The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 minutes. What is the probability that a flight is between 125 and 140 minutes

Answers

Answer 1

Answer: 0.5

Step-by-step explanation:

If the probability of the time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 minutes. Therefore, the probability that a flight is between 125 and 140 minutes is 0.5


Related Questions

Question 15 of 25
What is the solution to this equation?
X + 8 = -3​

Answers

Answer:

x=-11

Step-by-step explanation:

x+8=-3

x=-3-8 :- collect like term

since we are adding two negative numbers, we will let the number be negative but add them.

x=-11

Hope it helps :)

Answer:

x=-11

Step-by-step explanation:

x+8=-3

collect like terms;

x=-3-8

x=-11

Find the value of the chi-square test statistic for the goodness-of-fit test. You wish to test the claim that a die is fair. You roll it 48 times with the following results. Number 1 2 3 4 5 6Frequency 5 10 12 9 4 8Observed frequency (O) 5,10,12,9,4,8Expected frequency (E) 8,8,8,8,8,8What is the value of the 2 test statistic?a. X2 = 3.538b. X2 = 4.182c. X2 = 5.75d. X2 = 7.667

Answers

Answer:

The value of Chi-square test statistic is χ² = 5.75.

Step-by-step explanation:

The Chi-square Goodness of fit test will be used to determine whether the die is fair or not.

The hypothesis can be defined as follows:

H₀: The die is fair.

Hₐ: The die is not fair.

The Chi-square test statistic is given by:

[tex]\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}[/tex]

Consider the table attached below.

The value of Chi-square test statistic is χ² = 5.75.

i neeed help thanksssss

Answers

Answer:

Volume: 366.6

Surface Area: 314.2

Explanation (look at below)

Step-by-step explanation:

Volume:

The radius of this sphere is 5 (half of 10). The equation will be [tex]\frac{4}{3} \pi[/tex]5^3

When you calculate that, it will become: 366.6<-- rounded to the nearest tenth.

Surface Area:

4[tex]\pi[/tex]5^2

=100Π

=314.2<-- rounded to the nearest tenth.

314.2 is the nearest tenth digit no.

For the functions f(x)=8 x 2 +7x and g(x)= x 2 +2x , find (f+g)(x) and (f+g)(3)

Answers

Answer:

(f+g)(x)= 9x² + 9x

(f+g)(3) = 108

Step-by-step explanation:

f(x)=8x² +7x

g(x)= x² +2x

(f+g)(x) = f(x) + g(x) = 8x² +7x +x² +2x = 9x² + 9x

(f+g)(x)= 9x² + 9x

(f+g)(3)= 9*3² + 9*3 = 108

2. The first and last term of an AP are 1 and 121 respectively. If the sum of the
series is 671, find a) the number of terms in) in the AP b) the common
difference between them.​

Answers

Step-by-step explanation:

since you provided 1st and the last terms

the equation can be nth term

n/2 × ( a + l) = nth sum

n/2 × ( 1 + 121) = 671

n/2 × 122 = 671

61 n = 671

n = 11

a) so there are 11 terms

then,

so as 11th term is 121

let's find common diff

a + ( n-1) d = nth term

1 +( 11-1) d= 121

10d = 121 -1

10d = 120

common difference = 12

A study of the annual population of butterflies in a county park shows the population, B(t), can be represented by the function B(t)=137(1.085)t, where the t represents the number of years since the study started. Based on the function, what is the growth rate?

Answers

Answer:

The growth rate is of 0.085 = 8.5% a year.

Step-by-step explanation:

General growth equation:

[tex]B(t) = B(0)(1+r)^{t}[/tex]

In which B(t) is the population of butterflies after t years, B(0) is the initial population and r is the growth rate, as a decimal.

We have:

[tex]B(t)=137(1.085)^{t}[/tex]

Comparing to the general equation, we have that:

[tex]B(0) = 137, 1 + r = 1.085[/tex]

Growh rate:

1 + r = 1.085

r = 1.085 - 1

r = 0.085

The growth rate is of 0.085 = 8.5% a year.

Select the type of equations. Consistent. Equivalent. Inconsistent

Answers

Answer:

Consistent.

