The static frictional force between a 95-kilogram object and the floor is 45 Newtons. The kinetic frictional force is only 22 Newtons. What force must be exerted to accelerate the box at 0.5 meters per second to the south?​

Answers

Answer 1

Answer:

F = 69.5 [N]

Explanation:

We must remember that the friction force is defined as the product of the normal force by the coefficient of friction, and it can be calculated by the following expression.

[tex]f=N*miu[/tex]

where:

N = normal force [N]

miu = friction coefficient

f = friction force = 22 [N]

Now we must calculate the force exerted by means of Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

[tex]F - f = m*a[/tex]

where:

F = force exerted [N]

f = friction force [N]

m = mass = 95 [kg]

a = acceleration = 0.5 [m/s²]

Now replacing:

[tex]F - 22 = 95*0.5\\F = 47.5 + 22\\F = 69.5 [N][/tex]


Related Questions

. A ventilation fan has blades 0.25 m long rotating at 20 rpm (revolutions per minute). What is the centripetal acceleration of a point on the outer tip of a blade

Answers

Answer:

The centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²

Explanation:

Given;

length of the fan blade, r = 0.25 m

angular speed = 20 rpm

The angular speed in rad/s is given as;

[tex]\omega = \frac{20 \ rev}{ \ \ \min} \ \times \ \frac{2\pi}{1 \ rev} \ \times \ \frac{1 \ \min}{60s} = 2.095 \ rad/s \\\\[/tex]

The centripetal acceleration of a point on the outer tip of a blade is given as;

[tex]\alpha_c = \frac{v^2}{r} = \omega ^2r[/tex]

[tex]\alpha _c = (2.095)^2(0.25)\\\\\alpha _c =1.097 \ m/s^2[/tex]

Therefore, the centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²

Answer:

The centripetal acceleration = [tex]1.1m/s^2[/tex]

Explanation:

Given

[tex]rpm = 20[/tex]

therefore,

[tex]20rpm = \frac{20*2\pi}{60}\\\\=2.1 rad/s = w[/tex]

From,

[tex]V = rw\\\\V = 0.25 * 2.1\\\\V = 0.525m/s[/tex]

Centripetal acceleration,

[tex]a_c = \frac{V^2}{r}\\\\a_c = \frac{0.525^2}{0.25}\\\\a_c = 1.1m/s^2[/tex]

For more information centripetal acceleration, visit

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Dominic has a brain injury. Why is this MOST likely to be a serious injury?

Answers

If Dominic has a brain injury, then he must have sustained a serious injury.

Functions of the brain

The brain coordinates all the activities in the body such as speech, locomotion, coordination and intelligence. This makes the brain the master point of control in the body.

Brain injury

Whenever there is an injury to the brain, various parts of the body could be affected. Functions such as speech, locomotion and general coordination may become largely impaired.

Therefore, if Dominic has a brain injury, then he must have sustained a serious injury.

Learn more about the brain: https://brainly.com/question/5361122

the amplitude of an oscillator decreases to 36.8% of its initial value in 10.0 s. what is the value of the time constant

Answers

Answer:

τ = 5 s

Explanation:

When a vibrating body is damped. Its amplitude starts to decrease. This decrement is exponential. And it is given as follows:

[tex]X = X_{0}e^{-\frac{t}{2\tau}[/tex]

where,

τ = Time Constant = ?

X = Instantaneous value of amplitude

X₀ = Initial Value of amplitude

t = time interval = 10 s

The ratio of decrement is given as:

[tex]\frac{X}{X_0} = 36.8\% = 0.368[/tex]

therefore, using these values, we get:

[tex]\frac{X}{X_{0}} = 0.368 = e^{\frac{10\ s}{2\tau}}[/tex]

Taking natural log (ln) on both sides, we get:

[tex]ln(0.368) = \frac{10\ s}{2\tau}\\\\\tau = \frac{10\ s}{2ln(0.368)}[/tex]

τ = 5 s

The value of the time constant for the decrease in the amplitude of this oscillator is 5.

Given the following data:

Decrease in amplitude = 36.8% = 0.368Time = 10.0 seconds.

To determine the value of the time constant:

Mathematically, the amplitude for damped harmonic motion is given by the formula:

[tex]X = X_o e^\frac{t}{2 \tau}[/tex]

Where:

t is the time.[tex]\tau[/tex] is the time constant.X is the instantaneous value of amplitude.[tex]X_o[/tex] is the initial value of amplitude.

Rearranging the formula, we have:

[tex]\frac{X}{X_o} = e^{-\frac{t}{2 \tau}}[/tex]

Substituting the given parameters into the formula, we have;

[tex]0.368 = e^\frac{-10}{2 \tau}\\\\ln(0.368) = \frac{-10}{2 \tau}\\\\-0.9997 = \frac{-10}{2 \tau}\\\\2 \tau \times -0.9997 = 10\\\\-1.9994\tau=-10\\\\\tau =\frac{-10}{-1.9994} \\\\\tau = 5.0[/tex]

Time constant = 5

Read more: https://brainly.com/question/14708169

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