
r₁ = 8.1 10⁻⁶ /3.96 10⁻⁵
r₁ = 2.045 10⁻¹ m
r₁ = 20.5 cm
A proton moves with a speed of 1.00 x 106 m/s perpendicular to a magnetic field, B. As a result, the proton moves in circle of radius 20.0 m. If an electron were moving at the same speed perpendicular to the same magnetic field, what would be the radius of the circle the electron would move in
Answer:
0.0109 m ≈ 10.9 mm
Explanation:
proton speed = 1 * 10^6 m/s
radius in which the proton moves = 20 m
determine the radius of the circle in which an electron would move
we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)
For proton :
Mp*V^2 / rp = qp *VB ∴ rp = Mp*V / qP*B ---------- ( 1 )
For electron:
re = Me*V/ qE * B -------- ( 2 )
Next: take the ratio of equations 1 and 2
re / rp = Me / Mp ( note: qE = qP = 1.6 * 10^-19 C )
∴ re ( radius of the electron orbit )
= ( Me / Mp ) rp
= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20
= ( 5.45 * 10^-4 ) * 20
= 0.0109 m ≈ 10.9 mm
The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error
Answer: Steeper slopes mean lower speeds.
Explanation:
How does the law of universal gravitation apply to objects near Earth’s surface?
Universal gravitation pulls all the objects towards the earth which is also known as the gravity of the earth and the acceleration due to the gravity has a magnitude of 9.8 m/s².
What is gravitation?All the known universe material items are subject to the force of gravity, commonly known as gravitation. If there is a difference in mass between any two things or particles, gravity will tend to pull them in that direction.
Long ago, the prehistoric man understood that when things are launched close to the Planet's surface, they inevitably fall to the earth. In other words, the Earth pulls nearby objects toward itself.
Nearby objects are drawn to the Earth by its magnetic field. The Sun, as well as any other star and its satellites, are affected by this universal force. Each pulls the other in. Sir Isaac Newton gave a mathematical definition of this attraction.
To know more about gravitation:
https://brainly.com/question/29458450
#SPJ2
A 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.
Answer:
[tex]v=15.9499m/s[/tex]
Explanation:
From the question we are told that:
Mass of wood [tex]m=1kg[/tex]
force constants [tex]k= 200N-m[/tex]
Coefficient of kinetic friction [tex]\mu= 0.2[/tex]
Bullet mass [tex]m_b= 20 \approx 0.02kg[/tex]
Spring compresion [tex]y=15cm \approx 0.15 m[/tex]
Generally the equation for kinetic energy of bullet [tex]K>E_b[/tex] is mathematically given by
Complete Question
[tex]K.E_b=spring potential energy+work done against friction[/tex]
[tex]K.E_b=\frac{1}{2} mbv^2[/tex]
[tex]\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my[/tex]
[tex]\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)[/tex]
[tex]v=15.9499m/s[/tex]
[tex]v\approx16m/s[/tex]
1. Which of these can be used to observe the field of the
magnet?
A. bits of paper
C. small pieces of cloth
B. iron fillings
D. saw dust
2
Irgeckich of thon
g
Answer:
B. iron fillings
Explanation:
Electric current is a measure of
Group of answer choices
a. the amount of resistance provided by the circuit.
b. the amount of electric charge that passes within a certain amount of time.
c. the amount of electric potential an electron gains passing through a battery
d. the amount of protons that pass through a resistor.
Answer:
b. the amount of electric charge that passes within a certain amount of time
Answer:
The answer is B which is the amount of electric charge that passes within a certain amount of time in my opinion.
How far are two protons if they exert a force of 0.5 N on one another?
Answer:
5.08 metres
Explanation:
The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron
The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.
As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.
According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;[tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]Here, since both the particles are protons;[tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]Given that F = 0.5 NSubstituting the known values in the Coulomb's law equation, we get;[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]
ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]
Learn more about Coulomb's Law here:
https://brainly.com/question/1698562
When turning from your path onto a perpendicular path your speed
SHOULD BE at a STEADY
DRIVERS ED PLEASE HELP
Answer: 5-15MPH
Explanation: Trust me
A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move between adjacent tracks. What is the longest time needed to read an arbitrary sector located anywhere on the disk
Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Quantum mechanics is used to describe the vibrational motion of molecules, but analysis using classical physics gives some useful insight. In a classical model the vibrational motion can be treated as SHM of the atoms connected by a spring. The two atoms in a diatomic molecule vibrate about their center of mass, but in the molecule HIHI, where one atom is much more massive than the other, we can treat the hydrogen atom as oscillating in SHM while the iodine atom remains at rest.