Step-by-step explanation:

Since there is one solution ( the lines intersect), the equations are consistent

They would be inconsistent if the lines do not intersect

The would be equivalent if they are the same line

The answer would be consistent.

Step-by-step explanation:

In the graph shown here, there is only one solution

because the lines intersect at the point (5, 3).

In order for the lines to be inconsistent, the lines would have to not

meet or intersect each other but notice that this is not the case here.

The would be equivalent if they are the same exact line

so it would look like there would just be one line.

In the periodic compound interest formula Upper A equals Upper P (1 plus StartFraction r Over n EndFraction )Superscript nt ​, what does the variable n​ represent?

Answers

Answer:

The variable n represents the number of times in a year in which we compound the interest rate

Step-by-step explanation:

The periodic compound interest formula is given as;

A = P( 1 + r/n)^nt

The variable n represents the number of times in a year in which the interest rate is compounded

I can't solve this problem, can anyone help me?​

Answers

It not allowing me to click on it, there fore I can not answer sorry!!

Answer:

x < 5

Step-by-step explanation:

The total amount is 595$ and the amount Helena want to leave for equipement is 420$

595-420 = 175

The amount helena can use is 175$

each ticket costs 35$

175/35 = 5

so Helena can oly buy 5 tickets or less

x < 5     with x the number of tickets

Professor Easy's final examination has 9 true-false questions followed by 3 multiple-choice questions. In each of the multiple-choice questions, you must select the correct answer from a list of five. How many answer sheets are possible? choices

Answers

Answer:    2⁹5³ = 64,000

Step-by-step explanation:

There are 9 questions with 2 options (true or false) = 2⁹

There are 3 multiple questions with 5 options = 5³

true/false questions AND multiple choice questions

                  2⁹               x                5³                            = 2⁹5³

The marginal cost (dollars) of printing a poster when x posters have been printed is given by the following equation. C'(x)=x^-3/4 Find the cost of printing 142 more posters when 18 have already been printed.
The cost of printing 142 more posters when 18 have already been printed is $________.
(Round to the nearest cent as needed.)

Answers

Answer:

The cost of printing 142 more posters when 18 has already been printed is $5.57.

Step-by-step explanation:

We are given that the marginal cost (dollars) of printing a poster when x posters have been printed is given by the following equation C'(x)=x^-3/4.

The given equation is: [tex]C'(x) = x^{\frac{-3}{4} }[/tex]

The cost of printing 142 more posters when 18 have already been printed is given by;

Integrating both sides of the equation and using the limits we get;

[tex]\int_{a}^{b} C'(x) dx=\int_{18}^{142} x^{\frac{-3}{4}}dx[/tex]

As we know that  [tex]\int\limits {x}^{n} \, dx = \frac{x^{n+1} }{n+1}[/tex] , so;

          =  [tex]\frac{x^{\frac{-3}{4}+1 } }{\frac{-3}{4}+1 } ]^{142} __1_8[/tex]

          =  [tex]\frac{x^{\frac{1}{4} } }{\frac{1}{4} } ]^{142} __1_8[/tex]

          =  [tex]4[x^{\frac{1}{4} } } ]^{142} __1_8[/tex]

          =  [tex]4[(142)^{\frac{1}{4} }- (18)^{\frac{1}{4} }} ][/tex]

          =  $5.57

Hence, the cost of printing 142 more posters when 18 has already been printed is $5.57.

The measure of minor arc JL is 60°. Circle M is shown. Line segments M J and M L are radii. Tangents J K and L K intersect at point K outside of the circle. Arc J L is 60 degrees. What is the measure of angle JKL? 110° 120° 130° 140°

Answers

Answer:

angle JKL =  120 degrees

Step-by-step explanation:

Since arc JL is 60 degrees, the central angle is also 60 degrees.

Point K is the intersection of tanges at J and L, therefore KJM and KLM are 90 degrees.

Consider quadrilateral JKLM whose sum of internal angles = 360.

Therefore

angle JKL + angle KLM + angle LMJ + angle MJK = 360 degrees

angle JKL + 90 + 60 + 90 = 360

angle JKL = 360 - 90 - 60 -90 = 120 degrees

Answer:

120 degrees

Step-by-step explanation:

Since arc JL is 60 degrees, the central angle is also 60 degrees.

