The table below shows the students in an Algebra 1 class. What is the probability that a randomly chosen student will be a girl? (Note: If your fraction will reduce, you need to reduce it.)

Answer:

y= [tex]\sqrt{x}[/tex]

Step-by-step explanation:

Answer:  y = -2

Step-by-step explanation:

f(x) = A cos (Bx - C) + D

                                  ↓

                                center line (aka midline)

f(x) = 2 cos (3x - 5π/6) - 2

                                      ↓

                                  midline = -2

The midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D

It is defined as a function that is sin-cos wave in nature, and it has a domain of all real numbers and lies between the [a, a] where is the amplitude of the function.

It is given that the cos function is:

f(x) = 2cos(3x - 5π/6) - 2

As we know, the standard form of the cos function is:

f(x) = Acos(Bx - C) + D

Here, A is the amplitude

B is the period of the cos function

C is the phase shift of the cos function

D is the vertical shift of the cos function/midline

On comparing:

D = -2

The midline:

y = -2

Thus, the midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D

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Answer:

11

Step-by-step explanation:

6.7 / .6

Multiply top and bottom by 10

67/6

66/6 = 11 so this is close to 11

Answer:

80 pages

Step-by-step explanation:

Let's use a ratio to solve:

pages : seconds

   12    :       9

    4     :       3

    [tex]p[/tex]     :      60

It would seem that [tex]p[/tex] would equal 80. The printer can print 80 pages in 60 seconds or one minute.

Answer:

No

Step-by-step explanation:

The sum of two random sides of a triangle must be bigger than the third side and their differences must be smaller than the third side

For example

3 - 4 - 5 can be made into a triangle because 3 + 4 > 5 and 4 - 3 < 5

Answer:

La magnitud del desplazamiento resultante es 2045.463 kilómetros. La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.

Step-by-step explanation:

En primer lugar, se construye el triángulo. La figura resultante se encuentra incluida como archivo adjunto. La magnitud del desplazamiento resultante se determina mediante la Ley del Coseno:

[tex]r = \sqrt{(800\,km)^{2}+(1400\,km)^{2}-2\cdot (800\,km)\cdot (1400\,km)\cdot \cos 135^{\circ}}[/tex]

[tex]r \approx 2045.463\,km[/tex]

La magnitud del desplazamiento resultante es 2045.463 kilómetros.

La dirección del desplazamiento resultante es hallada por medio de la Ley del Seno, sabiendo que el ángulo del desplazamiento resultante a la recta de 1400 kilómetros:

[tex]\frac{1400\,km}{\sin \alpha} = \frac{2045.463\,km}{\sin 135^{\circ}}[/tex]

Se despeja el ángulo correspondiente:

[tex]\alpha = \sin^{-1}\left(\frac{1400\,km}{2045.463\,km}\times \sin 135^{\circ} \right)[/tex]

[tex]\alpha \approx 28.945^{\circ}[/tex]

La dirección absoluta del desplazamiento resultante es:

[tex]\alpha' = 180^{\circ}-\alpha[/tex]

[tex]\alpha' = 180^{\circ}-28.945^{\circ}[/tex]

[tex]\alpha' = 151.055^{\circ}[/tex]

La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.

Answer:

Octahedron  Answer B) in your list

Step-by-step explanation:

The octahedron is the three dimensional figure that contains 8 equilateral triangles as its faces. It looks like 2 pyramids with square base and lateral equilateral triangles joined by their square bases

Answer:

C

Step-by-step explanation:

apeeeex

Answer:

Step-by-step explanation:

[tex] \frac{7x + 19}{(x + 1)(x + 5)} [/tex]

Multiply each term in the first parentheses by each term in second parentheses ( FOIL)

[tex] \frac{7x + 19}{x(x + 5) + 1(x + 5)} [/tex]

Calculate the product

[tex] \frac{7x + 19}{ {x}^{2} + 5x + x + 5} [/tex]

Collect like terms

[tex] \frac{7x + 9}{ {x}^{2} + 6x + 5 } [/tex]

Hope this helps...

Best regards!!

Answer:

a. 4r² b. 2r c. 6 cm

Step-by-step explanation:

The surface area A of the cube is A = 24r². We know that the surface area, A of a cube also equals A = 6L² where L is the length of its side.