Part A
A classical estimate of the vibrational frequency is f = 7.0 x 1015 Hz. The mass of a hydrogen atom differs little from the mass of a proton. If the HI molecule is modeled as two atoms connected by a spring, what is the force constant of the spring? Express your answer to two significant figures and include the appropriate units. k= 320 N
Part B
The vibrational energy of the molecule is measured to be about 5 x 10-20 J. In the classical model, what is the maximum speed of the H atom during its SHM? Express your answer to one significant figure and include the appropriate units. v = 8000
Part C
What is the amplitude of the vibrational motion? Express your answer to one significant figure and include the appropriate units. • Ea ? I HÀ A = 3.4.1018 • • m
Part D
How does your result compare to the equilibrium distance between the two atoms in the HI molecule, which is about 1.6 x 10-10 m? Express your answer using one significant figure. IVO AQ R O 2 ? equilibrium distance = 2.25 • 10-2
Answer:
o my god how big is the question
A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to θ(t)=γt+βt3θ(t)=γt+βt3, where γ=γ= 0.450 rad/srad/s and β=β= 1.10×10−2 rad/s3rad/s3. Part A Calculate the angular velocity of the merry-go-round as a function of time. Express your answer in terms of the variables ββ, γγ, and tt. ωz(t)ωz(t) = nothing rad/srad/s SubmitRequest Answer Part B What is the initial value of the angular velocity? ωzωz = nothing rad/srad/s SubmitRequest Answer Part C Calculate the instantaneous value of the angular velocity ωzωz at t=t= 5.25 ss . ωzωz = nothing rad/srad/s SubmitRequest Answer Part D Calculate the average angular velocity ωav−zωav−z for the time interval t=0t=0 to t=t= 5.25 ss .
Answer:
hufiui
fihgpfghlfikgergkfkjhfkhjgkffhhh
Explanation:
jjgzgcjxhgygueyuufhfugkhkckgijljhgxjgjgffhgkgjxhxjgjcjckvjgghkhkgjgjfhfhfhffrusufsflslrsyfhldufñlñudtoqdyhjjxkgsgjfktwlyfñujxjxhlxlhdktstedoyñfuyñflldytidoyeyljjcñcjluffñui5woyepurñfuñufldyrajuñdlydstdyñudñydktshñxjcñydiw5uñfitwoyeoyeñufñfuñifjñufhlsyñeifññydoysitaiwtuñdyñdlsyltslsyoyeylsuñdñjjcyldlyslatlysñudidñjdñfjñjjxlhsmzhmzjjdjdlhdñhjdñjdñjddñhflhuñfhxltkds4urayraylraluarularuñstuñtsuñtsultsuñtsuñstñitsñktssistustlulsrustlularyralultalutslutajltsñgskjlgzljg?g o uguhxputxipyfugxiñhxiñhfuñdguldthgksjmgdjmgkhdjlgdjlgd
pduoyditsyafylrayoraourauptautospustistiptsñitsñitsñitsiptsiteitdustuñtsuñtsñitwiñstñitwñitsñstuuñrsoursurosoustjlsrlutejlgsjlstjfsjlgsultsjgzjñgsññkdylfhkñdgjlfshkadmjgsuñstñkydñkydñiykdhiñstñitsuñtsisñtñtieñietñietñiteñiwtñitskñgsiñteuñwrkñsturaluglsuñtwjlfalfjalhadoyfutdllgdñitswtkgsñktjrajtsurwñwñutiñtsiwñtuwñturqlñitwualtayoryarluarlietite
Suppose that the collector is held at a small negative voltage with respect to the grid. Will the accelerated electrons reach the collecting plate?
A) Yes, but only those electrons with energy less than the potential difference established between the grid and the collector will reach the collector.
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
C) Yes; all the accelerated electrons will reach the collector.
D) No, none of the electrons will reach the collector
Answer:
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
Explanation:
In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential
so according to the given situation, the option b is correct
And, the rest of the options are wrong
Which of the following would require the
greatest number of calories?
Answer:
Heating 100 g of water from 10◦C to 50◦C
Explanation:
m₁ ΔT₁ = 2000
m₂ ΔT₂ = 300
m₃ ΔT₃ = 4000
m₄ ΔT₄ = 70
A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 Pa. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere
Answer:
[tex]F \approx 19.5 N[/tex]
Explanation:
From the question we are told that:
Pressure of [tex]P_{CO_2}=1.50 * 105 Pa.[/tex]
Bottle cap area [tex]A_b= 4.40 * 10-4 m^2[/tex]
Generally the equation for Resultant pressure [tex]P_r[/tex] is give as is mathematically given by
[tex]P_r=P_{CO_2}-P_a[/tex]
Where
[tex]P_a=atmospheric\ pressure = 1.013*10^5 pa[/tex]
[tex]P_r=1.50 * 105 Pa-1.013*10^5 pa[/tex]
[tex]P_r=0.487*10^5 pa[/tex]
Generally the equation for Force exerted by screw F is give as is mathematically given by
[tex]F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N[/tex]
[tex]F \approx 19.5 N[/tex]
Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?
b) What will a negative test charge do when it is released from rest at B?
