Physics College

The velocity of a Bus is reduced uniformly from 15 m/s to 7 m/s while traveling a distance of 90 m.
i. Compute the acceleration.
ii. How much further will the Bus travel before coming to rest, provided the acceleration remain constant?

Answers

Answer 1

Answer:

i) a = 0.977 [m/s²]

ii) x = 115.06 [m]

Explanation:

In order to determine the acceleration, we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{o} ^{2} -2*a*x[/tex]

where:

Vf = final velocity = 7 [m/s]

Vo = initial velocity = 15 [m/s]

a = acceleration [m/s²]

x = displaciment = 90 [m]

Now replacing:

[tex](7)^{2} =(15)^{2} -2*a*90\\2*a*90 = 15^{2} - 7^{2} \\180*a=176\\a=0.977[m/s^{2}][/tex]

When the bus coming to rest.

[tex]v_{f}^{2} =v_{o} ^{2} -2*a*x\\0 = 15^{2} -2*0.977*x\\x = 115.06[m][/tex]

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Answers

Answer:

that is cool and i have one interesting fact

Explanation: North Korea and Cuba are the only places you can't buy Coca-Cola

this is sick :)

thanks for sharing , i mean i don’t really have a fun fact but did you know that every time you learn something new your brain wrinkles i think

7. How many forces are acting on this object? *
Fnorm
Ffrict
Fapp
Fgray
Å

Answers

Answer:

4

Explanation:

As you can see in the free body diagram there are 4 forces acting on the body.

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