Now, equating both expressions, 6L² = 24r²

dividing both sides by 6, we have

6L²/6 = 24r²/6

L² = 4r². Since the area of one face is L², the polynomial that determines the area of one face is A' = 4r².

b.  Since L² = 4r² the rea of one face of the cube, taking square roots of both sides, we have

√L² = √4r²

L = 2r

So, the polynomial that represents the length of an edge of the cube is L = 2r

c. The length of an edge of the cube is L = 2r. When r = 3 cm.

L = 2r = 2 × 3 cm = 6 cm

So, the length of an edge of the cube is 6 cm.

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

Answer:

prime

Step-by-step explanation:

x^2 - 2x + 3

What two numbers multiply to 3 and add to -2

There are none so this cannot be factored in the real numbers

The relation { (3,4), (-3, 8), (6,8) } is a function.

====================================================

Explanation:

Choice A can be ruled out because we have x = -3 repeat itself for different y values. For any x input, there must be exactly one y output. This is assuming the x value is in the domain of course.

Choice C can be ruled out for similar reasoning. This time x = 3 repeats.

Choice D is the same story, but we go back to x = -3 showing up twice.

Choice B is the only thing left. Each x value is unique or only written one time. This graph passes the vertical line test. The other graphs fail the vertical line test (it is possible to draw a vertical line through more than one point).

Answer:

Option D.

Step-by-step explanation:

From the given it is clear that the horizontal line intersect the y-axis at -1. So, the equation of horizontal line is y=-1.

The curves represent the graph of [tex]y=\tan x[/tex].

We need to find the equation which is represented by the intersection of the graphs.

We have two equations one is for curve and another for horizontal line.

[tex]y=\tan x[/tex]

[tex]y=-1[/tex]

Equate both equations to get the equation which is represented by the intersection of the graphs.

[tex]\tan x =-1[/tex]

Therefore, the correct option is D.

Answer:

11

Step-by-step explanation:

1650/15/10 = 11

Answer:

[tex]\boxed{\frac{25\pi }{36}}[/tex]

Step-by-step explanation:

Use the formula to convert from degrees to radians: [tex]x * \frac{\pi }{180}[/tex], where x is the value in degrees.

[tex]125 * \frac{\pi }{180}[/tex] = [tex]\frac{125\pi }{180}[/tex]

Then, simplify your fraction ⇒ [tex]\frac{125\pi }{180} = \boxed{\frac{25\pi}{36} }[/tex]

Answer:

2(a - 3). = 4

_______

3

Cross multiply.

2(a- 3) = 12

2a - 6 = 12

2a = 12 + 6

2a = 18

a = 18 ÷ 2

a = 9

Answer:

a = 9

Step-by-step explanation:

Given

[tex]\frac{2(a-3)}{3}[/tex] = 4 ( multiply both sides by 3 to clear the fraction

2(a - 3) = 12 ( divide both sides by 2 )

a - 3 = 6 ( add 3 to both sides )

a = 9

As a check substitute a = 9 into the left side of the equation and if equal to the right side then it is the solution.

[tex]\frac{2(9-3)}{3}[/tex] = [tex]\frac{2(6)}{3}[/tex] = [tex]\frac{12}{3}[/tex] = 4 = right side

Thus solution is a = 9

Answer:

10.375

Step-by-step explanation:

1.) Add up all the amount of pizzas |  12 + 9 + 11 +10+13+8+ 7,+ 13=83

2) Divide the total amount of pizzas by the amount of pizzas/amount of numbers of pizzas. | 83 divided by 8 =

10.375

Answer: The area of land =108 m²

Step-by-step explanation:

In the given piece of land is in the shape of a parallelogram.

Diagonals divide it into 2 equal parts.