[TG.05H]A geothermal plant has been built in a location. Which of these is the most likely impact of the plant on the location?
depletion of fossil fuels like coal
damage to hot springs and geysers
decrease in average annual temperature
increase in emission of greenhouse gases
The environmental impact that is most likely to occur in an area where there is a geothermal plant is decrease in average annual temperature.
What is a geothermal plant?A geothermal plant makes use of both heat and water in the generation of electricity.
The environmental impact that is most likely to occur in an area where there is a geothermal plant is decrease in average annual temperature.
Learn more about geothermal plant:https://brainly.com/question/27442707
#SPJ2
can someone help? NO LINKS OR IM REPORTING
Answer:
BjsjsjsiisudujdgjkkgywuuuyyyuwuA freight train car is moving at a constant speed with respect to the ground of Vcg. A man standing on a flatbed car throws a ball into the air and catches it as it falls. Relative to the flatbed car, the initial velocity of the ball is Vibc straight up. a. What are the magnitude and direction of the initial velocity of the ball as seen by a second man standing on the ground next to the track
Answer:
chiicken
Explanation:
What are the units for potential difference?
A. Ohms
B. Joules per second
C. Volts
D. Coulombs per second
TRUE OR FALSE??
____1.Light travels faster in liquid than in air.
____2.Optical fiber light has the ability to travel long distances.
____3.Light travels more slowly in water and glass materials.
____4.Light always travels in a straight line when going through a single medium.
____5. Laser is used by doctors in treating ailments in the internal organs such as the eyes.
Answer:
false, true, true, true, false
Explanation:
Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.
Explanation:
give me more detail and i well help you out
What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle ? Please explain good thank you
Answer:
The frecuency is 1.2*10¹¹ Hz.
Explanation:
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).
The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f * λ.
In this case:
v= 300,000,000 m/sf= ?λ= 0.0025 mReplacing:
300,000,000 m/s= f* 0.0025 m
Solving:
f= 300,000,000 m/s ÷0.0025 m
f= 1.2*10¹¹ [tex]\frac{1}{s}[/tex] = 1.2*10¹¹ Hz
The frecuency is 1.2*10¹¹ Hz.
The visible spectrum of sunlight shows a range of colors from red to violet. This spectrum has numerous dark lines spread throughout it. Noting that the surface of the Sun is much cooler than the interior, so that the surface is comparable to a cool gas through which light passes, which of the following statements correctly explains the dark lines?
a. The cooler, denser surface material scatters certain wavelengths of light, forming dark lines.
b. The atoms at the surface absorb certain wavelengths of light, causing the dark lines at those wavelengths.
c. The atoms in the Sun’s interior emit light of specific wavelength, so that parts of the spectrum are dark.
d. The atoms at the surface are excited by the high interior temperatures, so that the dark lines are merely wavelengths at which those atoms don’t emit energy.
A ball weighing 100 g is attached to a string and swung around with a speed of 2 m/s. If the centripetal force exerted by the string is
0.5 N, what is the length of the string?
A) 0.08 m
B) 0.8 cm
C) 8 m
D) 80 cm
Assuming the ball is swung around in a circle parallel to the ground, it has a centripetal acceleration a of
a = v ² / R
where v is the tangential speed of the ball and R is the length of the string.
The tension in the string is 0.5 N, so by Newton's second law, the ball has acceleration
F = m a → a = F / m = (0.5 N) / (0.1 kg) = 5 m/s²
where m is the ball's mass.
Solve for R :
a = v ² / R → R = v ² / a = (2 m/s)² / (5 m/s²) = 0.8 m = 80 cm
Two children are sitting on a see-saw, as shown. Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw.
We have that for the Question "Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw"
It can be said that
The distance = [tex]1.8m[/tex]From the question we are told
weights are = 300 N and 500 N
length l = 6 m
take x distance from the 300 N
total torque is zero
[tex]300*3 = 500x\\\\x = 1.8 m[/tex]
For more information on this visit
https://brainly.com/question/23379286
What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!
Answer:
Voltage is required for there to be a current but resistance can effect the amount of current.
Answer:
the answer is voltage
Explanation:
we just finished this unit in class