Point K is the intersection of tanges at J and L, therefore KJM and KLM are complementary or equal 90 degrees.

look at quadrilateral JKLM whose sum of internal angles = 360.

Therefore

angle JKL plus angle KLM plus angle LMJ plus angle MJK = 360 degrees

angle JKL + 90 + 60 + 90 = 360

PLEASE ANSWER FAST I WILL MARK BRAINLEIST AMD 20 POINTSBased on the figure below what is the value of X

Answers

Answer:

[tex]\boxed{9}[/tex]

Step-by-step explanation:

The two angles are complementary to each other.

That means they add up to 90 degrees.

[tex]5x+15+30=90[/tex]

[tex]5x+45=90[/tex]

[tex]5x=45[/tex]

[tex]x=9[/tex]

Answer:

x = 9

Step-by-step explanation:

So you know that the total is 90 degrees.

What you need to do is create an equation.

5x + 15 + 30 = 90

Then, solve the equation like this.

5x + 15 + 30 = 90

5x + 45 = 90

5x = 90 - 45

5x = 45

x = 45 ÷ 5

x = 9

Hope this helps! :)

In a random sample of 40 refrigerators, the mean repair cost was $150. Assume the population standard deviation is $15.50. Construct a 99% confidence interval for the population mean repair cost. Then change the sample size to n = 60. Which confidence interval has the better estimate?

Answers

Answer:  ($143.69, $156.31)

Step-by-step explanation:

Confidence interval to estimate  population mean :

[tex]\overline{x}\ \pm z\dfrac{\sigma}{\sqrt{n}}[/tex]

, where [tex]\sigma[/tex] = population standard deviation

n= sample size

[tex]\overline{x}=[/tex] Sample mean

z= critical value.

As per given,

n= 40

[tex]\sigma[/tex] = $15.50

[tex]\overline{x}=[/tex] $150

Critical value for 99% confidence level = 2.576

Then, 99% confidence interval for the population mean:

[tex]150\pm(2.576)\dfrac{15.50}{\sqrt{40}}\\\\\Rightarrow\ 150\pm6.31 \ \ (approx)\\\\\Rightarrow(150-6.31,150+6.31)=(143.69,156.31)[/tex]

Hence, the required confidence interval : ($143.69, $156.31)

How many times would a coin have to show heads in 50 tosses to have an experimental probability of 20% more than the theoretical probability of getting heads? Which of the following represents a function

Answers

Answer: The required number of heads = 30

Step-by-step explanation:

Given, Total tosses = 50

The theoretical probability of getting head = [tex]\dfrac{1}{2}[/tex]

As per given,

Experimental probability = Theoretical probability + 20% of Theoretical probability

= [tex]\dfrac{1}{2}+\dfrac{20}{100}\times\dfrac{1}{2}[/tex]

= [tex]\dfrac{1}{2}+\dfrac{1}{10}=0.5+0.1=0.6[/tex]

Required number of heads = (Experimental probability) x (Total tosses )

= 0.6 x 50

= 30

Hence, the required number of heads = 30

A relation is said to be a function if each input value corresponds to a  unique output value.

For example: {(1,2), (3,4), (2,3), (4,1))}

Answer:

35 is the Answer

The top and bottom margins of a poster are each 9 cm and the side margins are each 6 cm. If the area of the printed material on the poster is fixed at 864 cm2, find the dimensions of the poster with the smallest area.

Answers

Answer:

the dimensions of the poster with the smallest area is 36cm by 54cm

Step-by-step explanation:

✓Let us represent the WIDTH of the printed material on the poster as "x"

✓Let us represent the HEIGHT of the printed material on the poster as "y"

✓ The given AREA is given as 864 cm2

Then we have

864 cm2= xy ...................eqn(1)

We can make "y" subject of the formula.

y= 864/x .......................eqn(2)

✓The total height the big poster which includes the 9cm margin that is at the bottom as well as the top is

(y+18)

✓The total width of the poster which includes the 6cm margin that is at the bottom as well as the top is

(x+12)