So, area of parallelogram = 2 x (Area of triangle with sides 12m and 9 m and  15 m)

Heron's formula :

Area of triangle = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex], where [tex]s=\dfrac{a+b+c}{2}[/tex]

Let a= 12 , b= 9 and c = 15

[tex]s=\dfrac{12+9+15}{2}=18[/tex]

Area of triangle = [tex]\sqrt{18(18-12)(18-9)(18-15)}[/tex]

[tex]=\sqrt{18\times6\times9\times3}=\sqrt{2916}=54\ m^2[/tex]

Then, area of parallelogram= 2 x 54 = 108 m²

Hence, the area of land =108 m²

Answer:

the first one has one solution because eventually they will cross

The value of (f - g)(x) is x² + 4x + 3 if f(x) =  2x² - 5 and g(x) = x² - 4x - 8 option (B) is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x) =  2x² - 5

g(x) = x² - 4x - 8

(f - g)(x) = f(x) - g(x)

= (2x² - 5) - (x² - 4x - 8)

= 2x² - 5 - x² + 4x + 8

= x² + 4x + 3

(f - g)(x) = x² + 4x + 3

Thus, the value of (f - g)(x) is x² + 4x + 3 if f(x) =  2x² - 5 and g(x) = x² - 4x - 8 option (B) is correct.

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Answer:

T = - 3.2e + 80

Step-by-step explanation:

Given the following :

e = elevation in thousands of feets

T = temperature (°F)

e1 = 5 ; e2 = 10 (in thousands of feet)

T1 = 64° ; T2 = 48°

y = mx + c ; T = me + c

y = ; m = slope, c = intercept

64 = m5 + c - - - - (1)

48 = m10 + c - - - - (2)

From (1)

c = 64 - m5

Substitute c = 64 - m5 into (2)

48 = m10 + c - - - - (2)

48 = m10 + 64 - m5

48 - 64 = 10m - 5m

-16 = 5m

m = - 16 / 5

m = - 3.2

Substitute the value of m into c = 64 - m5

c = 64 - 5(-3.2)

c = 64 - (-16)

c = 64 + 16

c = 80

Inserting our c and m values into T = me + c

T = - 3.2e + 80

Where e is in thousands of feet

T is in °F

Answer:

1. Find the difference between the areas.

Area of the small rectangle: [tex](x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14[/tex]

Area of the big rectangle: [tex](x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99[/tex]

The difference is: [tex]11x+85[/tex]

[tex]( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85[/tex]

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

[tex]f(d)=h=-2d^2+7d+4[/tex]

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

[tex]f(0)=h=-2(0)^2+7(0)+4[/tex]

[tex]h=4[/tex]

The height is 4 meters.

b) 9 meters.

For [tex]d=1[/tex]

[tex]f(1)=h=-2(1)^2+7(1)+4[/tex]

[tex]f(1)=h=-2+7+4[/tex]

[tex]h=9[/tex]

b) The ball travels 4 meters.

But to calculate it, it is when [tex]h=0[/tex]

[tex]0=-2d^2+7d+4[/tex]

Using the quadratic formula:

[tex]$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$[/tex]

[tex]$d=\frac{-7\pm\sqrt{81}}{-4}$[/tex]

[tex]$d=\frac{-7\pm9}{-4}$[/tex]

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

[tex]$d=-\frac{1}{2} \text{ or }d=4$[/tex]

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

[tex]V=\pi r^2h[/tex]

[tex]V=\pi (2.5)^2 \cdot 5[/tex]

[tex]V=31.25 \pi[/tex]

[tex]V_{c} \approx 98.17 \text{ m}^3[/tex]

The volume of the sphere:

[tex]$V=\frac{4}{3} \pi r^2$[/tex]

[tex]V_{s} \approx 65.4 \text{ m}^3[/tex]

The volume of the capsule is approximately [tex]163.57 \text{ m}^3[/tex]

Answer:

0.15x + 0.20y = 1.80

Step-by-step explanation:

Here, we are interested in writing an equation for the total cost of the apples and bananas

before we write , kindly understand that 100p = £1

So the cost of apple which is 15p will be 15/100 =£ 0.15

The cost of bananas which is 20p will be 20/100 = £0.2

Thus, the total cost of the apples bought will be number of apples bought * price of apple bought = 0.15 * x = £0.15x

The cost of bananas = number of bananas bought * price of bananas = 0.2 * y = £0.2y

So the total cost of the apples and bananas will be;

0.15x + 0.20y = 1.80

Answer:

[tex]y = \frac{5x}{2} - 5[/tex]

Step-by-step explanation:

Given the equation 5x - 2y = 10, to write the equation in slope-intercept form, we need to write it in the standard format y = mx+c where m is the slope/gradient and c is the intercept.