✓Then AREA OF THE TOTAL poster

A= (y+18)(x+12) ...................eqn(3)

Substitute eqn (2) into eqn(3)

A= ( 18+ 864/x)(x+12)

We can now simplify by opening the bracket, as

A=18x +1080 +10368/x

A= 18x +10368/x +1080

Let us find the first derivative of A which is A'

A'= 18-(10368/x²)

If we set A' =0

Then

0= 18- (10368/x²)

18= (10368/x²)

x²= 10368/18

x²= 576

x=√576

x=24

The second derivatives will be A"= 2(10368)/x³ and this will be positive for x> 0, and here A is concave up and x=24 is can be regarded as a minimum

The value of "y" when x=24 can now be be calculated using eqn(2)

y= 864/x

y= 864/24

y=36cm

✓The total width of the poster= (x+12)

= 24+12=36cm

✓The total height big the poster= (y+18)=36+18=54cm

the dimensions of the poster with the smallest area is 36cm by 54cm

Answer:

The total width of the paper [tex]=36 cm.[/tex]

The total height of the paper [tex]=54cm[/tex]

Step-by-step explanation:

Given information:

Top margin of the paper = 9 [tex]cm\\[/tex]

Bottom margin of the paper = 6 [tex]cm\\[/tex]

Area of the printed material = [tex]864[/tex] [tex]cm^2[/tex]

Let, the width of the printed material = [tex]x[/tex]

And the height of the printed material = [tex]y[/tex]

So, Area [tex]x \times y=864[/tex] [tex]cm^2[/tex]

After including margins;

Width of the paper [tex]= (x+12)[/tex]

Height of the paper [tex]= (y+18)[/tex]

Area [tex](A) = (y+18) (x+12)[/tex]

[tex]A=18x+(10368/x)+1080\\[/tex]

Take first derivative:

[tex]A'= 18- (10368/x^2)[/tex]

When [tex]A'=0[/tex]

Then,

[tex]18-(10368/x^2)=0\\x^2=576\\x=24[/tex]

Now ,when we take second derivative and check if it is positive or not ,

We find that it is grater than zero so the obtained value can be consider as minimum and can be proceed for further solution.

Hence ,

[tex]x \times y=864\\y=864/24\\y=36\\[/tex]

Now ,

The total width of the paper

[tex]= 24+12\\=36 cm.[/tex]

And , total height of the paper

[tex]=36+18\\=54 cm.[/tex]

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The state of CT claims that the average time on death row is 15 years. A random survey of 75 death row inmates revealed that the average length of time on death row is 17.8 years with a standard deviation of 5.9 years. Conduct a hypothesis to test the state of CT's claim. What type of test should be run? t-test of a mean z-test of a proportion The alternative hypothesis indicates a right-tailed test left-tailed test two-tailed test Calculate the p-value. What is the decision? We reject the claim that the average time on death row is 15 years We fail to reject the claim that the average time on death row is 15 years

Answers

Answer:

a)The calculated value t = 4.111 > 1.9925 at 5 % level of significance

Null hypothesis is rejected

The claim that the average time on death row is not 15 years

b) The p-value is 0.000101<0.05

we reject Null hypothesis

The claim that the average time on death row is not 15 years

Step-by-step explanation:

Step(i):-

Sample size 'n' =75

Mean of the sample x⁻ = 17.8

standard deviation of the sample (S) = 5.9

Mean of the Population = 15

Null hypothesis:H₀:μ = 15 years

Alternative Hypothesis :H₁:μ≠15 years

Step(ii):-

Test statistic

                         [tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]

                        [tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }=\frac{17.8-15}{\frac{5.9}{\sqrt{75} } }[/tex]

                    t = 4.111

Degrees of freedom

ν = n-1 = 75-1=74

t₀.₀₂₅ = 1.9925

The calculated value t = 4.111 > 1.9925 at 5 % level of significance

Null hypothesis is rejected

The claim that the average time on death row is not 15 years

P-value:-

The p-value is 0.000101<0.05

we reject Null hypothesis

The claim that the average time on death row is not 15 years

Suppose that any baseball that has a coefficient of restitution that exceeds 0.625 is considered too lively. Based on the available data, what proportion of the baseballs in the sampled population are too lively

Answers

Answer:

hello some parts of your question is missing attached below is the missing parts of the question

Answer : The proportion of the baseballs in the sampled population that are too lively

P = x / n = 18 / 40 = 0.450

Step-by-step explanation:

coefficient of restitution > 0.625

Based on available data the proportion of the baseballs that is in the sampled population that are too lively can be calculated using the values below

n = 40

x = n ( p > 0.625 ) = 18

The proportion of the baseballs in the sampled population that are too lively

P = x / n = 18 / 40 = 0.450

Which is the simplified form of m Superscript negative 8 p Superscript 0? StartFraction 1 Over m Superscript 8 Baseline p EndFraction StartFraction 1 Over m Superscript 8 EndFraction StartFraction p over m Superscript 8 EndFraction m Superscript 8 PLS HELPP

Answers

Answer:

Correct Option is : StartFraction 1 Over m Superscript 8 EndFraction

Step-by-step explanation:

=> [tex]m^{-8} p^0[/tex]

According to law of exponents [tex]a^0 = 1[/tex]

=> [tex]m^{-8} (1)[/tex]

Using Law of exponents [tex]a^{-m} = \frac{1}{a^m}[/tex]

=> [tex]\frac{1}{m^8}[/tex]

The simplified form of [tex]m^{-8}p^0[/tex] is [tex]\frac{1}{m^8}[/tex].

The question is not well formatted the question might be as follows:

Which is the simplified form of [tex]m^{-8}p^0[/tex]?

[tex]\frac{1}{m^8p}[/tex][tex]\frac{1}{m^8}[/tex][tex]\frac{p}{m^8}[/tex]m⁸

What are exponents?

Exponents are numbers that say how many times a number is to be multiplied. For example, 2⁸ means 2 is multiplied 8 times.

How to solve the problem?

[tex]m^{-8}p^0[/tex] = [tex]m^{-8}[/tex]  since, p⁰=1.

⇒[tex]m^{-8}[/tex] = [tex]\frac{1}{m^8}[/tex] .

Hence, the simplified form of [tex]m^{-8}p^0[/tex] is [tex]\frac{1}{m^8}[/tex].

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find the slope of a line that is perpendicular to the line y= - 1/3x+7

Answers

the slope of the line is 3

Safegate Foods, Inc., is redesigning the checkout lanes in its supermarkets throughout the country and is considering two designs. Tests on customer checkout times conducted in two stores where the two new systems have been installed result in the following summary of the data: System A System B Size 120 100 mean 4.1 minutes 3.4 minutes Standard Deviation 2.2 minutes 1.5 minutes Test at the 0.05 level of significance to determine whether the population mean checkout times of the two systems differ. Which system is preferred?
Use both the critical and p-value approach.
Hypotheses:
Decision rule:
Calculations:
Conclusions:

Answers

Answer:

the answer would be calculations

Step-by-step explanation:

because they have do determine if the check out times differ between the two systems so they need to calculate the difference between the two

Find the zeros of g(x) = x3 + x2 – 9x – 9​

Answers

Answer: The zeros are -1,-3, and 3

Hope this helps

Answer:

let g[x]=0

then0=x3−x2-9x+9

rewrite it as x3−x2−9x+9=0

by factorising it becomes

(x−1)(x+3)(x−3)=0

therefore

either x-1=0  OR x+3=0  OR  x-3=0

which becomes

x=1   OR   x=-ve3  OR  x=3

are the zeroes of the polynomial

hope this helps

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Factor completely and then place the factors in the proper location on the grid. 4y2 + 25y + 6

Answers

Answer:

  (4y +1)(y +6)

Step-by-step explanation:

We can rewrite the middle term and factor by grouping.

  4y^2 + 25y + 6 = (4y^2 +24y) +(y +6)

  = 4y(y +6) +1(y +6)

  = (4y +1)(y +6)

A graph shows an x- and y-axis. The data line is in the shape of a "vee." The begins above the x-axis and to the left of the y-axis, extends below the x-axis to a point on the y-axis, and ascends above the x-axis to the right of the y-axis. Which statement describes the relationship between x and y? As x increases, y decreases. As x increases, y increases. As x increases, y increases and then decreases. As x increases, y decreases and then increases.