From the equation given  5x - 2y = 10, we will make y the subject of the formula as shown;

[tex]5x - 2y = 10\\\\subtract \ 5x \ from \ both \ sides\\\\5x - 2y - 5x = 10 - 5x\\\\-2y = 10-5x\\\\Dividing \ both \ sides\ by \ -2;\\\\\frac{-2y}{-2} = \frac{10-5x}{-2}\\ \\[/tex]

[tex]y = \frac{10}{-2} - \frac{5x}{-2} \\\\y = -5 + \frac{5x}{2}\\\\y = \frac{5x}{2} - 5[/tex]

Hence the equation that represents the first equation written in slope-intercept form is [tex]y = \frac{5x}{2} - 5[/tex]

==================================================

Work Shown:

T(2) = 20 means the second term is 20

T(1) = 26 because we go backwards from what the rule says (subtract 6) to step back one term. Going forward, 26-6 = 20.

Since a = 26 is the first term and d = -6 is the common difference, the nth term is

T(n) = a + d*(n-1)

T(n) = 26 + (-6)(n-1)

T(n) = 26 - 6n + 6

T(n) = -6n + 32

Plugging n = 1 into the equation above leads to T(1) = 26. Using n = 2 leads to T(2) = 20.

Plug in n = 10 to find the tenth term

T(n) = -6n + 32

T(10) = -6(10) + 32

T(10) = -60+32

T(10) = -28

Answer:

-28.

Step-by-step explanation:

T(1) = 20 + 6 = 26.

This is an arithmetic series  with:

nth term T(n) =  26 - 6(n - 1).

So T(10) = 26 - 6(10-1)

= 26 -54

= -28.

[tex](2+3)^{-1}\equiv5^{-1}\pmod7[/tex] is the number L such that

[tex]5L\equiv1\pmod7[/tex]

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so L = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

[tex]2a\equiv1\pmod7\implies a\equiv4\pmod7[/tex]

since 2*4 = 8, whose residue is 1 mod 7;

[tex]3b\equiv1\pmod7\implies b\equiv5\pmod7[/tex]

which we got for free by finding the inverse of 5 earlier. So

[tex]2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7[/tex]

and so R = 2.

Then L - R = 1.

Answer:

C

Step-by-step explanation:

x+4> 8

Subtract 4 from each side

x+4-4>8-4

x > 4

Open circle at 4, line going to the right

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▹ Answer

[tex]Solved - x > 4\\Graphed - C[/tex]

▹ Step-by-Step Explanation

x + 4 > 8

x > 8 -4

x > 4

When graphing inequalities, you have less than, greater than, less than or equal to, and greater than or equal too. When graphing an inequality with less than or greater than, you use an open circle. When graphing an inequality with less than or equal too or greater than or equal too, you used a closed circle.

Since the numbers are positive, we are going to move up the number line therefore leaving us with the answer of C.

Hope this helps!

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Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

B.

Step-by-step explanation:

First, let's start from the parent function. The parent function is:

[tex]f(x)=\sqrt{x}[/tex]

The possible transformations are so:

[tex]f(x)=a\sqrt{bx-c} +d[/tex],

where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.

From the given equation, we can see that a=1 (so no change), b=3, c=-3 (negative 3), and d=3.

Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the left (because it's negative), and a vertical shift of 3 upwards (because it's positive).

Answer:

Option B.

Step-by-step explanation:

According to the question, the data provided is as follows

[tex]H_o : p_1 - p_2 = 0\ (p_1 = p_2)\\\\ H_\alpha : p_1 - p_2 < 0\ (p_1 < p_2)[/tex]

Based on the above information,

The type ii error is the error in which there is an acceptance of a non rejection with respect to the wrong null hypothesis. The type I error refers to the error in which there is a rejection of a correct null hypothesis and the type II refers that error in which it explains the failure of rejection with respect to null hypothesis that in real also it is wrong  

So , the type II error is option B as we dont create any difference also the proportion is very less