Answers

Answer:

  As x increases, y decreases and then increases

Step-by-step explanation:

You need only understand your own description of the graph:

  begins above the x-axis, extends below the x-axis, and ascends above the x-axis

This is a description of decreasing, then increasing:

  As x increases, y decreases and then increases

Answer:

C. As x increases, y increases and then decreases.

Step-by-step explanation:

Just took the Unit Test and got it correct on Edge.

Find the slope of the line passing through the points (8,-4) and (4, -8).

Answers

Answer:

1

Step-by-step explanation:

We can find the slope using

m= ( y2-y1)/(x2-x1)

   = ( -8 - -4)/( 4 - 8)

   =  ( -8 +4)/( 4 - 8)

   = -4 / -4

   = 1

Answer:

slope equals 1

Step-by-step explanation:

To do this you would need to do an equation that is [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1}}[/tex] so in this case -8 would be y2 and -4 would be y1 and 4 would be x2 and 8 would b e x1 so if you plug it into the equation we would get [tex]\frac{-8-(-4)}{4-8}[/tex] and if we simplify we get [tex]\frac{-4}{-4}[/tex] which simplifies to 1 so the slope would equal 1

I don’t know if this is right, I’m stuck. Help!

Answers

Answer:

C

Step-by-step explanation:

According to SohCahToa, cosine is adjacent over the hypotenuse.

The adjacent when looking from angle b, is 21.

The hypotenuse of this triangle is 29.

So Cos B=21/29

Fifty students are enrolled in a Business Statistics class. After the first examination, a random sample of 5 papers was selected. The grades were 60, 75, 80, 70, and 90. a) Determine the standard error of the mean

Answers

Answer:

The standard error  S.E of the mean is 5

Step-by-step explanation:

From the given data;

Fifty students are enrolled in a Business Statistics class.

After he first examination, a random sample of 5 papers was selected.

Now; let consider a random sample of 5 papers was selected. with the following grades : 60, 75, 80, 70, and 90

The objective of this question is to determine the standard error of the mean

In order to achieve this ; we need to find the mean and the standard deviation from the given data.

TO start with the mean;

Mean [tex]\overline X[/tex] = [tex]\dfrac{1}{n} \sum x_i[/tex]

Mean [tex]\overline X[/tex] = [tex]\dfrac{1}{5} (60+75+80+70+90)[/tex]

Mean [tex]\overline X[/tex] = 0.2(375)

Mean [tex]\overline X[/tex] = 75

On the other hand; the standard deviation is :

[tex]s = \sqrt{\dfrac{1}{n-1}\sum(x_i - \overline X)^2}[/tex]

[tex]s = \sqrt{\dfrac{1}{5-1}((60-75)^2+(75-75)^2+(80-75)^2+(70-75)^2+(90-75)^2 )}[/tex]

[tex]s = \sqrt{\dfrac{1}{4}(225+0+25+25+225 )}[/tex]

[tex]s = \sqrt{\dfrac{1}{4}(500 )}[/tex]

[tex]s = \sqrt{125}[/tex]

s = 11.18

Finally; the standard error  S.E of the mean is:

[tex]S.E = \dfrac{s}{\sqrt{n}}[/tex]

[tex]S.E = \dfrac{11.18}{\sqrt{5}}[/tex]

[tex]S.E = \dfrac{11.18}{2.236}[/tex]

[tex]S.E = 5[/tex]

The standard error  S.E of the mean is 5

Improving the quality of high-value decision making by an executive will save an organization far more money than improving the quality of lesser-value decisions made at a lower level.
A. True
B. False

Answers

Answer:

A. True

Step-by-step explanation:

Since it is lesser, it will also bring in lesser profit :)

The square below represents one whole.

Answers

Answer:

6 percent

Step-by-step explanation:

6/100 is shaded. This is the same thing as 0.06. Once I move the decimal two places to the right, I get 6. (I move the decimal place because percents are out of 100, so two decimal places.) This means 6 percent.

Which choice is equivalent to 4 square root 8

Answers

Answer:

A

Step-by-step explanation:

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Other Questions
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